Before Europe colonized the Americas indigenous peoples used controlled burning to alter the landscape. Controlled fires were part of the environmental cycles and wildlife habitat protection that underpinned the cultures and economies of the Native American peoples.
Before European invasion tribes used controlled burning to remove shrubs that acted as craters returning nutrients to the soil preventing overcrowding and excessive competition for nutrients and water and maintaining healthy forests pastures. and cleared grasslands for wildlife such as water buffalo Prevent forest fires.
For many indigenous peoples fire was an essential part of life. Native Americans Alaskan Natives and Native Hawaiians used fire to clear land for crops and travel to cultivate land for certain plant and animal species to hunt game and for many other important purposes. used. Indigenous peoples were able to survive many natural disasters because they learned to move quickly when a disaster struck an area.
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Compare the value you calculated for the number of sand grains on Earth's beaches to the number of particles In
mole.
What can you conclude about the size of a mole?
The number of particles in a mole is about
the number of grains of sand on Earth's beaches.
So, the number of particles in a mole is about 80,000 the number of grains of sand on Earth’s beaches.
How to slove and Compare the value you calculated for the number of sand grains on Earth's beaches to the number of particles In mole?
Using sand grains that take up space of 1 mm, when these sand grains are laid side by side, there are about 1000 grains of sand per m, 1000000 per square m and 1000 × 1000 × 1000 per cubic m.
That is 10⁹ grains of sand per cubic meter.
An average beach has sand volume of (1.875 × 10⁷) cubic metres
There are over 400 beaches in the world, Using an estimate of 400 beaches
The number of grains of sand on Earth's beaches = 10⁹ × 400 × 1.875 × 10⁷
There are approximately (7.5 × 10¹⁸) grains of sand on all of the world's beaches
Then, Avogadro's number found that 1 mole of all particles contain
(6.022 × 10²³) particles.
So, the number of particles in a mole is about [(6.022 × 10²³)/(7.5 × 10¹⁸)]
the number of grains of sand on Earth’s beaches.
So, the division gives, (8.0 × 10⁴).
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How many moles of sodium sulfate (Na2SO4) are in 83.1 g of the compound?
Answer:
0.585 moles Na₂SO₄
Explanation:
To find the amount of moles of Na₂SO₄, you need to multiply the given mass (grams) by the molar mass. You can use the molar mass to convert between grams and moles because the molar mass exists as a ratio which compares the mass of Na₂SO₄ per every 1 mole. The ratio should be arranged in a way that allows for the cancellation of units (grams should be in the denominator). The final answer should have 3 sig figs like the given value.
Atomic Mass (Na): 22.990 g/mol
Atomic Mass (S): 32.065 g/mol
Atomic Mass (O): 15.999 g/mol)
Molar Mass (Na₂SO₄): 2(22.990 g/mol) + 32.065 g/mol + 4(15.999 g/mol)
Molar Mass (Na₂SO₄): 142.041 g/mol
83.1 grams Na₂SO₄ 1 mole
-------------------------------- x -------------------------- = 0.585 moles Na₂SO₄
142.041 grams
Identify each reactant and product in this reaction as a Brønsted acid or base.H,Y +H,Z =H,Y+HZ-acidbaseacidAnswer Bankbase
According to the definition of acids, for Bronsted-Lowry, an acid is any species that can donate a proton, which is H+, to another molecule, and a base is any species that is capable of accepting a proton. Therefore, according to this definition, we have the following reaction:
H2Y- + H2Z- <---> H3Y + HZ^2-
In this reaction, we can see that H2Z donated a H+ to H2Y, therefore H2Z is the acid on the reactants side, and H2Y will be the base.
On the products side, since we have a reversible reaction, H3Y will donate a H to HZ^-2, therefore H3Y will be the acid, and HZ^-2 will be the base
Please help me please
If air conditioning system won't be able to chill your home until the fan is fixed if it has stopped functioning.
What happens if your AC fan stops working?Your air conditioning system won't be able to chill your home until the fan is fixed if it has stopped functioning. The circuit breaker should be checked first if the AC unit fan is not whirling. Check to see if the circuit breaker for the air conditioning equipment has tripped. The heat from the motor and the weather outdoors can cause a circuit breaker to trip due to overheating.
If the fan won't turn on, the fan motor might be malfunctioning. If you are having trouble getting the blades to turn, the motor bearings may be dusty or stuck, or there may be debris wrapped around the fan axle.
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If the fan motor is malfunctioning, it could seriously harm your system. Your entire system could fail if the fan motor becomes stuck, which could lead to the compressor overheating and failing.
What would cause AC fan to stop?A dead capacitor is one of the most typical reasons fans cease spinning. The fan motor and the remainder of the AC unit are powered by small, cylindrical capacitors that transmit energy signals. An air conditioner fan motor can get too hot if it runs too hard and isn't properly maintained, just like any other motor. The stress may cause the fan motors to burn out if your AC has served you well for the majority of the summer. A lifespan of 10 to 20 years is more typical, which implies that by the time the AC motor breaks, it is frequently time to think about replacing the entire system. They are built to endure intense heat up to 140°F, which is one reason they stay so long.To learn more about cause AC fan to stop refer:
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Although an object's speed can vary while it moves, which speed listed is possible to calculate by
using total distance and total time?
A. average speed
B. total speed
C. initial speed
D. final speed
8. Which statements are true about why wind tends to blow from over the water to over the land on a sunny day? Highlight all the statements that apply.
A. Air over the water is cooler than air over the land is.
B. The air above the land has greater density.
C. The wind is caused by differences in density.
D. Cool, dense air from over the water flows toward the land, pushing warm air upward.
The wind tends to blow from over the water to over the land due to the differences in the density of air. Air over the water is cooler than air over the land and denser air from over the water flows toward the land. Therefore, options A, C, and D are correct.
What is sea breeze?The sea breeze is the wind that blows across the sea toward land throughout a sunny day. The air over land heats up more quickly during the day and starts to rise in coastal areas.
A low-pressure area forms on the surface of the land as the warm air rises, allowing air over the water to enter. As a result, during the day the wind direction is from the water to the land and this wind happens to be the sea breeze.
The sea breeze is a thermally produced wind during the day blowing from the cool ocean towards warm land. It is caused by the difference in the density of air between the land and the ocean.
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What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?(Specific heat of water is 4.184 J/g °C)
Answer:
dt=20.08
Explanation:
Q=msdt
840=10*4.184*dt
dt=840/(10*4.184)
dt=20.08
How do you identify a redox reaction?
Answer:
I think you have to calculate the oxidation number of each atom in the reaction.
Explanation:
Hope that helped! ^u^
Hi could you please I just want to be sure on how to do these diagrams
Explanation:
Formaldeyde
Lewis Structure:
Structural diagram:
3D diagram.
Calculate the [OH−] of each aqueous solution with the following [H3O+].milk, 3.5×10−7M Express the molarity to two significant figures.
Step 1
The equations used here:
[tex]\begin{gathered} pH\text{ = - log }\lbrack H3O+\rbrack\text{ \lparen1\rparen} \\ \lbrack H3O+\rbrack\text{ = concentration in M} \\ ------ \\ pOH\text{ = -log }\lbrack OH-\rbrack\text{ \lparen2\rparen} \\ ------ \\ pH\text{ + pOH = 14 \lparen3\rparen} \end{gathered}[/tex]------------
Step 2
Information provided:
[H3O+] = 3.5×10^−7 M
------------
Step 3
Procedure:
Firstly, from (1):
pH = -log [H3O+]
pH = -log (3.5×10^−7 M) = 6.5
----
From (3):
pH + pOH = 14
pOH = 14 - pH
pOH = 14 - 6.5
pOH = 7.5
----
From (2)
pOH = - log [OH-] => [OH-] = 10^-(pOH)
[OH-] = 10^-(pOH) = 10^-(7.5) = 3.2x10^-8 M
Answer: [OH-] = 3.2x10^-8 M
Need help with chemistry Atomic Masses: C-12.0 NA-23.0, O-16.0, P-31.0, Sn-119
INFORMATION:
We know that:
- 34.37 g of tin(IV) phosphate is added to 34.05 g of sodium carbonate
- 24.24 g of tin(IV) carbonate are made
And we must find the %yield
STEP BY STEP EXPLANATION:
Balanced equation:
Sn3(PO4)4 + 6Na2CO3 → 3Sn(CO3)2 + 4Na3PO4
1. We must find the amount of tin carbonate produced by tin phosphate
[tex]34.37gSn_3(PO_4)_4\times\frac{1molSn_3(PO_4)_4}{480.03gSn_3(PO_4)_4}\times\frac{3molSn(CO_3)_2}{1molSn_3(PO_4)_4}\times\frac{238.73gSn(CO_3)_2}{1molSn(CO_3)_2}=51.2790gSn(CO_3)_2[/tex]2. We must find the amount of tin carbonate produced by sodium carbonate
[tex]34.05gNa_2CO_3\times\frac{1molNa_2CO_3}{105.9888gNa_2CO_3}\times\frac{3molSn(CO_3)_2}{6molNa_2CO_3}\times\frac{238.73gSn(CO_3)_2}{1molSn(CO_3)_2}=38.3472gSn(CO_3)_2[/tex]3. We must find the theoretical amount of tin carbonate produced
Since sodium carbonate is the limiting reactant, then the theoretical amount of tin carbonate produced would be
[tex]38.3472gSn(CO_3)_2[/tex]4. Finally, the %yield would be
[tex]\text{ \%yield}=\frac{24.24gSn(CO_3)_2}{38.3472gSn(CO_3)_2}\times100=63.2119\text{ \%}[/tex]ANSWER:
1.
[tex]34.37gSn_3(PO_4)_4\frac{1molSn_{3}(PO_{4})_{4}}{480.03gSn_{3}(PO_{4})_{4}}\frac{3molSn(CO_{3})_{2}}{1molSn_{3}(PO_{4})_{4}}\frac{238.73gSn(CO_{3})_{2}}{1molSn(CO_{3})_{2}}=51.2790gSn(CO_3)_2[/tex]2.
[tex]34.05gNa_2CO_3\frac{1molNa_{2}CO_{3}}{105.988,8gNa_{2}CO_{3}}\frac{3molSn(CO_{3})_{2}}{6molNa_{2}CO_{3}}\frac{238.73gSn(CO_{3})_{2}}{1molSn(CO_{3})_{2}}=38.3472gSn(CO_3)_2[/tex]3.
[tex]38.3472gSn(CO_3)_2[/tex]4.
[tex]\operatorname{\%}\text{y}\imaginaryI\text{eld}=\frac{24.24gSn(CO_{3})_{2}}{38.347,2gSn(CO_{3})_{2}}\times100=63.2119\operatorname{\%}[/tex]Solution B What is the molarity of this solution? _____M
We have an initial concentration of a stock solution that has molarity equal to 1M. In a previous question, the stock solution was diluted 10 times, this solution was called solution A. The concentration of solution A found was equal to 0.1M.
Now, we are asked to find the concentration of solution B that starts from solution A.
The initial concentration C1 is the concentration of solution A, equal to 0.1M. The initial volume (V1) is 10mL, and the final volume (V2) is 100mL. We will apply the dilution equation that says:
[tex]C_1V_1=C_2V_2[/tex]We clear C2 and replace the known data:
[tex]C_2=\frac{C_1V_1}{V_2}[/tex][tex]\begin{gathered} C_2=\frac{0.1M\times10mL}{100mL} \\ C_2=0.01M \end{gathered}[/tex]Answer: The molarity of solution B is 0.01 M
5.238 x 10^24 molecules of aluminum bromide to grams
Answer
2319.698 g
Procedure
Use the Avogadro's number and then the molecular weight to convert into grams. The formula for aluminum bromide is AlBr₃.
[tex]5.238\times10^{24}\text{ molecules AlBr}_3\frac{1\text{ mole}}{6.022\times10^{23}}\frac{266.69\text{ g}}{1\text{ mole}}=2319.698\text{ grams}[/tex]Hydrochloric acid and oxygen gas form water and chlorine gas. How many moles of water are produced from 5.52 moles of oxygen gas?
Explanation:
According to the problem, hydrochloric acid will react with oxygen gas to produce water and chlorine gas.
hydrochloric acid + oxygen gas ----> water + chlorine gas
The balanced equation will be:
4 HCl + O₂ -----> 2 H₂O + 2 Cl₂
If we pay attention to the coefficients of the reaction we will see that 4 moles of HCl will react with 1 mol of O₂ to produce 2 moles of H₂O and 2 moles of Cl₂. So, 1 mol of O₂ will produce 2 moles of H₂O. The molar ratio between O₂ and H₂O is 1 to 2.
1 mol of O₂ : 2 moles of H₂O molar ratio
We can use this relationship to find the number of moles of H₂O that are produced from 5.52 moles of O₂.
moles of H₂O = 5.52 moles of O₂ * 2 moles of H₂O/(1 mol of O₂)
moles of H₂O = 11.0 moles
Answer: 11.0 moles of water are produced from 5.52 moles of oxygen gas.
Calculating the average atomic mass from Isotope data
The relative atomic mass of the given elements are:
Sulfur = 32.054 amuChlorine = 35.46 amuWhat is the relative atomic mass of an element?The relative atomic mass of an element can be defined as the number of times the average atomic mass of the element is heavier than one-twelfth the mass of an atom of carbon-12.
The relative atomic mass of an element is obtained by summing the product of the mass of each isotope of an element and its relative abundance.
The relative atomic mass of the elements are determined as follows:
Sulfur:
Relative atomic mass = (32.95 * 0.0075) + (31.972 * 0.950) + (33.967 * 0.042) + (36.01435 * 0.0002)
The relative atomic mass of sulfur = 32.054 amu
Chlorine:
Relative atomic mass = (34.97 * 0.755) + (36.97 * 0.245)
The relative atomic mass of chlorine = 35.46
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Which type of reaction has only one product?
Combination
Decomposition
Single Replacement
O Double Replacement
O Combustion
3
Clear selecti
The reaction type which gives one product is a combination reaction.
What is a combination reaction?
Combination reactions are those in which two or more chemical entities join together to form a single product.
Generally, all the other types mentioned in the question can give single products under different circumstances but a combination reaction always gives a single product as shown in the above reaction.
4Fe + 3O2 = 2Fe2O3
Hence, the answer is a combination reaction.
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39. Period is the force of attraction between objects resulting in objects pulling towards eachother.a. Trueb. False
Answer
a. True
Explanation
If there was nothing to avoid from objects pulling towards one another many results may happen.
A weather balloon with a volume of 171 L is launched at 20.0°C at sea level, where the atmospheric pressure is 1.00 atm. The balloon
rises to an altitude of 2.00 x 104 m, where atmospheric pressure is 61.0 mmHg and the temperature is 210.0 K. What is the volume of
the balloon at 2.00 × 104 m?
Volume of the balloon at 2.00 × 10⁴ m is 1.52x10³ L
Volume is the three dimensional qualities that is used to measure capacity of solid shape and atmospheric pressure is the air around you has weight and it weighs down everything it touches is called atmospheric pressure
Here given data is
Pi = 1.0 atmosphere = absolute atmospheric pressure
P f = 61.0 mm Hg = atmospheric pressure
= 61.0/760 atmosphere
= 0.0802 atmosphere
Vi = 171 L
T i = 20.0°C = 20+273 = 293 K
T f = 210 K
We have to find volume of the balloon at 2.00 ×10⁴ m =?
Then the formula is
Pi × Vi/T i = P f × V f/T f
1 atm×171 L/293 K = 0.0802× V f/210K
V f = 1.52x10³ L
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If the temperature of a gas remains constant the the pressure of gas will increase the
Answer:
If the temperature of a gas remains constant the the pressure of gas will increase the impacts on the walls of the container , thus increasing the volume
-Write the net ionic equation that shows the reaction of 1.0 M ammonia, NH3, when dissolved in water.
-At room temperature the Keq of the above solution is 1.1. If the initial concentration of NH3 is 1.0 M, quantitatively define the pH of above solution (Show calculations using an I.C.E. table and use the quadratic equation)
-What is the reaction that occurs when a solution of ammonia is added to a solution containing Fe3+ ions?
-Propose a chemical compound that can be used to dissolve the precipitate formed in part 1.c. Support your answer with a proper chemical equation
In essence, there is no chemical reaction between ammonia and water. Although it is frequently said to produce NH₄OH, the overall response is:
H₂O + NH₃ = NH₄⁺ + OH⁻
You might compare the acid strength of H₂O (pka 15.7) and NH4⁺ (pka 9.24) or the base strength of NH₃ and OH⁻ to see which way the reaction would proceed. The reaction would shift to the weaker acid (H₂O) or the weak base in either case (NH₃). Despite what the bottle claims, weak doesn't make strong. I mean, there might be a small amount of NH₄⁺ and OH⁻ in the air, but not much.
The iron (III) ion forms an insoluble hydroxide and precipitates out of solution when ammonia is added to the solution.
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Mass = 16.0 g Volume = 4.0 cm3.A student finds the mass of the sample to be 17.5 grams. What is the student's approximate percent deviation (percentage of error)?
The student's approximate percent deviation or percentage of error in the measurement of the mass of the sample is 9.38 %.
What is the percentage deviation?Percent deviation is calculated to determine the accuracy of data collected during an experiment by comparing it to the theoretical results. Percent deviation is commonly used to check for data errors in student experiments.
Percent deviation can be referred to how much measured data differs from a known or theoretical value. A negative percent deviation indicates that the measured data is lower than the theoretical value. A positive percent deviation shows that the measured value is higher.
Given the actual value of the mass = 16 g
The calculated or approx value by student = 17.5 g
The percentage deviation = [(Approx - actual)/ actual ] × 100
= [(17.5 - 16)/16] × 100
Percentage error = 9.38 %
Therefore, the student's approximate percent deviation is 9.38 %.
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you reach into the oven to take out the cookies but forgot to wear oven mittens. explain the transformation of thermal energy
When you reach into the oven to take out the cookies, the thermal energy from your hand transfers to the cookies. The cookies become hot while your hand becomes cooler.
What is thermal energy?
Thermal energy is the energy contained within a system that controls its temperature. The flow of thermal energy is defined as heat. Thermodynamics is a branch of physics that deals with how heat is transferred between different systems and how work is done in the process (see the first law of thermodynamics).
We are usually interested in the role of thermal energy in ensuring energy conservation in the context of mechanics problems. Almost every transfer of energy in real-world physical systems occurs with less than 100% efficiency and results in some thermal energy. Typically, this energy takes the form of low-level thermal energy.
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If 150g of orange Juice Contains 120mg of ascor bic acid (Vitamin C). What is the concentration. of Vitamine c in ppm & ppb ?
1. The concentration of the vitamin C in ppm is 800 ppm
2. The concentration of the vitamin C in ppb is 800000 ppb
1. How to determin the concentration in ppm
The concentration of the vitamin C in ppm can be obtained as follow:
Mass of vitamin C = 120 mg = 120 / 1000 = 0.12 gMass of solution (orange juice) = 150 gConcentration (in ppm) =?Concentration (in ppm) = (mass of solute / mass of solution) × 10⁶
Concentration (in ppm) = (0.12 / 150) × 10⁶
Concentration (in ppm) = 800 ppm
2. How to determin the concentration in ppb
The concentration of the vitamin C in ppb can be obtained as follow:
Mass of vitamin C = 120 mg = 120 / 1000 = 0.12 gMass of solution (orange juice) = 150 gConcentration (in ppb) =?Concentration (in ppb) = (mass of solute / mass of solution) × 10⁹
Concentration (in ppb) = (0.12 / 150) × 10⁹
Concentration (in ppb) = 800000 ppb
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2,2-dimethylbutane condensed structural formula
ANSWER
[tex]\text{ The condensed structural formula is CH}_3C(CH_3)_2CH_2CH_3[/tex]EXPLANATION
Determine the hybrid orbital of this molecule.
A. sp³d²
B. sp³d
C.sp
D. sp²
The hybrid orbital of this molecule is B. sp³d
What do sp2 and sp3 hybridizations entail?Trigonal symmetry was used to generate a combination of s and p orbitals, which are kept at 1200. Ethylene (C2H4) sp3 hybridization is an example of sp2 hybridization. To create a novel hybrid orbital known as the sp3 sp3 orbital, one's' orbital and three 'p' orbitals of equal energy are mixed in this type: One of four new comparable orbitals that result from geometrically combining one s orbital and three p orbitals to create a normal tetrahedron's four corners.
Again, we refer to them as sp3 particles because they are made up of a single s orbital and three p orbitals. These degenerate hybrid orbitals are created to offset the s-p transition's energy upward.
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I need asap answers for this question. I’m stuck.
Pls I need the answer quick
Answer:
on image
Explanation:
top numbers are mass numbers; bottom numbers are proton numbers
A student placed 20.0 g of glucose ( C6H12O6 ) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 45.0 mL sample of this glucose solution was diluted to 0.500 L . How many grams of glucose are in 100. mL of the final solution?Express your answer to three significant figures and include the appropriate units.
Answer:
1.80 g (grams) of glucose.
Explanation:
First, we dissolve 20.0 g of glucose in a volume of water of 100 mL (0.1 L), so let's calculate the concentration of glucose in g/L, like this:
[tex]Concentration=\frac{20.0\text{ g}}{0.1\text{ L}}=200\text{ g/L.}[/tex]Now, we take 45 mL (0.045 L) of this solution that contains a concentration of glucose of 200 g/L to create a new solution with 0.500 L.
From this new solution, we have to find the mass of glucose if we took 100 mL (0.1 L) of this solution, so we have to use the following equation:
[tex]C_1V_1=C_2V_2.[/tex]Where C is concentration, V is volume, and subindex 1 and 2 indicate the initial solution, which in this case, is C1 = 200 g/L, V1 = 0.045 L, and the final solution with unknown concentration (C2) and a volume of V2 = 0.500 L.
Let's solve for C2 and replace the given data to obtain the new concentration (final concentration) of the new solution of 0.500 L, like this:
[tex]\begin{gathered} C_2=\frac{C_1V_1}{V_2}, \\ C_2=\frac{200\text{ }\frac{g}{L}\cdot0.045\text{ L}}{0.500\text{ L}}, \\ C_2=18.0\text{ g/L.} \end{gathered}[/tex]The final concentration of glucose in 0.500 L would be 18.0 g/L.
The next and final step is to calculate the total mass using the volume that we took from the 0.500 L solution, which is 100.0 mL (0.1 L). To do this, we have to do a dimensional analysis to obtain the answer in units of grams, so the calculation will look like this:
[tex]\begin{gathered} mass\text{ of glucose=}18.0\frac{g}{L}\cdot0.1L, \\ mass\text{ of glucose=1.80 g.} \end{gathered}[/tex]The answer would be that we have 1.80 g (grams) of glucose in 100 mL from the 0.500 L solution.
In a monomolecular reaction A->B , at t =250C, the initial concentration decrease at 25% in t =52 min. Calculate:
a) the constant rate;
b) the time after the initial concentration decrease with 75%;
c) the initial reaction rate, if the initial concentration of the reactant is 2.5 mol/L·s
1) The rate constant is 9.22 * 10^-5 s-1
2) The time taken is 15033 s
3) The initial concertation is 9.22 * 10^-5 M
What is the rate of reaction?We can define the rate of reaction as the rate at which reactants are converted into products or the rate of which reactants disappear and the products appear in a given reaction.
We are told that in this reaction as we can see, the initial concentration decrease at 25% in t =52 min.
Initial concentration [A]o = [A]o
Final concentration = [A]o - 0.25 [A]o = 0.75 [A]o
Time taken = 52 min or 3120 s
We have that;
ln[A] = -kt + ln[A]0
k = -(ln[A] - ln[A]0)/t
k = - (ln0.75 [A]o/A]0)/3120
k = 9.22 * 10^-5 s-1
b)
Given that
[A] = [A]o - 0.75 [A]o = 0.25 [A]o
ln[A] = -kt + ln[A]0
t = -(ln[A] - ln[A]0)/k
t = - (ln0.25 [A]o/A]0)/9.22 * 10^-5
t = 15033 s
c) When the rate is 2.5 mol/L·s
k = - (ln0.25 (2.5)/ln(2.5))/15033
k = 9.22 * 10^-5 M
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What is the
formula weight of zinc phosphate? Provide an answer to two decimal
places.
The formula weight of zinc phosphate is 385g/mol.
The formula weight or molar mass of zinc phosphate is calculated by adding weight of every single element present in zinc phosphate.
Formula of zinc phosphate is Zn₃(PO₄)₂.
Weight of 3 zinc atoms = 3×65= 195g/mol
Weight of 2 phosphorus atoms =2×31=62g/mol
Weight of 8 oxygen atoms = 8×16= 128g/mol
So, the total molecular weight of the compound is 195+62+128= 385g/mol.
Thus, the molecular weight of zinc phosphate is 385g/mol.
Zinc phosphate is an inorganic chemical substance that is used as a priming pigment or as part of the electroplating process to provide a corrosion-resistant coating on metal surfaces. It is common practice to employ a seeding chemical as a pre-treatment because zinc phosphate adheres to crystalline structures better than bare metal. Dental practices use zinc phosphate, which is created from zinc phosphate cement.
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