48% of people in a certain country like to cook and 54% of people in the country like to shop, while 26% enjoy both activities. What is the probability that a randomly selected person in the country enjoys cooking or shopping or both? The probability that a randomly selected person in the country enjoys cooking or shopping or both is ________

Answers

Answer 1

The probability that a randomly selected person in the country enjoys cooking or shopping or both will be;

⇒ P (C ∪ S) = 0.76

What is mean by Probability?

The term probability refers to the likelihood of an event occurring.

Given that;

48% of people in a certain country like to cook.

And, 54% of people in the country like to shop, while 26% enjoy both activities.

Now,

Probability to like the cook P (C) = 48%

Probability to like the shop P (S) = 54%

Probability to like the both activity P (C∩S) = 26%

So, Probability to like the both activity P (C ∪ S) is calculated as;

P (C ∪ S) = P (C) + P (S) - P (C ∩ S)

P (C ∪ S) = 48% + 54% - 26%

P (C ∪ S) = 102% - 26%

P (C ∪ S) = 76%

P (C ∪ S) = 0.76

Thus, The probability that a randomly selected person in the country enjoys cooking or shopping or both will be;

⇒ P (C ∪ S) = 0.76

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Related Questions

Fay is paid semimonthly. The net amount of each paycheck is $670.50.What is her net annual income?a. $17,433b. $4,023c. $16,092d. $8,046

Answers

Answer:

c. $16,092

Explanation:

• Fay is paid semimonthly, that is, ,twice a month,.

,

• There are ,12 months in a year,.

Thus, the number of paychecks she receives annually is: 2 x 12 = 24.

The net amount of each paycheck is $670.50.

In order to get her net annual income, multiply the net amount on each paycheck by the number of payments.

[tex]\text{Net Annual Income}=24\times670.50=\$16,092[/tex]

Fay's net annual income is $16,092.

Option C is correct.

[tex] \rm\int_{0}^{ \frac{\pi}{2} } \frac{1}{ \sqrt{1 - {sin}^{2} ( \frac{1}2) {sin}^{2} \varphi } } d \varphi \\ [/tex]​

Answers

This is an another elliptical integral, but of the first kind:

[tex]\displaystyle F(k) = \int_0^{\pi/2} \frac{dx}{\sqrt{1-k^2\sin^2(x)}}[/tex]

[tex]\implies \displaystyle \int_0^{\pi/2} \frac{d\varphi}{\sqrt{1-\sin^2\left(\frac12\right)\sin^2(\varphi)}} = \boxed{F\left(\sin\left(\frac12\right)\right)}[/tex]

The table shows the amount of water Joel had in his bathtub to wash his dog and his desired water level. If the water drains at a rate of 14 gallons per minute, how many minutes will it take the tub to drain to his desired level?
Starting Water Level = 42 gallons
Desired Water Level = 28 gallons

Answers

It will take 1 minute to tub to drain to his desired level, by Rate of change.

What is rate of change?

Rate of change is used to mathematically describe the percentage change in value over a defined period of time.

Given, starting water value = 42 and desired water level = 28

Rate of change = 14 gallons.

Let x be the time,

According to question,

42-14x=28

-14x=-14

x=1

Hence, it will take one minute.

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Pls I need help with 2 problems as quick as possible thank you

Answers

To get the surface area of the prism given, we have to find the total area of the nets

We first split the nets into three and then find the areas

Lets us start with B

[tex]\text{Area of B=Area of a rectangle = length }\times Breadth[/tex]

Area of A and C are equal

so each of the areas is

[tex]\frac{1}{2}\times base\text{ }\times height[/tex]

But we can use a general formula for an equilateral traingular prism

[tex]\begin{gathered} =\frac{\sqrt[]{3^{}}\text{ }\times a^2}{2}+3(a\times h) \\ \text{where a=7} \\ h=18 \end{gathered}[/tex][tex]\text{Surface Area =}\frac{\sqrt[]{3^{}}\text{ }\times7^2}{2}+3(7\times18)[/tex]

Thus we have the total surface area to be approximately

[tex]\text{Surface area=}420.44ft^2[/tex]

Which ones are considered functions

Answers

Answer:

The answer is be because the x dose not repeat

Step-by-step explanation:

the x dose not repeat just look for the non repeating x

The table below gives the population of a town (in thousands) from 2000 to 2008. What was the average rate of change of population between 2002 and 2004, and between 2002 and 2006?

Answers

The average rate of change in population is -35 between 2002 and 2004, and -2.5 between 2002 and 2006 which represents the decrease in the population.

What is Lagrange mean value theorem?

Lagrange mean value theorem states that, if a function f is continuous over the closed interval [a, b] and differentiable over the open interval (a, b), then there must be at least one point c in the interval (a, b) where the slope of the tangent at the point c is equal to the slope of the tangent through the curve's endpoints, resulting in the expression f'(c) = {F(b) -F(a)}/(b-a)

As per the given data in the table, the required solution would be below

The average rate of change in population between 2002 and 2004 as:

⇒ (76-83)/(2004-2002)

⇒ -7/2

⇒ -3.5

The average rate of change in population between 2002 and 2006

⇒ (78-83)/(2006-2002)

⇒ -5/2

⇒ -2.5

This represents the decrease in the population.

Therefore, the average rate of change in population is -35 between 2002 and 2004, and -2.5 between 2002 and 2006.

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What does it mean to take a derivative? I know how it's done, but not why.

Answers

Finding the derivative of the function is just a way for us to discuss how the function changes. For example, if we want to get the derivative of function y, with respect to x (dy/dx), then it is a formal way of discussing, how y changes when x changes.

why is 5.1 bigger than 5.099

Answers

5.1 is greater than 5.099, because the value of the 1 in 5.1 is more than the value of the 99 in 5.099.

[tex]\begin{gathered} 5.1=5+0.1=5+\frac{1}{10}=5+\frac{100}{1000} \\ 5.099=5+0.099=5+\frac{99}{1000} \end{gathered}[/tex]

The value of 1 in 5.1 is 0.1, while the value of the 99 in 5.099 is 0.099.

Since 0.1 is bigger than 0.099, then 5.1 is bigger than 5.099.

Also, 5.1 is greater than 5.099 because a bigger number on 5.1 (which is 1) is closer to the decimal point compared to 5.099 (1 is bigger than 0). the closer a decimal is to the decimal point the higher its value.

A manufacturing process produces a critical part of average length 90 millimeters, with a standard deviation 2 of millimeters. All parts deviating by more than 5 millimeters from the mean must be rejected. What percentage of the parts must be rejected, on average? Assume a normal distribution.

Answers

We have that

[tex]X\sim N(\mu=90,\sigma^2=4^{})[/tex]

The parts the will be rejected when it's above 95 or when it's under 85, if we plot the normal distribution it would be

Then, the percentage of the parts that will be rejected corresponds to the area in blue, then, we must calculate the area under the normal distribution for

[tex]P(X<85)+P(X>95)[/tex]

The normal distribution is symmetrical, then calculate P(X < 85) is the same as P(X > 95), then we write it as

[tex]2\cdot P(X>95)[/tex]

Calculate that integral is very hard, then, we must transform that in a standard normal X ~ N(0, 1) and use a table to find the result, to do that we must write a value z, it's a transformation to take a value on our normal and leads it to the standard normal, it's

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

We have X = 95, μ = 90 and σ = 2

[tex]Z=\frac{95-90}{2}=2.5[/tex]

Then 2.5 is the value we are going to search in our table, using the complementary cumulative table for 2.5 we get 0.00621, which means

[tex]P(X>95)=0.00621[/tex]

And the total percentage will be

[tex]P(X<85)+P(X>95)=0.01242[/tex]

We can write it in percentage

[tex]0.01242=1.242\%[/tex]

Therefore, only 1.24% will be rejected.

It's a very low value, but it's expected because it's more than 2 standard deviations (95%).

find the exact value of cos90°.

Answers

cos90° is equal zero

What is the slope of the line that goes through the points (1,-5) and (4,1)?OA-4/3OB.-3/4Ос. 1/2OD. 2

Answers

We can calculate the slope using the next formula

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

where

(1,-5)=(x1,y1)

(4,1)=(x2,y2)

We substitute the values into the formula above

[tex]m=\frac{1+5}{4-1}=\frac{6}{3}=2[/tex]

the slope of the line is m=2, the answer is D

Suppose that the annual rate of return for a common biotechnology stock is normally distributed with a mean of 5% and a standard deviation of 6%. Find the probability that the one-year return of this stock will be negative. Round to four decimal places.

Answers

Answer:   0.2023

===================================================

Work Shown:

Compute the z score for x = 0.

z = (x - mu)/sigma

z = (0 - 0.05)/(0.06)

z = -0.83333 approximately

Then use a calculator to find that P(Z < -0.83333) = 0.2023

There's about a 20.23% chance of getting negative returns, i.e. the person will lose money on the investment.

Casey deposited $1,550 in a bank account that earned simple interest at an interest rate of 4%. How much interest, in dollars, was earned in 6 years?

Answers

Answer:

$372

Explanation:

From the given problem, we have the following:

• The amount deposited, Principal = $1,550

,

• The interest rate, r = 4%

,

• Time = 6 years

To determine the amount of interest earned, at simple interest, we use the formula below:

[tex]$$Simple\: Interest=\frac{Principal\times Rate\times Time}{100}$$[/tex]

Substitute the given values:

[tex]\begin{gathered} Simple\:Interest=\frac{1550\times4\times6}{100} \\ =\$372 \end{gathered}[/tex]

The interest that was earned in 6 years is $372.

An object is launched at 18.4 meters per second (m/s) from a 36.8-meter tall platform. The equation for the object's heights at time t seconds after launch is s(t) = -4.912 + 18.4t + 36.8, where s is in meters. • When does the object strike the ground? (Select ] How long did it take the object to get to its maximum height? Select ] What was the height of the object at 3.32 seconds? | Select ]

Answers

[tex]s(t)=-4.912t^2+18.4t+36.8[/tex]

1) To find when the object strikes the ground, we need to find the roots of the equation. Using quadratic formula:

[tex]\begin{gathered} t_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ t_{1,2}=\frac{-18.4\pm\sqrt[]{18.4^2-4(-4.912)(36.8)}}{2(-4.912)} \\ t_{1,2}=\frac{-18.4\pm\sqrt[]{1061.6064}}{-9.824} \\ \\ t_1=\frac{-18.4+32.582}{-9.824}=-1.44 \\ t_2=\frac{-18.4-32.582}{-9.824}=5.2 \end{gathered}[/tex]

t can't be negative, then the object strikes the ground after 5.2 seconds

2) The maximum height is the vertex of the parabola. The t-coordinate is computed as follows:

[tex]t=\frac{-b}{2a}=\frac{-18.4}{2(-4.912)}=1.87[/tex]

It takes 1.87 seconds for the object to get to its maximum height

3) To find the height after 3.32 seconds, we have to replace t = 3.32 int the equation:

[tex]\begin{gathered} s(3.32)=-4.192(3.32)^2+18.4(3.32)+36.8 \\ s(3.32)=-54.142+61.088+36.8 \\ s(3.32)=43.746 \end{gathered}[/tex]

The height was 43.746 meters

5. GMAT scores are approximately normally distributed with a mean of 547 and a standard deviation of 95. Estimate the percentage of scores that were(a) between 357 and 737. %(b) above 737. %(c) below 452. %(d) between 452 and 737. %

Answers

Problem Statement

The question tells us that the GMAT scores are approximately normally distributed with a mean of 547 and a standard deviation of 95.

We are asked to find the percentage of scores that were:

a) between 357 and 737.

b) above 737

c) below 452

d) between 452 and 737.

Solution

a) Between 357 and 737:

[tex]\begin{gathered} 357\text{ is 2 standard deviations less than the mean of 547. That is,} \\ 547-2(95)=357 \\ \text{This means that 357 is }\frac{95}{2}\text{ \% from the mean}=47.5\text{ \% from 547.} \\ \\ 737\text{ is 2 standard deviations greater than the mean of 547. That is,} \\ 737-2(95)=547. \\ \text{This means that 737 is }\frac{95}{2}\text{ \% from the mean }=47.5\text{ \% from 547} \\ \\ \text{Thus the range 'Between 357 and 737' is:} \\ (47.5+47.5)\text{ \%}=95\text{ \%} \end{gathered}[/tex]

b) Above 737

[tex]\begin{gathered} 737\text{ is 2 standard deviations away from the mean as shown in question A.} \\ \text{Thus, the percentage of scores above 737 must be:} \\ 100\text{ \% - (50 + 47.5)\% }=2.5\text{ \%} \end{gathered}[/tex]

c) Below 452:

[tex]\begin{gathered} 452\text{ is 1 standard deviation from the mean.} \\ \text{Thus the percentage of scores below 452 must be:} \\ 50\text{ \% - 34\% = 16\%} \end{gathered}[/tex]

d) Between 452 and 737:

[tex]\begin{gathered} 452\text{ is 1 standard deviation lower than the mean 547. Thus, the percentage from 452 to 547 is 34\%} \\ 737\text{ is 2 standard deviations higher than the mean of 547. Thus the percentage from 547 to 737 is: 47.5\%} \\ \\ \text{Thus the percentage between 452 and 737 is: (34 + 47.5)\%= 81.5\%} \end{gathered}[/tex]

LESSON Sine and Cosine Ratios 13-2 Practice and Problem Solving: A/B After verifying that the triangle to the right is a right triangle, use a calculator to find the given measures. Give ratios to the nearest hundredth and angles to the nearest degree. 1. Use the Pythagorean Theorem to confirm that the triangle is a right triangle. Show your work.

Answers

I saw this

is this correct? to start solving your question?

1.- Pythagorean theorem

6^2 = (5.2)^2 + (3)^2

36 = 27.04 + 9

36 = 36 Yes, it is a right triangle

2.-

[tex]\begin{gathered} \sin \text{ 1 = }\frac{5.2}{6} \\ \sin 2\text{ = }\frac{3}{6}\text{ = }\frac{1}{2} \end{gathered}[/tex]

A cube-shaped box has side lengths of 1.5 m, and it exerts a force of 63 N on the ground. Calculate the pressure, in N/m², that the box exerts on the ground. If your answer is a decimal, give it to 1 d.p.​

Answers

Answer:

28 N/m²

Step-by-step explanation:

Since you are calculating pressure, you want your question in N/m².

Note that the one side of the box has a length of 1.5m, and so to get the area of the bottom face, you need to square 1.5m::

(1.5m)² = 2.25m²

Then you need to use the formula P=F/A

Where P is pressure, F is force, and A is area, plug in your variables::

P = [tex]\frac{63N}{2.25m^{2} }[/tex]

Then you get an answer of:[tex]28 \frac{N}{m^{2} }[/tex]

You always want to make sure that the answer's units align with what you are told to solve for. In this case, they do, so no further steps are needed.

Hope this helps! :)

can you help me i have to see if it is a direct variation

Answers

a direct variation is a relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other. For instance,

[tex]y=mx[/tex]

in which variables x and y are related by a constant m. A numerical examples of a Direct variations are:

[tex]\begin{gathered} y=-5x \\ y=\frac{2}{3}x \\ y=-\frac{7}{6}x \end{gathered}[/tex]

etc. In our case, the figure shows a line. The general equation of a line is in the form

[tex]y=mx+b[/tex]

This is almost the same a direc variation, however it has the y-intercept b. In our case, form the graph, we can see that

b=4. In other words, b is the point in which the lines cross y-axis.

Hence, our line doesnt represent a Direct variation since there is a y-intercept b=4.

what is the least multiple of 8

Answers

The least multiple of a number is itself.

Least multiple of 8 : 8

Write the correct equation for the following statement.


The product of x and nine is three

Answers

Answer:

x*9 = 3

that's all

=)

Answer:

x*9=3

Step-by-step explanation:

Atleast I think so

1. Squares with side lengths 6, 8, and 10 meters?2. Squares with areas 64 in?, 100 in?, 144 in2? 3. Two squares with side length 5 feet and a square with area 50 square feet?4. Explain how you know whether three squares will join at their corners to form a right triangle.

Answers

In order to know if 3 squares will form a right triangle,

a. The sum of the length of two of the squares must be greater than the length of the last square.

b. The lengths of the squares (if they are integers) must form a Pythagorean triple.

Pythagorean triples are:

3, 4, 5

5, 12, 13

8, 15, 17

9, 40, 41

there are more triples but we only need these for this question

c. They must conform to the Pythagoras Theorem.

[tex]\begin{gathered} \text{Pythagoras theorem is:} \\ c^2=a^2+b^2 \\ \text{where c is the largest side of the right angled triangle or hypothenus} \\ \text{while a and b are adjacent and opposite of the right angled triangle} \end{gathered}[/tex]

Now we can proceed with these points at hand.

1. Squares with side lengths 6, 8, 10 can be written as:

2(3), 2(4), 2(5).

Ignoring the "2", we can see that this follows the Pythagorean triple.

therefore, 6, 8, 10 can form a right-angled triangle

2. 64, 100, 144 can be written as:

4(16), 4(25), 4(36)

Ignoring the "4", we can see that this does not follow the Pythagorean triple.

If we input the values into the Pythagoras theorem, we shall have:

[tex]\begin{gathered} 64^2+100^2\text{ = 4096 + 10000 = 14096} \\ 144^2=\text{ 20736} \\ \text{Therefore, we can s}ee\text{ that:} \\ 64^2+100^2\text{ }\ne\text{ }144^2 \end{gathered}[/tex]

Therefore, 64, 100, 144 cannot form a right-angled triangle

3. Two squares with lengths 5 and a Square with an area of 50 square feet:

We need to find the length of the square with an area of 50 square feet.

[tex]\begin{gathered} \text{Area of square = l}^2 \\ \text{where l is the length of the side} \\ 50=l^2 \\ \text{square root both sides} \\ l\text{ = }\sqrt[]{50\text{ }}\text{ = 5}\sqrt[]{2} \end{gathered}[/tex]

Now that we know the length of the 3rd and largest side of this triangle, we can now determine whether it is a right-angled triangle.

This case has a non-integer as part of the sides of the triangle, thus, condition b does not apply.

We must check via Pythagoras theorem:

[tex]\begin{gathered} By\text{ pythagoras:} \\ 5^2+5^2=25+25=50 \\ \text{while,} \\ (5\sqrt[]{2})^2=5^2\times(\sqrt[]{2})^2=25\times2=50 \\ \text{Thus we can s}ee\text{ that:} \\ 5,5,5\sqrt[]{2}\text{ can form a right-angled triangle} \end{gathered}[/tex]

Therefore, the final answer: 1 and 3 can form a right-angled triangle but 2 cannot

4. I have given the reasons why they form a right-angled triangle above. But let me restate them:

In order to know if 3 squares will form a right triangle,

a. The sum of the length of two of the squares must be greater than the length of the last square.

b. The lengths of the squares (if they are integers) must form a Pythagorean triple.

Pythagorean triples are:

3, 4, 5

5, 12, 13

8, 15, 17

9, 40, 41

there are more triples but we only need these for this question

c. They must conform to the Pythagoras Theorem.

[tex]\begin{gathered} \text{Pythagoras theorem is:} \\ c^2=a^2+b^2 \\ \text{where c is the largest side of the right angled triangle} \\ \text{while a and b are adjacent and opposite of the right angled triangle} \end{gathered}[/tex]

A hammock is suspended between two trees. The curve the hammock makes can bemodelled by the equation y = 0.2x² - 0.4x - 0.6, where x and y are measured inmetres.a) Find the x interceptsb) Find the vertex.c) What is the minimum height of the hammock?

Answers

We have the function that relates x and y expressed as:

[tex]y=0.2x^2-0.4x-0.6[/tex]

a) We have to find the x-intercepts.

To do that we can use the quadratic equation:

[tex]\begin{gathered} x=\frac{-(-0.4)\pm\sqrt{(-0.4)^2-4(0.2)(-0.6)}}{2(0.2)} \\ x=\frac{0.4\pm\sqrt{0.16+0.48}}{0.4} \\ x=\frac{0.4\pm\sqrt{0.64}}{0.4} \\ x=\frac{0.4\pm0.8}{0.4} \\ x=1\pm2 \\ x_1=1-2=-1 \\ x_2=1+2=3 \end{gathered}[/tex]

Then, we have x-intercepts at x = -1 and x = 3.

b) We have to find the vertex.

We can find the x-coordinate of the vertex using the linear coefficient b = -0.4 and the quadratic coefficient a = 0.2:

[tex]x_v=\frac{-b}{2a}=\frac{-(-0.4)}{2(0.2)}=\frac{0.4}{0.4}=1[/tex]

It can also be calculated as the average of the x-intercepts.

Knowing the x-coordinate of the vertex, we can find the y-coordinate of teh vertex using the formula applied to x = 1:

[tex]y=0.2(1)^2-0.4(1)-0.6=0.2-0.4-0.6=-0.8[/tex]

Then, the vertex is (1, -0.8).

c) The minimum height will be given by the y-coordinate of the vertex.

Relative to the horizontal axis (y = 0), the minimum height will be -0.8 meters below that level.

Answer:

a) The x-intercepts are x = -1 and x = 3.

b) The vertex is (1,-0.8)

c) The minimum height is 0.8 units below the horizontal axis.

Use the properties of exponents to write an equivalent expression for each given expression.
1. 6^4 x 6^3
2. (3^6)^-2
3. 7^3 x 2^3
4. 4^10 divided by 4^4

Please help :)

Answers

Answer:

Step-by-step explanation:

In earn contains two white marbles, three green marbles, and 5 red marbles. A marble is drawn and then replaced. Then the second marble is drawn. What is the probability that the first marbel was white and the second was Green?

Answers

[tex]\text{probability}=\frac{\text{ number of favorable outcomes}}{\text{ total number of outcomes}}[/tex]

total number of outcomes = 2 + 3 + 5 = 10

The probability of getting a white marble is:

[tex]P(white)=\frac{2}{10}=\frac{1}{5}[/tex]

The probability of getting a green marble is:

[tex]P(green)=\frac{3}{10}[/tex]

The events: getting a white marble and getting a green marble are independent since there is a replacement after each drawing. Then, the probability that the first marble was white and the second was Green is:

[tex]\text{ P(white and gr}een\text{) =}P(white)\cdot P(green)=\frac{1}{5}\cdot\frac{3}{10}=\frac{3}{50}[/tex]

A box has length 4 ft, width 5 ft, and height 6 ft. What is the volume?

Answers

The volume of box will be 120 ft.³

What is volume ?

Volume is a three dimensional space occupy by the body of particular shape such as here :

Volume of cuboidal box = lbh

where, length "l" = 4 ft.

width "b" =  5 ft.

height "h" = 6 ft.  

now, the volume of box will be :

V = lbh

V = 4 x 5 x 6

V = 120 ft.³

Therefore, the volume of box will be 120 ft.³

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What's the value of b ? See attached screenshot.

Answers

The value of b would be 25/4.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Since the equation of the line is 2y = 4.5, where c is a constant, the y-coordinate of the intersection point must be c.

The parabola has a equation y = -4x² + bx, where bis a positive constant.

The solution to this quadratic equation will gives the x-coordinate(s) of the point(s) of intersection

Since it’s given that the line and parabola intersect at exactly one point, the equation y = -4x² + bx has exactly one solution.

A quadratic equation in the form ax²+bx+c has exactly one solution when its discriminant b²−4ac is equal to 0.

Therefore, if the line y = 22.5 intersects the parabola defined by exactly one point, then by = 25/4 .

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Aurora raised money for a white water rafting trip Jacy made the first donation Gillermo’s donation was twice Jacy’s donation Rosa’s mother tripled what Aurora had raised so far now Aurora has $120. how much did Jacy donate?

Help please!!!

Answers

The amount of money donated by Jacy is $10.

Given that, Jacy made the first donation Gillermo’s donation was twice Jacy’s donation Rosa’s mother tripled what Aurora had raised so far now Aurora has $120.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the donation given by Jacy be $x.

Divide that amount by 4. One part is Guillermo's and Jacy's donation and three parts is the amount donated by Rosa's mother = 120 ÷ 4 = $30

Divide that amount by 3. One part is for Jacy's donation ($x) and two part is the amount Guillermo donated x = 30/3 = $10

Jacy was the first to donate. So, Jacy donated is $10

Therefore, the amount of money donated by Jacy is $10.

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4.
The Freshman Class treasury has 30
ten- and twenty-dollar bills that have
a total value of $430. How many of
each bill do they have?

Answers

There are 13 $20 bills and 17 $10 bills, respectively.

A linear equation is what?

Constants and variables are used in conjunction to create linear equations. A linear equation with one variable is shown in the following standard form: Where a 0 and x is the variable, ax + b = 0.

Due to that,

There are 30 bills in all.

Total = $430

Let,

x = the number of $20 bills.

Amount in $10 banknotes = (30-x)

20x+10(30-x) = 430

20x+300-10x = 430

10x = 430-300

10x = 130

x = 13

$20 bills: x = 20; y = 13.

30 x = 30 13 = 17 = number of $10 banknotes

Therefore, there are 13 $20 bills and 17 $10 banknotes.

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Find the measure of the missing angle. *Don't worry about the degree symbol

Answers

this is an ange formed by two intersecting chords

then the missing angle is given by

[tex]\theta=\frac{1}{2}(arcCB+arcSD)[/tex][tex]\theta=\frac{1}{2}(191+55)[/tex][tex]\theta=\frac{1}{2}(246)[/tex][tex]\theta=123\degree[/tex]

the missing angle is 123°

You have maxed out your $800 credit card from Utopian One Bank. The interest on the card is 21%. Find the interest and the final cost you pay on this bill. (Hint this problem is computed like sales tax)

Answers

Given the question

$800 dollars

21% interest

Caclulate the question how you would calculate the sales tax.

B1 = 800 dollars

B2 = the final cost

[tex]\frac{21\times800}{100}=168[/tex]

Interest rate = 168

800 + 168 = 968

968 is the final cost.

Interest rate = $168

Final cost = $968

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