To solve this question, we need to use the combined gas equation which is given as
[tex]\begin{gathered} \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} \\ p=\text{pressure} \\ v=\text{volume} \\ t=\text{temperature} \end{gathered}[/tex]Now we should write down the given data
[tex]\begin{gathered} v_1=28.4l \\ p_1=724\operatorname{mm}hg \\ T_1=303K \\ v_2=15.5L \\ T_2=379K \\ p_2=\text{ ?} \end{gathered}[/tex]So, we would use the previous equation i wrote down.
[tex]\begin{gathered} \frac{p_1v_1}{t_1}=\frac{p_2v_2}{t_2} \\ \frac{724\times28.4}{303}=\frac{p_2\times15.5}{379} \\ 67.8600=\frac{p_2\times15.5}{379} \\ 15.5p_2=67.86\times379 \\ 15.5p_2=25718.94 \\ \text{divide both sides by the coefficent of p2} \\ \frac{15.5p_2}{15.5}=\frac{25718.94}{15.5} \\ p_2=1659.28\operatorname{mm}hg \end{gathered}[/tex]From the calculations above, the final pressure of the gas is 1659.28mmHg
a gaseous product of a chemical reaction is collected at 285k and 1.3atm. what was the molar mass of the gas in grams per mole if 6.2 g of gas occupies 5.4l
The molar mass of the gas in grams per mole if 6.2 g of gas occupies 5.4L is 336.97 grams.
What is molar mass?Molar mass is defined as the mass of a sample of a certain chemical divided by the quantity of the material, expressed as the number of moles in the sample.
It can also be defined as the product of the mass of a specific substance and the amount of that substance in the sample.
Given Pressure = 1.3 atm
Temperature = 285 K
Volume = 5.4 L
Gas content = 8.3
So, PV = nRT
n = RT / PV
n = 8.3 x 285 / 1.3 x 5.4
n = 336.97 grams
Thus, the molar mass of the gas in grams per mole if 6.2 g of gas occupies 5.4L is 336.97 grams.
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Show the conversions required to solve this problem and calculate the grams of Al2O3 .
Calcium nitrate and potassium fluoride solutions react to form a precipitate. Classify this reaction.
When calcium nitrate and potassium fluoride solutions react to form a precipitate, the type of reaction involved is the process is double replacement
Calcium nitrate and potassium fluoride solutions react to form calcium fluoride and potassium nitrate. Calcium fluoride would precipitate out whereas potassium nitrate would be in aqueous form.
Ca (NO₃)₂ (aq) + 2 KF (aq) → CaF₂ (s) + 2 KNO₃ (aq)
In double replacement reaction, the ionic compounds would exchange their respective ions to form a new compound. Here two ionic compounds, nitrate and fluoride from calcium and potassium respectively are exchanged to form calcium fluoride and potassium nitrate.
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The element tellurium would be expected to form covalent bond(s) in order to obey the octet rule.
As per the octet rule, the element tellurium will make 2 covalent bonds to complete it's octet.
What is octet rule?
The octet rule describes an atom's propensity to favor eight electrons in its valence shell. Atoms with fewer than eight electrons in the outermost shell are more likely to interact with one another and create better stable molecules. We ignore d or f electrons while considering the octet rule. The octet rule is useful for main group elements (those not in the transition metal or inner-transition metal blocks) since it only involves the s and p electrons. An octet in these atoms corresponds to an electron configuration ending in s2p6.
According to octet rule, an element require to complete it's octet (i.e. 8 electrons in the outermost shell). So, in the case of tellurium there are 6 electrons in the outermost shell therefore, we require two more electrons to complete the octet for which the tellurium would be expected to make 2 covalent bonds.
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8. How many oxygen atoms are in 25 g of oxygen?
1.9 × 1024 atoms
2.4 × 1026 atoms
9.4 × 1023 atoms
1.5 × 1025 atoms
Answer:
9.4 × 10²³ atomsExplanation:
To find the number of entities in a given substance we use the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
However we weren't given the number of moles only the mass of oxygen was given. we can find the number of moles from that by using the formula
[tex]n = \frac{m}{M} \\ [/tex]
m is the mass
M is the molar mass
n is the number of moles
Molar mass of oxygen = 16 g/mol
mass in question = 25 g
We have
[tex]n = \frac{25}{16} = 1.56 \\ [/tex]
number of moles = 1.56 mol
The number of oxygen atoms is equal to
N = 1.56 × 6.02 × 10²³ = 9.3912 × 10²³
We have the final answer as
9.4 × 10²³ oxygen atomsHope this helps you
How many molecules are in 59.73 grams of the theoretical acid borofuric acid, H2B2O2?
remember units and sig figs.
The number of molecules in 59.73 grams of the theoretical acid borofuric acid, H₂B₂O₂ is 6.47 × 10²³ molecules.
How to calculate number of molecules?The number of molecules in a substance can be estimated by multiplying the number of moles in the substance by Avogadro's number (6.02 × 10²³) as follows:
no of molecules = no of moles × 6.02 × 10²³
According to this question, there are 59.73 grams of the theoretical acid borofuric acid. The molar mass of this acid is as follows:
H₂B₂O₂ = 1(2) + 10.8(2) + 16(2) = 55.6g/mol
moles = 59.73g ÷ 55.6g/mol = 1.07mol
no of molecules = 1.07 × 6.02 × 10²³
no of molecules = 6.47 × 10²³ molecules
Therefore, 6.47 × 10²³ molecules is the number of molecules in the acid.
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A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in aspherical air tank that measures 73.0 cm wide.The biologist estimates she will need 8200. L of air for the dive. Calculate the pressure to which this volume of air must becompressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to 3 significant digits.0atm0.0XS ?EoloPEBH
To solve the problem we will assume the following:
1. Air behaves as an ideal gas during all the process.
2. The initial air equivalent to 8200L is at atmospheric pressure. It means 1 atm.
3. The temperature remains constant.
Taking into account the above, we can apply the Boyle-Marriote Law that relates the change in pressure and volume at constant temperature. The equation that we will use will be:
[tex]P_1V_1=P_2V_2[/tex]Where,
P1 is the atmospheric pressure. 1atm
V1 is the initial volume of air required, 8200L
P2 is the final pressure we want to find
V2 is the final volume, it means the volume of the spherical air tank. We will calculate this volume using the volume equation for a sphere:
[tex]V_2=\frac{4}{3}\pi r^3[/tex]r is the radius of the sphere, r=73cm/2=36.5cm
So, the volume of the spherical air tank will be:
[tex]\begin{gathered} V_2=\frac{4}{3}\pi\times(36.5cm)^3=20.4\times10^4cm^3 \\ V_2=20.4\times10^4cm^3\times\frac{1L}{1000cm^3}=204L \end{gathered}[/tex]No, we clear P2 from the first equation and replace known data:
[tex]\begin{gathered} P_2=\frac{P_1V_1}{V_2} \\ P_2=\frac{1atm\times8200L}{204L} \\ P_2=40.3atm \end{gathered}[/tex]The pressure of the gas must be 40.3 atm
Answer: 40.3
For a species to survive it must be within its ________ for all ___________ factors.
For a species to survive it must be within its geographical zone for all the genetic factors.
What is a species and how it can be within its geographical area?A species is a group of organisms with most number of characters in common.A species is the smallest unit of taxanomic heirarchy , in which one finds the highest number of characters in common.We can predict there are more than thousand of species living on earth.One species depends on another species either for food or survival also .For all the genetic factors that can be taken into account like the character , and all species needs to live in its geographical area only , if crossed the geographical zone then can be killed.To know more about species visit:
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yes or no ? experimentation with corn and other crops led to the development of new fuels called biofuels
Yes, the experimentation with corn and other crops led to the development of new fuels called biofuels.
What are biofuels?Biofuel is a biodegradable, inexhaustible, fuel that is produced from Biomass. Biofuel is considered the easiest available and pure fuel on the earth. Biofuels are manufactured from biomass such as wood and straw, which are liberated by direct combustion of dry matter and converted into a gaseous and liquid fuel.
The organic matter such as sludge, sewage, and vegetable oils, can be changed into biofuels by a wet process such as fermentation and digestion. Biofuel is available in all regions of the world, and mainly includes fuels such as Biodiesel, Bioethanol, and Bio methanol.
The two types of biofuels are bioethanol and biodiesel most commonly used these days. Both of these biofuels are the first generation of biofuel technology.
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Please help me it’s due today!!!!
The following are the examples of a chemical property of a substance;
1) A banana reacts with orange and turns brown
2) Iron will rust when exposed to oxygen and water
3) Iron will react with acid to form iron chloride.
What is a chemical reaction?The term chemical reaction has to do with the change in the properties of substances that are combined together in order to yield a product. Recall that the properties of the reactant change as the product is formed.
When a chemical reaction occurs
1: A new color may appear
2) A new gas may be seen
3) The temperature may be changed
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what is combustion? explain to me pls
Answer:
rapid chemical combination of a substance with oxygen, involving the production of heat and light.
Explanation:
Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives off heat. The original substance is called the fuel, and the source of oxygen is called the oxidizer.
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Calculate the molar mass of gold (III) hydroxide, Au(OH)3
Explanation:
We have to find the molar mass of Au(OH)₃. To do that we have to look for the atomic masses of each element. Also we have to consider that one molecule of
Au(OH)₃ has 1 atom of Au, 3 atoms of O and 3 atoms H.
atomic mass of Au = 196.97 amu
atomic mass of O = 16.00 amu
atomic mass of H = 1.01 amu
molar mass of Au = 196.97 g/mol
molar mass of O = 16.00 g/mol
molar mass of H = 1.01 g/mol
molar mass of Au(OH)₃ = 1 * molar mass of Au + 3 molar mass of O + 3 molar mass of H
molar mass of Au(OH)₃ = 1 * 196.97 g/mol + 3 * 16.00 g/mol + 3 * 1.01 g/mol
molar mass of Au(OH)₃ = 248.0 g/mol
Answer: the molar mass of Au(OH)₃ is 248.0 g/mol.
An atom with 3 protons in the nucleus and 3 electrons in the orbitals would have what overall charge?
Ans6
wer:
b
Explanation:
6. In order to prepare 50.0 mL of 0.100 M NaCl you will add _____ grams of NaCl to _____ mL of wate
The first step to solve this problem is to find the number of moles of NaCl in 50.0mL of 0.100M NaCl. To do it, convert the volume of solution to liters and multiply it by the concentration of the solution (M=mol/L).
[tex]50mL\cdot\frac{1L}{1000mL}\cdot\frac{0.100mol}{L}=0.005mol[/tex]Now, use the molar mass of NaCl to find the mass of 0.005moles of it (MM=58.44g/mol):
[tex]0.005mol\cdot\frac{58.44g}{mol}=0.2922g[/tex]It means that you have to add 0.2922g to 50mL of water.
How many molecules are in 59.73 grams of the theoretical acid borofuric acid, H2B2O2?
remember units and sig figs.
If your answer is a very large number, use scientific notation with an 'E' in this format:
120,000,000 = 1.2E8
The number of molecules in 59.73 grams of the theoretical acid, borofuric acid, would be 6.44 x [tex]10^2^3[/tex] molecules.
Avogadro's numberAccording to Avogadro, 1 mole of any substance contains 6.022 x [tex]10^2^3[/tex] molecules.
Recall that: number of moles in a substance = mass of the substance/molar mass of the substance.
Molar mass of borofuric acid, [tex]H_2B_2O_2[/tex]:
H = 1 g/mol
B = 10.8 g/mol
O = 16 g/mol
(1x2) + (10.8x2) + (16x2) = 55.6 g/mol
Number of moles of 59.73 grams [tex]H_2B_2O_2[/tex] = 59.73/55.6
= 1.07 moles
Since 1 mole = 6.022 x [tex]10^2^3[/tex] molecules
1.07 moles of borofuric acid = 1.07 x 6.022 x [tex]10^2^3[/tex] molecules.
= 6.44 x [tex]10^2^3[/tex] molecules
Thus, 59.73 grams of borofuric acid contains 6.44 x [tex]10^2^3[/tex] molecules.
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The cost of electricity to deposit 10gm of Mg is Rs. 60. How much would it cost to deposit 100gm of copper from CuSO
, ? (At. wt. of Cu = 63.5)
The cost of electricity to deposit 100g of copper from CuSO₄ will be Rs227.1
We know, m = zit
1unit current= 1kwh
Energy=Vit
m= (E. weight/F)×it
m proportional to (E. weight)×cost
m₁/m₂ = E₁/E₂ × C₁/C₂
E.weight = (Molecular weight/n-factor)
According to question,
Cu² + 2e- --- Cu
Mg² + 2e- --- Mg { n-factor of both=2}
E₁ = (molecular weight of Mg/2) = (24÷2) = 12
E₂ = (molecular weight of Cu/2) = (63.5) = 31.7
So, M₁/M₂ = E₁×C₁/E₂×C₂ (C₁=cost given)
10/100 = 12×60/31.7×C₂
C₂= Rs227.1
Therefore the cost of electricity to deposit 100g of copper from CuSO₄ will be Rs227.1
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explain Maxwell equations and maxwell thermodynamics relations; it's significance and application to ideal gases?
Answer:
In order to understand the Maxwell equations and relations derived from Maxwell relations, you will have to know Euler's Reciprocity.
It states that for any state thermodynamic quantity (let x and y) having a state function phi, it must satisfy the following condition.
[tex](\frac{ {∂}^{2}\phi }{∂x \cdot∂y}) = (\frac{ {∂}^{2}\phi }{∂y \cdot∂x})[/tex]
Maxwell equations: These are a set of equations derived from the application of Euler's Reciprocity. The four Maxwell equations are as follows:
[tex]dH = TdS + VdP[/tex]
[tex]dG = VdP - SdT[/tex]
[tex]dA = -PdV - SdT[/tex]
[tex]dU = TdS - PdV[/tex]
Let's derive each Maxwell relations step by step,
1) dH = TdS + VdP
Enthalpy is a function of Entropy & Pressure
[tex] \sf \qquad \qquad H = f(S,P)[/tex]
[tex]dH = TdS + VdP[/tex]
[tex]dH = (\frac{∂H}{∂S})_{_P} dS + (\frac{∂H}{∂P})_{_S}dP[/tex]
Comparing both the above equation,
[tex]T = (\frac{∂H}{∂S})_{_P}[/tex]
[tex]V =(\frac{∂H}{∂P})_{_S}[/tex]
now we know that Enthalpy is a state function hence applying cross reciprocality,
[tex](\frac{∂V}{∂S})_{_P}= (\frac{∂T}{∂P})_{_S}[/tex]
This is called the first Maxwell relation,
Similarly,
2) dG = -SdT + VdP
Free energy is a function of Temperature & Pressure,
[tex] \sf \qquad \qquad G = f(T,P)[/tex]
[tex]dG = -SdT + VdP[/tex]
[tex]dG = (\frac{∂G}{∂P})_{_T} dP + (\frac{∂G}{∂T})_{_P}dT[/tex]
Comparing both the above equation,
[tex](\frac{∂G}{∂P})_{_T} = V [/tex]
[tex] (\frac{∂G}{∂T})_{_P}= -S[/tex]
now we know that Free energy is a state function hence applying cross reciprocality,
[tex]-(\frac{∂S}{∂T})_{_P}= (\frac{∂V}{∂P})_{_T}[/tex]
This is called the second Maxwell relation,
3) dA = -PdV - SdT
helmholtz free energy is a function of Temperature & Volume,
[tex] \sf \qquad \qquad A = f(T,V)[/tex]
[tex]dA = -PdV - SdT[/tex]
[tex]dA = (\frac{∂A}{∂V})_{_T} dV + (\frac{∂A}{∂T})_{_V}dT[/tex]
Comparing both the above equation,
[tex](\frac{∂A}{∂V})_{_T} = -P [/tex]
[tex] (\frac{∂A}{∂T})_{_V}= -S[/tex]
now we know that helmholtz free energy is a state function hence applying cross reciprocality,
[tex]-(\frac{∂S}{∂V})_{_T}= -(\frac{∂P}{∂T})_{_V}[/tex]
[tex](\frac{∂S}{∂V})_{_T}= (\frac{∂P}{∂T})_{_V}[/tex]
This is called the third Maxwell relation,
4) dU = TdS - PdV
Internal energy is a function of Entropy & Volume,
[tex] \sf \qquad \qquad A = f(S,V)[/tex]
[tex]dU = TdS - PdV [/tex]
[tex]dU = (\frac{∂U}{∂S})_{_V} dS + (\frac{∂U}{∂V})_{_S}dV[/tex]
Comparing both the above equation,
[tex](\frac{∂U}{∂V})_{_S} = -P [/tex]
[tex] (\frac{∂U}{∂S})_{_V}= T[/tex]
now we know that Internal energy is a state function hence applying cross reciprocality,
[tex](\frac{∂T}{∂V})_{_S}= -(\frac{∂P}{∂S})_{_V}[/tex]
This is called the fourth Maxwell relation,
The main significance of the Maxwell relation is that those thermodynamic quantities which are unmeasurable can be replaced with measurable quantities with the help of the Maxwell relation.
The derivative of the extensive asset in relation to the extensive asset gives the intensive asset; with respect to the intensive asset, the derivative of the extensive asset gives the extensive asset. This is the result of the overall Maxwell relations.
The coefficient of expansion and compression of a gas in thermodynamics is the application of the Maxwell relations.
There are 3 coefficients introduced,
Coefficient of thermal expansion (expansivity) α
[tex]α= \frac{1}{V} (\frac{∂V}{∂T} )_{_P}[/tex]
Coefficient of isothermal compressibility β
[tex]β = -\frac{1}{V} (\frac{∂V}{∂P} )_{_T}[/tex]
Isochoric thermal expansion coefficient γ
[tex] γ= \frac{1}{P} (\frac{∂P}{∂T} )_{_V}[/tex]
For ideal gases,
PV = nRT
For one mole ideal gas (n=1),
PV = RT
Taking derivative with respect to T at constant pressure,
[tex]V(\frac{∂P}{∂T} )_{_P}+ P(\frac{∂V}{∂T} )_{_P}= R(\frac{∂T}{∂T} )_{_P}[/tex]
At constant pressure ∂P = 0, & R.H.S = 1, hence
[tex](\frac{∂V}{∂T} )_{_P}= \frac{R}{P}[/tex]
[tex]α= \frac{1}{V} (\frac{∂V}{∂T} )_{_P}[/tex]
[tex]α= \frac{1}{V} \cdot \frac{R}{P}[/tex]
[tex]\sf Also, PV=RT\\ \frac{R}{PV} = \frac{1}{T}[/tex]
[tex]\boxed{α= \frac{1}{T}}[/tex]
Following the same procedure, by taking derivating w.r.t. pressure at constant temperature.
[tex]V(\frac{∂P}{∂P} )_{_T}+ P(\frac{∂V}{∂P} )_{_T}= R(\frac{∂T}{∂P} )_{_T}[/tex]
[tex]V+ P(\frac{∂V}{∂P} )_{_T}= 0[/tex]
[tex](\frac{∂V}{∂P} )_{_T}= \frac{-V}{P}[/tex]
Substituting the above value in,
[tex]β = -\frac{1}{V} (\frac{∂V}{∂P} )_{_T}[/tex]
[tex]β = -\frac{1}{V} \cdot \frac{-V}{P}[/tex]
[tex] \boxed{β = \frac{1}{P}}[/tex]
Repeating the same procedure again, i.e. derivative w.r.t. T at constant volume
[tex]V(\frac{∂P}{∂T} )_{_V}+ P(\frac{∂V}{∂T} )_{_V}= R(\frac{∂T}{∂T} )_{_V}[/tex]
At constant Volume ∂V = 0, and R.H.S = 1, hence overall equation becomes,
[tex]V(\frac{∂P}{∂T} )_{_V} = R \\ (\frac{∂P}{∂T} )_{_V} = \frac{R}{V}[/tex]
Substituting above value in,
[tex]γ= \frac{1}{P} (\frac{∂P}{∂T} )_{_V}[/tex]
[tex]γ= \frac{1}{P} \cdot \frac{R}{V}[/tex]
[tex] \boxed{γ= \frac{1}{T}}[/tex]
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The Maxwell equation in thermodynamics is very important and useful because the set of relations allows the scientists to change specific unknown quantities.
What are the Maxwell's thermodynamic?The Maxwell equation in thermodynamics is very useful because this is the set of relations that allows physicists to change certain unknown quantities that are hard to measure in the real world. These quantities need to be replaced by many easily measured quantities. Maxwell's relations are a set of equations in thermodynamics that are derivable from the second derivatives and from the definitions of the thermodynamic potentials. These relations are named for the nineteenth-century physicist James Clerk Maxwell. So entropy and pressure are the natural variables of enthalpy. Maxwell relations are thermodynamic equations that establish the relations between various thermodynamic quantities in equilibrium and other fundamental quantities known as thermodynamical potentials
So we can conclude that Maxwell's thermodynamics are the set of relations allows the scientists to change unknown quantities.
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Saturated solutions of each of the following compounds are made at 20°C. Circle the letter(s) of the solution(s), which will form a precipitate upon heating.a) NaClb) Na2SO4c) Li2CO3d) Sucrose
In this question, we need to analyze the solubility of some substances and the changes that can occur to each one upon heating, at 20°C, every substance listed is soluble, NaCl, Na2SO4, Li2CO3 and Sucrose, but when we have a change in temperature, it will affect directly the solubility of the solution, for example, if you increase the temperature, Lithium carbonate and Sodium sulfate, will have a lower solubility in water, therefore if we have a certain amount of these two substances at 20°C and in 100g of water, the solution will be soluble, but if we increase the temperature, the solubility will change and these two compounds will start to precipitate, as the solubility will be lowering down.
Therefore the answers are Na2SO4 and Li2CO3
Silver Sulfate reacts with Potassium Chloride according to the following reaction:Ag2SO4 + 2KCl -> 2AgC1 + K2SO4a. If 30.0 grams of Ag2SO4 reacts with 10.0 grams of KCl, what mass of AgCl is produced by the reaction b. the limiting reactant is ______c. how many grams ok K2SO4 can be produced.d. how many grams of excess reactant remain after the reaction e. what is the percent yield if there is 10.0g of AgCl
Answer:
Explanations:
Given the chemical reaction
[tex]Ag_2SO_4+2KCl\rightarrow2AgCl+K_2SO_4[/tex]Given the following
Mass of Ag2SO4 = 30grams
Mass of KCl = 10grams
Determine the moles of the reactants
[tex]\begin{gathered} mole\text{ of Ag}_2SO_4=\frac{mass}{molar\text{ mass}}molar\text{ mass} \\ mole\text{ of Ag}_2SO_4=\frac{30g}{311.799} \\ mole\text{ of Ag}_2SO_4=0.0962moles \end{gathered}[/tex][tex]\begin{gathered} mole\text{ of KCl}=\frac{10g}{74.5513} \\ moleof\text{ KCl}=0.1341moles \\ 1mole\text{ of KCl}=\frac{0.1341}{2}=0.06707moles \end{gathered}[/tex]B) B) Since the 1 moles of KCl is lower than the moles of Ag2SO4, hence KCl willl be the limiting reactant.
A) A) According to stoichiometry, 2 moles of KCl produces 2 moles of AgCl, the mass of AgCl produced will be given as;
[tex]\begin{gathered} mass=mole\times molar\text{ mass} \\ mass\text{ of AgCl}=0.1341\times143.32 \\ mass\text{ of AgCl}=19.22grams \end{gathered}[/tex]C) According to stoichiometry, 2 moles of KCl produces 1 moles of K2SO4, the mole of K2SO4 produced is;
[tex]\begin{gathered} mole\text{ of }K_2SO_4=\frac{1}{2}\times0.1341 \\ mole\text{ of }K_2SO_4=0.06707moles \end{gathered}[/tex][tex]\begin{gathered} mass\text{ of K}_2SO_4=mole\times molar\text{ mass} \\ mass\text{ of K}_2SO_4=0.06707\times174.259 \\ mass\text{ of K}_2SO_4=11.69grams \end{gathered}[/tex]The Ka of a monoprotic weak acid is 0.00469. What is the percent ionization of a 0.141 M solution of this acid?
Use quadratic equation.
The percent ionization of an acidic solution can be calculated from the H+ concentration. the percent ionization of the monoprotic acid of 0.141 M is 18.23 %.
What is percent ionization?Percent ionization of an acidic solution is the percent of H+ ions in the solution. Thus, mathematically, it is the ratio of H+ ion concentration to the concentration of solution multiplied by 100.
Let HA be the monoprotic acid when it ionizes, forming equal concentration of H+ and A- let it be x. Thus ionization constant can be written as follows:
Ka = [x]² /[HA]
0.00469 =[x]²/[0.141 M]
[X] = 0.025. = [H+]
Percentage ionization = (0.025 M / 0.141 M)× 100
= 18.23 %
Therefore percentage ionization of the acid is 18.23%.
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At STP, exactly 1 mole of any gas occupies 22.4 L. What size container (in Liters) do you need to hold 2.1mol O₂ gas at STP?(Show all work)A) 44.2B) 47.0C) 40.0D) 55.5
Answer
B) 47.0
Explanation
If at STP, exactly 1 mole of any gas occupies 22.4 L
Then, 2.1 moles of O₂ gas at STP will occupy x L container
To get x L, cross multiply and divide both sides by 1 mole.
[tex]x\text{ }L\text{ }container=\frac{2.1\text{ }mol}{1\text{ }mol}\times22.4\text{ }L=47.0\text{ }L[/tex]Therefore, the size of the container (in Liters) needed to hold 2.1 mol O₂ gas at STP is 47.0 L
The partial pressure of oxygen was observed To be 156 torr
When the partial pressure of oxygen is 156 torr and the atmospheric pressure is 743 torr, the mole fraction of oxygen is 0.210.
What is partial pressure?Partial pressure is the pressure exerted by an individual gas in a mixture of gases. The partial pressure of a gas depends on its mole fraction.
The relationship between the partial pressure of a gas and the total pressure is given by Dalton's law, which states that the sum of the partial pressures is equal to the total pressure.
We can calculate the partial pressure of oxygen using the mathematical expression of Dalton's law:
pO₂ = P × X(O₂)
X(O₂) = pO₂ / P
X(O₂) = 156 torr / 743 torr = 0.210
where,
pO₂ is the partial pressure of oxygen.P is the total pressure of the mixture.X(O₂) is the mole fraction of oxygen.The mole fraction of oxygen is 0.210 when its partial pressure is 156 torr and the atmospheric pressure is 743 torr.
The complete question is:
The partial pressure of oxygen was observed To be 156 torr in air with a total atmospheric pressure of 743 torr. Calculate the mole fraction of oxygen present.
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Sulfur hexafluoride gas is collected at -4.0 °C in an evacuated flask with a measured volume of 5.0 L. When all the gas has been collected, the pressure in the
flask is measured to be 0.220 atm.
Calculate the mass and number of moles of sulfur hexafluoride gas that were collected.
answer needs has the correct number of significant digits
Mole of sulfur hexafluoride gas that were collected is 20.081 mol
Mass of sulfur hexafluoride gas that were collected is 0.137 gram
Sulphur hexafluoride gas is used as the electrical insulating material in circuit and breaker, cables and capacitor and sulfur hexafluoride gas is the nontoxic gas and it is an inorganic compound it is colorless and odorless and non flammable
Here given data is
Pressure = 0.220 atm.
Temprature = -4.0 °C = -4.0 °C +273 .15 K = 269.15 K
Volume = 5.0 L
Using ideal gas quation
PV = nRT
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R = gas constant = 0.0821 L.atm/K.mol
Applying the equation as
0.220 atm × 5.0 L = n × 0.0821 L.atm/K.mol × 269.15 K
n = 22.09/1.1
n = 20.081
Molar mass of sulfur hexafluoride gas = 146.06 g/mol
The formula for calculations of mole
Moles = mass taken/molar mass
20.081 = mass/146.06 g/mol
Mass = 0.137 gram
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Calculate the heat of reaction when 25.00 mL of 0.1102 M HCl(aq) at 25.14°C is added to 50.00 mL of 0.1024 M NaOH(aq) at the same temperature in a coffee-cup calorimeter that has a calorimeter constant of 0.001 J/°C. After mixing the temperature of the solution was observed to be 25.93°C.
The heat of reaction is obtained from the calculation as -0.65kJ/mol.
What is the heat of reaction?We already know that the heat of the reaction is computed by the use of the information that have been presented in the question. We know that this is a 1:1 reaction thus;
Number of moles of HCl = 0.1102 M * 25/1000 = 2.755 * 10^-3 moles
Number of moles of NaOH = 0.1024 M * 50/1000 L = 5.12 * 10^-3 moles
We can see from above that the HCl is the limiting reactant.
The hat evolved is obtained from;
0.001 J/°C. * (25.93°C - 25.14°C) = 1.79 * 10^-3 J
The heat of the reaction is then;
-( 1.79 * 10^-3 J) * 10^-3 * 1/2.755 * 10^-3 moles
-0.65kJ/mol
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Will Argon, Neon, and Krypton react the same or differently? Explain. (make it clear and simple. thank u)
-need help asap. thank u so much :)
Will Argon, Neon, and Krypton react same
Reactivity is the relative capacity of an atom or molecule or radical to undergo a chemical reaction with another atom or molecule or compound called as reactivity
In the noble gases only helium and neon are inert and the other noble gases will react with a limited scale under very specific conditions and krypton will form solid with fluorine and xenon will form a variety of compounds with oxygen and fluorine and the name comes from the fact that these elements are virtually unreactive towards other elements and they do not react with other element
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Why are Roman numerals needed in the names of ionic compounds containing a metal that forms more than one type of ion? Type one contains a metal with a invariant charge-One that does not vary from one compound to another. Type two contains a metal with a charge that can differ in different compounds. Match the items in the left column to the appropriate blanks in the sentences on the right
Cation
Type 1
Type 2
Anion
What are Type 1 and Type 2 compounds?The Roman numeral represents charge and the oxidation state of the transition metal ion.
One of the example is, iron that forms two ions, Fe2+ and Fe3+. To differentiate, Fe2+ is named iron (II) and Fe3+ is named iron (III).
Those compounds in which the cation has only one charge are Type 1 binary ionic compounds whereas compounds in which the cation can have multiple forms are Type 2 binary ionic compounds.
Type II Binary Ionic Compounds contain Transition metals with non-metal ions.
A monatomic cation derives its name from the name of the element. For example, Na+ is called sodium whereas monatomic anion is named by taking the root of the element and then adding -ide.
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For the reaction A (g) → 3 B (g), Kp = 67900 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial pressure of A when the partial pressure of B is 2.00 atm for this reaction at 298 K.
The partial pressure is the individual pressure of a gas. The partial pressure of gas A is 1.11 × 10⁻⁴atm.
What is partial pressure?
In a mixture of gases, the partial pressure of a gas is the individual pressure of that gas in the mixture of gases.
Given the reaction; A (g) → 3 B (g)
Kp = P(B)³/PA
Where Kp = 67900
PB = 2.00 atm
67900 = (2)³/PA
PA = (2)³/67900
PA = 1.11 × 10⁻⁴atm
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15.00g of hydrated zinc sulfate loses 6.579 H2O during heating what is the formula for the hydrate
15.00g of hydrated zinc sulfate loses 6.579 H₂O during heating what is the formula for the hydrate is ZnSO₄.7H₂O
Mass of anhydrous ZnSO₄ = 15.00 g - 6.579 g = 8.421 g
8.412 g of anhydrous ZnSO₄ = 6.579 g
molar mass of anhydrous ZnSO₄ = 161.47 g/mol
161.47 g of ZnSO₄ = (6.579 × 161.47) / 8.421
= 126 g
no. of moles of H₂O = mass / molar mass
= 126 / 18
= 7 molecules of H₂O
the formula for hydrate is ZnSO₄.7H₂O
Thus, 15.00g of hydrated zinc sulfate loses 6.579 H₂O during heating what is the formula for the hydrate is ZnSO₄.7H₂O
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34.8 g of Na₂O are used to form a solution with a volume of 450.0 mL L. What is the
molarity?
34.89
Answer:
1.25 M
Explanation:
(Step 1)
Convert grams to moles using the molar mass of Na₂O.
Atomic Mass (Na): 22.990 g/mol
Atomic Mass (O): 15.999 g/mol
Molar Mass (Na₂O): 2(22.990 g/mol) + 15.999 g/mol
Molar Mass (Na₂O): 61.979 g/mol
34.8 g Na₂O 1 mole
---------------------- x --------------------- = 0.561 moles Na₂O
61.979 g
(Step 2)
Convert milliliters to liters.
1,000 mL = 1 L
450.0 mL 1 L
------------------ x ------------------- = 0.4500 L
1,000 mL
(Step 3)
Calculate the molarity using the molarity ratio.
Molarity = moles / volume (L)
Molairty = 0.561 moles / 0.4500 L
Molarity = 1.25 M
how many atoms are in 6 moles of oxygen