A scientific ________ must have a control, so that the variables that could affect the out come is reduced. A:experiment B:conclusion. C:investigation. D:reasoning

Answer:

We smell hot food from distance because of the diffusion process. Diffusion is the spreading out and intermixing of particles From one substance into another substance due to the movement of particles.

Explanation:

Answer:

0

Explanation:

Point J is on neither plane X or plane Y.  Hope this helps you.

Answer:

3

Explanation:

Answer:

0 kgm/s

Explanation:

The momentum of Bob while resting at the river is 0 kgm/s.

This is because the momentum of any object at rest is 0.

 Momentum is the quantity of motion a body contains. It is mathematically expressed as;

  Momentum  = m x v

m is the mass

v is the velocity

 So at rest, the velocity of a body is 0m/s and therefore, the momentum is O

Answer:

pioneer species, soil formation, plant growth

Explanation:

The events of succession after a volcano erupted in the proper order include pioneer species being visible. The pioneer species such as algae and Moss are usually found on rocks and dead matter.

After sometime the soil starts to form through weathering activities which then gives rise to and supports the growing of plant species.

Answer:

0.1 im pretty sure

because

All those squares equal to 1

So if we use some good ole division

We get 0.1

Answer:

This equation is not balanced because you don't have the same amount of each element on each side of the chemical reaction. The balanced equation is:

2 S + 3  ⇒ 2

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:

Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by sub-index 2)

Right side: 1 sulfur S and 3 oxygen O (subindice value)

As you can see, you have the same amount of sulfur on both sides of the equation but the amount of oxygen is different. This indicates that the chemical equation is not balanced. To balance it, as the amount of sulfur is the same, the amount of oxygen must be balanced, which is different on each side of the reaction.

A simple way is to balance the equation is to multiply the product by 2, that is, add a coefficient 2 in front of the SO3 molecule, the reaction being as follows:

S + 3  ⇒ 2

Now the amount of elements on each side of the equation is:

Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)

Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)

The oxygen is now balanced, but the amount of sulfur on both sides of the reaction varies. To balance the quantities of sulfur, as now on the right side you have an amount of 2, you can add the coefficient to sulfur. The chemical equation is as follows:

2 S + 3  ⇒ 2

Now the amount of elements on each side of the equation is:

Left side: 2 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)

Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)

Finally you have the same amount of sulfur and oxygen on both sides of the reaction. So the chemical equation is finally balanced.

Explanation:

Brainliest please?

Answer:

it is balenced beacuse both sides have the same ammount of particals

Explanation:

Heat required : 4.8 kJ

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

The heat needed to raise the temperature

Q = m . c . Δt

1. heat to raise temperature from -20 °C to 0 °C

[tex]\tt Q=10\times 2.09\times (0-(-20)=418~J[/tex]

2. phase change(ice to water)

[tex]\tt Q=10\times 333=3330~J[/tex]

3. heat to raise temperature from 0 °C to 25 °C

[tex]\tt Q=10\times 4.18\times (25-0)=1045~J[/tex]

[tex]\tt Q~tot=418+3330+1045=4793~J\rightarrow rounding~and~2~sig~figs=4.8~kJ[/tex]

Answer:

13598 J

Explanation:

Q = m × c × ∆T

Where;

Q = amount of energy (J)

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

m = 65g, specific heat capacity of water = 4.184J/g°C, initial temperature= 100°C, final temperature = 150°C

Q = 65 × 4.184 × (150 - 100)

Q = 271.96 × 50

Q = 13598 J

Hence, 13598 J of energy is required to boil 65 grams of 100°C water and then heat the steam to 150°C.

Answer:

A

Explanation:

I think by writing electronic configuration.

Another way of representing an atomic model is the use of  periodic table

There  are different ways in which an atom can be modelled  and  some of these methods includes:

All the ways listed above can be used to model/represent an atom graphically ( drawing ). while the periodic table can be used to model an atom into its element without drawing. The periodic table makes use of valance numbers of the atoms and chemical similarities between atoms when modeling an atom.

learn more : https://brainly.com/question/19054910

Answer:

300 K

Explanation:

add 273 to change to kelvin

plz mark as brainiest

Answer:

true!

Explanation:

Answer:

the answer is the second option

Explanation:

hope you have a great day though!

Answer:

44g

Explanation:

Answer: B2 + 3W2 ---> 2BW3

Explanation:

You have 2 B on the right and 1 B on the left to balance out B, you need to add 2 wich gives you 6 W on the left and 2 W on the right. To baance W on both sides you add a 3 to the W on the right which gives you 6  W on both sides.

AnsThe flow of matter in an ecosystem is not like energy flow. Matter enters an ecosystem at any level and leaves at any level. So, its always flowingwer:

Explanation:

Answer:All matter can move from one state to another. It may require extreme temperatures or extreme pressures, but it can be done. Sometimes a substance doesn't want to change states. You have to use all of your tricks when that happens. To create a solid, you might have to decrease the temperature by a huge amount and then add pressure. For example, oxygen (O2) will solidify at -361.8 degrees Fahrenheit (-218.8 degrees Celsius) at standard pressure. However, it will freeze at warmer temperatures when the pressure is increased.

Some of you know about liquid nitrogen (N2). It is nitrogen from the atmosphere in a liquid form and it has to be super cold to stay a liquid. What if you wanted to turn it into a solid but couldn't make it cold enough to solidify? You could increase the pressure in a sealed chamber. Eventually you would reach a point where the liquid became a solid. If you have liquid water (H2O) at room temperature and you wanted water vapor (gas), you could use a combination of high temperatures or low pressures to solve your problem.

Points of Change

Phase Changes: Pressure and temperature define the state of matter for water.Phase changes happen when you reach certain special points. Sometimes a liquid wants to become a solid. Scientists use something called a freezing point or melting point to measure the temperature at which a liquid turns into a solid. There are physical effects that can change the melting point. Pressure is one of those effects. When the pressure surrounding a substance increases, the freezing point and other special points also go up. It is easier to keep things solid when they are under greater pressure.

Generally, solids are more dense than liquids because their molecules are closer together. The freezing process compacts the molecules into a smaller space.

There are always exceptions in science. Water is special on many levels. It has more space between its molecules when it is frozen. The molecules organize in a specific arrangement that takes up more space than when they are all loosey-goosey in the liquid state. Because the same number of molecules take up more space, solid water is less dense than liquid water. There are many other types of molecular organizations in solid water than we can talk about here.

CHEMISTRY TERM PHASE CHANGE

Fusion/Melting

Freezing

Vaporization/Boiling

Condensation

Sublimation

Deposition

Solid to a Liquid

Liquid to a Solid

Liquid to a Gas

Gas to a Liquid

Solid to a Gas

Gas to a Solid

Explanation:

Answer:

D

Explanation:

Hope this helps

Grams of Ca(NO₃)₂ produced : 0.985 g

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

CaCl₂ + 2AgNO₃ → 2AgCl + Ca(NO₃)₂

MW AgNO₃ : 107.9+14+3.16=169.9

mol AgNO₃ :

[tex]\tt \dfrac{2}{169.9}=0.012[/tex]

mol ratio Ca(NO₃)₂ : AgNO₃ = 1 : 2, so mol Ca(NO₃)₂ :

[tex]\tt \dfrac{1}{2}\times 0.012=0.006[/tex]

MW Ca(NO₃)₂ : 40.1+2.14+6.16=164.1 g/mol

mass Ca(NO₃)₂ :

[tex]\tt 0.006\times 164.1=0.985[/tex]

Answer:

Reagent O₂ will be consumed first.

Explanation:

The balanced reaction between O₂ and C₄H₁₀ is:

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:

Being:

The molar mass of the compounds that participate in the reaction is:

Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:

If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

[tex]mass of O_{2} =\frac{416grams of O_{2}*62.4 grams ofC_{4}H_{10} }{116 grams of C_{4}H_{10}}[/tex]

mass of O₂= 223.78 grams

But 21.78 grams of O₂ are not available, 78.1 grams are available. Since you have less mass than you need to react with 62.4 g of C₄H₁₀, reagent O₂ will be consumed first.