3 lines are shown. A line with points C, A, F intersects a line with points E, A, B at point A. A line extends from point A to point D in between angle E A F. Angle C A E is 61 degrees, angle D A F is 90 degrees, and angle F A B is 61 degrees. Find the following angle measures. mAngleEAD = ° mAngleCAB = °
Answers
Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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m < EAD = 29 degrees
m < CAB = 119 degrees
It is given that Angle C A E is 61 degrees,
angle D A F is 90 degrees,
angle F A B is 61 degrees
We need to find mAngleEAD and mAngleCAB
What is sum of linear pair angles?
The sum of linear pairs is 180 degrees
Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
m<BAC + m<EAC = 180 degrees (sum of linear pair)
m<CAB = 180 degrees - m<EAC
Equation 1: m<CAB = m<EAF = 119 degrees
m<EAF = m<EAD + m< DAF
m<EAD = m<EAF - m<DAF
m<EAD = 119 degrees-90 degrees = 29 degrees
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