Solve x^2+14x=15 by completing the square.

Answer:

a) Brain sweep out 4 radians

b) Brian is -0.3922 km to the right of the center of the ski trail

c) Brian is -0.4541 km above of the center of the ski trail

Step-by-step explanation:

Given the data in the question;

circular ski trail radius = 0.6 km

Derek starts at the 3-o'clock position and travels 2.4 km in the counter-clockwise direction.

a) How many radians does Brian sweep out?

arc length = 2.4 km

from the diagram;

arc length = rθ

θ = arc length / r

θ = 2.4 / 0.6

θ = 4 radians

Therefore, Brain sweep out 4 radians

b) When Brian stops skiing, how many km is Brian to the right of the center of the ski trail?

from the diagram;

x = rcosθ

we substitute

x = 0.6 × cos(4)

x = 0.6 × -0.65364

x = -0.3922 km

Therefore Brian is -0.3922 km to the right of the center of the ski trail

c) When Brian stops skiing, how many km is Brian above of the center of the ski trail?

from the diagram;

m = rsinθ

m = 0.6 × -0.7568

m = -0.4541 km

Therefore, Brian is -0.4541 km above of the center of the ski trail

Answer:

B

Step-by-step explanation:

792 is a bigger number than 456

Answer: B

Step-by-step explanation: 792 is larger than 456

Answer:

7.8 feet

Step-by-step explanation:

We can determine the Horizontal distance using trigonometry ;

Using the relation :

Cosθ = adjacent / hypotenus

Cos 61 = x / 16

x = cos 61 * 16

x = 0.4848096 * 16

x = 7.756

x = 7. 8 feet

Answer: it’s a triangle

Step-by-step explanation:

Answer:

triangle

Step-by-step explanation:

Answer:

2.4

Step-by-step explanation:

i saw the answeres

Answer:

B. 80°

Step-by-step explanation:

55+45=100

180-100=80

Q=80°

Answer:

250

Step-by-step explanation:

85% · n = 212.5

[convert 85% to .85]

.85n = 212.5

n = 212.5/.85

n = 250

Answer:

Yes, you can use cross products to solve for x in this proportion. Also, x is 360.

Step-by-step explanation:

Yes, you can use cross products to solve for x in that proportion.

Here's how you do it :

[tex]\frac{18}{5} = \frac{x}{100}[/tex]

We cross product, getting :

18 * 100 = 5 * x

1800 = 5x

Divide by 5 on both sides to get x by itself.

360 = x

Yes, you can use cross products to solve for x in this proportion. Also, x is 360.

Hope this helps, please mark brainliest if possible. Have a great day.

Hope this help!!!

Have a nice day!!!

Answer:

The answer is 16

Step-by-step explanation:

Hi there!

The angles shown are supplementary

Supplementary angles have a measure of 90 degrees

This means that 3x + 5 + 37 = 90

3x + 5 + 37 = 90

Combine like terms

3x + 42 = 90

Take away 42 from each side

3x = 48

Divide by 3

x = 16

Hope this helps! :)

Answer:

O B) 16

Step-by-step explanation:

90° (total) - 37° = 53°

(3x+5) = 53°

(3x-5)  = -5°         Subtract 5 from both sides!

3x = 48               Solve

x = 16

9514 1404 393

Answer:

  8

Step-by-step explanation:

The number of servings can be found by dividing the quantity available by the amount per serving.

  (6 cups)/(3/4 cup/serving) = (6)(4/3) servings = 8 servings

Answer:

12000

Step-by-step explanation:

Done

Answer:

12000 lbs

Step-by-step explanation:

configuration for tons to pounds is by multiplying the tons by 2000 lbs

1 ton = 2000 lbs

6 ton= ?

6 ton x 2000 lbs = 12000 lbs

Given:

The table of values of the function f(x).

To find:

How much greater is the average rate of change over the interval [5, 7] than the interval [2, 4]?

Solution:

The average rate of change of a function f(x) over the interval [a,b] is:

[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]

The average rate of change over the interval [5, 7] is:

[tex]m_1=\dfrac{f(7)-f(5)}{7-5}[/tex]

[tex]m_1=\dfrac{5002-3452}{2}[/tex]

[tex]m_1=\dfrac{1550}{2}[/tex]

[tex]m_1=775[/tex]

The average rate of change over the interval [2,4] is:

[tex]m_2=\dfrac{f(4)-f(2)}{4-2}[/tex]

[tex]m_2=\dfrac{1048-230}{2}[/tex]

[tex]m_2=\dfrac{818}{2}[/tex]

[tex]m_2=409[/tex]

The difference between the average rate of change over the interval [5, 7] and the interval [2, 4] is:

[tex]Difference=m_1-m_2[/tex]

[tex]Difference=775-409[/tex]

[tex]Difference=366[/tex]

Therefore, the average rate of change over the interval [5, 7] is 366 more than the interval [2, 4].

Answer:

366

Step-by-step explanation:

I took the test lol

Answer:

tn = 8n -7

Step-by-step explanation:

given : t2=9, t4=25

the formula is:

tn = t1 + (n-1) d

gonna find d first:

d = (25-9) /(4-2) = 16/2 = 8

and find tn1:

t1 = 9-8 = 1

so, tn = 1 + (n-1) (8) = 1 +8n -8

tn = 8n -7

Answer:

Solution given

n th term[tn]=?

1st term =a

difference =d

we have

t2=9

a+(n-1)d=9

a+(2-1)d=9

a+d=9

a=9-d..................[1]

again

t4=25

a+(n-1)d=25

a+(4-1)d=25

now

substituting value of a

9-d+3d=25

2d=25-9

d=16/2

d=8

substituting value of d in equation 1.

,a=9-8

a=1

we have

tn term =a+(n-1)d=1+(n-1)8=1+8n-8=8n-7

n th term =8n-7

Step-by-step explanation:

c is an upside down parabola but it is not wide, it is very then so maybe e?

Answer:

here u go

Step-by-step explanation:

1.  Given -- that's pretty much always the first step

2. LN=NW, SN=NK.     That's the Definition of Midpoint.

3. angle LNS=WNK.   That's the Vertical Angles Theorem - vertical angles are congruent.

4. Triangle LNS=WNK.  That's SAS, side-angle-side congruence.

Answer:

It should be 33 degrees!

Step-by-step explanation:

This can be found out when we realize that all complimentary degrees add up to 90!

Answer:

33 degrees

Step-by-step explanation:

Answer:

75.6

Step-by-step explanation

HOPE I HELPED ;)

Answer:

x = 22

y = 6

Step-by-step explanation:

GIVEN :-

TO FIND :-

GENERAL CONCEPT TO BE USED IN THIS QUESTION :-

SOLUTION :-

In the figure given in the question , ∠FBE & ∠FBD are linear pair.

⇒ (3x - 2)° + (5x + 6)° = 180°

⇒ 8x + 4 = 180

⇒ 8x = 176

⇒ x = 22°

Also , AB⊥CF.

⇒ ∠ABE & ∠FBE are complementary angles.

⇒ (4y + 2)° + (3x - 2)° = 90°

⇒ 4y + (3×22) = 90   [∵ Putting x = 23]

⇒ 4y + 66 = 90

⇒ 4y = 24

⇒ y = 6

Answer:

[tex]x^{2} + 2x - 1[/tex]

Step-by-step explanation:

We are solving for :

[tex]\frac{x^{3}+ 5x^{2} + 5x - 3 }{x + 3}[/tex]

Factor [tex]x^{3} + 5x^{2} + 5x - 3 : (x + 3)(x^{2} + 2x - 1)[/tex]

[tex]\frac{(x + 3)(x^{2} + 2x - 1)}{x + 3}[/tex]

= [tex]x^{2} + 2x - 1[/tex]

Answer:

40     Right Angle Triangle

Step-by-step explanation:

180-50-90=x

x=40

Right angle triangle

Answer:

40

Step-by-step explanation:

90 + 50 = 140

A triange = 180

A right angle(aka the square) = 90

180 - 140 = 40

x = 40

Answer:

A; 120 cubic inches

Step-by-step explanation:

Let us start with the formula of the volume of a rectangular prism,[tex]V=l*w*h[/tex], where l represents the length of the prism, w represents the width of the prism, and h represents the height of the prism. It is given to us that h =5 inches, w =3 inches, and l =8 inches. Let's plug the values in:

[tex]V= 8*3*5\\V=120[/tex]

A. The volume of the rectangular prism is 120 cubic inches.

I hope this helps! Let me know if you have any questions :)

Answer:

f(x)=7x+11

Step-by-step explanation:

15-4-7x= 7x+11. Sp y or f(x)= 7x+11

Answer:

[tex]\begin{array}{ccc}{Industry} & {Frequency} & {RF}& {Bank} & {26} & {13\%}& {Cable} & {44} &{22\%} & {Car} & {42} & {21\%} &{Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} &{Total} & {200} & {100\%}\ \end{array}[/tex]

Step-by-step explanation:

Given

[tex]n =200[/tex]

[tex]Bank = 26; Cable = 44; Car = 42; Cell = 60; Collection = 28[/tex]

Required

The frequency relative frequency table

The frequency table is as follows:

[tex]\begin{array}{cc}{Industry} & {Frequency} & {Bank} & {26} & {Cable} & {44} & {Car} & {42} & {Cell} & {60} & {Collection} & {28} & {Total} & {200} \ \end{array}[/tex]

Relative frequency (RF) is calculated using:'

[tex]RF = \frac{Frequency}{Total} * 100\%[/tex]

So, we have:

[tex]Bank = \frac{26}{200} * 100\% = 13\%[/tex]

[tex]Cable = \frac{44}{200} * 100\% = 22\%[/tex]

[tex]Car = \frac{42}{200} * 100\% = 21\%[/tex]

[tex]Cell = \frac{60}{200} * 100\% = 30\%[/tex]

[tex]Collection = \frac{28}{200} * 100\% = 14\%[/tex]

So, we have:

[tex]\begin{array}{ccc}{Industry} & {Frequency} & {RF}& {Bank} & {26} & {13\%}& {Cable} & {44} &{22\%} & {Car} & {42} & {21\%} &{Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} &{Total} & {200} & {100\%}\ \end{array}[/tex]