3
1 point
The formula for acetic acid is HC H302
What is the percent composition of carbon in acetic acid?
molar mass of the element you need to find a percentage of
molar mass of the entire substance
40.0%
20.0%
33.3
41.4%
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Answer:

it is logic: everybody

Explanation:

that's the song

Answer:

Explanation

Answer:

I guess it WATER

Answer:

C and B are the correct answers

Answer:

Mars and jupiter

Explanation:

Similarities

-both circle the sun

-both have atmospheres

- both have moons

Differences

-mars is red and rocky

-jupiter is the largest planet

-mars is most like our earth

- jupiter has rings

Answer:

Here are a few more examples:

Smoke and fog (Smog)

Dirt and water (Mud)

Sand, water and gravel (Cement)

Water and salt (Sea water)

Potassium nitrate, sulfur, and carbon (Gunpowder)

Oxygen and water (Sea foam)

Petroleum, hydrocarbons, and fuel additives (Gasoline)

Heterogeneous mixtures possess different properties and compositions in various parts i.e. the properties are not uniform throughout the mixture.

Examples of Heterogeneous mixtures – air, oil, and water, etc.

Examples of Homogeneous mixtures – alloys, salt, and water, alcohol in water, etc.

Explanation:

Answer:

smog,mud, cement?

Explanation:

Smoke and fog (Smog)

Dirt and water (Mud)

Sand, water and gravel (Cement)

Answer:

Answer:

you have 6 pbco3 ok

fgbhh

Answer:

5

Explanation:

Answer:

5

Explanation:

Answer:

Sucrose contains two sugars (fructose and glucose) joined by their glycosidic bond in such a way as to prevent the glucose isomerizing to aldehyde, or the fructose to α-hydroxy-ketone form. Sucrose is thus a non-reducing sugar, which does not react with Benedict's reagent.

Explanation:

Answer:

Sucrose contains two sugars (fructose and glucose) joined by their glycosidic bond in such a way as to prevent the glucose isomerizing to aldehyde, or the fructose to α-hydroxy-ketone form. Sucrose is thus a non-reducing sugar, which does not react with Benedict's reagent.

Explanation:

please give me brainlist and follow

Answer:

M=0.380 M.

Explanation:

Hello there!

In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:

[tex]n_{Br^-}^{in\ AlBr_3}=4.85 gAlBr_3*\frac{1molAlBr_3}{266.69gAlBr_3}*\frac{3molBr^-}{1molAlBr_3} =0.05456molBr^-\\\\n_{Br^-}^{in\ ZnBr_2}=7.75gZnBr_2*\frac{1molZnBr_2}{225.22gZnBr_2}*\frac{2molBr^-}{1molZnBr_2} =0.06882molBr^-[/tex]

Now, we compute the total moles of bromide:

[tex]n_{Br^-}=0.05456mol+0.06882mol\\\\n_{Br^-}=0.12338mol[/tex]

Then, the total volume in liters:

[tex]150mL+175mL=325mL*\frac{1L}{1000mL} \\\\=0.325L[/tex]

Therefore, the concentration of total bromide is:

[tex]M=\frac{0.12338mol}{0.325L}\\\\M=0.380M[/tex]

Best regards!

Answer:

The sand and water end up at the same temperature. The sand consists of material that all has the same specific heat. The relations between temperature change and heat lost by the water and gained by the sand can be written separately as: (1) where and are the specific heats of water and sand, respectively. By assumption, the heat gained

Explanation:

Answer:

Explanation:

i think the anwer would be that its elliptical orbit and the tilt an its axis.

Answer:

Crystallization or crystallisation is the process by which a solid forms, where the atoms or molecules are highly organized into a structure known as a crystal. Some of the ways by which crystals form are precipitating from a solution, freezing, or more rarely deposition directly from a gas.

Answer:

By strengthening the weak coral that is on the reef.

Answer: To encourage plants and animals to set up homes there to increase biodiversity.

Answer:

The claim is incorrect because the exact position of matter is always visible or can be determined.

Answer:

The molecular formula of this compound is (2) C2H4O2.

Explanation:

Answer:

an ecosystem

Explanation:

it compromises of living and non living things in an environment.

Answer:

pH and pOH are related to one another; THEY ARE NOT INDEPENDENT OF EACH OTHER. As pH increases, pOH decreases. As pH decreases, pOH increases. By knowing what ion you are measuring on which scale, this will tell you whether or not the solution is acidic or basic.

Explanation:

So now i don't know if that will get more or less basic. But errr.... Hope this helps!!

If the pOH increases is a solution, the solution is getting less basic and more acidic.

We know that when pH increases, pOH decreases. We also know that when pH increases acidity decreases and basic nature of solution increases but in pOH, the sequence is opposite. When pOH increases acidity increases and basic nature of solution decreases.

So we can conclude that If the pOH increases is a solution, the solution is getting less basic and more acidic.

Learn more about basic here:  https://brainly.com/question/3948796

Answer:

pH = 9.475

Explanation:

Hello there!

In this case, according to the basic ionization of the hydroxylamine:

[tex]HONH_2+H_2O\rightarrow HONH_3^++OH^-[/tex]

The resulting equilibrium expression would be:

[tex]Kb=\frac{[HONH_3^+][OH^-]}{[HONH_2]} =1.1x10^{-8}[/tex]

Thus, we first need to compute the initial concentration of this base by considering its molar mass (33.03 g/mol):

[tex][HONH_2]_0=\frac{1.34g/(33.03g/mol)}{0.500L} =0.0811M[/tex]

Now, we introduce [tex]x[/tex] as the reaction extent which provides the concentration of the hydroxyl ions to subsequently compute the pOH:

[tex]1.1x10^{-8}=\frac{x^2}{0.0811-x}[/tex]

However, since Kb<<<<1, it is possible to solve for [tex]x[/tex] by easily neglecting it on the bottom to obtain:

[tex]x=[OH^-]=\sqrt{1.1x10^{-8}*0.0811}= 2.99x10^{-5}[/tex]

Thus, the pOH is:

[tex]pOH=-log(2.99x10^{-5})=4.525[/tex]

And the pH:

[tex]pH=14-4.525\\\\pH=9.475[/tex]

Regards!

Answer:

Glow sticks  and match would be light emission, slime would be preciptate, and cookies would be gas.

Explanation:

Answer:

[tex]\boxed {\boxed {\sf +4}}[/tex]

Explanation:

Lead (Pb) has 2 positive oxidation states, +4 and +2.

Sulfur (S) has 3 oxidation states: +6, +4, and -2. Since lead creates a positive ion, sulfur must be a negative ion to balance the charges.

There are 2 atoms of sulfur, each with a charge of -2. Therefore, their overall charge is -4, because 2* -2= -4.

A compound has a net charge of 0. To achieve this, lead must have a charge of +4 to balance out the -4 charge of sulfur.

Lead has a +4 ionic charge in PbS₂

Answer:

When these atoms gain electrons, they acquire a negative charge because they now possess more electrons than protons. Negatively charged ions are called anions. Most nonmetals become anions when they make ionic compounds. A neutral chlorine atom has seven electrons in its outermost shell.

Explanation:

Hope this helps!

Answer:

0.0986M is the concentration of the Na₂S₂O₃ solution

Explanation:

Potassium iodate, KIO₃, reacts with sodium thiosulfate, Na₂S₂O₃, as follows:

KIO₃ + 6Na₂S₂O₃ +5KI + 3H₂SO₄ → 3H₂O + 3K₂SO₄ + 3Na₂S₄O₆ + 6NaI

To solve this question we must find the moles of sodium thiosulfate that reacts as follows:

Moles KIO₃:

0.0250L * (0.0100mol / L) = 2.5x10⁻⁴moles KIO₃

Moles Na₂S₂O₃:

2.5x10⁻⁴moles KIO₃ * (6mol Na₂S₂O₃ / 1mol KIO₃) = 1.5x10⁻³ moles Na₂S₂O₃

Molar concentration:

1.5x10⁻³ moles Na₂S₂O₃ / 0.01521L =

Answer:

A

Explanation:

Answer:

Explanation:

A covalent bond is formed between two non-metals that have similar electronegativities. Neither atom is "strong" enough to attract electrons from the other

Answer:

[tex]Ka=4.71x10^{-4}[/tex]

Explanation:

Hello there!

In this case, according to the Henderson-Hasselbach equation, it is possible to write:

[tex]pH=pKa+log(\frac{[A^-]}{[HA]} )[/tex]

Next, since we are given the pH and the [A–]/[HA] ratio, we can solve for the pKa as shown below:

[tex]pKa=pH-log(\frac{[A^-]}{[HA]} )[/tex]

Now, we plug in the values to obtain:

[tex]pKa=3.92-log(0.41 )\\\\pKa=3.33[/tex]

Next, Ka is:

[tex]Ka=10^{-pKa}=10^{-3.33}\\\\Ka=4.71x10^{-4}[/tex]

Best regards!