see the picture please!!

Answer:

good luck

Step-by-step explanation:

you will get answers after some time

Answer:

base 48

width 8 and length 6

pls brainliest. should work and you get points back

Yes I can help you. what do you want the help for?

Answer:

AOB = 65 degree angle

DOE = 35 degree angle

AOC = 90 degree angle

EOB = 115 degree angle

DOB = 80 degree angle

Step-by-step explanation:

Use the protractor to measure. Each dash around the edge is equal to 5 degrees.

Answer:Ping Pong Balls

Step-by-step explanation:

Answer:

answer a and d

Step-by-step explanation:

one thing i could say it would not be C because if it were symetric, i already see 2 lines that are not symetrical in anyway

sure the graph could extend to infinity and negative infinity and if you see the right arrow, it is pointing down-wards, so if it goes bellow 0, point (0,0) would not be your expected number to see as the minimum

and between -1 and 1, yes, we can already see that the line from -1 and 1 is exponentially increasing

Answer:

C

Step-by-step explanation:

correct me if iam wrong

Answer:

B

Step-by-step explanation:

Have a nice day :)

Answer:

Fewer students are between 44 and 52 inches than between 52 and 60 inches in height.

Step-by-step explanation:

Given

See attachment for histogram

Required

Select the true statement

Option A: Class 46-50 = 12 students

From the histogram, we have:'

[tex]Class\ 46 - 48 = 8; Class\ 48 - 50 = 3[/tex]

So:

[tex]Class\ 46 - 48 = Class\ 46 - 48 + Class\ 48 - 50[/tex]

[tex]Class\ 46 - 48 = 8+ 3[/tex]

[tex]Class\ 46 - 48 = 11[/tex]

(a) is false

Option B: %Class 52-54 = 18%

From the histogram, we have:'

[tex]Class\ 52-54 = 18[/tex]

and

[tex]Total = 53[/tex]

So, the percentage is:

[tex]\% Class\ 52-54 = \frac{Class\ 52-54}{Total}[/tex]

[tex]\% Class\ 52-54 = \frac{18}{53}[/tex]

[tex]\% Class\ 52-54 = 0.3396[/tex]

Express as percentage:

[tex]\% Class\ 52-54 = 33.96\%[/tex]

(b) is false

Option C: Class 54-60 > Class 46 - 50 students

From the histogram, we have:'

[tex]Class\ 54-60 =Class\ 54-56 + Class\ 56-58 + Class\ 58-60[/tex]

[tex]Class\ 54-60 = 4 + 4+3[/tex]

[tex]Class\ 54-60 = 11[/tex]

In (a), we have:

[tex]Class\ 46 - 48 = 11[/tex]

By comparison:

[tex]Class\ 54-60 =Class\ 46 - 48 = 11[/tex]

(c) is false

Option D: Class 44-52 < Class 52 - 60 students

From the histogram, we have:'

[tex]Class\ 44-52 =Class\ 44-56 + Class\ 46-48 + Class\ 48-50 +Class\ 50-52[/tex]

[tex]Class\ 44-52 = 4+8+3+9[/tex]

[tex]Class\ 44-52 = 24[/tex]

[tex]Class\ 52-60 =Class\ 52 - 54 + Class\ 54-56 + Class\ 56-58 + Class\ 58-60[/tex]

[tex]Class\ 52-60 = 18+ 4 + 4+3[/tex]

[tex]Class\ 52-60 = 29[/tex]

By comparison:

[tex]24 < 29[/tex]

i.e.

[tex]Class\ 44 - 55 < Class\ 52 - 60[/tex]

(d) is true

Answer:

720 degrees

Step-by-step explanation:

sum of interior angles of any polygon is given by the equation

[tex]sum \: = (n - 2) \times 180[/tex]

where n is the number of sides of the polygon. in the question the polygon has 6 sides. hence n = 6 and

[tex]sum \: = (6 - 2) \times 180 \\ = 4 \times 180 \\ = 720 \: degrees[/tex]

Answer:

Step-by-step explanation:

37

Answer:

 40

Step-by-step explanation:

you mutiply then take away the 2 last digits

Answer:

Step-by-step explanation:

0.6*3t+0.8*4t=75

so t=15

apple=3t=45

orange=4t=60

Answer:

The answers for your question is 0.17

Answer:alternate exterior angles

Step-by-step explanation:

Since they’re on the outside of the parallel lines that makes them exterior

Answer:

17t+6q-6

Step-by-step explanation:

18t -t +6q-6​

Combine like terms

17t+6q-6

Answer:

17t+6q-6

Step-by-step explanation:

18t-t =17t

others don't change as they are not the factors of the same character

Answer:

[tex] \frac{7}{4} - \frac{3}{4} = \frac{4}{4} [/tex]

Step-by-step explanation:

To find the number midway between 3/2 and 4/2, add them up and divide by 2

we have, 3/2 + 4/2 = 7/2

7/2 ÷ 2 = 7/4

Repeat the same for the number midway between 1/2 and 2/2 to get 3/4

The answer then is, 7/4 - 3/4 = 4/4

Answer:

2x -3y =1 and 3x-2y= 4 has

Step-by-step explanation:

The pair of linear equations 2x-3y=1 and 3x-2y=4 has one unique solution. , then it has a unique solution other wise not. Since , , it means the pair of linear equations has only one unique solution. Hence, the pair of linear equations 2x-3y=1 and 3x-2y=4 has only one unique solution.

a1/a2= 2/3

b1/b2= 3/-2 (-) cancle so it remains

c1 / c2 = 1/4

a1/a2 = b1/b2 not equal to c1/c2 as no solution

y=-3x+9

explanation

m=-3 (X1,Y1) = (4,-3)

(y-y1)= m×(x-x1)

(y-(-3))=-3(x-4)

y+3= -3x+12

y=-3x+12-3

y=-3x+9

Answer:

57.4

Step-by-step explanation:

82.4 - 25 is too easy, a calculator can solve this.

Answer:

12m

7m

2520 m³

Step-by-step explanation:

Answer:

h=7m

top width=12m

v=l*w*h

=28*12*10=3360

volume of the top=3*20*12

720

v of the shape is= 3360-720

=2649

Answer:

0.5

Step-by-step explanation:

Answer:

.5

Step-by-step explanation:

calculator

Answer:

Invested at 11% : 3100

Invested at 6% : 3200

Step-by-step explanation:

let x= amount invested at 11%

let y= amount invested at 6%

we can write

Equation 1: x+y=6300

Equation2: .11x+.06y=533

Divide equation 2 by .06 to get

1.8333333x+y=8883.33333333

Subtract equation 2 from equation 1

.8333333x= 2583.33333333

x= 3100

Plug in x= 3100 into equation 1

3100+y= 6300

y= 3200

Answer:

using brainly

Step-by-step explanation:

Answer:

waking up everyday and listening to them fuss about calling home even though im already home

Answer:

The claim is false.

Step-by-step explanation:

Given the data :

13 24 21 37 15 25 18 22 40 32

The sample mean and standard deviation can ben calculated for the given sample.

Using calculator :

Sample mean, xbar = 24.7

Sample standard deviation, s = 9.04

Sample size, n = 10

The hypothesis :

H0 : μ = 17

H1 : μ ≠ 17

The test statistic :

(xbar - μ) ÷ (s/√(n))

(24.7 - 17) ÷ (9.04/√(10))

7.7 / 2.8586990

Test statistic = 2.694

We can obtain the Pvalue, at α = 0.05 ; df = n-1 = 9

Pvalue = 0.0246

Since Pvalue < α ; we reject the null ; Hence, there is significant evidence to conclude that an adult American does not spend average of 17 hours in leisure

Answer:

3/8 cup

Step-by-step explanation:

Dog : 3/4 cup

Cat: 1/2 (Dog) = 1/2 (3/4 cup) = 3/8 cup

Hope this helps!!!

Have a great day!!!

Answer:

24

Step-by-step explanation:

The LCM of 8 and 12 is 24. Find least common multiple (LCM) of: 16 & 24 4 & 6 24 & 36 40 & 60 56 & 84 16 & 12 8 & 24 24 & 12 8 & 36 40 & 12 8 & 60 56 & 12 8 & 84

Answer:

10 / 12

simplified:

5/6

since 5 is a prime number, we can't simplify this ratio any further

Answer:

x = y - 6

Step-by-step explanation:

y = x + 6 (Given)

y - 6 = x (Subtracted 6 on both sides)

Answer:

a) 0.4856 = 48.56% probability that the total weight is greater than 190 lbs.

b) A total weight of 155.9 lbs.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 188.6 lbs. and a standard deviation of 38.9 lbs.

This means that [tex]\mu = 188.6, \sigma = 38.9[/etx]

21 lbs of baggage are taken into consideration in this estimate.

a.) If one adult male is randomly selected and is assumed to be also carrying 21 lbs. due to clothing and baggage, find the probability that the total weight is greater than 190 lbs.

This is 1 subtracted by the the p-value of Z = 190. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{190 - 188.6}{38.9}[/tex]

[tex]Z = 0.036[/tex]

[tex]Z = 0.036[/tex] has a p-value of 0.5144.

1 - 0.5144 = 0.4856.

0.4856 = 48.56% probability that the total weight is greater than 190 lbs.

b.) What total weight would separate the lower 20% of men carrying 21 lbs. of clothing and baggage from the top 80%?

This is the 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.84 = \frac{X - 188.6}{38.9}[/tex]

[tex]X - 188.6 = -0.84*38.9[/tex]

[tex]X = 155.9[/tex]

A total weight of 155.9 lbs.