A mass hanging from a pendulum at the end of a string of negligible mass. The string has a length of 0.84 m. With the string hanging vertically, the object is given an initial velocity of 1.4 m/s parallel to the ground and swings upward on a circular arc. Eventually, the object comes to a momentary halt at a point where the string makes an angle θ with its initial vertical orientation and then swings back downward. Find the angle θ.

Answer:

(I'm not 100% sure about this)

Maybe its because the soccer ball is faulty. Such troublemakers can include holes in the ball, preventing it from inflating.

Answer:

51.54 m/s

Explanation:

Applying,

Law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = mv+m'v'.................... Equation 1

Where m = mass of the head of the golf club, m' = mass of the gulf ball, u = initial velocity of the head of the gulf club, u' = initial velocity of the gulf ball, v = final velocity of the head of a gulf club, v' = final velocity of the gulf ball

From the question,

Given: m = 151 g = 0.151 kg, u = 43.9 m/s, m' = 46 g = 0.046 kg, u' = 0 m/s (at rest), v = 28.2 m/s

Substitute these values into equation 1

0.151(43.9)+0.046(0) = 0.151(28.2)+0.046(v')

solve for v'

6.6289+0 = 4.2582+0.046v'

0.046v' = 6.6289-4.2582

0.046v' = 2.3707

v' = 2.3707/0.046

v' = 51.54 m/s

Answer:

Thermal physics

Explanation:

Because it uses temperature

Answer:

In my opinion both are easier if you'll work hard on it...

Answer:

We know that the length is 79 (there are no units of length in the question, so i will leave it as it is written, without units) when the temperature is 2°C.

We want to find the increase in length when the temperature is 35°C, knowing that the linear expansion coefficient is 11*10^(-6) °C^-1

The change in length is just given by the equation:

[tex]\Delta L = \alpha*L_0* (T_1 - T_0)[/tex]

where:

α = 11*10^(-6) °C^-1

T₀ is the initial temperature, so T₀ = 2°C

T₁ is the final temperature, so T₁ = 35°C

L₀ is the initial length, so L₀ = 79

Replacing these in the equation we get:

ΔL = ( 11*10^(-6) °C^-1)*79*(35°C - 2°C)

     = 0.28677

So the length of the railroad will increase by 0.28677  

Answer:

Quantity of charge = 1800 Coulombs

Explanation:

Given the following data;

Current = 1 A

Time = 0.5 hours

Conversion:

1 hour = 60 * 60 = 3600 seconds

0.5 hour = 0.5 * 3600 = 1800 seconds

To find the charge passing through the wire;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge = current * time

Substituting into the formula, we have;

Quantity of charge = 1 * 1800

Quantity of charge = 1800 Coulombs

Answer:

1150J

Explanation:

Voltage = energy / charge

energy = Voltage * charge

energy = 230v * 5C = 1150J

Answer: D

Explanation: because doing a yoga desk program is physical activity, 10k steps is pysical activity, riding a bike or walking/running is also physical activity. so it should be D, all of the above.

Answer:

6.86 N

Explanation:

Applying,

F = mg............... Equation 1

Where F = Force exerted by gravity on the mass, m = mass, g = acceleration due to gravity

Note: The Force exerted by gravity on the mass is thesame as the weight of the body.

From the question,

Given: m = 700 g = (700/1000) = 0.7 kg

Constant: g = 9.8 m/s²

Substitute these values into equation 1

F = 9.8(0.7)

F = 6.86 N

Answer:

The purpose of the choke is to provide a very high voltage initially between the filaments (across the two ends of the tube light). Again once the gas in the tube is ionized the choke provides a low voltage. A choke is a coil of wire. Fluorescent tubes/lamps are filled with mercury vapor

Explanation:

i hope it will help you

Answer:

Resistance = 1728.57 Ohms

Explanation:

Given the following data;

Power = 7 Watts

Voltage = 110 Volts

To find the resistance of each bulb;

Mathematically, power can be calculated using the formula;

[tex] Power = \frac {Voltage^{2}}{resistance} [/tex]

Making resistance the subject of formula, we have;

[tex] Resistance = \frac {Voltage^{2}}{power} [/tex]

Substituting into the formula, we have;

[tex] Resistance = \frac {110^{2}}{7} [/tex]

[tex] Resistance = \frac {12100}{7} [/tex]

Resistance = 1728.57 Ohms

Answer:

10 N

Explanation:

Given that,

A 2 kg hammer is used to nail a 0.002 kg nail with a force of 10 N.

We need to find how much force is applied to the hammer.

We know that, every action has an equal and opposite reaction. Both the action and reaction occurs in two different objects.

Hence, the force applied to the hammer is equal to 10 N.

Answer:

Explanation:

The Law of Momentum Conservation for us has the equation

[tex][m_rv_r+m_gv_g]_b=[m_rv_r+m_gv_g]_a[/tex] and filling in:

[tex][(.50)(5.0)+(.50)(0)]=[(.50)(2.0)+(.50)v_g][/tex] and

2.5 = 1.0 + .50v and

1.5 = .50v so

v = 3 m/s

The final speed of the green ball is 3m/s. This can be calculated by the law of conservation of momentum. Thus, the correct option is D.

The principle of the law of conservation of momentum states that if any two objects undergo collision, then the total momentum of the objects before and after the collision will be the same if there is no external force acting on the colliding objects.

The Law of Conservation of Momentum has the equation which is:

m₁ × u₁ + m₂ × u₂ = m₁ × v₁ + m₂ × v₂

where, m₁ = mass of object 1,

u₁ = initial velocity of object 1 before collision,

m₂ = mass of object 2,

v₁ = final velocity of object 1 after collision,

v₂ = final velocity of the object 2 after collision.

0.50 × 5 + 0.50 × 0 = 0.50 × 2 + 0.50 × v₂

2.5 + 0 = 1.0 + 0.50 × v₂

2.5 - 1.0 = 0.50 × v₂

1.5 = 0.50 × v₂

1.5/ 0.5 = v₂

v₂ = 3m/s

Therefore, the correct option is D.

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Answer:

Size of an object, and the distance between the objects.

When the mass of an object increases the force of gravity increases as well.

Explanation:

The magnitude of this force depends upon the mass of each object and the distance between the centers of the two objects. Mathematically, we say the force of gravity depends directly upon the masses of the objects and inversely upon the distance between the objects squared.

Explanation:

that is my answer thank me later

Answer:

oxygen difluoride a polar molecule

Answer:

5 Stars

Explanation:

Because every Star from 1 to 5 vary energy consumption of the electrical device...So 5 star product uses a very less energy compared to 1 star product...

Hope it is helpful

There are 0 to 5 star are used in the star rating label of electrical appliance.

The appliance is more energy efficient if it has more stars on the Energy Rating Label. To perform at the same level as comparable models of the same size or capacity, efficient appliances require less electricity. A model will use less energy and cost you less to run if it is more energy efficient.

Example a 3-star refrigerator saves a lot more energy compared to a 2 star.

Number of stars in the star rating label of an electrical appliance should be used is five for most efficient electrical device.

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Answer:

he sound waves travel to the window in the form of vibrations of air molecules. The air molecules near to the window receive the vibration and hit the window thereby passing on on the vibration.

The sound waves are transmitted to the window as air molecule vibrations. The vibration is transmitted to the window by hitting nearby air molecules that have picked up the disturbance.

Vibration is a periodic back-and-forth motion of the particles in an elastic body or medium that occurs when practically any physical system is moved out of its equilibrium condition and is left to react to forces that work to bring it back into balance.

Free and forced vibrations are the two types of vibrations. Free vibrations happen when the system is briefly perturbed and then allowed to move unrestrained. A weight suspended from a spring offers a timeless illustration. The system has the least amount of energy and the weight is at rest in an equilibrium state. The system will respond by vibrating vertically if the weight is dragged down and then let go.

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Answer:

3,13 N

Explanation:

Del enunciado de la segunda ley del movimiento de Newton;

F = ma

Dónde;

F = Fuerza aplicada

m = masa del cuerpo

a = aceleración del cuerpo

Sustitución de valores;

F = 5,9 kg * 0,53 m / seg2 = 3,13 N

Por tanto, la fuerza aplicada es 3,13 N

Answer:

Yes.

Explanation:

Yes, this system transmitting energy between your bodies because everybody is in thermal equilibrium with other body. Thermal equilibrium occurs when there is same amount of thermal energy is gained by the body and same amount of energy lost by the body so there is no increase or decrease occur in the thermal energy of each body so we can say that the system transmitting energy between the bodies.

Answer:

the correct address is B

In Rutherford's model of the atom, the positive charge is concentrated at the center of the atom.

The model described the atom as a tiny, dense, positively charged core called a nucleus, in which nearly all the mass is concentrated, around which the light, negative constituents, called electrons, circulate at some distance, much like planets revolving around the Sun.

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Answer: A.0,0097s

Mas a unidade aí deveria ser Hertz (Hz)

Explanation:

Answer:

103 hz

Explanation:

Answer:

Mass = 52.63 kilograms

Explanation:

Given the following data;

Acceleration due to gravity = 3.8 m/s²

Weight = 200 N

To find mass;

Mathematically, the weight of a physical object is given by the formula;

Weight = mass * acceleration due to gravity

Substituting into the formula, we have;

200 = mass * 3.8

Mass = 200/3.8

Mass = 52.63 kg

Answer:

Its Letter C Because Gravity's characteristic is to draw objects (including us) toward its center (which in this case, Earth).

Answer:

V = 5 m³

Explanation:

The density of air, d = 1.2 kg/m³

Mass of the dry air, m = 6 kg

We need to find the volume o the gas. We know that, the density of an object is given by mass divided by its volume. So,

[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{6}{1.2}\\\\V=5\ m^3[/tex]

So, the volume of the dry air is 5 m³.

Answer:

In 1 round 62.857m

In 1.5 round 94.2855m

In 2 round 125.714m

In 2.5 round 157.1425

Answer:

R = 4.77 ohms

Explanation:

Four resistors are given such that,

R₁ = 2 ohms

R₂ = 3 ohms

R₃ = 5 ohms

R₄ = 10 ohms

Here, R₁ and R₂ in series. The equivalent is given by :

R₁₂ = R₁ + R₂

= 2 + 5

R₁₂ = 7 ohms

Similarly, R₃ and R₄ are in series. so,

R₃₄ = R₃ + R₄

= 10+5

R₃₄ = 15 ohms

Now, R₁₂ and R₃₄ are in parallel. So,

[tex]\dfrac{1}{R}=\dfrac{1}{R_{12}}+\dfrac{1}{R_{34}}\\\\\dfrac{1}{R}=\dfrac{1}{7}+\dfrac{1}{15}\\\\R=4.77\ \Omega[/tex]

So, the equivalent resistance s 4.77 ohms.

Answer:

[tex] |B| = \sqrt{ {B _{x} }^{2} + {B _{y} }^{2} } \\ = \sqrt{ {7}^{2} + {5}^{2} } \\ = \sqrt{74} \\ = 8.6[/tex]

[tex]let \: the \: angle \: be \: \theta \\ \tan(\theta) = \frac{B _{y} }{B _{x} } \\ \tan( \theta) = \frac{ - 5}{7} \\ \theta = { \tan }^{ - 1} ( \frac{ - 5}{7} ) \\ = 35.5 \degree[/tex]

Answer:

B

A

Explanation:

please mark as brainliest :)

Answer:

YOUR answer is given below:

Explanation:

Drug B will retain the highest percentage of initial concentration.

First order degradation means that both solution will degrade by same amount in same time because first order is directly proportional relationship between given both aqueous solution.

Given that Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes.

Since, initially concentration of Drug B is more. Therefore, at all instant concentration of Drug will be highest.

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Resistance (R) = 9.375 ohm (Ω)

Steps:

[tex]R = \frac{V}{I} [/tex]

[tex] = \frac{12 \: volt}{1280 \: milliampere} [/tex]

[tex] = \frac{12 \: volt}{1.28 \: ampare} [/tex]

[tex] = 9.375 \: ohm (Ω)[/tex]

Answer:

Inertia : a property of matter by which it continue in its existing state of rest or uniform motion in a straight line, unless that state is changed by external force.

HOPE ITS HELPS!!

[tex]\boxed{\color{red}\huge\tt\bold\purple{Answer}}[/tex]

Inertia is the tendency of an object to continue in the state of rest or of uniform motion. The object resists any change in its state of motion or rest.