please answer both questions​

Answer:

Solution given:

a.

tn=12-n

1 st term =12-1=11

2nd term =12-2=10

3rd term=12-3=9

4th term=12-4=8

10th term=12-10=2

b.

tn=5-2n

1st term=5-2*1=3

2nd term=5-2*2=1

3rd term=5-2*3=-1

4th term=5-2*4=-3

10th term=5-2*10=-15

(a) Solution

T(n) = 12 - n

T(1) = 12 - 1 = 11

T(2) = 12 - 2 = 10

T(3) = 12 - 3 = 9

T(4) = 12 - 4 = 8

T(10) = 12 - 10 = 2

(b) Solution

T(n) = 5 - 2n

T(1) = 5 - 2 = 3

T(2) = 5 - 4 = 1

T(3) = 5 - 6 = -1

T(4) = 5 - 8 = -3

T(10) = 5 - 20 = -15

Answer:

54.3°

Step-by-step explanation:

sinθ=opposite/hypotenuse

sinθ=26/32

sinθ=0.8125

θ=54.3°

Answer:

the correct answer is option D. 7

Answer:

p-value = 0.0145

Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )

we reject null hypothesis.

Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year

Step-by-step explanation:

Given the data in the question;

Hypothesis;

Null hypothesis             : H₀ : Car accidents are equally distributed throughout the year

Alternative hypothesis : Hₐ : Car accidents are NOT equally distributed throughout the year

significance level ∝ = 0.05

x ;

Spring = 27

Summer = 39

Fall = 31

Winter = 53

Test Statistics;

Chi Square = ∑[ (O – E)²/E ]

                         O               E                   (O – E)²/E

Spring               27            37.4                2.94

Summer            39            37.4                0.06

Fall                    31             37.4                1.1267

Winter               53            37.4                6.4067

Total                 150           150                 10.5334

so; z = ∑[ (O – E)²/E ] = 10.5334

{from table}

p-value = 0.0145

Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )

we reject null hypothesis.

Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year

In this exercise we have to use probability knowledge to calculate the distribution during the year, so we find that:

There is sufficient evidence to conclude that car accidents are not equally distributed throughout the year.

Given the data in the question;

Now the values ​​given in the statement can be exemplified below as:

In this way, we can assemble a table of values ​​with the statistical data previously informed and using the formula given below:

[tex]Z=\sum[\frac{(O-E)^2}{E}][/tex]

[tex]Z = 10.5334[/tex]

So:

[tex]\ \ \ \ \ \ \ \ \ \ \ O \ \ \ \ \ E \ \ \ \ (O - E)^2/E\\Spring \ \ 27 \ \ 37.4 \ \ \ \ 2.94\\Summer \ 39 \ 37.4 \ \ \ \ 0.06\\Fall \ \ \ \ \ \ 31 \ 37.4 \ \ \ \ 1.1267\\Winter \ \ \ 53 \ 37.4 \ \ \ 6.4067\\Total \ 150 150 \ 10.5334[/tex]

Hence, Since pvalue ( 0.0145 ) is less than significance level ( 0.05 ), so we reject null hypothesis.

See more about probability at brainly.com/question/795909

answer:

1393.84

Step-by-step explanation:

since the formula for a square base pyramid is a^2×h/3

we can find out the height for the pyramid by dividing the a^2×h/3 by a^2 =h/3

1568/7^2=32 since 32 = h/3 we multiply by 3 to find the height which = 96

now that we have the height we usee the pathagorean Therom to find the height of one of the face triangles

so 96^2+3.5^2=L^2 so L =96.06

so now that we have all we need

the surface area of the square at the bottom of the pyramid is 7×7

the surface area of the triangles are 96.06 ×7/2 since the area of a triangle is h×b/2

since there are 4 triangles and on square 49+4(96.06×7/2)= 1393.84

Answer:

C

Step-by-step explanation:

I've completed the test before. :)

Answer:

128° because it is corresponding with <4

[tex] < 5 = \: < 3 \\ = \: < 4 \\ < 5 = 128 \degree[/tex]

Answer:

Step-by-step explanation:

( x - 1 )2 + ( y + 3 )2 = 90

Answer:wpeleoe

Step-by-step explanation:

The value of x is 7.

A triangle is a three-sided polygon that consists of three edges and three vertices.

The two triangles PQR and P'Q'R' are similar triangles

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .

Firstly let us find the P'Q' by using pythagoras theorem

R'Q'²=PR'²+P'Q'²

12²=10²+P'Q'²

144-100=P'Q'²

44=P'Q'²

P'Q'=6.6

The value of PR is x

The value of x is 7. as R it is a midpoint of P'Q'R'

Hence the value of x is 7

To learn more on Triangles click:

https://brainly.com/question/2773823

#SPJ2

Answer:

1/3

Step-by-step explanation:

Hope this is useful even though there isn't any working

Answer:

Step-by-step explanation:

A = P(1+r/n)^ nt

A = 2000(1+.04/2)^(5*2)

A = [tex]2000(1.02)^{10}[/tex] = $2437.99

Answer:

D (The square root property should have been applied to both complete sides of the equation instead of to select variables)

Step-by-step explanation:

On edge 2021

Answer:

bugo.ka pag answer bobo ka bah ha wag kanang umasa dito piste ka

Answer:

total of the data points = 1200

Step-by-step explanation:

The 'average' of a data set is the total of the data points divided by the number of data points.

Here:

total of the data points

---------------------------------- = 48

                 25

Multiplying both sides of this equation by 25 yields:

total of the data points = 1200

Answer:

3179cm^3

Step-by-step explanation:

[tex]volum = height × width × length \\ = 17cm \times 17cm \times 11cm \\ = {3179cm}^{3} [/tex]

Answer:

[tex]P(A_1\ n\ A_2) = 0.40[/tex]

Step-by-step explanation:

Let:

[tex]A_1 \to[/tex] An Individual likes vehicle 1

[tex]A_2 \to[/tex] An Individual like vehicle 2

[tex]P(A_1) = 0.55[/tex]

[tex]P(A_2) = 0.65[/tex]

[tex]P (A_1\ u\ A_2 ) = 0.80[/tex]

Required

[tex]P(A_1\ n\ A_2)[/tex] --- probability that both vehicles are liked by the individual.

This is calculated as:

[tex]P(A_1\ n\ A_2) = P(A_1) + P(A_2) - P(A_1\ u\ A_2)[/tex]

So, we have:

[tex]P(A_1\ n\ A_2) = 0.55 + 0.65 - 0.80[/tex]

[tex]P(A_1\ n\ A_2) = 0.40[/tex]

Answer: you can buy 6apples for$1

Step-by-step explanation: you divide 36 by 6 and get 6 so it’s 6apples.

Answer:

[tex]m {}^{2} - 100 = - 99[/tex]

Step-by-step explanation:

Set up the binomial.

[tex](m - 10)[/tex]

[tex](m + 10)[/tex]

Multiply the binomial.

[tex](m - 10)(m + 10) = - 99[/tex]

Apply difference of squares rule

[tex](p + q)(p - q) = p {}^{2} - q {}^{2} [/tex]

[tex]m {}^{2} - 100 = - 99[/tex]

Answer: m^2-100=-99

Step-by-step explanation:

Set up the binomial.

(m-10)

(m+10)

Multiply the binomial.

(m-10)(m+10)=-99

Apply difference of squares rule

(p+q)(p-q) = p2-q2

Answer: m^2-100=-99

Answer:

Surface area add together all 6 sides = 24+36+108=168m^2

Volume L x W x D = 2 x 6 x 9 = 108 m ^3

Step-by-step explanation:

2 x 6 = 12

12 x 2 = 24 base and top

2 x 9 = 18

2 x 18 = 36 identical pair sides

6 x 9 = 54

2 x 54 = 108 identical pair sides

Surface area add together all 6 sides = 24+36+108=168m^2

Volume L x W x D = 2 x 6 x 9 = 108 m ^3

Answer:

2821.51

73425.64

28124.24

4124.24

Step-by-step explanation:

Effective rate: .058/2 = .029

This question is kind of ambigous and I'll make the assumption that there is no payment at time 0

[tex]175000=x\frac{(1+.029)^{2*18}-1}{.029}\\x=2821.511[/tex]

interested earned:

175000-2821.51*36= 73425.64

2.)

Same assumption as question 1 (there is no payment at time 0)

effective rate: .063/12= .00525

[tex]400(\frac{(1+.00525)^{60}-1}{.00525})=28124.24[/tex]

Interest earned: 28124-400*60=4124.24

Answer:

First problem: monthly payment $2741.99; interest earned $76,288.36

Second problem: amount in account $28,271.90; interest earned $4271.90

Step-by-step explanation:

First problem:

You open an account with a deposit. The deposit is the first monthly payment. This means that this is an annuity in which you pay at the beginning of the pay period. That makes it into an "annuity due."

[tex] A = \dfrac{F}{\frac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

where A = periodic payment,

F = future value

i = interest rate per compounding period, n = number of compounding periods

[tex]A = \dfrac{175000}{\frac{(1 + \frac{0.058}{2})^{2 \times 18} - 1}{\frac{0.058}{2}} \times (1 + \frac{0.058}{2})}[/tex]

[tex] A = 2741.99 [/tex]

Interest earned:

[tex] 2 \times 18 \times 2741.99 - 175000 = 76288.36 [/tex]

Second problem:

Once again, the account starts with a deposit of the monthly payment, so this is also an annuity due, meaning the payments occur at the beginning of each compounding period. Here, we are given the monthly payment, an d we need to find the future value.

[tex] F = A \times \dfrac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

[tex] F = 400 \times \dfrac{(1 + \frac{0.063}{12})^{5 \times 12} - 1}{\frac{0.063}{12}} \times (1 + \frac{0.063}{12})} [/tex]

[tex] F = 28271.90 [/tex]

The interest earned is:

[tex] 28271.90 - 12 \times 5 \times 400 = 4271.90 [/tex]

Answer:

Step-by-step explanation:

y is the remote exterior angle. The remote exterior angle has the strange property that it is equal to the two remote interior angle. The two remote interior angles are the two, neither of which is the supplement of the exterior angle

So y = x/2 + x/2 which are marked as being opposite equal angles.

1/2 x + 1/2 x = x

y by substitution is = x /2 + x/2

y = x

Answer:

Root         Multiplicity

 -4                    2

 -1                     2

  2                     1

   5                    3

---------------------------

y = a(x + 4)²(x + 1)²(x - 2)(x - 5)³

find "a" using point (0, 20000)

20000 = a(0 + 4)²(0 + 1)² (0 - 2)(0 - 5)³

20000 = a(16)(1)(-2)(-125)

20000 = a (4000)

a = 20000/4000

a = 5

y = 5(x + 4)²(x + 1)²(x - 2)(x - 5)³

Answer:

-2

Step-by-step explanation:

range is y values

Answer:

-2

Step-by-step explanation:

That's the minimum range, which is basically the lowest point on the y-axis that the line touches

Answer:

option 3

Step-by-step explanation:

ORIGINAL                REFLECTED

A = ( 2, 0)                    A' = (-2, 0)

B = (5 , 0)                    B' = (-5, 0)

C = (5, -2)                    C' = (-5, -2)

D = (2, -2)                    D' = (-2, -2)

Answer:

The student is comparing the different heart rates due to the temperature. The independent variable is the Temperature and the dependent variable is the beats of the heart from the larva.