A second-hand car costs $2400. The price falls by 25% when it is sold again. How much is it sold for?

Answer:

Step-by-step explanation:

Answer:

[tex]\frac{(x+2)(x+3)^2(x-3)}{(x-4)^2(x+4)}[/tex]

Step-by-step explanation:

i'm going to assume what you have looks like

[tex]\frac{x^2-9}{\frac{x^2-16}{\frac{x^2+5x+6}{x-4}}}[/tex]

Let's start by factoring everything

x²-9= (x+3)(x-3)

x²-16= (x+4)(x-4)

x²+5x+6=(x+3)(x+2)

x-4= x-4

which means what we have looks like

[tex]\frac{(x+3)(x-3)}{\frac{(x+4)(x-4)}{\frac{(x+3)(x+2)}{x-4}}}=\frac{(x+3)(x-3)}{(x+4)(x-4)}\div\frac{x-4}{(x+3)(x+2)}=\frac{(x+3)(x-3)}{(x+4)(x-4)}*\frac{(x+3)(x+2)}{x-4}=\frac{(x+3)^2(x-3)(x+2)}{(x+4)(x-4)^2}[/tex]

And I think that's as simplified as it can get

Answer:

It's indeed A. Yet I think of reporting multiple same questions as spam and nonsense titles.

but nah, I won't, would be kinda focused on the toxic part then :D

Answer: Should be (3, 1) :)

Step-by-step explanation:

Answer: (4,-8)

Step-by-step explanation:

you look at the point it is and flip it to a negative

Answer:

y=1x+27

y=1(3)+27

Y=30

Step-by-step explanation:

X=DAYS

M=DOLLARS

Hope this helps brotha

Answer:

72 m^3

Step-by-step explanation:

volume of the kiosk = volume of cylinder + volume of cone

volume of a cylinder = nr^2h

n = 3.14

r = radius = 5/2 = 2.5

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

3.14 x (2.5^2) x 3 = 58.88  

Volume of a cone = 1/3(nr^2h)

3.14 x 1/3 x (2.5^2) x 2 = 13.08

13.08 + 58.88 = 71.96

To round off to the nearest cubic meter, look at the first number after the decimal, if it is less than 5, add zero to the units term, If it is equal or greater than 5, add 1 to the units term.

= 72 m^3

[tex]\longrightarrow{\blue{ 2 \: ( \: 32 \: y + 3 \: x \: )}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]64 \: y + 6 \: x[/tex]

[tex] = 2 \: ( \: 32 \: y + 3 \: x \: )[/tex]

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer:

2 ( 32y + 3 x)

Step-by-step explanation:

64 y + 6x

factor out 2 from the equation

2 ( 32y + 3 x)

Answer:

$213,200,000 or 2.132*10[tex]^{5\\}[/tex]

Step-by-step explanation:

82000*2600

Answer:

they are similar cuz it resembles a "z" pattern. The angles are so the same.

Answer:

HCF=8

LCM=480

Step-by-step explanation:

prime factor trees

Answer:

60

Step-by-step explanation:

48=2×2×2×2×3

64=2×2×2×2×2×2

80=2×2×2×2×5

H.C.F.=2×2×2×2=16

L.C.M=2×2×2×2×2×2×3×5

L.C.M.÷H.C.F.=(2×2×2×2×2×2×3×5)/(2×2×2×2)=2×2×3×5=60

Answer:

x = ±3 sqrt(2)

Step-by-step explanation:

x^2 = 18

Take the square root of each side

sqrt(x^2) = sqrt(18)

x = ± sqrt(18)

x =±sqrt(9*2)

x = ±sqrt(9) sqrt(2)

x = ±3 sqrt(2)

Answer:

$920

Step-by-step explanation:

800(1.15) = 920

Answer:

t=time

v=speed

t=k/v

8hr=k/36 mi/hr

k=288 mi

t=288 mi24 mi/hr =12 hours.

-------------------

The distance is 288 miles by multiplying 36 by 8.

divide that by 24 mph, and it is 12 hours.

===================================================

Work Shown:

(5 oranges)/(2 dollars) = (20 oranges)/(x dollars)

5/2 = 20/x

5x = 2*20 .... cross multiply

5x = 40

x = 40/5 .... dividing both sides by 5

x = 8

20 oranges cost $8

--------------

Another way to approach the problem is to note that the jump from "5 oranges" to "20 oranges" is "times 4".

5*4 = 20

So we'll apply the "times 4" operation to the old cost of $2 to get the new cost being 2*4 = 8 dollars

Answer:

$8

Step-by-step explanation:

if 5 oranges cost $2 then 1 orange costs 2/5 of a dollar, or 40 cents

20 oranges multiplied by 40 cents is $8

or you can set up a proportion:

2/5 = x/20

cross-multiply to get:

5x = 40

x = 8

Answer:

x = 12.35

Step-by-step explanation:

Tan(39) = 10/x

Tan(39) * x = 10

x = 10 / Tan(39)

x = 12.35

Hope this helps!

Answer:

Step-by-step explanation:

Remember SOHCAHTOA.

In this case, we use TOA.

tan(39) = 10/x

x = 10/tan(39)

x = 12.349

To me, this means doing a righteous act has no constraint based on what situation anyone is in.

Answer:

$1,040

Step-by-step explanation:

First, turn your percent into a decimal

8% = 0.08

Next, multiply your decimal by 65.

0.08 × 65 = 5.2

Lastly, multiply your product by $200

5.2 x $200 = $1,040

Answer:

9 < √97 < 10

Step-by-step explanation:

√97 is a little less than √100

Which is 10

9 < √97 < 10

=====================================================

Explanation:

Consider that 81 < 97 < 100 is a true statement. Note the 81 and 100 are perfect squares such that 81 = 9^2 and 100 = 10^2

We can apply the square root to all three sides to get the following

[tex]81 < 97 < 100\\\\\sqrt{81} < \sqrt{97} < \sqrt{100}\\\\\sqrt{9^2} < \sqrt{97} < \sqrt{10^2}\\\\9 < \sqrt{97} < 10\\\\\text{The number }\sqrt{97} \text{ is between 9 and 10}\\\\[/tex]

Using a calculator, we can help verify this

[tex]\sqrt{97} \approx 9.85[/tex]

Answer:

Max

Step-by-step explanation:

the function given that h = -16t³+64t+10

the general function Equation:

h = at²+bt+c

=> t at the highest point is defined by t = -b/2a

= -64/2(-16) = -64/-32 = 2 second

the total times that the ball hits the ground

= 2× 2 seconds = 4 seconds.

so, Max is right

Answer:

Solution given:

Let h=0=when the ball hit the ground,the height=0.

h= -16t^2 + 64t + 10.

0=16t²-64t-10

8t²-32t-5=0

∆=[tex] \frac{32±\sqrt{32²+4*5*8}}{2*8}=\frac{8±\sqrt{74}}{4}[/tex]

taking positive

t1=[tex] \frac{8+\sqrt{74}}{4}=4.15seconds[/tex]

t2=[tex] \frac{8-\sqrt{74}}{4}(t2<O)(neglected)[/tex]

So

t=4.15seconds closer to 4seconds.So

Max is closer.

Answer:

x=12

Step-by-step explanation:

since they are similar triangle .Use these ratios

9/6=x+9/14

do cross multiplication

6(x+9)=14*9

6x+54=126

6x=126-54

x=72/6

x=12

Answer:

30-12=18

18-18=0

Step-by-step explanation:

2x + 12 = 30

X represents the snacks, 2 represents the $2 per snack, 12 represents the $12 entry fee, and 30 represents the $30 Olivia had.

Answer:

a₄ = 123

Step-by-step explanation:

a₁ = 1

a₂ = (1)² + 2

a₂ = 3

a₃ = (3)² + 2

a₃ = 11

a₄ = (11)² + 2

a₄ = 123

Answer:

b = 14

u = 4

Step-by-step explanation:

I manually counted because I forgot how to solve this. HAHA

Hope this helps

Answer:

The base of the ladder is 3.2 meters far from the wall.

Step-by-step explanation:

We need to calculate the base of a right triangle. The given information is:

h: hypotenuse = length of the ladder = 6 m      

b: is the base =?

θ: is the angle between the hypotenuse and the base = 58°

To find the base we can use the following trigonometric equation:

[tex]cos(\theta) = \frac{b}{h}[/tex]

[tex] b = cos(\theta)*h = cos(58)*6 = 3.2 m [/tex]

Therefore, the base of the ladder is 3.2 meters far from the wall.

I hope it helps you!

Answer:

3/25

Step-by-step explanation:

Answer:

=325

Showing Work:

12%=12100

=0.12

=0.121×100100

=12100

=325

Answer:

First : Unbiased

Second : Biased

Hope This Helps!!!

Hope This Helps!!!Have A Great Day!!!

Step-by-step explanation:

[tex]\frac{120+30}{\frac{66}{1126}-8*3+17-4*4 }[/tex]

[tex]\frac{-42225}{6458}[/tex]

Answer:

x = sqrt(33)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

4^2 + x^2 = 7^2

16 + x^2 = 49

Subtract 16 from each side

x^2 = 49-16

x^2 = 33

Take the square root of each side

sqrt(x^2) = sqrt(33)

x = sqrt(33)

[tex]\quad\quad\quad \boxed{ \tt{\color{blue}{c}^{2} = {a}^{2} + {b}^{2} }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{\color{blue}{a} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{\color{black}{a} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {7}^{2} - {4}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {49} - {16} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt \color{black}{{x} = \sqrt{ 33} }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt \color{green}{{x} = \sqrt{ 33} }}[/tex]

_________

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