Answers
Answer:
P1V1T2
T1= _______
P2V2
Step-by-step equation:
Related Questions
Please see attachment below Is the following an example of theoretical probability or empirical probability? A fisherman notes that eight out of ten times that he uses a certain lure to catch a fish within an hour. He concludes that the probability that the lure wil catch a fish on his next fishing trip is about 80%. Is it empirical or theoretical?
Answers
From the information provided, we know that the fisherman has already conducted some experiments and from these events he was able to conclude the probability of catching a fish on his next fishing trip. This is an example of EMPIRICAL PROBABILITY.
This is probability calculated after the event has occured.
ANSWER:
Empirical
On a flight from Chicago, Illinois, to Denver, Colorado,
the typical cruising altitude of a passenger jet is approximately
38,000 feet. As the flight departs from O'Hare International Airport,
the jet begins to ascend. At 4.3 miles away from the airport, the jet
is at an altitude of 4200 feet. The jet reaches an altitude of 36,700
feet at 167.5 miles away from the airport.
Determine the slope of ascent of the flight given that 5280 feet = 1 mile.
Round your answer to the nearest thousandth.
Answers
The slope of ascent of the flight is 0.04
How to calculate the slope of ascent?From the question, we have the following parameters that can be used in our computation:
Typical cruising altitude = 38,000 feetInitial point of ascend = 4.3 miles at 4,200 feetAnother point of ascend = 167.5 miles at 36,700 feetThe above parameters can be represented as
(x, y) = (4.3, 4200) and (167.5, 36,700)
The slope is then calculated as
Slope = (y₂ - y₁)/(x₂ - x₁)
Where x and y are defined above
So, we have
Slope = (36700 - 4200)/(167.5 - 4.3)
Evaluate
Slope = 199.14 feet per mile
Recall that 5280 feet = 1 mile.
So, we have
Slope = 199.14 feet/5280 feet
Evaluate
Slope = 0.04
Hence, the required slope is 0.04
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Someone please help I don’t understand this at all would really appreciate some help !!!!
Answers
The results of the operations of functions evaluated at are listed below:
Addition - (f + g) (- 2) = 9Subtraction - (f - g) (- 2) = 3Multiplication - (f · g) (- 2) = 18Division - (f / g) (- 2) = 2 / 3How to evaluate operations of functions
In this problem we four cases of operations between two functions, a quadratic equation f(x) and a linear equation g(x). There are four operations:
Addition - f (x) + g (x) = (f + g) (x)
Subtraction - f (x) - g(x) = (f - g) (x)
Multiplication - f (x) · g (x) = f · g (x)
Division - f (x) / g (x) = (f / g) (x)
If we know that f(x) = x² - x and g(x) = 3 · x + 9, then the compositions of functions evaluated at x = - 2 are, respectively:
(f + g) (- 2) = (- 2)² - (- 2) + 3 · (- 2) + 9
(f + g) (- 2) = 4 + 2 - 6 + 9
(f + g) (- 2) = 9
(f - g) (- 2) = (- 2)² - (- 2) - 3 · (- 2) - 9
(f - g) (- 2) = 4 + 2 + 6 - 9
(f - g) (- 2) = 3
(f · g) (- 2) = [(- 2)² - (- 2)] · [3 · (- 2) + 9]
(f · g) (- 2) = 6 · 3
(f · g) (- 2) = 18
(f / g) (- 2) = [(- 2)² - 2] / [3 · (- 2) + 9]
(f / g) (- 2) = 2 / 3
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What is the ones digit in the number 2 to the 2056 Power?Hint: start with smaller exponents to find the pattern
Answers
Follow the steps below to find the ones digit in the number:
[tex]\begin{gathered} 2^{2056} \\ \text{The base = 2} \\ \text{The power = 2056} \end{gathered}[/tex]step 1: Identify the unit digit in the base - the unit digit is 2.
step 2:
If the power or exponent is exactly divisible by 4
case 1: The unit digit of the number is 6 if the unit digit in the base is any of 2, 4, 6, 8.
case 2: The unit digit of the number is 1 if the unit digit in the base is 3, 7, 9.
In this case, the power 2056 is exactly divisible by 4 and the unit digit in the base is 2.
Therefore, the ones digit is 6
What is the slope of a line perpendicular to the line whose equation is x+3y=-15. Fully simplify your answer.
Answers
ANSWER
The slope of the line perpendicular line of the equation is 3
STEP-BY-STEP EXPLANATION:
What to find? The slope of a line perpendicular to the line whose equation is x + 3y = -15
Given the equation
x + 3y = -15
The slope-intercept form of an equation is given as
[tex]y\text{ = mx + b}[/tex]Where m = slope of the line
y = the intercept of the y-axis
The next step is to re-arrange the above equation in the slope-intercept format
[tex]\begin{gathered} \text{Given the equation of a straight line as} \\ x\text{ + 3y = -15} \\ \text{Isolate 3y by substracting x from both sides} \\ x\text{ - x + 3y = -15 - x} \\ 3y\text{ = -x - 15} \\ \text{Divide through by 3} \\ \frac{3y}{3}\text{ = }\frac{-1}{3}x\text{ -}\frac{15}{3} \\ y\text{ = }\frac{-1}{3}x\text{ - 5} \\ \text{Hence, the slope}-\text{intercept form of the above equation is given as} \\ y\text{ = }\frac{-1}{3}x\text{ - 5} \end{gathered}[/tex]NB: That the two lines are perpendicular to each other
From y = mx + b
m = -1/3
The slope of the equation
[tex]\begin{gathered} \text{ For two perpendicular lines, we can calculate the slope as follows} \\ m_1\cdot m_2\text{ =- 1} \\ \text{where m}_1\text{ = }\frac{-1}{3} \\ \frac{-1}{3}\cdot m_2\text{ = -1} \\ \frac{-1\cdot m_2}{3}=\text{ -1} \\ \text{Cross multiply} \\ -m_2\text{ = -1 }\cdot\text{ 3} \\ -m_2\text{ = -3} \\ \text{Divide through by -1} \\ \frac{-m_2}{-1}\text{ = }\frac{-3}{-1} \\ m_2\text{ = }3 \\ \text{Hence, the slope of the perpendicular line to the equation is 3} \end{gathered}[/tex]a man paddles his canoe at a rate of 12 kilometers per hour. write this rate as meters per minute
Answers
Answer
12 kilometers per hour = 200 meters per minute
Explanation
In order to convert 12 kilometers per hour into meters per minute, we need to note that
1 kilometer = 1000 meters
1 hour = 60 minutes
[tex]\begin{gathered} 12\frac{kilometers}{hour} \\ We\text{ ne}ed\text{ to note that } \\ \frac{1000\text{ meters}}{1\text{ kilometers}}=1 \\ \frac{1\text{ hour}}{60\text{ minutes}}=1 \\ 12\frac{\text{kilometers}}{\text{hour}}\times1\times1 \\ =12\frac{\text{kilometers}}{\text{hour}}\times\frac{1000\text{ meters}}{1\text{ kilometer}}\times\frac{1\text{ hour}}{60\text{ minutes}} \\ =\frac{12\times1000\times1}{1\times60}\frac{meters}{\min ute} \\ =200\frac{\text{meters}}{\text{minute}} \end{gathered}[/tex]Hope this Helps!!!
Graph 10 and its opposite. HHHHHHHHHHHHHH -201816141210-8-6-4-2 0 2 4 6 8 101214161820 0-0 0-0 - 0 0 < PREV 1 7
Answers
The opposite of 10 is -10.
Graph 10 and -10 on the number line.
The numbers are represented by points (dots) on the number line.
xx yyy
121212 363636
181818 545454
252525 757575
Find the constant of proportionality (r)(r)left parenthesis, r, right parenthesis in the equation y=rxy=rxy, equals, r, x.
Answers
The constant of proportionality for the given set is 3.
Given,
The set;
x y
12 36
18 54
25 75
We have to find the constant of proportionality;
Here,
y = x × r
Where r is the constant of proportionality.
Lets see;
Case 1; 12 and 36
36 = 12 × r
r = 36/12
r = 3
Case 2; 18 and 54
54 = 18 × r
r = 54/18
r = 3
Case 3; 25 and 75
75 = 25 × r
r = 75/25
r = 3
Therefore,
The constant of proportionality for the given set is 3.
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Joe drinks 0.55 L of milk every day. How much milk does he drink in 5 days? Write your answer in milliliters.
Answers
Given that
Joe drinks 0.55 l of milk every day and we have to find the milk he can drink in 5 days.
Explanation -
Let the given condition be represented as
1 day = 0.55 L milk
So multiplying by 5 on both sides we have
1 x 5 days = 0.55 x 5 L milk
5 days = 2.75 L milk
And conversion is
1L = 1000 ml
So multiplying by 2.75 in the above equation we have
2.75L = 2.75 x 1000 ml = 2750 ml
So Joe will drink 2750 ml of milk in 5 days.
Hence the final answer is 2750 ml.which of the following is a key property of the quadratic parent function?it is in quandrants I and IIIt is not a functionit is not a parabolaits vertex is in quandrant III
Answers
quadrants
In this case, we'll have to carry out several steps to find the solution.
Step 01:
We must analyze the statements to find the solution.
Step 02:
it is in quadrants I and II ==> True
It is not a function ==> False
it is not a parabola ==> False
its vertex is in quandrant III ===> False
The answer is:
It is in quadrants I and II
What is the interquartile range of the sample data represented on the stem and leaf diagram below?
0 | 2 3 5 7 9
1 | 3
2 | 1 2 3
Answers
The interquartile range of the sample data represented on the stem and leaf diagram is 21.
What is the interquartile range?
IQR(interquartile range) is the difference between the third and first quartile.
The range of a set of data is the difference between the largest and smallest values. The difference is specific; the range of a set of data is the result of subtracting the sample maximum and minimum.
Range = Maximum value - Minimum value
Range = 23 - 02 = 21
We know that the range is the difference between the smallest and the largest value and in the interval we write it as:
From a to b where a is the smallest value and b is the maximum value.
Hence, The interquartile range of the sample data represented on the stem and leaf diagram is 21.
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A local newspaper charges $13 for each of the first four lines of a classified ad, and $7.50 foreach additional line. Express the cost of a -line ad, c(x), as a piecewise function
Answers
The cost is the basic cost increased by the product of the number of extra lines and the price per additional line, then:
Let x be the number of additional lines
c(x)=13+7.50x
I need help on question 10.The solution of the system below is:3x + 2y = 143x – 2y = 10
Answers
Given the system of equations:
[tex]\begin{cases}3x+2y=14 \\ 3x-2y=10\end{cases}[/tex]We'll multiply the second equation by -1 and then add both equations up:
[tex]\begin{gathered} \begin{cases}3x+2y=14 \\ 3x-2y=10\end{cases}\rightarrow\begin{cases}3x+2y=14 \\ -3x+2y=-10\end{cases} \\ \\ \rightarrow4y=4 \end{gathered}[/tex]Solving the resulting equation for y ,
[tex]\begin{gathered} 4y=4\rightarrow y=\frac{4}{4} \\ \\ \Rightarrow y=1 \end{gathered}[/tex]We'll plug in this y-value in the first equation and solve for x ,
[tex]\begin{gathered} 3x+2y=14 \\ \rightarrow3x+2(1)=14 \\ \rightarrow3x+2=14\rightarrow3x=12\rightarrow x=\frac{12}{3} \\ \\ \Rightarrow x=4 \end{gathered}[/tex]Therefore, we can conclude that the solution to our system is:
[tex]\begin{gathered} x=4 \\ y=1 \end{gathered}[/tex]For the line y = 1 - 3x, create a table to show the values of x and y where x is from -2 to 2.
Answers
For the line y = 1 - 3x the values of x and y are given below:
Given,
y = 1 - 3x
putting x = -2
y = 1 - 3x
y = 1 - 3(-2)
y = 7
Putting x = -1
y = 1 - 3(-1)
y = 4
putting x = 0
y = 1 - 3(0)
y = 1
Now putting x = 1
y = 1 - 3(1)
y = -2
putting x = 2
y = 1 - 3(2)
y = -5
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The price-demand and cost functions for the production of microwaves are given asP= 180 - q/50and C(q) = 72000 + 110g,where q is the number of microwaves that can be sold at a price of p dollars per unit and C(q) is the total cost (in dollars) of producing q units.(C) Find the marginal revenue function in terms of q.R'(q) =(D) Evaluate the marginal revenue function at q=1100.R'(1100) =(E) Find the profit function in terms of q.P(q)(F) Evaluate the marginal proft function at q = 1100.P'(1100)
Answers
Answer:
A)
[tex]\begin{equation*} C^{\prime}(q)=110 \end{equation*}[/tex]B)
[tex]\begin{equation*} R(q)=180q-\frac{q^2}{50} \end{equation*}[/tex]C)
[tex]\begin{equation*} R^{\prime}(q)=180-\frac{q}{25} \end{equation*}[/tex]D)
[tex]\begin{equation*} R^{\prime}(1100)=136 \end{equation*}[/tex]E)
[tex]\begin{equation*} P(q)=-\frac{q^2}{50}+70q-72000 \end{equation*}[/tex]F)
[tex]\begin{equation*} P^{\prime}(1100)=26 \end{equation*}[/tex]Explanation:
Given:
[tex]\begin{gathered} p=180-\frac{q}{50} \\ C(q)=72000+110q \end{gathered}[/tex]where q = the number of microwaves that can be sold at a price of p dollars per unit
C(q) = the total cost (in dollars) of producing q units.
A) To find the marginal cost, C'(q), we'll go ahead and take the derivative of the total cost as seen below;
[tex]\begin{gathered} C(q)=72000+110q \\ C^{\prime}(q)=0+110 \\ \therefore C^{\prime}(q)=110 \end{gathered}[/tex]So the marginal cost, C'(q) = 110
B) We'll go ahead and determine the revenue function, R(q), by multiplying the price, p, by the quantity, q, as seen below;
[tex]\begin{gathered} R(q)=p*q=(180-\frac{q}{50})q=180q-\frac{q^2}{50} \\ \therefore R(q)=180q-\frac{q^2}{50} \end{gathered}[/tex]C) We'll go ahead and determine the marginal revenue function, R'(q), by taking the derivative of the revenue function, R(q);
[tex]\begin{gathered} \begin{equation*} R(q)=180q-\frac{q^2}{50} \end{equation*} \\ R^{\prime}(q)=180-\frac{2q^{2-1}}{50}=180-\frac{q}{25} \\ \therefore R^{\prime}(q)=180-\frac{q}{25} \end{gathered}[/tex]D) To evaluate the marginal revenue function at q = 1100, all we need to do is substitute the q with 1100 in R'(q) and simplify;
[tex]\begin{gathered} \begin{equation*} R^{\prime}(q)=180-\frac{q}{25} \end{equation*} \\ R^{\prime}(1100)=180-\frac{1100}{25}=180-44=136 \\ \therefore R^{\prime}(1100)=136 \end{gathered}[/tex]Therefore, R'(1100) is 136
E) To find the profit function, P(q), we have to subtract the total cost, C(q), from the revenue cost, R(q);
[tex]\begin{gathered} P(q)=R(q)-C(q) \\ =(180q-\frac{q^2}{50})-(72,000+110q) \\ =180q-\frac{q^2}{50}-72000-110q \\ =-\frac{q^2}{50}+180q-110q-72000 \\ =-\frac{q^2}{50}+70q-72000 \\ \therefore P(q)=-\frac{q^2}{50}+70q-72000 \end{gathered}[/tex]F) To Evaluate the marginal profit function at q = 1100, we have to first determine the marginal profit, P'(q), by taking the derivative of the profit function, P(x);
[tex]\begin{gathered} \begin{equation*} P(q)=-\frac{q^2}{50}+70q-72000 \end{equation*} \\ P^{\prime}(q)=-\frac{2q^{2-1}}{50}+70(1*q^{1-1})-0=-2q^{50}+70q^0=-\frac{q}{25}+70 \\ \therefore P^{\prime}(q)=-\frac{q}{25}+70 \end{gathered}[/tex]We can now go ahead and find P'(1100) as seen below;
[tex]\begin{gathered} P^{\prime}(1100)=-\frac{1100}{25}+70=-44+70=26 \\ \therefore P^{\prime}(1100)=26 \end{gathered}[/tex]So P'(1100) = 26
A girl is pedaling her bicycle at a speed of 0.10 km/min. How far will she travel in three hours?
Answers
Answer:
18 km
Step-by-step explanation:
.1 km/min * 60 min/hr * 3 hr = 18 km
Answer: 18 km
Step-by-step explanation:
First, you know that 60 minutes equal one hour so to get a km/hr ratio you need to multiply the 0.10km by 60 and the minute (1) to get 6(km)/1(hr), then you multiply the 6km by 3 as well as the 1hr by 3 since we need to get to three hours. With this you get 18(km)/3(hr).
What is 75.6 divided by 4
Answers
Answer:
18.9
Step-by-step explanation:
Calculators, haha
What’s the correct answer answer asap i need help can somebody answer this question?
il give you brainlist
Answers
Answer:
Virtuosity on the piano
Answer: a
Step-by-step explanation:
which statement would justify selecting plan B instead of plan A?Plan A: C = 30dPlan B: C = 25d + 15
Answers
We have two rental car plans.
We have to compare them to find the one that offers the minimum cost.
Plan A has no fixed fee but has a cost of $30 per day:
[tex]C=30d[/tex]Plan B has a fixed fee of $15 and a cost per day of $25:
[tex]C=25d+15[/tex]We expect the plan A to have a smaller cost for few days, while plan B becomes more convenient when we increase the number of days.
We can calculate the break even point when both costs are the same:
[tex]\begin{gathered} C_A=C_B \\ 30d=25d+15 \\ 30d-25d=15 \\ 5d=15 \\ d=\frac{15}{3} \\ d=5 \end{gathered}[/tex]Then, we know that for less than 5 days, Plan A is more convenient.
For more than 5 days, Plan B is more convenient.
For exactly 5 days, the decision is indifferent as both plans will have the same total cost.
Answer: The only statement that would justify selecting Plan B instead of A is if Marcus rents a car for 5 days.
Determine the values of x in the equation x^2 = 81. Please help
x = −9
x = ±9
x = ±40.5
x = 40.5
Answers
The value of x in the quadratic equation is ±9.
As equation is [tex]X^{2}[/tex] = 81
Taking square root on both sides
⇒ [tex]\sqrt{x^{2} } = \sqrt{81}[/tex]
⇒ X = ± 9
∴ The value of X is ± 9
The roots of the given quadratic equation are +9 and -9.
How to solve a quadratic equation?An equation of degree 2 containing a single variable is known as the quadratic equation. . Its general form is [tex]Ax^{2}+ Bx^{} + C[/tex], where variables are x and constants are a, b, and c.
Examples are [tex]X^{2}[/tex] = ± 3, [tex]X^{2}[/tex] = ±9, [tex]X^{2}[/tex]=4 or any real number.
Some other examples are [tex]x^{2} + 2X+2[/tex], etc.
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Luisa bought 4.4 kilograms of apples. How
many ounces of apples did she buy? Use the
conversion rates 1 kilogram = 2.20 pounds
and 1 pound = 16 ounces. Round to the
nearest ounce.
Answers
the measure of <1 is 39°. find the measure of the Adjacent angle to <1.
Answers
Explanation
by the graph we can conclude
[tex]\text{angle}\measuredangle1+angle\measuredangle2=90[/tex]if
angle1=39
replace,
[tex]\begin{gathered} \text{angle}\measuredangle1+angle\measuredangle2=90 \\ \text{39}+angle\measuredangle2=90 \\ \text{subtract 39 in both sdies} \\ \text{39}+angle\measuredangle2-39=90-39 \\ angle\measuredangle2=51 \end{gathered}[/tex]I hope this helps you
If 4–(x – 4) = 1 over 16 what is the value of x? (2 points)
–2
–6
6
2
Answers
Answer: these are the answers that i got -2 for x =10 -6= 14 6=2 and 2= 6
Step-by-step explanation:
solve im giving 40 points ASAP
Answers
A point P on the line segment starting at A and ending at B can be parameterized by
[tex]p(t) = (1-t)(-2,-4) + t (6,1)[/tex]
with [tex]0\le t\le1[/tex].
If AP/PB = 3/2, then point P is 3/5 of the length of AB from A, and 2/5 of the length of AB from B. So the coordinates of P are obtained at [tex]t=\frac35[/tex], and we find
[tex]p\left(\dfrac35\right) = \left(1-\dfrac35\right)(-2,-4) + \dfrac35 (6,1) = \boxed{\left(\dfrac{14}5, -1\right)}[/tex]
Hello, just want to check my answers at Part B. Thanks!
Answers
SOLUTION
The given functions are:
[tex]f(x)=(x-2)(x-1)(x-1),g(x)=\sqrt[3]{x}-2[/tex]Notice that when x=0
[tex]\begin{gathered} f(0)=(0-2)(0-1)(0-1) \\ f(0)=-2 \end{gathered}[/tex]Also
[tex]\begin{gathered} g(0)=\sqrt[3]{0}-2 \\ g(0)=-2 \end{gathered}[/tex]This shows that f(0)=g(0)
Hence there are no breakes in the domain of h(x)
Find the percent change and tell whether it is a percent decrease orincrease.Original amount: 30End amount: 45
Answers
Step 1
Since the end amount is greater than the original amount, it is, therefore, percentage increase
Step 2
Calculate the percentage increase
The formula is given by
[tex]\begin{gathered} \text{Percentage increase =}\frac{Increase}{\text{Original}}\times100 \\ \text{Increase}=\text{ }45\text{ - 30 = 15} \\ \end{gathered}[/tex][tex]\text{Percentage increase =}\frac{15}{30}\times100=\text{ 50 percent}[/tex]The answer is therefore 50%
whats the average for 62,81,72,60,100,79
Answers
Answer:
75.66
Step-by-step explanation:
62, 81, 72, 60, 100, 79
To find the average, add all the numbers together then divide by how many numbers there are.
62 + 81 + 72 + 60 + 100 + 79 = 454
454 ÷ 6 = 75.66 or rounded 76
I hope this helps!
The question is in the ss
Answers
An algebraic expression that is equivalent to the given expression
(2c³)⁵(4c⁴) / (8c⁶)² is equal to 2c⁷.
As given in the question,
Given algebraic expression is equal to :
(2c³)⁵(4c⁴) / (8c⁶)²
Law of indices:
mᵃ × mᵇ = mᵃ⁺ᵇ
mᵃ ÷ mᵇ = mᵃ⁻ᵇ
To get equivalent expression simplify the given expression
(2c³)⁵(4c⁴) / (8c⁶)² using law of indices:
(2c³)⁵(4c⁴) / (8c⁶)²
= ( 2⁵c¹⁵) ( 2²c⁴) / ( 2³c⁶)²
=( 2⁵c¹⁵) ( 2²c⁴) / ( 2⁶c¹²)
= 2⁵⁺²⁻⁶ c¹⁵⁺⁴⁻¹²
= 2c⁷
Therefore, an algebraic expression that is equivalent to the given expression (2c³)⁵(4c⁴) / (8c⁶)² is equal to 2c⁷.
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Which combination could the coach buy?Click on the correct answer.Remember, the coach1) needs to buy at least 4 bats and atleast 8 balls2) cannot spend more than $1206 bats, 10 balls12-3 bats, 10 balls84 bats, 9 balls-4-110T14812x24y2815x + 5y = 120
Answers
It is important to know that the yellow area represents all the possible solutions because there all the areas intercept. So, among the options, the correct one is 4 bats, 9 balls because it represents (3,10) which is inside the yellow region.
Hence, the answer is option 3.To pass a course with a B grade a student must have an average of 80 or greater. The students grades on three test are 80, 81 and 70. Find what score the student must get on the next test to get a B average or better.
Answers
Given that the student's grades on three tests are 80, 81 and 70
Let the student's grade on the fourth test be X
In order to pass the course, the student must have an average of 80 or greater.
Hence,
[tex]\begin{gathered} \frac{80+81+70+X}{4}\ge80 \\ \frac{231+X}{4}\ge80 \\ 231+X\ge320 \\ X\ge320-231 \\ X\ge89 \end{gathered}[/tex]The score the student must get on the next test to get a B average or better is greater than or equal to 89