Answer in your PE notebook
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Answer:

Static friction

Explanation:

Answer:

Static friction

Explanation:

Answer:

The answer is given as follows,

Explanation:

Gold large-sized weight 100 g < M < 250g

50 g < Magenta small-sized weight < 100g

100g < Blue medium-sized weight < 250g

Hence,

100g < Blue medium-sized weight < 250g

50 g < Magenta small-sized weight < 100g

100 g < Gold large-sized weight < 250g.

Answer:

Find answers below.

Explanation:

A graph can be defined as the graphical representation of data (informations) on horizontal and vertical lines i.e x-axis and y-axis respectively.

On the x-coordinates, we have the following points or values;

1. Smiley face = 2

2. Diamond = 2

3. Sun = 0

4. Heart = 3.75

On the y-coordinates, we have the following points or values;

1. Smiley face = 1

2. Diamond = 3.75

3. Sun = 3.75

4. Heart = 0

Note: to read the points on a graph, you would look at the exact points marked on the x-coordinates (x-axis) and y-coordinates (y-axis) respectively.

The scale used for this graph is 0.75 for each unit on the x-coordinates and y-coordinates respectively.

Answer:

oh 50 points! how did you do it??!?!?!?! I see up to 8 points only

Answer:

Hello, thank you for giving out points, you are very kind !

True

Hope this helps! :)

Answer:

true because when trow the frisbee gives u level

Answer:

the area of the rectangular field is 10.5 m²

Explanation:

Given;

length of the rectangular field, L = 42 cm = 0.42 m

breadth of the rectangular field, b = 25 m

The area of the rectangular field is calculated as follows;

Area = Length x breadth

Area = 0.42 m x 25 m

Area = 10.5 m²

Therefore, the area of the rectangular field is 10.5 m²

Answer:

Answer: Speed is not a vector quantity. It has only magnitude and no direction and hence it is a scalar quantity.

Answer:

Sorry I don't know the answer

Answer: 1.85 C

Explanation:

Given

charges on the conductors are [tex]-1.8\ C[/tex] and [tex]5.5\ C[/tex]

They are connected by a conducting wire for a short period of time and then disconnected. During this time charge flow from the wire and net charge becomes [tex]5.5-1.8=3.7\ C[/tex]

This charge will be equally distribute among the two conductors i.e. 1.85 C on each conductor.

Answer:

F' = F/16

Explanation:

The gravitational force between masses is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]

If the distance between the center of two objects is quadrupled, r' = 4r

New force will be :

[tex]F'=G\dfrac{m_1m_2}{r'^2}\\\\F'=G\dfrac{m_1m_2}{(4r)^2}\\\\F'=\dfrac{Gm_1m_2}{16r^2}\\\\F'=\dfrac{1}{16}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{16}[/tex]

So, the new force will change by a factor of 16.

Answer:

yhgigy6ftu5cg l8vbbnnbbgtccccvhklhaywje nc 62bbnzmakbdbvfvdbf93bdldmffmfkqhdv

the answer is 396 joules :D

Answer:

W = 20 J

Explanation:

Given that,

Charge, q = 2 C

It is moves from a point at 118 volt to a point at 128 volt.

We need to find the work done in moving the charge,

[tex]W=\Delta VQ[/tex]

Put all the values,

[tex]W=(128-118)\times 2\\\\W=20\ J[/tex]

So, the work done in moving the charge is 20 J.

Answer:

(a) Radius = 4.6 x 10^11 m

(b) speed = 16.96 km/s

Explanation:

Time period, T = 5.4 earth years

mass of sun, M = 1.989 x 10^30 kg

(a) Let the orbital radius is R.

use the formula of period

[tex]T^2 = \frac{4 \pi^2 R^3}{G M}\\\\\left ( 5.4\times 365\times 24\times 3600 \right )^2 = \frac{4\times3.14\times 3.14\times R^3}{6.67\times10^{-11}\times 1.989\times 10^{30}}\\\\R = 4.6\times 10^{11} m[/tex]

(b) Let the speed is v.

[tex]v=\frac{2 \pi\times R}{T}\\\\v=\frac{2\times 3.14\times 4.6\times 10^{11}}{5.4\times 365\times 24\times 3600}\\\\v = 16963.6 m/s =16.96 km/s[/tex]

Answer:

22.5 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 30 m/s

Time (t) = 1.5 s

Final velocity (v) = 0 m/s

Distance (s) =?

The distance to which the car move before stopping from the time the driver applied the brake can be obtained as follow:

s = (u + v)t/2

s = (30 + 0)1.5 / 2

s = (30 × 1.5) / 2

s = 45 / 2

s = 22.5 m

Thus, the car will move to a distance of 22.5 m before stopping from the time the driver applied the brake.

M1 = 15/g = 15/9.8 = 1.53 kg = mass of object in air. M2 = 12/9.8 = 1.22 kg = mass of object immersed. M1-M2 = 1.53-1.22 = 0.31 kg lost by object = mass of water displaced. ... Do = 4.94 g/cm^3 = density of object.

Answer:

A

Explanation:

weight of the tree =normal force

Horizontal force =coefficient of friction x Fnormal

0.5×430=215

Answer:Alternativa A.   Damos o nome de interferência a superposição de efeitos que ocorre ao ser produzido dois pulsos de onda, que serão propagados e acabarão inevitavelmente por se encontrar. No instante em que os pulsos se cruzarem, há então, uma superposição de efeitos individuais de cada um deles. Se durante o cruzamento, houver um reforço das ondas, estará ocorrendo a este fenômeno.

The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm. Option A is correct.

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of the given mechanical machine.

Mechanical advantage is a measure of how much a machine multiplies the input force.

The equation for the mechanical advantage of a lever is;

MA =length of effort arm/length of resistance arm

[tex]\rm MA=\frac{L_E}{L_R}[/tex]

The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm.

Hence, option A is correct.

To learn more about the mechanical advantage, refer to the link;

https://brainly.com/question/7638820

#SPJ1

The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm. Option A is correct.

What is the mechanical advantage?

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of the given mechanical machine.

Mechanical advantage is a measure of how much a machine multiplies the input force.

The equation for the mechanical advantage of a lever is;

MA =length of effort arm/length of resistance arm

Answer:

a)  v_f = 5,06 m/s, b)  GAIN in kinetic energy.

Explanation:

a) For this exercise we will use the relationship between work and kinetic energy

           W = ΔK

Work is defined by

           W = F. d

bold indicates vectors

the displacement is

            d = x_f - x₀

            d = 4 -1

            d = 3i m

we calculate

          W = 20 10⁻² 3 i.i

let's remember that

         i.i = j.j = 1

         i.j = 0

          W = 6.0 10⁻¹ J

we substitute in the first equation

          W = K_f - K₀

          W = ½ m (v_f ² -v₀²)

          v_f ² = [tex]\frac{2W}{m} + v_o^2[/tex]

let's calculate

          v_f ² = 2 6.0 10⁻¹ /2 + 5²

          v_f = √25.6

          v_f = 5.06 m / s

b) we can see that the speed at the end of the movement is greater than the initial speed, therefore there is a GAIN in kinetic energy.

Answer:

564

Explanation:

product of force and perpendicular distance

Answer:

As the number of free electrons increases, the resistance of this type of non-metallic material decreases with increasing temperature.

Explanation:

Answer:

the tension in the tightrope is 233.68 N

Explanation:

Given the data in the question;

Time taken to reach the opposite tower t = 0.9 s

Distance between the two towers S = 26 m

mass per one meter length =  0.28 kg

First we calculate the velocity;

Velocity V = Distance / time

we substitute

Velocity V = 26 m / 0.9 s

Velocity V = 28.889 m/s

We know that Velocity V can also be expressed as;

V = √( T / m )

we make T the subject of formula

V² = T / m

T = mV²

we substitute

T = 0.28 × ( 28.889 )²

T = 233.68 N

Therefore,  the tension in the tightrope is 233.68 N

Explanation:

The logarithmic damping decrement of a mathematical pendulum is DeltaT=0.5. How will the amplitude of oscillations decrease during one full oscillation of the pendulum

Answer:

the work required is 0.163 J

Explanation:

Given;

Energy applied to the spring, E = 2 J

initial length of the spring, x₀ = 32 cm

final length of the spring, x₁ = 46 cm

Extension of the spring, Δx = x₁ - x₀ = 46 cm - 32 cm = 14 cm = 0.14 m

The spring constant is calculated as follows;

E = ¹/₂kΔx²

[tex]k = \frac{2E}{(\Delta x)^2} = \frac{2\times 2}{(0.14)^2} = 204.1 \ N/m^2[/tex]

The extension of the spring when it is stretched from 37 cm + 41 cm:

Δx =  41 cm - 37 cm = 4 cm = 0.04 m

The work required:

W = ¹/₂kΔx²

W = ¹/₂ x (204.1) x (0.04)²

W = 0.163 J

Therefore, the work required is 0.163 J

Answer:

because it is helpful to human beings I think

Answer:

a) the most probable speed of the molecules is 409.2 m/s

b) required temperature of xenon is 1322 K

Explanation:

Given the data in the question;

a)

Maximum probable speed of hydrogen molecule (H₂)

[tex]V_{H_2[/tex] = √( 2RT / [tex]M_{H_2[/tex] )

where R = 8.314 m³.Pa.K⁻¹.mol⁻¹ and given that T = 20.3 K

molar mass of H₂; [tex]M_{H_2[/tex] = 2.01588 g/mol

we substitute

[tex]V_{H_2[/tex] = √( (2 × 8.314 × 20.3 ) / 2.01588 × 10⁻³  )

[tex]V_{H_2[/tex] = √( 337.5484 / 2.01588 × 10⁻³  )

[tex]V_{H_2[/tex] = 409.2 m/s

Therefore, the most probable speed of the molecules is 409.2 m/s

b)

Temperature of xenon  = ?

Temperature of hydrogen = 20.3 K

we know that;

T = (Vxe² × Mxe) / 2R

molar mass of xenon; Mxe = 131.292 g/mol

so we substitute

T = ( (409.2)² × 131.292 × 10⁻³) / 2( 8.314  )

T = 21984.14167 / 16.628

T = 1322 K

Therefore, required temperature of xenon is 1322 K

Answer:

[tex]V_{a/c} = V_{a/b} + V_{b/c}[/tex]

Explanation:

The relative velocity of an object is the velocity of the object relative to the observer or frame of reference.

The velocity of particle "A" with respect to particle "B" is written as [tex]V_{A/B} = V_{A} - V_{B}[/tex]

From the given options, the second option is the correct answer.

[tex]V_{a/c} = V_{a/b} + V_{b/c}\\\\Re-arrange \ the \ above \ equation;\\\\V_{a/c} - V_{b/c}= V_{a/b}\\\\or\\\\V_{a/b}= V_{a/c} - V_{b/c}[/tex]