Find the range of the data.
The ages of kids playing at a park.
4, 1, 3, 9, 6, 3, 2, 4
Range: [?]

Step-by-step explanation:

this is the first time ⏲️has a very

Answer:

1.80 in^3

1.0 fluid ounces^3

Step-by-step explanation:

volume of a cone = 1/3 πr²h

π = 3.14

r = 2.2 / 2 = 1.1

h = the value of h can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

1.8² = 1.1² + b²

3.24 = 1.21 + b²

3.24 - 1.21 = b²

2.03

b = √2.03 = 1.42

Volume = 1/3 x 3.14 x 1.21 x 1.42 = 1.80 in^3

1.80 x 0.554 = 1.0 fluid ounces^3

Answer:

575 feet

Step-by-step explanation:

the final depth = 725-150= 575

Answer:

12.8 units

Step-by-step explanation:

PQ=(X2-X1)²+(Y2-Y1)²

=(7-(-1))²+(3-(-7)

=164

then find square root of 164 that gives you 12.8units

Answer:

The answer is "287.19"

Step-by-step explanation:

Please find the complete question in the attached file.

[tex]\alpha=1-0.90=0.10\\\\\frac{\alpha}{2}=0.05\\\\Z=1.64\\\\Marginal \ error=Z \times \frac{\sigma_x}{\sqrt{n}}\\\\n=(\frac{Z \times \sigma_x}{error})^2\\\\n=(\frac{1.64 \times 31}{3})^2\\\\n=287.1895\approx 287.19[/tex]

Answer:

the maximum amount that something can contain. hope this helps :)

Step-by-step explanation:

Answer:

Fig. 1 :- 7.6

Fig. 2 :- 15

Step-by-step explanation:

We can use Pythagoras theorem to solve for x

[tex]c^{2} =a^{2} +b^{2}[/tex]

Figure 1:

[tex]c^{2} =7^{2} +3^{2}[/tex]

[tex]c^{2} =49+9[/tex]

[tex]c^{2} =58[/tex]

[tex]c=\sqrt{58}[/tex]

[tex]c=7.615773106[/tex]

You can now round your answer:

[tex]c=7.6[/tex]

Figure 2:

[tex]c^{2} =12^{2} +9^{2}[/tex]

[tex]c^{2} =144+81[/tex]

[tex]c^{2} =225[/tex]

[tex]c=\sqrt{225}[/tex]

[tex]c=15[/tex]

I hope this helps :)

Step-by-step explanation:

fig(1)

h=x

p=3

b=7

now,

h^2=p^2+b^2. (by Pythagoras theory)

or, x^2=3^2+7^2

or, x^2=9+49

or, x^2=58

or, x=√58

fig(2)

h=x

p=12

b=9

now,

h^2=p^2+b^2

or, x^2=12^2+9^2

or, x^2=144+81

or, x^2=225

or, x=15

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

Answer:

ok so if he starts by doing 10 and does 2 evrey day that means he will be doing 70 push ups on the last day of the month since

2*30+10=70

Answer:

The answer is either (3) or (4) because drawing a line of best fit and finding its gradient is going to give you a negative answer

Answer:

-0.93

Step-by-step explanation:

As mentioned by Nicolas above, the line of best fit should give a negative coefficient because as x increases, y decreases.

Furthermore, since the lines do not make a perfect line, it cannot be the perfect fit, or a correlation of -1.00.

So we choose a negative answer but not -1.00 as explained previously.  That lease the only choice of -0.93, by elimination without doing any calculations.

2. 144/1:2 is 144/ ½ = 144 x 2/1 = 288

Answer:

10n + 28

Step-by-step explanation:

a + d (n-1)

a = 38

d = 10

38 + 10 (n-1)

38 + 10n -10

10n +38 - 10

10n + 28

Hope this helps!

Step-by-step explanation:

B/-7 = 4

Cross multiple

-7×4 = B

-28 = B

Answer:

-28

Step-by-step explanation:

First, multiply 4*-7= -28.

You're done. B=-28

Hope this helps!

Answer:

Step-by-step explanation:

Step-by-step explanation:

the equation is

c =>

4.50 + 1.70 w = 16

Answer:

328 paces

Step-by-step explanation:

180m=180,00cm

18000÷55=3600/11=327 3/11

Answer:

Because 1/9 is a fraction with integers meaning it is a fraction with whole numbers.

Step-by-step explanation:

Any number that can be written as a fraction with integers is called a rational number. For example, 17 and −34 are rational numbers. (Note that there is more than one way to write the same rational number as a ratio of integers. For example, 17 and 214 represent the same rational number.)

Hope this helps

Answer: 267.7

I just did the math and I got this answer

Answer:

35 degrees

Step-by-step explanation:

Answer:

C. Chad is incorrect because intersecting lines are sometimes perpendicular.

Step-by-step explanation:

SOMETIMES perpendicular (90 degree angle, aka right angle) not always.

Chad is incorrect because intersecting lines are sometimes perpendicular.

If the angle between two lines is 90 degrees, lines are called perpendicular lines.

If two lines intersect each other, it is not necessary that they will intersect at 90°.

Sometimes they can intersect at 90° and sometimes not.

So, Chad is incorrect because intersecting lines are sometimes perpendicular.

Hence, Chad is incorrect because intersecting lines are sometimes perpendicular.

To get more about intersecting lines visit:

https://brainly.com/question/18013592

Given:

A car traveled 150 km in 3 hour.

To find:

The unit rate.

Solution:

We have,

Distance = 150 km

Time = 3 hours.

In this case speed is the unit rate.

[tex]Speed=\dfrac{Distance}{Time}[/tex]

Substituting the given values, we get

[tex]Speed=\dfrac{150\text{ km}}{3\text{ hr}}[/tex]

[tex]Speed=50\text{ km/h}[/tex]

Therefore, the unit rate is 50 km/h.

It's C, just look at where the points are.

Answer:

It's C,

hope it helps

Answer:

cant see the picture

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

w

Answer:

1/(4^(n-1))

Step-by-step explanation:

if you start at zero then this should be the solution

Answer:

x = 2

y = 7

Step-by-step explanation:

Graphing calculators are everywhere but ok.

I attached a graph.

Answer:

Step-by-step explanation:

Equation of a line passing through a point (h, k) and slope 'm' is given by,

y - h = m(x - k)

Equation of a line passing through (-6, 1) and slope = 5,

y - 1 = 5(x + 6)

y = 5x + 31

Input-output values of the given equation,

x        -6              -4              -2              0                            

y          1               11              21             31              

Now plot these points on a graph.

Answer:

Neither perpendicular or parallel

Step-by-step explanation:

The y-intercept would not be the same, and the slope would be different. That means that line wont be parallel, or perpendicular.

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

Multiply the numerator and the denominator of the fraction by 2.

Step-by-step explanation:

Here are the options :

Divide the numerator and denominator of the fraction by 2.

Subtract 40 from the numerator and denominator of the fraction.

Multiply the numerator and the denominator of the fraction by 2.

Add 50 to the numerator and denominator of the fraction.

(45 x 2) / (50 x 2) = 90/100

Multiply 90/100 by 100 = 90%

the same answer would be gotten if 45/50 is multiplied by 100

45/50 x 100 = 90%