(3x2)(−2x4) = 3(−2)x2∙4 = 6x8 can you find whats wrong with this problem

Answer:

the equal sign

Step-by-step explanation:

The final correct result is:[tex](3x^2)(-2x^4) = -6x^6[/tex]

Given that:

The expression: [tex](3x^2)(-2x^4) = 3(-2)x^{2\times4} = 6x^8[/tex]

The error is in the second step of the simplification:

[tex](3x^2)(-2x^4) = 3(-2)x^{2\times4} \\(3x^2)(-2x^4) = 6x^8[/tex]

[tex](3x^2)(-2x^4) = 3(-2)x^{2\times4} = 6x^8[/tex]

The second step is incorrect. The correct rule for multiplying powers with the same base is to add the exponents, not multiply them.

Here, add the power of x is 2 and 4, that is,

2 + 4 = 6

And multiply the coefficient of x as:

The coefficient of x are 3 and (-2).

So, the multiplication as:

3 × (-2) = -6

The correct simplification should be:

[tex](3x^2)(-2x^4) = 3\times(-2) \times x^{2+4}\\(3x^2)(-2x^4) = -6x^6[/tex]

So, the multiplication as:

3 × (-2) = -6

So, the final correct result is:

[tex](3x^2)(-2x^4) = -6x^6[/tex]

Hence, the error occupied in second step.

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