A car has a velocity of 24 m/s. Two seconds later it reaches the bottom of the hill with a velocity of 45 m/s. What is the acceleration of the coaster?

Answer:

The initial velocity of the ball is 28.714 m/s

Explanation:

Given;

time of flight of the ball, t = 2.93 s

acceleration due to gravity, g = 9.8 m/s²

initial velocity of the ball, u = ?

The initial velocity of the ball is given by;

v = u + (-g)t

where;

v is the final speed of the ball at the given time, = 0

g is negative because of upward motion

0 = u -gt

u = gt

u = (9.8 x 2.93)

u = 28.714 m/s

Therefore, the initial velocity of the ball is 28.714 m/s

Answer:

c

Explanation:

ur changing the way it move not to make it easier

The direction of the force, has nothing to do with how the machine will work easier. The correct option is C

A machine is any devices that make work easier. An ideal machine takes in small effort to overcome large load.

Since work has to be done in a machine, and work is the product of force and perpendicular distance, for a machine to work easier, the work done will depend  on size of the force applied, the type of force applied, and also, the magnitude of the distance involved.

The direction of the force, has nothing to do with how the machine will work easier. Therefore, the correct option is C

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Answer:

It involves observation

It involves experimentation

It is supported by evidence

Explanation:

Science can be described as a system of knowledge based on the understanding of the natural world. The subject of science requires the scientific method - a chronological series of steps that have to be followed while trying to understand events in the natural world. These steps are:

Hence, science involves observation, experimentation, and it is supported by evidence.

Answer:b. c. e

Explanation:

Given :

Initial pressure, [tex]P_i=200\ kPa[/tex].

Initial volume, [tex]V_i= 4\ m^3[/tex].

Final volume, [tex]V_f = 2 \ m^3[/tex].

To Find :

Final pressure, [tex]P_f[/tex].

Solution :

We know, at constant temperature :

[tex]P_iV_i=P_fV_f\\\\P_f=\dfrac{P_iV_i}{V_f}\\\\P_f=\dfrac{200\times 4}{2}\\\\P_f=400\ kPa[/tex]

Therefore, new pressure is 400 kPa.

Hence, this is the required solution.

Answer:

F = 108.5 [N]

Explanation:

To solve this type of problem we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces [N]

m = mass = 35 [kg]

a = acceleration = 0.5 [m/s²]

f = friction force [N]

F - f = m*a

F - 91 = (35*.5)

F = 91 + 17.5

F = 108.5 [N]

Answer:here you goo

Explanation:

A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. ... A rock is an aggregate of one or more minerals, or a body of undifferentiated mineral matter.

Answer:

Minerals are naturally occuring solid while rocks are naturally occuring substances consist of aggregate minerals clumped together with other materials

Answer:

Resultant force = [tex]\sqrt{91}[/tex]N

Explanation:

Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]

Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]

Rf = [tex]\sqrt{36+25+30}[/tex]

Rf = [tex]\sqrt{91}[/tex]

doesn't look right though...

The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Given parameters:

Two forces are 6 N and 5N.

Angle between them is 60 degree.

So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N =  = 9.54 N.

Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°)  } = 33⁰.

Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.

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Answer:

Havent seen this one before but the explanation should help you out :)

Explanation:

There are only three atomic bonds.

Ionic bonding.

Covalent bonding.

Metallic bonding.

19km in 30mins

1 hour is twice of 30 mins.

Twice the time means twice the distance.

therefore 2(19km) in 2(30 mins)

19km in 30mins = 38km/hour

Answer: False

Explanation:

Answer:

Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral.  (I'm sorry if that wasn't helpful)

Explanation:

Answer:

10.7*[tex]10^{6}[/tex]

Explanation:

Answer:

0.61°

Explanation:

Since the box move at constant velocity, it means there is no acceleration then we can say it has a balanced force system.

Pulling force= resistance force

From the formula for pulling force,

F(x)= Fcos(θ)

= 425×cos(35.2)

=347N

The force exerted downward at an angle of 35.2° below the horizontal= Fsin(θ)= 425sin(35.2)

=425×0.567=245N

Resistance force= (325N+ 245N) (α)= 570N(α)

We can now equates the pulling force to resistance force

570 (α)= 347N

(α)= 347/570

= 0.61

Answer:

100°c = 373.15 K

100°C=212°F

Explanation:

To convert Celsius to Kelvin, we need the following equation.

°C + 273.15 = K

100°C + 273.15 = K

373.15 = K

Therefore, 100°c = 373.15 K

F = 9/5C + 32

   =9/5(100)+32

  = (180) + 32

  = 212°

Therefore,

100°C=212°F

Answer:

Different

Explanation:

The hollow one will expand even more making it have a larger volume then the solid one so they are different

Answer:

roddy i guess?

Explanation:

Answer:

Dababy and Roddy Ricch. Jason's songs use to be fire years back but now....not so much.

Explanation:

Answer:

F = 39.2 N   (hand force) and    N = 68.6 N (shoulder force)

Explanation:

In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole

Let's set the reference system at the fit point of the shoulder

     ∑ τ = 0

We will assume that the counterclockwise turns are positive

    w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0

all distances are measured from the support of the man (x₀ = 0.60 m)

    F = (w₁ 0.60 + W 0.1) / 0.4

    F = (m₁ 0.6 + m 0.1) g / 0.4

let's calculate

    F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4

    F = 39.2 N

this is the force that the hand must exert to keep the system in balance

We apply the translational equilibrium condition

    -w₁ -W + N - F = 0

     N = w₁ + W + F

     N = (m₁ + m) g + F

let's calculate

     N = (2.6 + 0.4) 9.8 + 39.2

     N = 68.6 N

The effort must move 8•0

Answer:

4.04 seconds

Explanation:

In order to solve this problem, we must keep in mind that the initial 2.00 seconds at which the fuel is exhausted does not signal when the rocket reaches its maximum height.

From this moment on, the rocket has a downward acceleration of 9.8 m/s² but it still has an upwards velocity, which we will calculate. This upwards velocity keeps the rocket moving up for a certain period of time, which we will also calculate.

For this problem, let's set the upwards direction to be positive and the downwards direction to be negative.

To find the time that the rocket takes to reach its maximum height, we are going to use the initial 2.00 seconds and find the additional seconds it takes to reach a final vertical velocity of 0 m/s. This represents the time at which the rocket stops moving and heads in the downwards direction, which takes place after the rocket has reached its maximum height.

The time in the air of an object in projectile motion can be found using this equation, derived from one of the constant acceleration kinematic equations.

Time in the air (projectile motion):

Solve for [tex]v_i[/tex] by plugging in 2.00 seconds for t, 30 degrees for theta, and 20.0 m/s² for acceleration, since this is not a constant acceleration problem.

Multiply sin(30) and 2 together.

Multiply 20 to both sides of the equation.

Now we know that the initial velocity of the rocket is 40 m/s. We need to solve for the vertical component of the rocket's velocity in order to solve for the additional time it took after the 2.00 seconds to reach its maximum height.

Vertical component:

The vertical component of the velocity vector is 20 m/s.

Now, in order to solve for the additional seconds that the rocket took to reach its maximum height, let's use one of the kinematic constant acceleration equations that uses the variables [tex]v_f[/tex], [tex]v_i[/tex], [tex]a[/tex], and [tex]t[/tex].

Since we are trying to solve for time, we need to use this equation in terms of the vertical direction, aka the y-direction. Time is the same in either case.

The final vertical velocity of this rocket is 0 m/s at the top, or its maximum height. We found that the vertical component, aka the rocket's initial vertical velocity, is 20 m/s. The acceleration is given to us: -9.8 m/s² (since it's falling downwards, the acceleration must be negative because we already established this in the beginning).

We are trying to solve for time t. Substitute the known values into the equation.

Subtract 20 from both sides of the equation.

Divide both sides of the equation by -9.8.

Now we can take this time and add it to the initial 2.00 seconds of the rocket. This time we just solved for is the time after these initial seconds that the rocket kept going upwards, since its initial vertical velocity was not 0 m/s yet.

The time that the rocket takes to reach its maximum height is 4.04 seconds.

Answer:

4.04 second is your answer hope it help you........

Answer:

1010 m

Explanation:

The following data were obtained from the question:

Height (h) of cliff = 500 m

Horizontal velocity (u) = 100 m/s

Horizontal distance (s) =?

Next we shall determine the time taken for the cannon ball to hit the ground. This can be obtained as follow:

Height (h) of cliff = 500 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

500 = ½ × 9.8 × t²

500 = 4.9 × t²

Divide both side by 4.9

t² = 500/4.9

Take the square root of both side

t = √(500/4.9)

t = 10.1 s

Finally, we shall determine the horizontal distance travelled by the cannon ball.

This can be obtained by using the following formula (s = ut) as illustrated below:

Horizontal velocity (u) = 100 m/s

Time (t) = 10.1 s

Horizontal distance (s) =?

s = ut

s = 100 × 10.1

s = 1010 m

Thus, the cannon ball was launched 1010 m away from the cliff.

Answer:

it is an upside-down image but the brain realizes it and corrects it in its orientation so we see it in right direction.

Answer:

The lens of the eye is a convex lens. The image that it forms on the retina is upside down.

Explanation:

The eye makes an image, but it is upside down, the brain corrects the image and turns it right side up

Answer:

The acceleration of the skateboarder over the 3.3s time interval is 3.15 m/s²

Explanation:

Acceleration can be described as the rate of change of velocity (as seen in the question). The formula to be used here to determine the acceleration is

Acceleration (in m/s²) = velocity (m/s) ÷ time (s)

Acceleration = 10.4 ÷ 3.3

Acceleration = 3.15 m/s²

Thus, the acceleration of the skateboarder over the 3.3s time interval is 3.15 m/s²

Write each force in component form:

v ₁ : 50 N due east   →   (50 N) i

v ₂ : 80 N at N 45° E   →   (80 N) (cos(45°) i + sin(45°) j ) ≈ (56.5 N) (i + j )

The resultant force is the sum of these two vectors:

r = v ₁ + v ₂ ≈ (106.5 N) i + (56.5 N) j

Its magnitude is

|| r || = √[(106.5 N)² + (56.5 N)²] ≈ 121 N

and has direction θ such that

tan(θ) = (56.5 N) / (106.5 N)   →   θ ≈ 28.0°

i.e. a direction of about E 28.0° N. (Just to clear up any confusion, I mean 28.0° north of east, or 28.0° relative to the positive x-axis.)

Answer:

(C) 40m/s

Explanation:

Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's  velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

Answer:

The mammoth bone is 22726 years old.

Explanation:

We can find how hold is the mammoth bone using the decay equation:

[tex]N(t) = N_{0}*e^{-\lambda t}[/tex]   (1)

Where:

N(t): is the quantity at time t = 6.25%N₀

N₀: is the initial quantity

λ: is the decay constant

First, we need to find λ:

[tex] \lambda = \frac{ln(2)}{t_{1/2}} = \frac{ln(2)}{5700 y} = 1.22 \cdot 10^{-4} y [/tex]

Now, by solving equation (1) for t we have:

[tex]t = \frac{ln(\frac{N(t)}{N_{0}})}{-\lambda} = \frac{ln(0.0625)}{-1.22 \cdot 10^{-4}} = 22726 y[/tex]      

Therefore, the mammoth bone is 22726 years old.

I hope it helps you!

Explanation:

Power is the rate at which work is done. It is expressed as:

     Power  = [tex]\frac{work done}{time taken}[/tex]  

To find the power of the man climbing the ladder, we must know the work he is doing and the duration of the work done.

 Work done  = force x distance

  Since he climbs,

           Force  = weight  = mg (mass x acceleration due to gravity)

    distance  = height = h

Power  = [tex]\frac{mgh}{t}[/tex]

t is the time

    If we know these parameters, we can find the power.