Ice, H2O(s), is classified as: An ionic compound, a molecular compound, a homogeneous mixture, a heterogeneous mixture

Answer:

Sphere

Explanation:

The shape of the s-sublevel is spherical in shape.

This sublevel has an azimuthal quantum number of 0 and it is spherical in shape;

Answer:

Explanation:

Ca₃( PO₄)₂ = 3 Ca⁺² + 2 PO₄⁻³

x                      3x            2 x

Let solubility be x mole per litre

solubility product = (3x )³ x ( 2x )²

= 108 x⁵ = 1.2 x 10⁻²⁹

x⁵ = .0111 x 10⁻²⁹ = .111 x 10⁻³⁰

x = .64 x 10⁻⁶ moles / litre

Answer:

B

Explanation:

Newton's third law. states that:

Action and reaction are equal and opposite.

Answer:

This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur.

Explanation:

Answer:

Freezing Point Depression. The freezing point of a solution is less than the freezing point of the pure solvent. This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur

Answer:

A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.

The enthalpy : 320.3 kJ/mol

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation  

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)  

Based on the principle of Hess's Law,

the change in enthalpy of a reaction will be the same even though it is through several stages or ways  

Reaction

2Fe (s) + 3Cl₂ (g) → 2FeCl₃ (s) ∆H° = -800.0 kJ/mol  x 2

4Fe (s) + 6Cl₂ (g) → 4FeCl₃ (s) ∆H° = -1600.0 kJ/mol

Si(s) + 2 Cl₂ (g) → SiCl₄ (s) ∆H° = -640.1 kJ/mol

Reverse

SiCl₄ (s) → Si(s) + 2 Cl₂ (g) ∆H° = 640.1 kJ/mol x 3

3SiCl₄ (s) → 3Si(s) + 6Cl₂ (g) ∆H° = 1920.3 kJ/mol

------------------------------------------------------------------------ +

3 SiCl₄ (s) + 4 Fe (s) → 4 FeCl₃ (s) + 3 Si (s) ∆H° = 320.3 kJ/mol

The enthalpy for the formation of 4 moles of [tex]\rm FeCl_3[/tex] has been 320.3 kJ/mol.

The enthalpy of formation of 1 mole at standard temperature and pressure has been termed the standard enthalpy of formation.

The reaction enthalpy to be calculated has reactants of 3 moles of [tex]\rm SiCl_4[/tex], and 4 moles of Fe.

The enthalpy for the formation of [tex]\rm SiCl_4[/tex] has been -640.1 kJ/mol.

The enthalpy for the dissociation of [tex]\rm SiCl_4[/tex] has been the reverse of the formation reaction = +640.1 kJ/mol.

The enthalpy for the dissociation of 3 moles of [tex]\rm SiCl_4[/tex] has been = 3 [tex]\times[/tex] 640.1 kJ/mol.

The enthalpy for the dissociation of 3 moles of [tex]\rm SiCl_4[/tex] has been = 1920.3 kJ/mol.

The enthalpy for the formation of 2 moles of [tex]\rm FeCl_3[/tex] = -800 kJ/mol

The enthalpy for the formation of 4 moles of [tex]\rm FeCl_3[/tex] = -1600 kJ/mol.

The final reaction has 3 moles of  [tex]\rm SiCl_4[/tex], and 4 moles of [tex]\rm FeCl_3[/tex].

Thus, the final enthalpy of reaction will be: 1920 kJ/mol + (-1600 kJ/mol)

The final enthalpy of reaction will be = 320.3 kJ/mol.

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Answer:

Its B

Explanation:

Answer:

i can only help with 2 :( atimic mass is: 35.453  and number of electrons is:17

Explanation:

Answer:

Throughout the overview section following portion, the description and according to particular circumstance is defined.

Explanation:

As per the question,

⇒ [tex]NH_3(aq)+H_2O\leftrightarrow NH_4+(aq)+OH-(aq)[/tex]

⇒ [tex]NH_3+(aq) \leftrightarrow NH_3(aq)+H+(aq)[/tex]

However, it is also available in NH3 form throughout the aqueous solution much of the moment.

Answer:

A circle graph, or a pie chart, is used to visualize information and data. A circle graph is usually used to easily show the results of an investigation in a proportional manner. Bar graphs are used to compare things between different groups or to track changes over time. However, when trying to measure change over time, bar graphs are best when the changes are larger.

Explanation:

In short, bar graphs are better to keep track of data over long periods of time, and circle graphs are better when you are trying to visualize a specific set of data.

Circle graph can be also be called pie chart, which  is more widely used. It is usually made up of a circle, divided into parts or pies. In the divided parts, it is used to differentiate between different data.

Bar charts on the other hand are like graphs having both x and y axis. It is used to represent data with respect to the height of the graph. Each data is divided into different smaller parts on the graph.

Example of what they look like is attached below.

First one is bar chart while the second is a circle graph

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Answer:

I believe its 1,2, and 5

Explanation:

C D E

temperature of medium

type of wave

type of medium

Answer:

Carbon

Explanation:

Answer:

Pentyl Ethanoate, CH3COOC5H11, which smells like bananas, is produced from the esterification reaction: CH3COOH(aq) +C5H11OH(aq) → CH3COOC5H11(aq) + H … 2O(l) A reaction uses 3.58g of CH3COOH and 4.75g of C5H11OH and has a yield of 45.00%. Determine the mass of ester that foorms

Answer:

[tex]23.093\ \text{torr}[/tex]

Explanation:

[tex]M_g[/tex] = Molar mass of glucose = 180.2 g/mol

[tex]M_w[/tex] = Molar mass of water = 18 g/mol

[tex]m_g[/tex] = Mass of glucose = 76.6 g

[tex]m_w[/tex] = Mass of water = [tex]250\times 1\ \text{g/mL}=250\text{g}[/tex]

[tex]P_0[/tex] = Vapor pressure of pure water at 25°C = 23.8 torr

The mole fraction of glucose is

[tex]x_g=\dfrac{\dfrac{m_g}{M_g}}{\dfrac{m_g}{M_g}+\dfrac{m_w}{M_w}}=\dfrac{\dfrac{76.6}{180.2}}{\dfrac{76.6}{180.2}+\dfrac{250}{18}}\\\Rightarrow x_g=0.0297[/tex]

Mole fraction of the solute would be

[tex]\dfrac{P_0-P}{P_0}=x_g\\\Rightarrow 0.0297=\dfrac{23.8-P}{23.8}\\\Rightarrow P=23.8-0.0297\times23.8\\\Rightarrow P=23.093\ \text{torr}[/tex]

The vapor pressure of the solution is [tex]23.093\ \text{torr}[/tex].

Answer:

[tex]0.192\ \text{M}[/tex]

Explanation:

A = Absorbance of solution

E = Molar absorptivity

l = Length of cuvette = 1 cm

c = Concentration of solution

Beer's law is given by

[tex]A=Elc[/tex]

The equation of a straight line is given by

[tex]y=mx+c[/tex]

Comparing the above equations we get

Value on [tex]y[/tex] axis = A = Absorbance of solution = 0.23

[tex]m[/tex] = Slope of line = El = Molar absorptivity multiplied with length = [tex]1.2\times 1\ \text{M}^{-1}[/tex]

[tex]x[/tex] = Value of x axis = c = Concentration of solution

So we get

[tex]c=\dfrac{A}{El}\\\Rightarrow c=\dfrac{0.23}{1.2\times 1}\\\Rightarrow c=0.192\ \text{M}[/tex]

The molar concentration of the sample is [tex]0.192\ \text{M}[/tex]

Answer:

Cultivated rice paddies

Drilling of natural deposits

Fossil fuel use

Burning of biomass

Landfills

Explanation:

The bulk of the methane released into the atmosphere are as a result of various human activities.

Answer:

0.56 mL

Explanation:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachloride would be produced by this reaction if 1.1 mL of chlorine were consumed.

Step 1: Write the balanced equation

CH₄(g) + 2 Cl₂(g) → CCl₄(g) + 4 HCl (g)

Step 2: Calculate the moles corresponding to 1.1 mL of Cl₂

At standard temperature and pressure, 1 mole of a gas has a volume of 22.4 L.

1.1 × 10⁻³ L × 1 mol/22.4 L = 4.9 × 10⁻⁵ mol

Step 3: Calculate the moles of CCl₄ formed from 4.9 × 10⁻⁵ moles of Cl₂

The molar ratio of Cl₂ to CCl₄ is 2:1. The moles of CCl₄ are 1/2 × 4.9 × 10⁻⁵ mol = 2.5 × 10⁻⁵ mol.

Step 4: Calculate the volume corresponding to 2.5 × 10⁻⁵ moles of CCl₄

At standard temperature and pressure, 1 mole of a gas has a volume of 22.4 L.

2.5 × 10⁻⁵ mol × 22.4 L/mol = 5.6 × 10⁻⁴ L = 0.56 mL

Answer:

[tex]$Cu_2+(SO_3)^2 \rightleftharpoons CuSO_3 \ (insoluble)$[/tex]

[tex]$Cu_2+2(SO_3)^2 \rightleftharpoons [Cu(SO_3)_2]_2 \ (soluble)$[/tex]

Explanation:

A ligand may be defined as a molecule or an ion or that binds to the central metal atom in order to form a more coordination complex. Sulfite is one such ligand and it behaves similarly as hydroxide as a ligand.

Now, according to the question, when we react copper with sulfite ion, it forms copper sulfite. The equation is

[tex]$Cu_2+(SO_3)^2 \rightleftharpoons CuSO_3 \ (insoluble)$[/tex]

Now when excess of the sulfite ion is used in the reaction, we get a complex formation, which is shown by

[tex]$Cu_2+2(SO_3)^2 \rightleftharpoons [Cu(SO_3)_2]_2 \ (soluble)$[/tex]

The way the sulfite reacts is quite similar to hydroxide ion where they form a complex ion when hydroxide ion in excess is used in the reaction with metal cation.

Answer:

residue is whatever remains after something else has been removed while filtrate is the liquid or solution that has passed through a filter, and which has been separated from the filtride.

filtration id done by placing a filter paper on the beaker or container then pour the filtride then let it settle and it will pass through and you will have the fitrate and residue

Explanation:

Answer:

ion is missing

Explanation:

Answers:

1. Chemistry

2. Cold

3. Heat

4. Protons and neutrons

5. Positive

6. Neutral

7. True

8. Nucleus

9. Protons

10. Nobel gasses

11. Dmitri Mendeleev

12. the bottom of the square

13. True

14. Helium

Option ( C ). Hydrolysis (/haɪˈdrɒlɪsɪs/; ancient Greek for "water" and "to dissolve") is a chemical reaction in which water molecules break one or more chemical bonds.)

What does the example of hydrolysis mean?

Hydrolysis is the process of breaking down compounds by adding water. Here is an example of hydrolysis:

Sodium acetate is a type of salt. When sodium acetate is mixed with water, the chemical bonds are broken and it breaks down into sodium ions and acetate ions.

What is function of hydrolysis?

Hydrolysis reactions break the bonds and release energy. Biopolymers are ingested and hydrolyzed in the gastrointestinal tract to form small molecules that can be absorbed by cells and further broken down to release energy.  

Where does the hydrolysis take place?

Hydrolysis is the process by which compounds are broken down into simpler compounds and involves the chemical uptake of water. Almost all tissues contain enzymes that catalyze hydrolysis, but the highest concentration is in the liver.

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Answer:

0.16 L

Explanation:

From the question given above, the following data were obtained:

Mole = 0.0806 mole

Molarity = 0.490 M

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the volume of the solution as illustrated below:

Mole = 0.0806 mole

Molarity = 0.490 M

Volume =?

Molarity = mole /Volume

0.490 = 0.0806/volume

Cross multiply

0.490 × volume = 0.0806

Divide both side by 0.490

Volume = 0.0806 / 0.490

Volume of solution = 0.16 L

Thus, the volume of the solution is 0.16 L.

A solution is a mixture of solute in the solvent. The volume of the solution is 0.16 L.

A solution is a mixture of solute in the solvent.

An example of a solution is a mixture of salt in water.

Given,

Moles = 0.0806 mol [tex]\rm CaCl_2[/tex]

Molarity = 0.490 M

To find: the volume of the solution

[tex]Molarity = \dfrac{n}{V}[/tex]

Putting the values

[tex]0.490 M = \dfrac{ 0.0806}{V}\\\\0.490 M \times V = 0.0806\\\\Divide\; both\;side\; with\; 0.490\\\\V= \dfrac{ 0.0806}{0.490}=0.16 L[/tex]

Thus, the volume so the solution is 0.16 l.

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Answer:

53.5%

Explanation:

Step 1: Given data

Step 2: Calculate the mass corresponding to 0.00875 moles of KClO₃

The molar mass of KClO₃ is 122.55 g/mol.

0.00875 mol × 122.55 g/mol. = 1.07 g

Step 3: Calculate the percent by mass of KClO₃ in the mixture

We will use the following expression.

%m/m = mass of KClO₃/mass of the sample × 100%

%m/m = 1.07 g/2.00 g × 100%

%m/m = 53.5%

The percent by mass of KClO3 in the original mixture is 53.5%.

Since

The mass of the sample should be 2.00 g

Moles of KClO₃: 0.00875 mol

The molar mass of KClO₃ is 122.55 g/mol.

Now the mass is

= 0.00875 mol × 122.55 g/mol.

= 1.07 g

Now the percentage should be

= mass of KClO₃/mass of the sample × 100%

= 1.07 g/2.00 g × 100%

= 53.5%

hence, The percent by mass of KClO3 in the original mixture is 53.5%.

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Answer:

A

Explanation:

I took the test