Copper metal has a specific heat of 0.385 J/g.C. calculate the amount of heat required to raise the temperature of 22.8g of copper metal from 20.0C to 875°C

Answer:

See explanation and image attached

Explanation:

According to Markovnikov regiochemistry, the negative part of the addendum is joined to the more substituted carbon atom. The addition of H-OH to alkynes occurs in the presence of mercury(II) sulfate as a Lewis acid catalyst.

So, the -OH group is added to the highly substituted carbon and the H adds to the less highly substituted carbon.

The enol produced is shown in the mechanism attached to this answer. Rearrangement of this enol form due to keto-enol tautomerism yields the ketone as shown.

Image credit: chemistry steps

Answer:

It is energy

Explanation:

Your welcome! :)

Energy flows in one direction in an ecosystem.

An ecosystem is a system which shows the interaction between the living organisms and the non-living part of their environment.

An ecosystem usually shows a flow of nutrient and energy

Nutrients are cycled in an ecosystem but energy flows in only one direction.

Therefore, in an ecosystem, energy flows in one direction.

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Answer: D.) The volume of stock solution used was more than 5 liters

Explanation:

Answer:

b

Explanation:

i got it

Answer:

Work is a force causing the movement or displacement of an object

law of conservation mass:

1. Atoms cannot be created or destroyed in a chemical reaction.

2. Molecules cannot be created or destroyed in a chemical reaction.

3. Compounds cannot be created or destroyed in a chemical reaction.

4. Heat cannot be created or destroyed in a chemical reaction.

Answer:

A parasitic relationship is one in which one organism, the parasite, lives off of another organism, the host, harming it and possibly causing death. The parasite lives on or in the body of the host.

Answer:

–0.13 Pa.m²

Explanation:

From the question given above, the following data were obtained:

Measurement (Pa.mm²) = –1.3×10⁵ Pa.mm²

Measurement (Pa.m²) =?

We can convert from Pa.mm² to Pa.m² by doing the following:

1 Pa.mm² = 1×10¯⁶ Pa.m²

Therefore,

–1.3×10⁵ Pa.mm² = –1.3×10⁵ Pa.mm² × 1×10¯⁶ Pa.m² / 1 Pa.mm²

–1.3×10⁵ Pa.mm² = –0.13 Pa.m²

Thus, –1.3×10⁵ Pa.mm² is equivalent to –0.13 Pa.m².

The complete equation will be:

[tex](-1.3\times 10^5 Pa.mm^2)\times 10^{-6}=(-0.13) Pa.m^2[/tex]

Explanation:

Given:

The equation to convert a measurement:

[tex](-1.3\times 10^5 Pa.mm^2)\times ? = ? Pa.m^2[/tex]

To find:

The missing part of the equation.

Solution:

[tex](-1.3\times 10^5 Pa.mm^2)\times ? = ? Pa.m^2[/tex]

On LHS the unit is in [tex]Pa. mm^2[/tex] and RHS the unit is in [tex]Pa.m^2[/tex] which means that we have to convert [tex]mm^2[/tex] to [tex]m^2[/tex]

In 1 millimeter there are 0.001 meters.

[tex]1 mm = 0.001 m\\1 mm^2=0.000001 m^2=10^{-6} m^2[/tex]

So, the complete equation will be:

[tex](-1.3\times 10^5 Pa.mm^2)\times 10^{-6}=(-0.13) Pa.m^2[/tex]

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Answer:

plastic

........................

Explanation:

looks like c is the answer

Answer:

7.4

Explanation:

Plasma proteins are part of the buffer systems of blood plasma. Plasma contains both positively and negatively charged amino and carboxyl groups. These compounds' charged portions can attract and link hydrogen(H) and hydroxyl ions(OH-), therefore act as buffers.

Plasma serves as a weak and ineffective buffer. The pH of a buffer should always be around 7.4 which is nearly neutral. As such we may deduce from the first experimental observation that there is no change in pH.

Answer:

Hi, there the answer is D.

Explanation:

Answer:

The initial temperature of the water is -75.08 K.

Explanation:

Given that,

Mass of water, m = 27 g

Heat absorbed, Q = 1,5000 J

Final temperature of water, T₂ = 57.7 K

The specific heat of water is 4.184 J/​g-K

We know that,

[tex]Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_1=T_2-\dfrac{Q}{mc}[/tex]

Put all the values,

[tex]T_1=57.7-\dfrac{15000}{27\times 4.184 }\\\\=-75.08\ K[/tex]

So, the initial temperature of the water is -75.08 K.

Answer:

oxygen is add to ATP providing energy to the cell

Answer:

The most abundant isotope is ⁴⁰Ca and the least abundant is ⁴⁶Ca

Explanation:

The mass, in percentage, of eah isotope of Calcium is their fractional composition multiplied by 100:

40Ca-0.96941*100 =  96.941% of ⁴⁰Ca

42Ca-0.00647*100 = 0.647% of ⁴²Ca

43Ca-0.0013*100 = 0.13% of ⁴³Ca

44Ca-0.02086*100 = 2.086% ⁴⁴Ca

46Ca-0.00004*100 = 0.004% ⁴⁶Ca

48Ca-0.00187*100 = 0.187% of ⁴⁸Ca

That means the most abundant isotope is ⁴⁰Ca and the least abundant is ⁴⁶Ca

Answer:

Hey mate......

Explanation:

This is ur answer......

molecules in liquids are weaker than solids but stronger than gases......

Hope it helps!

Brainliest pls!

Follow me! :)

Answer:

red it has to be red cuz it is the largest one out of it

Answer:

Apparently its Green

Explanation:

just took the test on A P E X

Answer:

43.2 mol C

115 mol H

158 mol of atoms

Explanation:

Step 1: Given data

Moles of C₃H₈: 14.4 mol

Step 2: Calculate the number of moles of C

The molar ratio of C₃H₈ to C is 1:3. The moles of C are 3/1 × 14.4 mol = 43.2 mol.

Step 3: Calculate the number of moles of H

The molar ratio of C₃H₈ to H is 1:(. The moles of H are 8/1 × 14.4 mol = 115 mol.

Step 4: Calculate the total number of moles of atoms

n = nC + nH = 43.2 mol + 115 mol = 158 mol

Explanation:

hope the picture make sense :)

Answer: The frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is [tex]5.49 \times 10^{14} s^{-1}[/tex].

Explanation:

Given: Wavelength = 546 nm [tex](1 nm = 10^{-9} m)[/tex] = [tex]546 \times 10^{-9} m[/tex]

The relation between frequency and wavelength is as follows.

[tex]\nu = \frac{c}{\lambda}[/tex]

where,

[tex]\nu[/tex] = frequency

c = speed of light = [tex]3.0 \times 10^{8} m/s[/tex]

[tex]\lambda[/tex] = wavelength

Substitute the values into above formula as follows.

[tex]\nu = \frac{c}{\lambda}\\= \frac{3.0 \times 10^{8} m/s}{546 \times 10^{-9} m}\\= 5.49 \times 10^{14} s^{-1}[/tex]

Thus, we can conclude that the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is [tex]5.49 \times 10^{14} s^{-1}[/tex].

Answer:

Q:Use the Hertzsprung-Russell diagram and temperature and luminosity data to identify each star

Explanation:

Take it as u please

Answer:

white dwarf- star C

main sequence- star A

giant- Star B

Explanation:

Got it right

Answer:

SI

Explanation:

I would say silicon because it is also another metalloid. Boron is a metalloid.

Answer: 232

Explanation:

Answer:

gas

Explanation:

the force of attraction between the particles of gases is very weak hence the particles of a gas are in constant random motion

Answer:

21g

Explanation:

no.ofmol fe2o3=39.5/(56×2+16×3)=0.25mol

from equation 1mole fe2o3 react with 3mole co

so,0.25mol fe2o3 react with 0.75mol co

mass of co=0.75×(12+16)=21g

Answer:

Approximately [tex]20.8\; \rm g[/tex].

Explanation:

[tex]\rm Fe_2O_3 \, (s) + 3\; CO\, (g) \to 2\; Fe\, (s) + 3\; CO_2\, (g)[/tex].

Relative atomic mass:

Formula mass:

[tex]\begin{aligned}M({\rm Fe_2O_3}) &= 2 \times 55.845 + 3 \times 15.999\\ &= 159.687\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

[tex]\begin{aligned}M({\rm CO}) &= 12.011 + 15.999\\ &= 28.010\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Number of moles of [tex]\rm Fe_2O_3[/tex] formula units in [tex]39.5\; \rm g[/tex] of this compound:

[tex]\begin{aligned}&n({\rm Fe_2O_3}) \\ &= \frac{m({\rm Fe_2O_3})}{M({\rm Fe_2O_3})} \\ &= \frac{39.5\; \rm g}{159.687\; \rm g \cdot mol^{-1}}\approx 0.247\; \rm mol\end{aligned}[/tex].

Refer to the balanced equation for this reaction.

Hence, for every formula unit of [tex]\rm Fe_2O_3[/tex] that this reaction consumes, [tex]3\; \rm mol[/tex] of [tex]\rm CO[/tex] molecules would also need to be consumed. Therefore, if neither reactant is in excess:

[tex]\displaystyle \frac{n({\rm CO})}{n({\rm Fe_2O_3})} = \frac{3}{1} = 3[/tex].

Calculate the number of moles of [tex]\rm CO[/tex] required to react with that [tex]39.5\; \rm g[/tex] of [tex]\rm Fe_2O_3[/tex]:

[tex]\begin{aligned}&n({\rm CO}) \\ &= n({\rm Fe_2O_3}) \cdot \frac{n({\rm CO})}{n({\rm Fe_2O_3})} \\[0.5em] &\approx 0.247\; \rm mol \times 3 \approx 0.742\; \rm mol\end{aligned}[/tex].

Make use of the formula mass of [tex]\!\rm CO[/tex] to find the mass of that [tex]0.742\; \rm mol[/tex] of [tex]\rm CO[/tex] molecules:

[tex]\begin{aligned} m({\rm CO}) &= n({\rm CO}) \cdot M({\rm CO}) \\ &\approx 0.742\; \rm mol \times 28.010\; \rm g \cdot mol^{-1} \\ &\approx 20.8\; \rm g\end{aligned}[/tex].

Answer:

Rate = 0.83M/s

Explanation:

Rate of a chemical reaction is the 'absolute value' of change in concentration per unit time. That is ...

Rate = |Change in concentration / unit time|

= |Δ[Conc]/Δtime|

= |(1.17M -2.00M) / 25.3s|

= |- 0.83M/s|

= 0.83M/s*

------------

*Note: Some scholars define rate of reaction as a 'scaler' quantity having only magnitude as rate of reaction in a physical sense (up, down, right, left) is not definitive. In physical mechanics, rate is assigned a direction and magnitude of action and becomes a 'vector' quantity.

The speed at which the reaction occurs is called the rate of reaction. The rate of reaction for the decreased concentration is 0.83 M/s.

The reaction rate is the increase or decrease in the concentration of the products per unit of time. The formula for a reaction rate is given as,

[tex]\rm Rate = \rm \dfrac {\text{Change in concentration}} {Unit \; time}[/tex]

Given,

Initial concentration = 1.17 m

Final concentration = 2.00 M

Time = 25.3 sec

Substituting values in the above equation:

[tex]\begin{aligned} &= \dfrac{1.17 - 2.0} {25.3}\\\\&= -0.83\\\\&= 0.83 \;\rm M/s\end{aligned}[/tex]

Therefore, 0.83 M/s is the reaction rate.

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Answer:

Option D

Explanation:

A double displacement reaction is a type of reaction in which two reactants exchange ions to form two new compounds.

CaBr2 + 2NaOH → Ca(OH)2 + 2NaBr

Calcium Bromide + Sodium Hydroxide = Portlandite + Sodium Bromide

Answer:

2.6

Explanation:

Step 1: Given and required data

Step 2: Calculate the acid dissociation constant (Ka) of butanoic acid

We will use the following expression.

pKa = -log Ka

Ka = antilog - pKa

Ka = antilog -4.82 = 1.51 × 10⁻⁵

Step 3: Calculate [H⁺] of the solution

For a weak acid, we can use the following expression.

[H⁺] = √(Ca × Ka)

[H⁺] = √(0.35 × 1.51 × 10⁻⁵) = 2.3 × 10⁻³ M

Step 4: Calculate the pH of the solution

pH = -log [H⁺] = -log 2.3 × 10⁻³ = 2.6

Answer:

Kr- Dispersion Forces

H2O- Hydrogen Bonding

CHCI3- Dipole-Dipole Forces

HF- Hydrogen Bonding

C2H6- Dispersion Forces

HBr- Hydrogen Bonding Forces

Explanation:

Dispersion forces occurs in all substances. They are the dominant intermolecular interaction in all non polar substances such as C2H6 and Kr.

Hydrogen bonding occurs when hydrogen is bonded to a highly electronegative atom such as Cl, Br, O etc. It is the dominant intermolecular interaction in HF, HBr and H2O.

Dipole-Dipole interactions occur when a permanent dipole exists in a molecule such as in CHCI3

Answer:

C₁₅N₃H₅

Explanation:

Let's assume we have 240 g of the dye (1 mol), in that case we'd have:

Now we convert the masses of each element into moles, using their respective molar masses:

Thus the molecular formula is C₁₅N₃H₅.