Supplementary angles add 180 degrees.
One of the two angles is 8 degrees more than 3 times the other.
If one of the angles is A and the other is B, then:
[tex]A=8+3B[/tex]As they are supplementary, they add 180 degrees:
[tex]A+B=180[/tex]We replace the information of the second equation in the first one and solve:
[tex]\begin{gathered} A=180-B \\ A=8+3B=180-B \\ 8+3B=180-B \\ 4B+B=180-8 \\ 5B=172 \\ B=\frac{172}{5} \\ B=34.4 \end{gathered}[/tex]Now we can solve for the other angle:
[tex]A=8+3B=8+3(34.4)=8+103.2=111.2[/tex]The measure of the angles is 34.4 degrees and 111.2 degrees.
2. A membership to the theme park is $48 per year. Marcos cancelled his membership early and is only required to pay for 0.25 of a year. How much will he need to pay?
Marcos needs to pay $12 for 0.25 of a year due to cancelling the membership
Membership cost to the theme park per year = $48
Payment required to be made by Marcos = 0.25 of a year
When we divide a whole into smaller parts, we get decimals. Then, there are two parts to a decimal number: a whole number part and a fractional part. The whole component of a decimal number has the same decimal place value system as the complete number. However, as we proceed to the right following the decimal point, we obtain the fractional portion of the decimal number.
Converting the decimal into a fraction we get:
=0.25
= 25/100
= 1/4 of a year
So, Marcos needs to pay the membership fees for only 1/4 of a year
According to which we get: 48*1/4 = $12
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I just need to know how to work it out for future problems. (Business Calc)
Find the price elasticity of the demand function as a function of p.
1. q=D(p)=600-3p
A)E(p)= p/p-200
B)E(p)= p/600-3p
C)E(p)= p/200-p
D)E(p)= p(200-p)
The price elasticity of the demand function as a function of p is C. E(p)= p/200-p
How to illustrate the information?It should be noted that the price elasticity of demand simply means the ratio of the percentage change in quantity demanded to the percentage change in price.
In this case, the function is given as:
q = D(p) = 600-3p
Differentiate with respect to p
D'(p) = 3
The elasticity of demand will be:
= (P / 600 - 3p) × (-3)
= P / (200 - P)
In conclusion, the correct option is C.
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Rajan climbed to a height of 15 ft from the bottom of a climbing wall. He then climbed up an additional 10 ft.
What must he do to return to the bottom of the climbing wall?
In the first blank, say whether Rajan must climb up or down. In the second blank, state the number of feet Rajan must travel up or down.
Rajan must climb_____ft to return to the bottom of the climbing wall.
Rajan must climb down 25 ft to return to the bottom of the climbing wall
Height climbed from the bottom of the wall = 15ft
Height: The measurement of an object's height from the base to the top is known as height. It is sometimes referred to as altitude in geometry. The vertical distance between the lowest and highest point is measured. In coordinate geometry, it is often the measurement along the y-axis of an object.
Additional height climbed = 10ft
Total height climbed = 25ft
He should climb down the distance, as climbing up will further move him away from the bottom of the wall
Distance to climb down to the bottom of the wall = 25ft
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Suppose 72% of students chose to study French their freshman year, and that meant that there were 378 such students. How many students chose not to take French their freshman year?
As per the given percentage, there are 147 students are not take French their freshman year.
Students:
The students are the person formally engaged in learning, especially one enrolled in a school or college.
Given,
Suppose 72% of students chose to study French their freshman year, and that meant that there were 378 such students.
Here we need to find the number of students who are not take French as their freshman year.
Let x be the total number of students in the freshman year.
So according to the given question, we know that,
72% of x = 378
Therefore, we have to find the value of x, so we have to move the others,
Then we get,
x = 378/72%
x = 378 x 100/72
x = 525
So, the total number of students are 525.
Then the students who are not taken French is,
=> 525 - 378 = 147
Therefore, the students who are not taken French is 147.
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it says on top that the image is not drawn to scale.
D; Both statements are correct
Here, we want to check the correct statement
Basically from the diagram, it is confirmed that what we have is a 30-60-90 triangle
Now, for a 30-60-90 degrees triangle, the side lengths are in a particular ratio
From the diagram, MO faces the right angle and thus, it is the longest side and the hypotenuse
Now, let us take a look at the ratio of the sides in both submissions
For a 30-60-90 degrees triangle, the ratio of the sides is;
[tex]1\colon\sqrt[]{3}\text{ :2}[/tex]Hence, one side must be twice the length of the other
From Kellie's statement we can see MO is twice NO
From Eddie's statement, we can also see that MO is twice NO
Lastly, we can also see in both that dividing MN by NO yields the root of 3 in both statemets which confirms the existence of the theoretical ratio
So the conclusion here is that;
Both students are correct
5 tons of rocks cost $7,000.00. What is the price per pound ??
Answer: Per rock or pound?
on a map where each unit represents one kilometer two marinas are located at p(4,2) and q(8,12). if a boat travels in a straight line from one marina to the other how far does the boat travel. Answer choices: 14 kilometers 2sqrt296 kilometer 2sqrt5 kilometers
Solution:
Given the points below
[tex]p\left(4,2\right)and\text{ }q\left(8,12\right)[/tex]To find the distance between two points, the formula is
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Where point p represents coordinates 1 and point q represents coordinates 2
Substitute the coordinates into the formula above
[tex]\begin{gathered} d=\sqrt{(8-4)^2+(12-2)^2} \\ d=\sqrt{4^2+10^2} \\ d=\sqrt{16+100} \\ d=\sqrt{116} \\ d=\sqrt{4\times29} \\ d=2\sqrt{29}\text{ units} \end{gathered}[/tex]Since, 1 unit represents 1 kilometer on the map,
Hence, the answer is
[tex]2\sqrt{29}\text{ km}[/tex]Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Find the difference. Write your answer in simplest form.
The mixed fraction 11 [tex]\frac{7}{16}[/tex] - 4[tex]\frac{7}{12}[/tex] is equivalent to the fraction to 6 41/48
How to solve an equation?An equation shows the relationship between two or more numbers and variables.The mixed fraction 11 7/16 is equivalent to the fraction (11 * 16 + 7)/16 = 183/16
The mixed fraction 4 7/12 is equivalent to the fraction (4 * 12 + 7)/12 = 55/12
Substituting:= 18 [tex]\frac{3}{16}[/tex] - 5 [tex]\frac{5}{12}[/tex]
Simplifying:= 329/48
= 6 41/48
11 [tex]\frac{7}{16}[/tex] - 4 [tex]\frac{7}{12}[/tex] is equal to 6 [tex]\frac{41}{48}[/tex]
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Four of the twelve members of the panel were late for
the meeting. What fraction of the members were on
time?
Answer:
2/3
Step-by-step explanation:
If 4 were late, then 8 were on time.
8/12 Divide the top and bottom by 4
2/3
Helping my son with homework.. I have no clue what this is
Answer:
45 times
Step-by-step explanation:
it is 45 times because it can land on blue or green 5 out of 8 times so u do 72 divided by 8 and u get 9 so I do 9 times 5 and u get 45
Write the inequality shown by the shaded region in the graph with the boundary line y = -3x +5
Inequality is an inequality comparison of numbers or expressions.
Given inequality:
y < -3x+5, y < x+2, y < -1
Graph the above inequality using Geogebra's online graphing calculator.
Answer:
...................... Hoffe er u
can you help me factor the expression x^2+4x-21
To factor this expression we need to find two numbers which sum is 4 and the product is -21.
Now, 21 has only 2 factors (besides 1 and 21), 7 and 3, se we need to write them in a way such that they sum 4, so
[tex]x^2+4x-21=(x+7)(x-3)[/tex]we see that 7-3=4 and 7(-3)=-21, so the factorization is correct.
How many times larger is 8.1 than 2.7
Can you please help me solve this questions. I want a clear explanation thank you.
Given:
[tex]\begin{gathered} \text{Mean}=\mu=21.4 \\ \text{Standard deviation=}\sigma=5.0 \\ \text{Smple size=n=66} \end{gathered}[/tex]The z-score for 90 percent is 1.64.
To find the 90 percent confidence interval,
[tex]\begin{gathered} \mu+(\frac{\sigma}{\sqrt[]{n}}\times1.64)=21.4+(\frac{5}{\sqrt[]{66}}\times1.64) \\ =21.4+1.0094 \\ =22.4094\ldots\ldots(\text{ upper limit)} \\ \text{And} \\ \mu-(\frac{\sigma}{\sqrt[]{n}}\times1.64)=21.4-(\frac{5}{\sqrt[]{66}}\times1.64) \\ =21.4-1.0094 \\ =20.3906\ldots\ldots\ldots(\text{lower limit)} \end{gathered}[/tex]Answer: The 90 % confidence interval is ( 20.3906 , 22.4094 )
Question 10The table below shows the amount of water that is in a bathtub that is being filled.Minutes1234Gallons ofWater12172227Which of the following functions could model the amount of gallons of water, f(x), that the bathtub will contain after x minutes of being filled?Аf(x) = 5x + 7Bf(x) = 5x + 12сf(x) = 7x + 5Df%) = 12x + 5No
A person tosses a coin 14 times. In how many ways can he get 10 heads?
Jolie is redesigning a water bottle to fit better in her cup holder. The diameter will have to be no larger 2.5 in. The water bottle is straight up and down. What would the height of the bottle be if she wants it to have a 99.34 in3 volume. (Round to nearest whole number)
20in
Explanations:The water bottle in question is known to be cylindrical in shape. The formula for calculating the volume of a cylinder is expressed as:
[tex]V=\pi r^2h[/tex]where;
r is the radius
h is the height
Given the following parameters
diameter = 2.5in
radius = 2.5/2 = 1.25in
volume = 99.34 in^3
Required
Height of the water bottle
Substitute the given parameters intothe formula
[tex]\begin{gathered} 99.34=3.14(1.25)^2\times h \\ 99.36=4.90625h \\ h=\frac{99.36}{4.90625} \\ h=20.25\approx20in \end{gathered}[/tex]The height of the water bottle will be 20in
If you spend 1 hours a week studying for English and 3.5 hours studying for math what is the ratio of time spent studying in math to studying for English?
The ratio of time spent studying math to studying English is 7:2.
According to the question,
We have the following information:
One spends 1 hour a week to study English and 3.5 hours to study math.
Now, we know that the ratio can be simply understood as the division.
So, we will divide the number of hours devoted to math by the number of hours devoted to English.
Ratio of time spent studying math to studying English = 3.5/1
Ratio of time spent studying math to studying English = 35/10
(Now, we will convert this fraction into the simplest form by dividing both the numerator and denominator of the fraction by 5.)
Ratio of time spent studying math to studying English = 7/2
Ratio of time spent studying math to studying English = 7:2
Hence, the ratio of time spent studying math to studying English is 7:2.
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If f (x) = x
2 − 2 x , g (x) = x − 2
1) prove that : f(2) = g(2)
2) If g (K) = 7 , find : the value of k
1. The value of f(2) = 0 and g(2) = 0
2. The value of k is 9
What is a function?A function can simply be described as a law, rule, theorem or expression that explains the relationship between two terms.
These terms are known as;
The dependent variableThe independent variableGiven the functions;
f(x) = x^2 - 2xg(x) = x - 21To prove that f(2) = g(2)
Substitute the value of x as 2 in the functions, we have;
f(2) = 2^2 - 2(2)
expand the bracket
f(2) = 4 - 4
f(2) = 0
Then for g(2), we have;
g(2) = 2 - 2
g(2) = 0
Then, f(2) = g(2) = 0
If g(k) = 7
Then, we have;
k - 2 = 7
collect like terms to determine the value of k
k = 7 + 2
k = 9
Hence, the value is 9
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(3ax - n) ÷ 5
Solve for X.
Answer:
x = 10/a; restrictions a ± 0
Answer:
[tex]x = \cfrac{n+5}{3a}[/tex]=============================
Given expression
[tex](3ax - n) : 5 = 1[/tex]Solve it for x in steps below:
[tex]3ax - n = 5[/tex][tex]3ax = n + 5[/tex][tex]x = \cfrac{n+5}{3a}[/tex]To rent a certain meeting room, a college charges a reservation fee of $46 and an additional fee of $6.70 per hour. The math club wants to spend less than$106.30 on renting the meeting room.What are the possible amounts of time for which they could rent the meeting room?Use t for the number of hours the meeting room is rented, and solve your inequality for t.
As given by the question
There are given that the college charges a reservation fee of $46.
Now,
According to the question, the inequality is:
[tex]46+6.70t<106.30[/tex]Then,
To solve the above inequality, collect the constant terms on the right side
So,
[tex]\begin{gathered} 46+6.70t<106.30 \\ 6.70t<106.30-46 \\ 6.70t<60.3 \\ t<\frac{60.3}{6.70} \\ t<9 \end{gathered}[/tex]Hence, the room could be rented for up to 9 hours less than the stated amount.
PLS HELP WILL MARK YOU BRAINLIEST!!
Point B is the midpoint of AC. AB=2x and AC=3x+20.
What is the value of x?
x=-20
x=20
x=4
x=6
Answer:
X=4
Step-by-step explanation:
i got the answer on a different app
Answer: The correct answer is 20 or -20
Step-by-step explanation:
its between 20 and -20 since i selected x=6 and x=4 and they were both wrong lol
In the distribution shown, state the mean and the standard deviation. Hint: The vertical lines are 1 standard deviation apart.
We are given a distribution graph.
The mean of the distribution is the center that is 125.
[tex]\operatorname{mean}=\mu=125[/tex]The standard deviation is given by
[tex]std=\sigma=153-125=28[/tex]Therefore, the mean of the distribution is 125 and the standard deviation is 28.
Find X.
Cirucumscribed angles
Answer:
x = 64
Step-by-step explanation:
to find x add make an equation to solve for x. the equation is 90+90+44+2x+8=360. after solving for x, x will equal 64.
The number of hours it takes for ice to melt varies inversely with the air temperature. A block of ice melts in 2.5 hours whenthe temperature is 54 degrees.How long would it take for the same block of ice to melt if the temperature was 45 degrees?
Let t be the time in hours it takes a block of ice to melt at T degrees.
Since both variables have an inverse relation, we can say that:
[tex]t=\alpha\cdot\frac{1}{T}[/tex]Where alpha is a constant value.
Since we know that a block of ice melts in 2.5 hours when the temperature is 54 degrees, we can plug in such data and find alpha as following:
[tex]\begin{gathered} 2.5=\alpha\cdot\frac{1}{54}\rightarrow2.5\cdot54=\alpha \\ \Rightarrow\alpha=135 \end{gathered}[/tex]Therefore, our expression would be:
[tex]t=\frac{135}{T}[/tex]For T = 45,
[tex]\begin{gathered} t=\frac{135}{45} \\ \\ \Rightarrow t=3 \end{gathered}[/tex]We can conclude that it would take 3 hours for the block of ice to melt.
HELP ASAP HELP ASAP PLEASEEEEE
The distance between the parallel lines measured in the y direction is 3 units.
How to find the distance between the two given linesgiven data
y = - 3x + 4
y = - 3x + 1
let line 1 be y = - 3x + 4 and line two be y = -3x + 1
Analyzing the two lines show that the slope is equal hence parallel
slope = -3
The y intercept of the line or just the intercept is what varied
line 1 = 4line 2 = 1The difference between these two pints represents the distance between them measured in the y direction.
The difference is solved as
4 - 1 = 3 units
The distance is 3 units
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What is the exact decimal equivalent of 7/12
Answer:
0.58333333333
convert these measurements to centimeters : (a)73.1 cm and (b) 0,0012km
Answer:
(a) 73.1 cm (b) 120 cm
Step-by-step explanation:
Step-by-step explanation:
Part (a)
73.1 cm [It remains the same as it is already given in cms]
Part (b)
To convert 0.0012km to cm we multiply x 100000
=> 0.0012 x 100000
=> 120 cm
Find sinθ, tanθ, and secθ, where θ is the angle shown in the figure. Give exact values, not decimal approximations.sinθ=tanθ=secθ=
1) We have here a right triangle, so we can use the Pythagorean Theorem to find the adjacent leg. Note that the hypotenuse is leg opposite to the right angle. In this case, a=4.
a²=b²+c²
4²=b²+3²
16=b²+9
16-9=b²
b=√7
2) Let's find the trigonometric functions. The first one is the sine (θ), which relates the opposite side and the hypotenuse:
[tex]\sin (\theta)\text{ =}\frac{3}{4}[/tex]2.2)Moving on, we can deal with the tangent of theta, relating the opposite side over the adjacent, for this one we have to rationalize it:
[tex]\begin{gathered} \tan (\theta)\text{ =}\frac{3}{\sqrt[]{7}} \\ \tan (\theta)=\frac{3\sqrt[]{7}}{7} \end{gathered}[/tex]Finally, let's find the reciprocal function of the cosine function by setting this as the reciprocal of the cosine, and then calculating it:
[tex]\begin{gathered} \sec \text{ (}\theta)=\frac{1}{\cos(\theta)}\Rightarrow\sec (\theta)=\frac{1}{\frac{\sqrt[]{7}}{4}}\Rightarrow\sec (\theta)\text{ =}\frac{4}{\sqrt[]{7}} \\ \sec (\theta)\text{ =}\frac{4\sqrt[]{7}}{7} \end{gathered}[/tex]which number is the closest approximation to the value of 3/94?
Answer:
[tex] \frac{1}{3} [/tex]
Step-by-step explanation:
[tex] \frac{3}{94} = 0.31 \\ \\ \frac{1}{3} = 0.33[/tex]