What test may be used to determine if a stain is a blood or not?
Answer:
Kastle-Meyer Color Test is used to determine if a stain is blood or not.
Explanation:
In three to five sentences, explain how you would conduct an experiment to investigate the relationship between the applied force and the displacement of the spring, and describe its expected results.
Hooke's law states that the applied force F equals a constant k times the displacement or change in length x.
What is Hooke's law?
The force necessary to extend or compress a spring by a certain distance scales linearly with respect to that distance, according to Hooke's law, an empirical law in physics.
Hooke's Law is a principle of physics that states that the that the force needed to extend or compress a spring by some distance.
F = K.x
A straight line passing through the origin can be drawn by plotting the spring's stretch versus the weight that has been applied to the hanger. This implies that a spring's extension is inversely proportional to the force used to stretch it.
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Which of the following is a reason that the interior of the Earth is HOT?
there will be an image below but if you dont already know, dont answer.
The option that is a reason that the interior of the Earth is hot is option C: Leftover heat from formation.
Which of the following is a reason that the interior of the Earth is hot?The heat from when the planet formed and the heat from radioactive element decay are the two main causes of the extremely heated interior of Earth.
Note that the Earth's interior is warm because the accretion process, which created Earth, produced a lot of heat. Through the course of geologic time, radioactive decay of unstable isotopes has supplied more heat (heat is a byproduct of the decay process). Only the outer core is heated enough to be above the melting point for material of that composition under that level of pressure, making molten rock or magma extremely uncommon in the interior of the earth.
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what is the power of 600 joules of work done in 4 seconds?responses 150 watts 150 watts 240 watts 240 watts 600 watts 600 watts 2,400 watts
150 Watts is the power of 600 J of work completed in 4 seconds.
The rate at which work is completed is referred to as power. It has the following mathematical expression:
[tex]Power = work/time[/tex]
The power can be obtained using the above formula.
From the mentioned query, the following information was observed:
Work = 600 J
Time = 4 s
Power =?
[tex]Power = Work/Time \\Power = 600/4[/tex]
power = 150 watts
Thus, 150 Watts are generated by 600 J of work completed in 4 seconds.
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A) assume the object moves with a constant acceleration as it rolls down the incline. write an equation that includes acceleration and quantities that can be measured or obtained from measurements by using the available equipment in the list.
1 point for an equation that includes acceleration and is conceptually relevant to the procedure described in part b.
1 part is earned for stating or implying that the initial speed of the object is 0 when released from the top of the incline.
example response: x = 1/2 at^2
The acceleration of a sphere on an inclined plane can be analyzed to a first approximation ignoring frictional forces. In this case without rotation, the sphere has no torque to rotate so it just slides down the slope with an acceleration of a = g sin θ. The greater the angle, the greater the acceleration of the object. The description for this refers to the component we drew.
As the angle increases the force component parallel to the slope increases, and the force component perpendicular to the slope decreases. Acceleration is the change in velocity divided by the change in time. A car traveling freely up and down a ramp has constant acceleration. The object then accelerates down the inclined surface due to the presence of an unbalanced force. The parallel component of gravity causes this acceleration.
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True or false Condensation occurs with the removal of thermal energy.
true. condensation is when gas converts to liquid. the molecules move slower because of a loss of thermal energy, so it forms liquid
if a radioactive isotope emits 6000 alpha particles in 10 minutes, what is its activity in bequerels?
The radioactivity of the isotope in becquerels is 10 decay/s.
What is radioactivity?
Radioactivity is a phenomenon exhibited by radioactive elements or isotopes by emitting energy and subatomic particles spontaneously.
The radioactivity of a radioactive element or isotope in becquerels is denoted by decay per second.
The radioactivity of the isotope in becquerels is calculated as follows;
Bq = decay / time
decay = 6000 alpha particlestime = 10 minutes = 10 mins x 60 s/min = 600 secondsBq = 6000 / 600
Bq = 10 decay/s
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what is gravitational potential and what is the formula for it
Here is defination of gravitational potential.
gravitational potential energy is the energy possessed or acquired by a object due to a change in it position when it is present in a gravitational is field. In the simple term it can be said to that energy is an gravitatonal potential energy that is related to gravitational force or to gravity.
Formula -
The equation for gravitational potential energy is-
⇒ GPE = m⋅g⋅h
Where-
m is the mass in kilograms of
g is the acceleration due to the gravity (9.8 on Earth)
h is the height above the ground in meter.
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Ask Tutor a question about your assignment
The current in each branch of the circuit is 9.5 A and 0 A.
Point B, according to Kirchoff's junction law equation is
i = i₁ + i₂ ......equation 1
Now, according to Kirchoff's Loop law,
Loop 2 is anticlockwise, calculates the current i₂ equation is
21.4 - 50i₂ - 6 - i - 100i₂ = 0
150i₂ + i = 15.4 ......equation 2
Loop 1 is clockwise, calculates the current i₁ equation is
20.5 - 30i₁ - 6 - i - 40i₁ - i₁ = 0
80i₁ + i = 14.5 ........equation 3
substitute equation 1 in equation 3 for the value of i,
81i - 80i₂ = 14.5 .....equation 3
Upon, subtracting equation 3 from equation 2, we get i₂ = 9.5 A
substituting the value of i₂ in equation 3, we get i = 9.5A
Hence on substituting value for i₁, in equation 1 , we get i₁ = 0 A
Hence, the current in each branch of the circuit is 9.5A, 9.5A, 0A
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How is a mitochondria and a generator alike
All human cells contain mitochondria, which function as the cell's main "power generator" by transforming energy from food into a form the cell can use. Mitochondria are found in the cytoplasm of all human cells.
How do a generator and a mitochondria compare?
A little DNA strand that functions as a second human genome is also present in them. Additionally, they have a small DNA strand that functions as an additional human genome. Nutrients get into the bloodstream after being broken down.The nutrients can be utilized as fuel or raw materials.Adenosine triphosphate, or ATP, is the major energy source for all of our cells and it is produced by the mitochondria.Our cells include tiny organelles called mitochondria.Consider them the cell's energy producers.The Krebs Cycle, also known as the citric acid cycle, is a mechanism by which mitochondria make ATP, which is used by all cells for energy.Although ATP only exists in minute amounts in each cell, the body can use its entire weight in ATP every day due to its importance as an energy source.Oxygen is the second important component in the process because mitochondria use oxidation (also known as cellular respiration) to produce the energy cells need to function.We need to breathe in order to replenish our bodies' oxygen supply and exhale in order to get rid of carbon dioxide, which is a byproduct of oxidation, because it is produced during the process of cellular respiration. Although ATP only exists in minute amounts in each cell, the body can use its entire weight in ATP every day due to its importance as an energy source.Oxygen is the second important component in the process because mitochondria use oxidation (also known as cellular respiration) to produce the energy cells need to function.We need to breathe in order to replenish our bodies' oxygen supply and exhale in order to get rid of carbon dioxide, which is a byproduct of oxidation, because it is produced during the process of cellular respiration.
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5.12 ** consider a simple harmonic oscillator with period r. let ( f ) denote the average value of any variable f (t), averaged over one complete cycle: 1 f (f)
considering simple harmonic oscillator with period r E=1/2mw²A² , T= 1/4mw²A² V = 1/4mw²A² therefore T=V=E/2.
A model with numerous significant applications in both conventional and quantum mechanics is the harmonic oscillator. It acts as a model for the mathematical analysis of a wide range of phenomena, including elasticity, acoustics, AC circuits, molecular and crystal vibrations, electromagnetic fields, and the optical characteristics of matter. A body is referred to be a linear harmonic oscillator or a simple harmonic oscillator when it oscillates about its location along a linear straight line under the influence of a force that is directed towards the mean location and is proportionate to the displacement at any moment from this location. Periodic motion is best demonstrated by this type of oscillation. The period is completely independent of the initial displacement from equilibrium (amplitude of oscillation). The period is unaffected by how far the cart is moved from its equilibrium location. the greatest displacement from the mean position, is the angular speed of the body rotating around in a circle, and t is the duration.
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1. An object has a velocity of 3 m/s and a mass of 12 kg.
What is its momentum?
Answer:
Calculate its momentum. Solution:
Given,
Mass of an object (m)=12kg
Velocity (v)=3m/s
then,
p=36kg m/s
Explanation:
while finding momentum ,we should use the formula p=mv
Q2. A stone leaves a slingshot horizontally with an initial speed of 15.2 m/s from a
height 1.1 m above the ground. Determine the stone's:
a) total air time
b) maximum height
c) range
d) final velocity
Horizontal
VX =
dx = ?
t = ?
Vertical
dy = -1.1m
v1y =
v2y= ?
a =
t = ?
Answer:
Assume that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex]. Also assume that that the air resistance on this stone is negligible.
The total air time of this stone is approximately [tex]1.5\; {\rm s}[/tex].
The maximum height of this stone is [tex]1.1\; {\rm m}[/tex], same as the height of the slingshot.
The range of this stone is approximately [tex]23\; {\rm m}[/tex].
The final velocity of this stone is approximately [tex]21\; {\rm m \cdot s^{-1}}[/tex].
Explanation:
If the air resistance on this stone is negligible, this stone will accelerate towards the ground with a vertical acceleration [tex]a_{y}[/tex] of [tex]a_{y} = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].
At the same time, the horizontal velocity [tex]v_{x}[/tex] of this stone will stay the same during the entire flight: [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex].
The stone was launched from a height of [tex]1.1\; {\rm m}[/tex] above the ground. Therefore, the vertical displacement [tex]x_{y}[/tex] of the stone will be [tex]x_{y} = (-1.1)\; {\rm m}[/tex] when the stone hits the ground.
The initial vertical velocity [tex]u_{y}[/tex] of this stone would be [tex]u_{y} = 0\; {\rm m\cdot s^{-1}}[/tex] since the stone was launched horizontally.
Let [tex]v_{y}[/tex] denote the final vertical velocity of this stone right before landing. Apply the SUVAT equation [tex](v_{y})^{2} - (u_{y})^{2} = 2\, a\, x[/tex] to find [tex]v_{y}\![/tex]:
[tex](v_{y})^{2} - (u_{y})^{2} = 2\, a\, x[/tex].
[tex](v_{y})^{2} = (u_{y})^{2} + 2\, a\, x[/tex].
[tex]\begin{aligned}v_{y} &= -\sqrt{(u_{y})^{2} + 2\, a\, x} \\ &= -\sqrt{0^{2} + 2\, (-9.81) \, (-1.1)}\; {\rm m\cdot s^{-1}} \\ &\approx -14.6908 \end{aligned}[/tex].
(Final vertical velocity [tex]v_{y}[/tex] is negative since the stone is travelling downwards toward the ground.)
Let [tex]t[/tex] denote the duration of this flight. Apply the SUVAT equation [tex]t = (v_{y} - u_{y}) / (a)[/tex] to find [tex]t\![/tex]:
[tex]\begin{aligned} t &= \frac{v_{y} - u_{y}}{a} \\ &\approx \frac{(-14.6908) - 0}{(-9.81)}\; {\rm s} \\ &\approx 1.49753\; {\rm s} \end{aligned}[/tex].
In other words, this stone was in the air for approximately [tex]1.5\; {\rm s}[/tex].
Also because the stone was launched horizontally, the vertical velocity of this stone started at [tex]u_{y} = 0\; {\rm m\cdot s^{-1}}[/tex] and became negative (toward the ground) immediately after.
Hence, this stone would not have travelled upward during the entire flight. The height of this stone would be maximized immediately after the stone was launched: [tex]1.1\; {\rm m}[/tex].
Multiple the horizontal velocity [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex] of this stone by the duration of the flight [tex]t \approx 1.49753\; {\rm s}[/tex] to find the range (horizontal displacement) of this stone:
[tex]\begin{aligned} (\text{range}) &= v_{x}\, t \\ &\approx (15.2\; {\rm m\cdot s^{-1}})\, (1.49753\; {\rm s}) \\ &\approx 23\; {\rm m} \end{aligned}[/tex].
Right before landing, the stone would be travelling with a vertical velocity of [tex]v_{y} \approx (-14.6908)\; {\rm m\cdot s^{-1}}[/tex] and a horizontal velocity of [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex]. Apply the Pythagorean Theorem to find the overall velocity of this stone at that moment:
[tex]\begin{aligned} v &= \sqrt{{(v_{x})}^{2}\, {(v_{y})^{2}} \\ &\approx \sqrt{(15.2\; {\rm m\cdot s^{-1})^{2} + (-14.6908)^{2}}\; {\rm m\cdot s^{-1}} \\ &\approx 21\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].
use letter B below to explain what is wrong with the orbital diagram for beryllium
Electronic Configuration:
Normally, the electronic configuration will be written through the atomic number of the particular element. The electrons fill in this accruing to the energy level and orbitals like s, p, d, and f
The atomic number for the Beryllium is 4. So, the electronic configuration of beryllium is
[tex]1s^22s^2[/tex]In option B, the s block has two electrons and both are having an upward spin orientation. This is incorrect, as one must be in the upward orientation and the other will be in the downward orientation
When we see saturn going through a period of apparent retrograde motion, it means.
In its orbit, Earth is passing Saturn, with both planets on the same side of the Sun.
What is apparent retrograde motion?
When a planet appears to be moving backward relative to other bodies in its solar system when viewed from a certain angle, this is known as apparent retrograde motion. Motion in the same direction as other bodies is referred to as direct motion or prograde motion.
Mars typically looks to be traveling to the left of the stars. Mars, however, moves right in relation to the stars during "retrograde motion" periods. Truth be told, that is only an illusion that lasts for around two years. In reality, Earth is orbiting the Sun and is currently passing past Mars. Mars is only occulted by Earth once every 26 months since it orbits the Sun more closely and moves quicker than Mars. Mars typically moves from west to east in the sky, but when Earth passes in front of it, we see it move from east to west, creating the impression that it is going backward.
Hence, the earth is passing Saturn in its orbit, with both planets on the same side of the Sun.
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4. A certain microwave has a wavelength of 0.032 meters. Calculate the frequency of this microwave.
The frequency of this microwave is 9.375 x 10^9 Hz
The frequency of a certain microwave having a wavelength of 0.032m will be 9.375 x 10^9 Hz.
Let:
'v' be the velocity of EMW; v = c 'f' be the frequency of EMW'λ' be the wavelength of EMW; λ = 0.032mUsing the relation between frequency and wavelength:
v = f.λ
c = f(0.032m)
3 x 10^8m/s = f(0.032m)
f = 3 x 10^8/0.032
f = 9.375 x 10^9 Hz
Electromagnetic Waves always travel at the speed of light. Electromagnetic Waves possess both electric and magnetic fields aligned perpendicularly to each other.
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suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. the first child exerts a force of 74.0 n, the second a force of 89.0 n, friction is 8.00 n, and the mass of the third child plus wagon is 23.0 kg.
The wagon and the child inside it make up the system of interest, acceleration equals 0.13 m/s² in the direction of child 1 and Zero acceleration if friction is 15.0 N.
When two things are moved against one another, instant friction results. The motion will be opposed by the friction, who will also be working against it. When an item is in motion and its velocity changes, the concept of acceleration takes place. Friction, which opposes motion, always lowers acceleration. An object and a surface come into contact and cause friction. The features of the surface and the item, as well as whether or not the object is moving, determine its magnitude. Always, friction works in the opposite direction of motion. As a result, friction cancels out some of the force driving motion when it is there. Therefore, there will be less acceleration and net force.
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What distance will a car traveling at a speed of 50 km/hr cover in 0.25 hr?
Answer: 12.5
Explanation: 50 x 0.25 = 12.5 km
a system of diatomic ideal gas contracts from a volume of 4.1 m3 to a final volume of 1.3 m3. if the process proceeds at constant pressure of 148 kpa, calculate the energy in kj transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system.
A system of diatomic ideal gas contracts from a volume of 4.1 m3 to a final volume of 1.3 m3. if the process proceeds at constant pressure of 148 kpa. The energy transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system is(Q)= 1450.4 KJ
What is energy?Energy is a physical term that means if a force is applied on a object and the object move some distance that means there is some energy is generate in that object. It is a vector quantity. It can be measured in Joule.
How can we calculate the energy?To calculate the energy we using the formula,
Q = nCp AT
Or, Q = nCp(T₂-T₁)
Or, Q = nCp[P(V₂ - V₁) /nR] ....eq(1)
Here we are given,
V₁ =Initial volume = 4.1 m³
V₂= final volume = 1.3 m³
Process is isobaric so,
p= Constant pressure= 148 kP = 148 x 10³ P
n = Number of moles = 1
Cp= specific heat at constant pressure.
For diatomic molecule Cp = 7R/2
we know, AT = T₂-T₁
From ideal gas equation
PV = nRT
T = PV/ nR
T₁= PV₁/nR
And T₂ = PV₂/nR
Now to calculate energy = Q in KJ transferred by heat at constant pressure.
Substitute all these values in eq (1)
Q = n(7R/2) [P(V₂ - V₁) /nR]
Or, Q = 7P(V₂ - V₁)/2
Or, Q = 3.5(148 × 10³ P) (4.1- 1.3) m³
Or, Q = 1450.4 x 10³ J ........(P.m3 = J)
Or, Q = 1450.4 KJ
From the calculation we can say that, The energy transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system is(Q)= 1450.4 KJ
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A 75-N box rests on a perfectly smooth horizontal surface. The minimum force need to start the box moving
is
A) 7.5 N. B) 75 N.
C) 750 N. D) any horizontal force greater than zero.
Here, if take it that you mean "perfectly smooth" to mean that there is no friction. If that is the case, then the box begins to move whenever there is a net horizontal force acting on it. (D) It goes without saying that the force increases as the box accelerates.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.F = ma
Where, F is the force on the box and m is the mass of the box and a is the acceleration.
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Describe how the amplitude of the oscillations of pendulum could be measured.
(3marks)
To find the amplitude of the oscillations of the pendulum, take newton's second law for rotational systems into consideration.
T = I α
-mg sin∅ = mL² d²∅ / dt²
Rearranging the equation as
d²∅ / dt² + g / L sin∅ = 0
If the amplitude of angular displacement is small enough, so the small angle approximation holds, then the equation of motion reduces to the equation of simple harmonic motion
d²∅ / dt² + g / L ∅ = 0
The simple harmonic solution is
∅(t) = ∅' cos(ωt)
where ∅' = initial angular displacement
and ω = √g/L the natural frequency of the motion.
The time period for one oscillation is
T = 2π / ω = 2π√L/g
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Following your push the ball rolls down the lane at 4. 2m/s. What is the net force on the ball as it rolls down the lane at the constant speed?
The net force on the ball as it rolls down the lane at the constant speed of 4.2 m / s is zero
F = m a
a = v - u / t
F = Net force
m = Mass
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time
u = v = 4.2 m / s
a = 0
F = 0
This is the result of Newton's first law which states that if there is no external force acting ( F = 0 ) on the object, the object will stay at rest if it is at rest or at constant speed if it is already moving.
Therefore, the net force on the ball as it rolls down the lane at the constant speed is zero
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A motorbike and its rider have a mass of 261 kg. If they experience an acceleration of 4.7 m/s2, what force was exerted on them?
Answer:
1226.7
Explanation:
force=ma
261×4.7=1226.7N
Why is speed the magnitude of velocity?
Yes, Speed is the magnitude of its velocity.
What is speed?
velocity is a vector, and Speed is a scalar (just a number). Whereas a velocity has both a direction and a magnitude. As I said, the magnitude of the velocity is known as the speed.
A moving object's speed is the distance it travels in a given length of time. The average speed of an object in a given time is equal to the distance traveled divided by the time. The distance traveled by an object per unit of time is also known as its speed. When an object's speed changes, it becomes faster or slower. Acceleration occurs when the speed of an object increases. Deceleration, or negative acceleration, occurs when an object becomes slower as its speed drops.
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1. Which pair of charges experiences the weakest electrostatic force?
In order to compare the eletrostatic forces, let's calculate each one using the formula:
[tex]F=k\frac{q_1q_2}{r^2}[/tex]Where k = 9 * 10^9, q1 and q2 are the charges and r is the distance between them.
So we have:
[tex]\begin{gathered} q_1=3\cdot10^{-6},q_2=5\cdot10^{-6},r=2\colon \\ F=9\cdot10^9\cdot\frac{3\cdot10^{-6}\cdot5\cdot10^{-6_{}}}{2^2} \\ F=0.03375 \\ \\ q_1=3\cdot10^{-6},q_2=3\cdot10^{-6},r=2\colon \\ F=9\cdot10^9\cdot\frac{3\cdot10^{-6}\cdot3\cdot10^{-6_{}}}{2^2} \\ F=0.02025 \\ \\ q_1=3\cdot10^{-6},q_2=3\cdot10^{-6},r=3\colon \\ F=9\cdot10^9\cdot\frac{3\cdot10^{-6}\cdot3\cdot10^{-6_{}}}{3^2^{}} \\ F=0.009 \\ \\ q_1=5\cdot10^{-6},q_2=5\cdot10^{-6},r=3\colon \\ F=9\cdot10^9\cdot\frac{5\cdot10^{-6}\cdot5\cdot10^{-6_{}}}{3^2} \\ F=0.025 \end{gathered}[/tex]So the weakest force is the one in the third case (bottom left option): charges of -3 uC and +3 uC, and distance of 3 meters.
a 100 kg crate is being pulled across the floor at a constant velocity with a rope that makes an angle of 40 degrees to the horizontal. if the force applied is equal to 300 n, what is the force of friction acting on the box
What is an ellipse?
an elliptical shape
a perfectly round circle
an undefined shape
Answer: In geometry, an ellipse is a two-dimensional shape, that is defined along its axes. An ellipse is formed when a cone is intersected by a plane at an angle with respect to its base.
Explanation:
what is the speed of the book when it reaches the hands? (b) if we substituted a second book with twice the mass, what would its speed be? (c) if, instead, the book were thrown down, would the answer to (a) increase, decrease, or remain the same?
Anything thrown from a structure, you have a downward velocity if you throw it down correctly. Additionally, you have little G, thus the ball will keep accelerating. As a result of the acceleration, your final velocity will undoubtedly be much higher.
At the bottom of the structure, a book is currently being dropped; a man is standing nearby with his hands extended in a very linear motion. The height of these arms is also determined, de Unlike this book, which stands at a specific height Big D The weight of this book has increased to two kilograms. two kg. This small D is equivalent to one point five meters on the issue whereas this enormous D is equal to ten meters of wire. seeks to know the speed at which it will reach this person's grasp.
We have a starting energy and a finishing energy. We also have one more energy. We only have gravitational potential energy, after all. What is our final energy, then? The book is falling, so we have kinetic energy, and since Cromwell is not written in it, we have gravitational potential energy. really easy Therefore, we have M g Big D, followed by 1/2 em, the last square, and M g Little T. What should we do next, then? really easy As a result of our velocity solution, the final square's mg big d minus m g tiny d is equal to 1/2.
Therefore, the final square is equal to two times mg big D, minus mg small D, and you merely need to solve for V divide. I divide by an, you square root it, and the result is equal to two mg large D minus two mg little D all over.
Because if you thought about this properly, your speed would increase. You must simply consider anything. anything falls from a structure. If you throw it down correctly, it will move downward at a speed. Furthermore, since you have little G, the ball will keep accelerating. Because it is accelerating, it follows that your final velocity will be much higher.
Both your initial kinetic energy and your gravitational potential energy would be present, as would your final kinetic energy and gravitational potential energy. Because it is at its highest point, you would have a 1/2 M V initial square plus M g Big D and he would have a 1/2 em final square plus M g tiny. +00 It's not a huge D or small D now that it's in their palm. Therefore, the answer would alter. Your speed would actually rise, in my opinion, if you give this some careful thought. You only need to consider anything.
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How does changing the mass of an object in the system's acceleration when a constant force is applied?
When a constant force is applied, an increase in the mass of an object decreases its acceleration and vice versa.
What is the relationship between the force, mass, and acceleration of an object?The mass of an object is the quantity of matter present in the object.
Force is a push or pull agent that causes a change in the motion or state of rest of an object.
Acceleration of an object is the change in velocity with time of the object.
The relationship between the force, mass, and acceleration of an object is given below:
Force = mass * accelerationMass = Force / accelerationAcceleration = Force / massFrom the above formulas, it can be seen that mass and acceleration have an inverse relationship such that as one increases, the other decreases, and vice versa.
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Yani is speaking to an elementary school class on the importance of good nutrition. Without getting into the breakdown of macronutrients and what they
do, how might Yani BEST advise these children to have a balanced diet?
OA. Stick to meat and dairy only, cutting out carbs.
O B.
Don't ever eat candy, cake, or other junk food.
O c.
Try to have many different colors of foods.
OD.
Stick with raw foods instead of cooked ones.
The best advice Yani can give these elementary school children to have a balanced diet is "Don't ever eat candy, cake, or other junk food".
All the given options are true and correct regarding a balanced diet. But for an elementary school child to understand about a balanced diet, one must not et into the breakdown of macronutrients and what they do.
Option A mentions carbs which is a macronutrient. So it is incorrect. Option C is explaining to eat different types of fruits and vegetables. But it might be interpreted wrongly because even junk foods and candies will look colorful. Option D is not a good diet for a child.
Therefore, the best advice Yani can give these elementary school children to have a balanced diet is "Don't ever eat candy, cake, or other junk food".
To know more about macronutrients
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Answer:
Try to have many different colors of foods.
Explanation: