GROUP THE LIKE TERMS FIRST.
[tex]9x - 3x = 7 + 9[/tex]
WHEN TERMS CROSS THE EQUAL SIGN THEY CHANGE SIGN.
[tex]6x = 16 \\ \frac{6x}{6} = \frac{16}{6} \\ x = \frac{16}{6} [/tex]
x can be simplified further
[tex]x = \frac{8}{3} [/tex]
HOPE THIS HELPS.
Answer:
The answer should be x=2.6
Step-by-step explanation:
9x-9=3x+7
-first you should move the numbers so you can get all your x values on one side and all your regular numbers on the other like this
9x-3x=7+9
-What i basically did was i passed the 3x from the right side to the left side of the equation, since in adding the 3x originaly, when i pass it to the left side itll be subtracting. then i passed my -9 to the right side of my equation, since i was subtracting originaly ill have to now switch it to adding
-after you do this you are going to want to want to combine like terms
6x=16
-then you are going to want to devide on both sides so you can get x alone
x=2.6
exercise after work, Albert (A) went running and Tanisha (T) walked for exercise. Their times and distances are showing in the graph below. How much as Albert running than Tanisha walking in miles per hour? Explain how you found your answer.
In the picture, there are two lines that graph distance versus time, so the slope of the line is teh rate or the speed of Albert or Tanisha.
We need to calculate the slope of each line. We can note that the two lines start in the origin point (0, 0), so:
[tex]\begin{gathered} \text{For Albert, we can s}ee\text{ that the point (10, 1) is in the line, so:} \\ slopeofAlbert=m_A=\frac{1}{10}=0.1\frac{miles}{\min ute} \\ \text{For Tanisha, we can se}e\text{ thet the point (}20,\text{ 1) is in the line. so:} \\ slopeofTanisha=m_T=\frac{1}{20}=0.05\frac{miles}{\min ute} \end{gathered}[/tex]The different between the slopes (speed) is:
[tex]\begin{gathered} m_A-m_T=0.1\frac{miles}{\min ute}-0.05\frac{miles}{\min ute}=0.05\frac{miles}{\min ute} \\ In\text{ miles/hours is:} \\ m_A-m_T=0.05\frac{miles}{\min ute}\cdot\frac{60\text{minutes}}{1\text{hour}}=3\frac{miles}{hour} \end{gathered}[/tex]Albert goes 3 miles/hour faster than Tanisha
f(x) = (x-1.5)^2 find the vertex
The given function is
[tex]f(x)=(x-1.5)^2[/tex]It is important to know that the function is in vertex form
[tex]f(x)=a(x-h)^2+k[/tex]Where h and k are the coordinates of the vertex.
Having said that, we can deduct that the vertex of the given function is (1.5, 0) because those are the values for h and k.
Hence, the answer is V(1.5, 0).Let d represent the number of $2 decreases i price. Let r be the company’s revenue. Write a quadratic function that reflects the company’s revenue.
Answer:
Let d be the number of $2 decreases, and r be the company´s revenue, then the company can sell:
[tex]800+40d[/tex]cellphones per week at a price of:
[tex]80-2d[/tex]dollars.
Therefore, the quadratic equation that represents the revenue is:
[tex](800+40d)(80-2d)\text{.}[/tex]Now, graphing the above equation we get:
From the above graph, we can determine the vertex and the vertex gives us for which value of d the company gets the maximum revenue.
The company should charge $80-10($2)=$80-$20=$60.
please help me please
It's a line that slopes down
The second choice is the answer because the slope is negative.
Question 10(Multiple Choice Worth 1 points)
(08.01 LC)
Susan wants to conduct a survey to find how much time the students of her school spent eating in a local cafeteria. Which of the following is an appropriate statistical question for this survey?
Who eats at the cafeteria on weekends?
How many students eat in the cafeteria on Mondays?
How many students eat in the cafeteria once a week?
How many hours during the week do you eat in the cafeteria?
Write the statement in if-then form.
Prime numbers only have two factors, 1 and itself.
Answer:
If the wide variety has only two factors, 1 and itself, then it if truth be told is top in a very huge way. If the variety has usually greater than two factors, then it is for all intents and functions composite in a refined way.
Answer:
See below
Step-by-step explanation:
If a number only has factors of one and itself, then the number is a prime number.
One positive integer is 2 less than twice another. The sum of their squares is 745.
The numbers are 13 and 24
What is Integers?
The negative numbers are the additive inverses of the corresponding positive numbers.[2] In the language of mathematics, the set of integers is frequently denoted by the boldface Z or blackboard bold displaystyle mathbb Z mathbb Z.[3][4][5] An integer is the number zero (0), a positive natural number (1, 2, 3, etc.), or a negative integer with a minus sign
y=first number
x=2y-2 (second number)
y^2+(2y-2)^2=745
y^2+4y^2-8y+4=745
5y^2-8y+4-745=0
5y^2-8y-741=0
Now, from the equation we can solve
5y^2 -65y +57y - 741 = 0
5y(y - 13) + 57(y - 13) = 0
(5y + 57)(y - 13)= 0
now, since the Integers are positive so the value obtained from (5y + 57) = 0 can't hold true.
So, y-13 = 0
y = 13
The first number is : 13
The second number is :
x = 2(13) - 2
x = 26 - 2
x = 24
The second number is : 24
Hence, the numbers are 13 and 24
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The bank that the Payans would like to borrow from uses the back-end ratio to determine loan qualification, approving applications if the back-end ratio is less than 36%. So, the Payans have collected some information on what the bank will consider to calculate the ratio, including what they estimate their monthly mortgage payment will be.According to the Payans' back-end ratio calculation, the bank will ______(most likely, not) lend the Payans $250,000 to purchase the home because their back-end ratio is_____(equal to, higher than, lower than) 36%
Approved if back-end ratio is less than 36%
Total income: $10,000
Total expenses:
$1,100 + $150 + $500 + $1,000 + $400 = $3,150
Back-end ratio: (Total expenses) / (Total Income) x 100
= (3150/10000)x100 = 31.5%
According to the Payans' back-end ratio calculation, the bank will most likely lend the Payans $250,000 to purchase the home because their back-end ratio is lower than 36%
I need help finding
The proeprty of rhombus is that
The diagnol of a rhombus VX bisect the angle WVY in two equal parts .
Therefore, the angle YVX = angle XVW.
[tex]\angle YVX=(9n+4)^{\circ}[/tex]The another property of rhombus is that the diagnol are perpendicular .
[tex]3n^2-0.75=90[/tex]How many times larger is (1.008 x 101) than (6 x 10-f)?
0.168
5.95
11.682
16.8
Answer:
11.682 many times larger
Answer:
16.8
Step-by-step explanation:
To find how many times larger (1.008 × 10¹) is than (6 × 10⁻¹), divide the first expression by the second expression:
[tex]\implies \dfrac{1.008 \times 10^1}{6 \times 10^{-1}}[/tex]
[tex]\textsf{Apply the fraction rule} \quad \dfrac{ab}{cd}=\dfrac{a}{c} \times \dfrac{b}{d}:[/tex]
[tex]\implies \dfrac{1.008}{6} \times \dfrac{10^1}{10^{-1}}[/tex]
Divide the numbers 1.008 and 6:
[tex]\implies 0.168 \times \dfrac{10^1}{10^{-1}}[/tex]
[tex]\textsf{Apply the exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:[/tex]
[tex]\implies 0.168 \times 10^{(1-(-1)}[/tex]
Simplify:
[tex]\implies 0.168 \times 10^{2}[/tex]
[tex]\implies 0.168 \times 10 \times 10[/tex]
[tex]\implies 1.68 \times 10[/tex]
[tex]\implies 16.8[/tex]
plss help me with this i need help
Jay had 60 tickets he could turn in at the end of the year for extra-credit points he had earned during the year. Some tickets were worth two points and others were worth five points. If he was entitled to a total of 231 extra-credit points, how many two-point tickets did he have?
Answer:
23 2-points + 37 5-points = 231
Step-by-step explanation:
Answer:
53 two-point tickets.
Step-by-step explanation:
This is a system of equations:
x + y = 60
2x + 5y = 231
Then..
-2x - 2y = -120
2x + 5y = 231
Then...
3y = 111
y=7
All you need to do now is plug it in:
x + 7 = 60
60-7 = x
x = 53
Determine the slope of any line perpendicular to the line illustrated in the graph below.
Points (2, -1) and (1,-4)
Finding slope
[tex]m=\frac{-4+1}{1-2}=\frac{-3}{-1}=3[/tex]For slope for the perpendicular line
[tex]m=\frac{-1}{3}[/tex]Hello, I could use some help understanding this question please.
To determine the total number of employees, we need to determine first how many are men in the company.
To determine the number of men in the company, we can use the given ratio 7 men is to 5 women and apply direct proportion.
[tex]\frac{7men}{5women}=\frac{?}{135women}[/tex]To solve for the number of men (?), let's apply cross multiplication in the equation above.
[tex]\begin{gathered} \frac{7men\times135women\text{ }}{5women\text{ }}=? \\ \frac{945}{5}=\text{?} \\ 189men=? \end{gathered}[/tex]Hence, there are 189 men in the company.
In total, there are 189 men + 135 women = 324 employees in the company.
The length of a rectangular piece of steel in a bridge is 2 meters less than triple the width. The perimeter of the piece of steel is 60 meters. Find the length of the pieceof steel. Find the width of the piece of steel.
Let "x" represent the width of the rectangular steel, then the length, which is 2meters less than triple the width, can be expressed as "3x-2".
The perimeter of the rectangular piece is 60meters.
The formula for the perimeter is the following:
[tex]P=2w+2l[/tex]Replace the formula with the expressions for the width and length and the given perimeter of the piece of steel:
w=x
l=3x-2
P=60
[tex]60=2x+2(3x-2)[/tex]From this expression, you can determine the value of x.
-First, distribute the multiplication on the parentheses term
[tex]\begin{gathered} 60=2x+2\cdot3x-2\cdot2 \\ 60=2x+6x-4 \end{gathered}[/tex]-Second, simplify the like terms and pass "-4" to the left side of the expression by applying the opposite operation "+4" to both sides of it
[tex]\begin{gathered} 60=8x-4 \\ 60+4=8x-4+4 \\ 64=8x \end{gathered}[/tex]-Third, divide both sides by 8 to determine the value of x
[tex]\begin{gathered} \frac{64}{8}=\frac{8x}{8} \\ 8=x \end{gathered}[/tex]The value of x is 8m, which means that the width of the piece of steel is 8m
To determine the length you just have to replace the expression by x=8
[tex]\begin{gathered} l=3x-2 \\ l=3\cdot8-2 \\ l=24-2 \\ l=22 \end{gathered}[/tex]The length is 22m
Evaluate x^3 - 6y + 2 for x = 4 and y= 6.
The given expression is x^3 - 6y + 2
We are gven x = 4 and y = 6
Substituting the given values into the expression, it becomes
4^3 - 6*6 + 2
= 12 - 36 + 2
= - 22
Given the function defined in the table below, find the average rate of change, in
simplest form, of the function over the interval 1 < x < 5.
2
f(x)
1
77
2
68
3
59
4
50
5
5
41
-
Given:
Function interval
[tex]1\leq x\leq5[/tex][tex]\begin{gathered} x\rightarrow f(x) \\ \\ 1\rightarrow77 \\ \\ 2\rightarrow68 \\ \\ 3\rightarrow59 \\ \\ 4\rightarrow50 \\ \\ 5\rightarrow41 \end{gathered}[/tex]Find-: Average rate of change.
Sol:
The average rate of change is:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Choose any two-point.
[tex]\begin{gathered} (x_1,y_1)=(1,77) \\ \\ (x_2,y_2)=(2,68) \end{gathered}[/tex]So average rate of change is:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ m=\frac{68-77}{2-1} \\ \\ m=\frac{-9}{1} \\ \\ m=-9 \end{gathered}[/tex]The average rate of change is -9.
Create your own quadratic equation whilst explaining how to use the quadratic formula to solve it. Be specific, using a, b, and c of your equation and give solutions to theequation you chose.
Let the quadratic equation is
[tex]x^2-8x+16=0[/tex]Here, a is the coefficient of x^2, b is the coefficient of x and c is the constant.
For the equation we have a = 1, b = -8 and c = 16.
We know that the quadratic formula is given by:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]So, the solution of the quadratic equation is:
[tex]\begin{gathered} x=\frac{-(-8)\pm\sqrt[]{(-8)^2-4(1)(16)}}{2(1)} \\ x=\frac{8\pm\sqrt[]{64-64}}{2} \\ x=\frac{8\pm\sqrt[]{0}}{2} \\ x=\frac{8}{2} \\ x=4 \end{gathered}[/tex]Thus, there are two real and equal solutions for the given quadratic equation that is x = 4 and x = 4.
Question is down below Answer choices are the same for each drop down menu.
Given:
The triangles EFG and PQR are given.
To find: The correct answer
Explanation:
a) An angle bisector:
As we know,
An angle bisector is a line or ray that divides an angle into two congruent angles.
Here, The line FJ is the angle bisector for angle F.
Thus, the angle bisector is line FJ.
b) Perpendicular bisector:
As we know,
A perpendicular bisector is a line that bisects another line segment at a right angle, through the intersection point.
Here, the line SL bisects another line segment PQ at a right angle, through the intersection point S.
Thus, the perpendicular bisector is SL.
c) A point is equidistant from the line segment FE and EG:
The point that is equidistant to all sides of a triangle is called the incenter.
Here, H is the point that is equidistant from the line segment FE and EG.
Thus, the point is H only.
d) A point is equidistant from the points P and Q:
The point that is equidistant to all vertices of a triangle is called the circumcenter.
Here, L is the point that is equidistant from the points P and Q.
Thus, the point is L only.
According to the given information, segment AB is parallel to segment DC and segment BC is parallel to segment AD. Construct diagonal A C with a straightedge. It is congruent to itself by the Reflexive Property of Equality. Angles BAC and DCA are congruent by the Alternate Interior Angles Theorem. Angles BCA and DAC are congruent by the same theorem. __________. By CPCTC, opposite sides AB and CD, as well as sides BC and DA, are congruent.
The parallelogram can be redrawn as,
To Prove: The opposite side of the parallelogram are equal.
Given: In the given parallelogram AB is parallel to CD and BC is parallel to AD.
Construction: Diagonal AC is drawn.
Proof:
[tex]\begin{gathered} AC=AC\text{ (Common)} \\ \angle BAC=\angle DCA\text{ (Alternate angles)} \\ \angle BCA=\angle DAC\text{ (Alternate angles)} \\ \Delta ABC\cong\Delta CDA\text{ (ASA)} \\ AB=CD\text{ (CPCT)} \\ BC=DA\text{ (CPCT)} \end{gathered}[/tex]Thus, traingle ABC is congruent to triangle CDA by ASA congruency theorem is the missing information from the paragraph.
the equation of line m is y =9/5x +9. line n is parallel to line m. what is the slope of line n?
the slope for the line n is 9/5
The scatterplot shows the average miles per gallon
versus the age, in years, of cars at a used car dealership.
Fuel Efficiency
Miles per Gallon
35
30
25
20
15
10
5
●
0 1 2 3 4 5 6 7 8 9 10
Age (Years)
Select the most likely value of r for this data set.
O-0.78
O-0.35
O 0.15
O 0.88
Answer:
-0.78
Step-by-step explanation:
The close to 1 or -1 it is the straight the line will be. 0 will be no correlation.
6 hours into minute i want answer of this
Answer: 6 hours into minutes is 360
Step-by-step explanation:
solve the equations and verify the answer
6.6 is value t in of linear equation .
What is linear equation with example?
Ax+By=C represents a two-variable linear equation in its standard form. A standard form linear equation is, for instance, 2x+3y=5. Finding both intercepts of an equation in this format is rather simple (x and y).A linear equation with one variable has the conventional form Ax + B = 0. x is a variable, A is a coefficient, and B is constant in this situation.2t + 3/3 = 3t - 8/2
2( 2t + 3 ) = 3( 3t - 8 )
4t + 6 = 9t - 24
9t - 4t = 9 + 24
5t = 33
t = 33/5
t = 6.6
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Geometric properties of the section are
Answer:
The geometric properties of sections, which are indicators of the structural performance and load resistance capacity of sections, are characterized by the section shape and dimensions, regardless of material properties.
Robert has two more than three times the number of cards that Amanda has which expression represents the number of cards that Robert has
To state the equation that represents the given situation, we take x as the number of cards Amanda has. Three times the number of cards is 3x, two more is +2. It means that the expression that represents this situation is:
[tex]3x+2[/tex]Consider the following graph. Does a graph represent a function? Yes or no?
Concept
A technical definition of a function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
Next
The graph is a function because every input has unique output.
Final answer
It is a function
4. During a long weekend, Devon paid a total of x dollars for a rental car so he could visit his family. He rented the care for 4 days at a rate of $36 per day. There was an additional charge of $0.20 per mile after the first 200 miles.
a. Write an expression to represent the amount Devon paid for additional mileage.
b. Write an expression to represent the number of miles over 200 miles that Devon drove.
c. How many miles overall did Devon drive overall if he paid $174 for the car rental? Show work.
Answer:
A)
c = 0.20m + 144
Where c is total cost and m is miles driven.
B)
c = (200 + 0.20m) + 144
C)
174 = 0.20m + 36x4
174 = 0.20m + 144
30 = 0.20m
30/0.20 = m
m = 150+200
m = 350miles
Hope that helps
How many pairs of parallel edges are there in a rectangular prism
Answer:
A rectangular prism has 3 pairs of congruent parallel faces.
−8(2) +5(2 − 12)+ (−2)(5 −2) +(−3)(3)
Answer:
The answer is -81.
Step-by-step explanation:
Let me know if I got it wrong.