ldentify the location of the values used to create a box
plot.

A=
B=
C=
D=
E=

Answer:

A. Dennis can complete less than 24 questions.

Step-by-step explanation:

Let x represent the remaining number of questions to be completed.  He can complete each of them in 5/2 minutes each; this gives us the expression 5/2x.

He has already spent 10 minutes; this gives us 5/2x+10.

He has less than 70 minutes to spend; this gives us the inequality

5/2x+10<70

Subtract 10 from each side:

5/2x+10-10 < 70-10

5/2x < 60

Divide both sides by 5/2:

5/2x÷5/2 < 60÷5/2

x < 60/1 ÷ 5/2

To divide fractions, flip the second one and multiply:

x < 60/1 × 2/5

x < 120/5

x < 24

Answer:

Dennis can complete fewer than 24 questions.

Step-by-step explanation:

9514 1404 393

Answer:

  x = 6

Step-by-step explanation:

The parallel lines divide the sides proportionally. So, we can write the equation ...

  x/4 = (x +3)/6

  3x = 2(x +3) . . . . . multiply by 12

  x = 6 . . . . . . . . . . . subtract 2x

Answer:

Amish driving buggies and using horses and mules instead of tractors

Step-by-step explanation:

Answer:

a.3.30

Step-by-step explanation:

Answer:

3.30

Step-by-step explanation:

Because I did le Quiz

Answer:

Slope = 7

Y intercept = 23

Step-by-step explanation:

(can I get brainliest now)

Answer:

D

Step-by-step explanation:

Answer:

scalene trangle

Step-by-step explanation:

Answer:

[tex]x = 16[/tex]

Step-by-step explanation:

Given

[tex]log_{16}(x) + log_4(x) + log_2(x) = 7[/tex]

Required

Solve for x

[tex]log_{16}(x) + log_4(x) + log_2(x) = 7[/tex]

Change base of 16 and base of 4 to base 2

[tex]\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7[/tex]

Express 16 and 4 as 2^4 and 2^2 respectively

[tex]\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7[/tex]

The above can be rewritten as:

[tex]\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7[/tex]

[tex]log_22 = 1[/tex]

So, we have:

[tex]\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7[/tex]

[tex]\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7[/tex]

Multiply through by 4

[tex]4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4[/tex]

[tex]log_2(x) + 2}log_2(x) + 4log_2(x) = 28[/tex]

[tex]7log_2(x) = 28[/tex]

Divide through by 7

[tex]\frac{7log_2(x)}{7} = \frac{28}{7}[/tex]

[tex]log_2(x) = 4[/tex]

Apply the following law of logarithm:

If [tex]log_ab = c[/tex] Then [tex]b = a^c[/tex]

So, we have:

[tex]x = 2^4[/tex]

[tex]x = 16[/tex]

Answer:

776

Step-by-step explanation:

Answer:

They are congruent bc they are the same size and shape

Answer:

Congruent by SAS

Step-by-step explanation:

As given by the diagram, we have two congruent sides already. From the set of parallel lines, we see that two angles are congruent because they are corresponding. Luckily, this angle falls between the two congruent sides, which gives you the proof of SAS.

Answer The Greatest Common Factor of 16, 40, 68 is 4. But the GCF of 16s^3t, 40s^5 and 68t^2 is 1, as there are no common terms for these given alphanumeric terms.

Step-by-step explanation:

Answer:

no

Step-by-step explanation:

i copied the person above me :)

sorryyy not sorry lol

#respectfully

Answer:

Step-by-step explanation:

−2 1/6 divided by 1 1/4:

1) to divide that mixed number we'll need to turn it into an improper fraction:

[tex] - 2\frac{1}{6} = - ( \frac{6 \times 2 + 1}{6} ) = - \frac{13}{6} \\ 1 \frac{1}{4} = \frac{4 \times 1 + 1}{4} = \frac{5}{4} [/tex]

2) now let's divide it, reciprocating 1 1/4 and multiplying both fractions one by another:

[tex] - \frac{13}{6} \times \frac{4}{5} = - \frac{52}{30} = - \frac{26}{15} [/tex]

3) Hence the answer is -26/15

Answer:  -6 and 6

Step-by-step explanation:  

Possible factors that could produce 3x² + 6x +3 are  (x + 1)(3x + 3)

the solution for values of x: x+1=0, x= -1  3x+3=0,  3x= -3 . x= -1 . Same.

Possible factors that could produce 3x² - 6x +3 are  (x - 1)(3x - 3)

the solution for values of x: x-1=0, x= 1  3x-3=0,  3x= 3 . x= 1 . Same.

From the attached graph of the possible equations, you can see that 9 and -9 won't produce ONE real solution. They each have "zeros" at two points on the x-axis. That is two solutions that would make x = 0.

The equations with -6 and +6 each touch the x-axis at only one point each.

Answer:

Can you show the pie chart please.

Step-by-step explanation:

Answer:

show pie chart

Step-by-step explanation:

Answer:

190,750 decreased by 9% is 173,582.5

Step-by-step explanation:

Hello.

To find this, divide the cost per amount.

In this case, the cost of the tickets is $27, and the amount is 3.

Divide 27 by 3.

27 / 3 = 9

Each ticket costs $9.

Answer:

$9 per ticket

Step-by-step explanation:

all you do is divide 27 by 3 and get 9

Answer:

5

Step-by-step explanation:

80 divided by 8 = 10 divided by 2 = 5

Answer:

1.5 repeating

Step-by-step explanation:

The equations that are correctly written in standard form are

A. 3/7x + 2y =9

C. 5x – 4y = 9

D. -3x + 7y = 12

From the question, we are to determine which of the given equations are written in standard form

The standard form of a linear equation is Ax + By = C.

Where A, B, and C are constants,

and

x and y are variables

Hence, the equations that are correctly written in standard form are

A. 3/7x + 2y =9

C. 5x – 4y = 9

D. -3x + 7y = 12

Learn more on Standard form of a Linear equations here: https://brainly.com/question/1293412

#SPJ1

Answer:

C

Step-by-step explanation:

I'm pretty sure it's C

Answer:

not sure but b or c because it says less than

Step-by-step explanation:

Answer:

P(A∩B) = 0.12

Step-by-step explanation:

Given:

Students receive financial aid P(A) = 40% = 0.4

Students receive financial aid and first generation P(B/A) = 30% = 0.3

Find:

Probability [Selected student receives financial aid and is first generation college student] P(A∩B)

Computation:

P(A∩B) = P(A) x P(B/A)

P(A∩B) = 0.4 x 0.3

P(A∩B) = 0.12

Answer:

1. y=3x+2

2. slope=3 It represents the rate of which the panda gained weight over the course of 4 weeks

3. 2 It represents the weight of the panda at the first week

Step-by-step explanation:

Answer:

give them all a common denominator

1/3= 2/6

5/6= 5/6

1/2= 3/6

1/6= 1/6

and then use the "new" fraction to order the other ones. but be sure to use the original values, not the ones you made using the GCF. so the answer would be:

1/6, 1/3, 1/2, 5/6

Answer:

-7/10

Step-by-step explanation:

Answer:

you got you must be so Mad rn that I'm not helping you with your question Jiggle what you going to do with that big old behind

Step-by-step explanation:

y-1= ±3/10(x-2)

Im not sure how to get this answer but my teacher gave it to me so i hope this helps!

The equation of the asymptote of the given hyperbola is; y - 1 = ±(3/10)(x - 2)

We are given the equation of the hyperbola as;

[(y - 1)²/9] - [(x - 2)²/100] = 1

We can rewrite this equation as;

[(y - 1)²/3²] - [(x - 2)²/10²] = 1

The general equation form of hyperbola is;

[(y - k)²/a²] - [(x - h)²/b²] = 1

Comparing this general form to our given equation we can see that;

k = 1

h = 2

a = 3

b = 10

Now the equation of the asymptote of a hyperbola follows the general formula;

y = ±[a(x - h)/b] + k

Plugging in the relevant values gives us;

y = ±(3/10)(x - 2) + 1

y - 1 = ±(3/10)(x - 2)

Read more about hyperbola asymptotes at;https://brainly.com/question/12919612

Answer: 2800 dollars in intrest

Step-by-step explanation:

Answer:

3 • 74509

I this is right

Answer:

Sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 is [tex]\mathbf{S_n=\frac{781}{125} }[/tex]

Step-by-step explanation:

We need to find sum of the first five terms of the geometric sequence in which a1=5 and r=1/5

The formula used to find sum of the geometric sequence is: [tex]S_n=\frac{a(r^n-1)}{r-1}[/tex]

Where a is the first term, r is the common ratio and n is the number of terms

Now finding sum of the first five terms of the geometric sequence

We have a=5, r=1/5 and n=5

Putting values in the formula:

[tex]S_n=\frac{a(r^n-1)}{r-1}\\S_n=\frac{5((\frac{1}{5}) ^5-1)}{\frac{1}{5}-1}\\S_n=\frac{5(\frac{1}{3125}-1)}{\frac{1-5}{5}}\\S_n=\frac{5(\frac{1-3125}{3125})}{\frac{-4}{5}}\\S_n=\frac{5(\frac{-3124}{3125})}{\frac{-4}{5}}\\S_n=5(\frac{-3124}{3125})}\times{\frac{-5}{4}}\\S_n=\frac{781}{125}[/tex]

So, sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 is [tex]\mathbf{S_n=\frac{781}{125} }[/tex]