A charge of 15C has flowed past a point in the circuit with a current of 2A. How long has this charge been flowing through this circuit?
Round the answer to 2 decimal places.

Answer:

Vx = 53 m / 4 sec = 13.25 m/s       horizontal speed

Vy = 2 sec* 9.80 m/sec^2 = 19.6 m/s      vertical speed

V = (13.25^2 + 19.6^2)^1/2 = 23.7 m/s

Check:

Range = V^2 sin 2θ / g

tan θ = 19.6 / 13.25 = 1.48     θ = 55.9 deg

R = 23.7^2 sin 112 deg / 9.8 = 53.1 m

The car’s average acceleration is 3m/s².

What is the Car's average acceleration?

The average acceleration in the question measures the change in the velocity of the car by the time it used to cover the distance.

Average acceleration of the car is the change in the velocity of the car by the change in the time the car traveled.

ΔVelocity = 4.5m/s -( -3.0m/s)

                = 7.5m/s

The initial velocity is negative 3.0m/s as the car started  moving  backwards.

The time is 2.5s

The

The average acceleration of the car = 7.5m/s ÷ 2.5s

                                                            = 3m/s²

In summary, the car coasting backward downhill at an initial speed of 3.0 m/s would have an average acceleration of  3m/s² After increasing the speed to 4.5 m/s at a time of 2.5s.

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The angular difference between true north and magnetic north is called declination.

What is declination?

Declination is the said to be the angle between magnetic north and geographic north in the horizontal plane that changes with time and geographic location. The true north or geographic north is a fixed point on the globe that points towards the north pole directly while the magnetic north unlike the true north changes over time, and it is the direction a compact needle points to as it aligns with the earth's magnetic field.

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The transfer of momentum increases when the velocity of the marble increases and vice versa.

The transfer of momentum increases when the mass (number of marbles) increases and vice versa.

The momentum of a single marble can be calculated from the product of its mass and velocity.

If two marbles together are moving at the same speed as a single marble, the two marbles will have greater momentum because of their greater mass.

Momentum can be shown as a vector because the direction of the momentum of a body is specified.

The momentum of a body is the product of the mass and the velocity of the body.

Mathematically;

Since the velocity of an object is a vector, the momentum of a body is also a vector.

The momentum of a body is directly proportional to its mass and velocity.

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Answer:486.1 J

Explanation:

False. The most energetic region of the electromagnetic spectrum is NOT the microwave region. It is the Gamma rays.

What are Gamma rays?
The electromagnetic radiation with the shortest wavelength and maximum energy is known as a gamma ray. The wavelengths of gamma radiation are often less than a few tenths of an angstrom (1010 meter), yet the energy of gamma photons exceed tens of thousands of electron volts.

Gamma rays are created when radioactive atomic nuclei break apart and when certain subatomic particles decay. Pair annihilation, in which two photons are formed along with the disappearance of an electron and its antiparticle, a positron, also results in the production of gamma rays. Additionally, they can be produced when some unstable subatomic particles, such the neutral pion, decay.

Therefore, The most energetic region of the electromagnetic spectrum are gamma rays.

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The solution to this ques is available in the image.

Given,

Force= 1N

Mass= 0.11kg

Time= 5sec

Force= mass X accelaration

Accelaration= velocity/ time

Speed=distance/ time

Hence, the speed is 45 m/s and the distance is 225 m.

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With the use of range formula, also, in multiple of 180 degree, 59 and 239 degrees are the angles of projection.

A projectile in kinematic under physics can be defined as any object that is projected or thrown to take a trajectory path.

Given that a tennis player makes a return at a speed of 15 m/s and at height of 3m to land in the court at a horizontal distance of 12 m from her.

Let us assume that the ball fall at height 3m. U = 0. Let us find the time

h = ut + 1/2gt²

3 = 0 + 1/2 × 9.8 × t²

3 = 4.9t²

t² = 3/4.9

t² = 0.612

t = √0.612

t = 0.782 s

Total time T = 2t

T = 2 × 0.782

T = 1.564 s

The possible angles of projection of the ball can be calculated by using the range formula

R = UcosФT

12 = 15cosФ × 1.564

12 = 23.46cosФ

cosФ = 12 / 23.46

cosФ = 0.512

Ф = [tex]Cos^{-1}[/tex] (0.512)

Ф =  59. 2 degree

Ф = 59°

Therefore,  the possible angles of projection of the ball are 59° and 239°

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The frequency of light  is 3.88x10^23Hz

E = 1.55 x J/ mol

E = hv

v = (1.55 x /1mol  x 1mol/6.023 x )/6.626 x 10^34

velocity = 3.88x10^23 s-1

since 1 Hz = 1/ s = 1

velocity =3.88x10^23 Hz

The portion of the electromagnetic spectrum contains the electromagnetic radiation that the human eye perceives as light or visible light. Visible light typically possesses wavelengths between 400 and 700 nanometers (nm) or frequencies between 750 and 420 terahertz, which are halfway between infrared and ultraviolet (with longer wavelengths) (with shorter wavelengths).

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Sample question: What is the frequency of light when the energy for a mole of photons is 1. 55 × 1013 j?.

Answer:

150J (joules)

Explanation:

25% efficiency of 1000J = 250J

40% efficiency of 1000J= 400J

400-250=150

The wavefront B is travelling at the speed(5000m/s) closest to that of a sound wave(6000m/s) travelling through solid.

The velocity of the sound waves in solids is nearly 6000 meters per second.

Let us check the velocity for all the three wave fronts,,

Wavefront A,

We know,

speed = distance/time taken

Distance travelled by the wavefront A is 10m,

Time taken by the wavefront A to travel the distance is 0.01 seconds,

Putting all the values,

Speed = 10/0.01

Speed = 1000m/s.

Speed of wavefront A is 1000m/s.

Wavefront B,

Again we know,

speed = distance/time taken

Distance travelled by the wavefront Bis 50m,

Time taken by the wavefront B to travel the distance is 0.01 seconds,

Putting all the values,

Speed = 50/0.01

Speed = 5000m/s.

Speed of wavefront B is 5000m/s.

Wavefront C,

We know,

speed = distance/time taken

Distance travelled by the wavefront C is 1000m,

Time taken by the wavefront C to travel the distance is 100 seconds,

Putting all the values,

Speed = 1000/100

Speed = 10m/s.

Speed of wavefront C is 10m/s.

Wavefront D,

Again using the formula,

speed = distance/time taken

Distance travelled by the wavefront is 2000m,

Time taken by the wavefront to travel the distance is 2000 seconds,

Putting all the values,

Speed = 2000/2000

Speed = 1m/s.

Speed of wavefront D is 1m/s.

As we can see, The speed of wavefront B is closest to the speed of sound waves in solids.

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Answer:

So, at moon g’=1.62 m/s^2

Therefore, mg’=99N (as given , where m is the mass )

so, m=99/1.62 =61.11 kg

hence, weight on earth will be mg( where g is the acceleration due to gravity at earth, 9.8m/s^2)

61.11*9.8=598.878 N will be the weight on earth

Explanation:

hope it helps

Answer:

Hope the picture will help

The constant acceleration of the plane is 7.33 m/[tex]s^{2}[/tex].

Use this formula of acceleration, [tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as,

a =  [tex]v^{2}[/tex] - [tex]u^{2}[/tex]   / 2s

v = velocity

s = distance

a = acceleration

Put the values in this formula, a =  [tex]v^{2}[/tex] = [tex]u^{2}[/tex]  / 2s

a = (240× 240) - (200 × 200)/ 2 × 1200

a = 7.33 m/[tex]s^{2}[/tex]

Hence, the constant acceleration of the plane is 7.33 m/[tex]s^{2}[/tex].

Acceleration is the rate of change of velocity per unit time. It is vector quantity and its S.I. unit is m/[tex]s^{2}[/tex].

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2 and 23/75 as a percentage is 2.30666666666. Hope this helps! :)

An artificial satellite can be called a celestial body as it orbits around a planet.

Objects in space such as the sun, moon, planets, and stars are known as celestial bodies or heavenly bodies. Satellites are revolving bodies that orbit planets. They are the fundamental component of celestial bodies. These could be transmitted by humans or be of natural origin.

The moon orbits the earth as a natural satellite because it is held in place by the gravity of the planet. Additionally, man has positioned artificial or man-made satellites in orbit around the earth and other planets for communication and scientific research.

As a artificial satellite also orbits around a natural celestial body, it can be called as a celestial body.

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The submarine is 288.04 meters below the surface of the water.

As we can see,

The submarine is making an angle of 40.5° with the water surface and moving down till a displacement L of 397 meters.

The displacement L moved by the submarine will have two components because displacement is a vector quantity.

One along water surface Lcos(40.5°) and one along the line perpendicular to water surface Lsin(40.5°).

The depth D of the submarine below the water surface is along the line perpendicular to the water surface.

Here,

D = Lsin(40.5°)

Value of cos 40.5°is 0.76.

So,

D = 397×0.76

D = 288.04 meters.

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A full circuit is required for the flow of electrical current, and all electrical energy transmissions need the formation of a circuit with two wires—one going to the recipient and the other going back to the sender.

The construction of a circuit with two wires—one going to the recipient and the other back to the sender—is necessary for all electrical energy transmissions in order for current to flow. Due to the fact that all wireless signals are essentially delivered as electromagnetic signals rather than electrical signals, electromagnetic interference, often known as EMI, is a common problem in wireless communications.

This suggests that any interference with an electromagnetic signal (wave) may cause it to be amplified, destroyed, or lost (assuming constructive interference).

The interference brought on by electromagnetic disturbance is known as electromagnetic interference. Radio frequency interference is another name for it. We refer to interference that occurs in the radio frequency spectrum as radio frequency interference.

These days, wireless communication is expanding at an unprecedented rate. Over a large concentration, a small spectrum is available. Because of this, there is a greater likelihood of mutual interference. The performance of the device and the channel can both be impacted by a slight electromagnetic disturbance. It is crucial to keep interference at a minimal for better wireless performance.

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A swimmer needs to cross a river as quickly as possible. The swimmer’s speed in still water is 1.35 m/s.

(a) If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, it will take the time swimmer to cross the river is (t) = 72.57 S, if he swims so that his body is angled slightly upstream while crossing, and he ends up on the far bank directly across from where he started.

(b) If he points his body directly across the river and is therefore carried downstream, it will take time to get across the river is (t)=72.57 S, and the distance downstream from his starting point will he end up is (S) = 43.542m.

Velocity means that the covered distance in a given time. In other words mathematically distance divided by time called velocity. It can be measured in m/s and cm/s.

(a)To calculate the time for the first case we are using the formula, S=vt.

The swimmer’s speed in still water is 1.35 m/s.=v₁=1.35j m/s.

the river’s current speed is 0.60 m/s.=v₂=0.60i m/s.

Now, let us apply the rule of relative velocity:

v=v₁+v₂=1.35j+0.60i

Or, |v|=√(1.35)²+(0.60)²

Or, |v|=1.47 m/s

Now we know the velocity of the water, v=1.47 m/s.

The wide of the river, S=106.68 m

Now we have to calculate the time to travel of the swimmer= t s

Now we put the values in above equation,

S=vt

Or, t=S/v

Or, t= 106.68/1.47

Or, t=72.57 s.

From the above calculation we can say that, If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, it will take the time swimmer to cross the river is (t)=72.57 S

(b) If he points his body directly across the river and is therefore carried downstream, The time taken by the swimmer is the same as the first case.

So the time would be (t)=72.57 S.

The distance downstream from his starting point will he end up,

S = vt

Or, S= 0.6*72.57

Or, S=43.542

So according to the solution, If he points his body directly across the river and is therefore carried downstream, it will take to get across the river is (t)=72.57 S, and the distance downstream from his starting point will he end up is (S)=43.542m.

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The values of velocity at point  A,C,E and G is 15m/s, the values of velocity at point B, D, F and H is 10m/s, 20m/s, 30m/s and 40m/s respectively.

The projectile is launched from the top of the cliff with a horizontal velocity of 15m/s.

Throughout the motion of the projectile the velocity will have two components. On along vertical and one along horizontal.

Here, the direction of the acceleration is only downwards because only gravity is there and that in only downwards direction.

There is no acceleration in the horizontal direction. So, the velocity in the horizontal direction will never change.

So, the velocity at A,C,E and G is 15m/s throughout the motion.

We know that,

t = √(2h/g)

h = 1/2gt²

Where,

H is height of the cliff at that point,

t is the time,

g is gravity which is equal to 10m/s².

So, the height at point,

B is 1/2(10)(1)² = 5m

D is 1/2(10)(2)² = 20m

F is 1/2(10)(3)² = 45m

H is 1/2(10)(4)² = 50m.

The vertical velocity can be found by using the formula,

V = √2gh

So, vertical velocity at point,

B is √2(10)(5) = 10m/s.

D is √2(10)(20) = 20m/s.

F is √2(10)(45) = 30m/s.

H is √2(10)(80) = 40m/s.

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120 centimeters per second, is the wave speed or wave velocity.

Wave velocity is the amount of distance a wave travels in one unit of time. The rate at which a particle disturbance like a crest or trough or compression or rarefaction spreads in a medium is known as the particle's propagation speed.

Given,

Amplitude (A) = 2cm,

Frequency (f) = 12hz,

Time period [tex]T=\frac{1}{f} =\frac{1}{12} s[/tex]

The horizontal distance between the closest peak or trough, respectively, is referred to as the wavelength. A crest's distance from the closest tough was specified. The distance between a crest and the closest crest is therefore two times that distance.

This is the wave length :

λ=(2)(5)

=10cm

The wave velocity or wave speed is given by:

v = λf

v=(10)(12)

=120 cm/s

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Answer: this is true

Explanation:

if the object is moving and there is nothing stooping it, it will keep moving  

For nuclear meeting It should be used on a school bus driver's handle. Adapt to the outcome this couple force into a couple moment occurred to be that implies that we must act now to find a better situation.

Open to a nuclear meeting It is intended to be used on a school bus driver's handle. respect the outcome This couple of forces occurred to be in a couple at this time. That suggests that at this moment, we need to discover a better situation and start acting.

And at this time, 400 people are throwing up. Toe in toe is what is known as a couple of forty meters. As the radius of the handle is 30 millimeters in this instance, you can translate it to meters and use the force to draw up on a spot rather four upon it. Are you in favor of addressing this issue? 1 33 nuclear will be Therefore, one till people comprehend that is supposed f.

Now, we must determine a slow speed consent business. Once more, a boardroom mingled. I am. Carletto is a PVR as well. In contrast to the original five meters, Cal critic M is supplied four on a separated radius of five millimeters.

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The total time taken by the feather to fall to the surface of moon will be 1.29 seconds.

Given is a feather dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s².

The second equation of motion is -

S = ut + 1/2 at²

We can write -

[S] = 1.4 m

[a] = 1.67 m/s²

[u] = 0 m/s

Using the second equation of motion -

S = ut + 1/2 at²

S = 1/2 at²

1.4 = 1/2 x 1.67 x t²

1.4 = 0.835 x t²

t = 1.29 seconds

Therefore, the total time taken by the feather to fall to the surface of moon will be 1.29 seconds.

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13.13 m/s is the velocity of the truck was when a truck of mass 3170 moving in the opposite direction collides with the car and the 2 vehicles stop immediately without sliding.

Momentum of car= 1850(22.5)=41625 kg m/s

Momentum of car = momentum of truck

Let the speed of truck = v m/s

Momentum of truck= v(3170)=3170 v  kgm/s

3170v = 41625

v = 13.13 m/s

Speed of truck = 13.13 m/s

The pace at which a moving object changes position as seen from a certain point of view and as measured by a particular time standard is known as its velocity.

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Answer:  

Explanation:

at first the rock is at rest so initial velocity is zero
after accelerating it reaches a final velocity
we are supposed to find that final velocity


[tex]v^{2} = u^{2} +2ax[/tex]
v= final velocity
u= initial velocity
x= distance
a= acceleration

[tex]v^{2} = 0^{2} + 2(9.8)(14.4)[/tex]
[tex]v^{2} = 282.24[/tex]
[tex]v= \sqrt{282.24}[/tex]
[tex]v= 16.8 m/s[/tex]

0.145 Newton is the required steady force of each rocket if the satellite is to reach 32 rpm in 5.0 min , starting from rest

mass of satellite ( M ) = 3500 kg

radius of satellite ( r )  = 4.4 m

mass added by each rocket ( m ) = 220 kg

Angular speed of satellite = 32 rpm

Time = 5 mins  

moment of inertia

[tex]I=1/2Mr^2+4mr^2[/tex]

M = 3500 kg  m = 220 kg,  r =4.4 m

I=33880+17036

Insert values into equation ( 1 )

I =20416 kg-m^2

angular acceleration

∝ = ω / t

= ( 2π×32 ) /  3600×5

= 0.0112 rad/s²

steady force required by each rocket

Τ = I × ∝     ( 1 )

T = 4rF

Equation ( 1 ) becomes

4rF = I × ∝

Force = I×∝ / 4r

= ( 228×0.0112 ) / 4×4.4

=2.56/17.6

= 0.145 N .

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In the case of a paramecium moving at a constant speed, there is no net force acting on it.

The paramecium's cilia exerts a force on water that is equal to the force that the water exerts on the paramecium's cilia, according to Newton's third law.

The strength of the viscous force the water is exerting on the paramecium will be equal to the strength of the force the paramecium's cilia are exerting on the water.

How does Paramecium use cilia?

Cilia, or tiny strands like hair, cover the whole surface of parasites like cilia, which beat rhythmically to move them and guide bacteria and other food particles into their mouths.

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Mass of air that escapes the tank is M =2.8075 kg and  the amount of heat transferred to the tank is Q = 1008.942 kj

In physics, mass is a numerical representation of inertia, which is a basic characteristic of all matter. The resistance a body of matter offers to a change in its speed or location as a result of the application of a force is what it is in essence. The change a force applies produces a change that is smaller the more mass a body has. The kilogramme, which is defined in terms of Planck's constant as equal to 6.62607015 1034 joule second, is the unit of mass in the International System of Units (SI). One kilogramme times one square metre per second squared is equivalent to one joule. Accurate measurements of Planck's constant are used to determine the kilogramme since the second and the metre are already defined in terms of other physical constants.When a body breaks up into fragments, the mass also breaks up into bits, thus the total mass of all the pieces equals the original mass.

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1. The acceleration of the cyclist is 0.42 m/s²

2. The total distance travelled by the cyclist is 2437.5 m

1. How to determine the acceleration    

We can obtain the acceleration of theration of the cyclist as follow:

a = (v – u) / t

a = (25 – 12.5) / 30

a = 12.5 / 30

a = 0.42 m/s²

Thus, the acceleration is 0.42 m/s²

2. How to determine the total distance

We'll begin by obtaining the distance travelled in the first 30 s. This can be obtained as follow:

s = (u + v)t / 2

s = [(12.5 + 25) × 30] / 2

s = [37.5 × 30] / 2

s = 1125 / 2

s = 562.5 m

Next, we shall determine the distance in the next 60 second.

s = vt

s = 25 × 60

s = 1500 m

Next, we shall determine the distance in the last 15 seconds.

s = (u + v)t / 2

s = [(25 + 0) × 15] / 2

s = [25 × 30] / 2

s = 750 / 2

s = 375 m

Finally, we shall determine the total distance travelled.

Total distance = 562.5 + 1500 + 375

Total distance = 2437.5 m

Thus, the total distance travelled is 2437.5 m

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