suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. the first child exerts a force of 74.0 n, the second a force of 89.0 n, friction is 8.00 n, and the mass of the third child plus wagon is 23.0 kg.

Force of friction if the coefficient of static friction is 0.44 is 189.728N. The force of friction if the coefficient of kinetic friction is 0.27 is 116.424N.

Force of friction:

The force that resists the sliding or rolling of one solid object over another is called the force of friction.

The formula for the force of friction is:

F =μN

F = force of friction

μ= coefficient of friction

N = normal force

We have to find the force of friction when the coefficient of static friction is 0.44.

[tex]F_{s}[/tex] = μ N

    = μmg

    = 0.44× 44×9.8

    = 189.728N

Now we have to find the force of friction when the coefficient of kinetic friction is 0.27

[tex]F_{k}[/tex] = μN

    = μmg

    = 0.27 × 44 × 9.8

    = 116.424N

Therefore the force of friction [tex]F_{s}[/tex] is 189.728N and [tex]F_{k}[/tex] is 116.424N

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The expected result of the experiment is that the liquid air will boil because the extreme difference in temperature will cause heat to be transferred from the ice to the liquid air ( B ).

The temperature of the liquid air = - 200 °C

The temperature of the block of ice = - 12 °C

Since they are in a thermally insulated flask, the heat will be transferred until both the objects' temperature becomes equal. So the temperature of liquid air rises and the temperature of ice decreases. The boiling point of liquid air is - 194.35 °C. So the liquid air boils.

Option A would have been correct if the final statement was decrease in temperature and not increase in temperature. Option C is incorrect because the ice becomes colder. Option D is incorrect because liquid air will boil.

Therefore, the expected result of the experiment is that the liquid air will boil because the extreme difference in temperature will cause heat to be transferred from the ice to the liquid air and the molecules of the liquid air will begin to leave the liquid ( B ).

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In case of a block resting on the top of a  table and we are considering only the forces acting upon the block.          

                      (block)

     _______[[[[[[[[[]]]]]]]]]]_______  ( table)

             /                                \

           /                                     \

         /                                         \

figure represents block resting on a table,

Gravity P

Spring: A

Tension A

Normal: P

Friction A

Air Res.: A

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Answer:

i don't know what?

Explanation:

i said what?

Answer:

Kinetic Energy is 1.59x10^7 Newtons

Potential Energy cannot be determined since no height is given. An example calculation is provided that assumes 3000 meters.

Explanation:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: 

K.E. = 1/2 m v2.

If the mass is in kilograms and the velocity in meters per second, the kinetic energy has units of kilograms-meters per second squared, which is 1 Newton. (A newton is defined as 1 kg⋅m/s2. 1 Joule is defined as 1 N*m, or 1 kg⋅m2/s2

Data: 8500 kg airplane

220 km/h flight speed

We'll convert the speed from km/h to m/sec.

(220 km/h)*(1 h/3600 sec)*(1000m/1km) = 61.1 m/s

Kinetic Energy:

K.E. = 1/2 m v2

K.E. = 1/2 (8500 kg)*(61.1 m/s)^2

K.E. = 1/2 (8500 kg)*(3733 m^2/s^2)

K.E. = 1.59x10^7 kg*m^2/s^2

K.E. = 1.59x10^7 Newtons

Potential Energy

The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.

P.E. = mgh

P.E. = (8500kg)*(9.8 m/s^2)*(h)

I don't see a height given for the plane, so we can't calculate a potential energy. If it were at 3000 meters (1.86 miles), the calculation would be:

P.E. = (8500kg)*(9.8 m/s^2)*(3000 m)

P.E. = (2.5x10^8 kg*m/s^2) or 2.5x10^8 Newtons

Substances that are soluble in water are polar substances which is a molecular characteristics that is not possessed by insoluble substances.

The molecular characteristics of a substance is the features that are exhibited by the ions and molecules of that substance that makes it unique from others.

Soluble substances are those substances that are able to dissolve in water while insoluble substances are those substances that are not able to form solution with water.

Example of soluble substances are salt and sugar while examples of insoluble substances are metals and fat.

The soluble substances are polar substances are they possess a negative and a positive pole in their molecules that allows for dissolution in water.

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The torque on the motor's shaft is 1.375 Nm.

We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as

τ = F x r

where τ is torque, F is perpendicular force and r is radius.

From the question above, the parameter given are

m = 1.1 kg

d = 25 cm

r = 12.5 cm

Convert radius to meter

r = 12.5 cm

r = 12.5 x 10¯² m = 0.125 m

Find the weight

W = m . g

W = 1.1 . 10

W = 11 N

By substituting the parameters, we get

τ = F x r

τ = 11 x 0.125

τ = 1.375 Nm

Hence, the moment applied is 1.375 Nm

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The car can coast up to the height of 30.34m and (b) the thermal energy generated by friction is 118047.75J.

The energy in which an object that has as a result of motion is called as kinetic energy. A force is applied to an object in instruct to accelerate it. We have to put the effort in order to apply the force. After the completion of the work the energy is removed from the item and then it moves at a new, constant speed.

Potential energy is defined as the form of stored energy which is dependent on the ordering of system components.

(a) given; [tex]v=24.4m/s^{2}[/tex], [tex]g=9.81m/s^{2}[/tex]

KE(initial)= PE(final)

[tex]\frac{1}{2} mv^{2}[/tex]=[tex]mgh[/tex]

[tex]h=\frac{v^{2} }{2g}[/tex]

[tex]h=\frac{24.4^{2} }{2*9.81}[/tex]

h=30.34m

(b) If, in actuality, a 750 kg car with the same initial speed is observed to coast up a hill to a height 14.3 m above its starting point

E(friction)=KE(initial)-PE(final)

E(friction)=[tex]\frac{1}{2} mv^{2}-mgH[/tex]

E(friction) =[tex]\frac{1}{2}(750)24.4^{2} - (750)(9.81)(14.3)\\[/tex]

E(friction)=118047.75J

A friction is defined as the force which prevents two objects from moving against each other.

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Answer:

a

Explanation:

The equivalent resistance of a circuit reduces as more parallel resistors are added, but the circuit's overall current increases. Additional branches via which charge can flow are comparable to more resistors being added in parallel.

A circuit can have parallel or series connections connecting two or more electrical components. The circuit is referred to as a parallel circuit when all of the devices are linked utilizing parallel connections. Each device is located in a distinct branch of a parallel circuit. Branch lines indicate that there are numerous paths for charge to move via the external circuit.

A single resistor located in a single branch will be contacted by each charge moving through the external circuit's loop. A charge choose which branch it will take on its way back to the low potential terminal when it reaches the branching site or node.

It was made clear that increasing the number of resistors in a parallel circuit has the very surprising effect of reducing the total resistance. The addition of a second resistor in a different branch creates a second avenue for charge to travel through the circuit's primary area of resistance because there are numerous ways for it to do so.

By increasing the number of branches, the resistance will reduce, which will increase the pace at which charge flows (also known as the current).

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From steam table,

(a).

The final temperature is 180°C.

At 10 bar, saturated liquid,

Temperature = 180°C

(b).

Heat removed from the steam is  2065.6 kJ/kg.

At 10 bar - 200°C, h1 = 2828.27 kJ/kg

At 10 bar, saturated liquid, h2 = 762.68 kJ/kg

Heat removed = h1 - h2 = 2065.6 kJ/kg

(c).

Work done is 204.9 kJ/kg.

Work done = heat removed - change in internal energy = 2065.6 - (2622.26 - 761.55) = 204.9 kJ/kg

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Option c is the right solution. This shows that it has gone beyond the threshold when the difference is immediately noticeable.

The lowest kinetic energy that two moving particles must have when they collide is known as the threshold energy in particle physics. Always larger than or equal to the desired particle's rest energy is the threshold energy. As a result, this is changed to: f = W/h, where h is the Planck constant. So, we can calculate the threshold frequency if we know the work function. Photoelectric effect in radioactivity. The frequency at which the effect is only feasible is known as the photoelectric threshold frequency, denoted by the Greek letter nu with the subscript zero, v0. The threshold energy is the lowest energy that each colliding molecule must have in order for the collisions to be successful.

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The range of baseball thrown at a speed of Vo at an angle of elevation theta is Vo^2sin2theta/g.

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Answer:

Tungsten oxide...

hop e it helps

The net force exists 0 when the forces are in equilibrium. They have the same impact as if there were no forces at all.

Net Force, which is essentially the total of all the forces operating on an item, is the combination or consequence of those forces.

The total of all forces exerted on an object is known as the net force. A mass can accelerate due to net force. A body is subject to another force whether it is at rest or in motion. When there exists a lot of forces acting on a system, the term "net force" exists employed.

Equal in size and directed in the opposite direction, balanced forces are. When forces are evenly distributed, motion remains unchanged. One of your scenarios from the previous section involved pushing or pulling an object with the equal amount of force in opposite directions.

The complete question is:

Directions: Answer each question by circling the correct choice. After you have completed all of the questions, color the picture using the assigned colors.

Question

Choice A

1. The sum of all forces acting on an object is known as...

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In astronomy class friends plan to get married at sunset, and they want the moon to be high in the sky. The moon should be First Quarter phase.

The study of the cosmos and everything in it that is not within the atmosphere of Earth is referred to as astronomy. Astronomers investigate the locations, movements, and characteristics of celestial objects. Astrology tries to understand how those placements, motions, and qualities impact people and events on Earth. The main distinction between astrology and astronomy is what determines the outcome. The Sun and Moon's effects during a particular zodiac sign are interpreted by the ancient tradition of astrology. 12 divisions of the sky, each measuring precisely 30 degrees, are said to exist in astrology. The scientific community has rejected astrology because it lacks the ability to explain how the cosmos works. The premises and claimed effects described in astrological traditions have not been proven by scientific research to be true.

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The magnitude of the average velocity of chickadee flight is 2.5 m/s

Average velocity is defined as the rate of change of displacement with respect to time. Mathematically, we can write -

v = Δx/Δt

Given is a chickadee who flies 30 m to the West for 6 seconds and then 40 m to the North for 14 seconds.

Now, the displeacement of the chickadee, can be calculated as follows -

|Δx|² = (30)² + (40)²

|Δx|² = 900 + 1600

|Δx|² = 2500

|Δx| = [tex]\sqrt{2500}[/tex]

|Δx| = 50

Now, the average velocity of the chickadee will be -

v = |Δx|/Δt

v = 50/(6 + 14)

v = 50/20

v = 2.5 m/s

Therefore, the magnitude of the average velocity of chickadee flight is 2.5 m/s

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A singularity is a point where some property is infinite.

In technology, singularity describes a hypothetical future where technology growth is out of control and irreversible. Most especially, the singularity would require computer programs to become so advanced that artificial intelligence transcends human intelligence, potentially rubbing out the boundary between humanity and computers. Nanotechnology is recognized as one of the key technologies that will make singularity a truth. The technological singularity or simply the singularity is a hypothetical future point in time at which technological growth becomes uncontrollable and irreversible, resulting in unforeseeable changes to human civilization.

So we can conclude that a point where something is infinite is known as a singularity.

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a. Angular speed, w = v/r where  v is the linear speed, r is the radius

b. v = w*r

c. I(disk)=1/2mr^2,I(hoop)=mr^2, I(Ball)=8/3mr^2 disk is the smallest moment of inertia.

A body has an attribute called inertia that makes it resist attempts to move it or, if it is already moving, to alter the speed or direction of its motion. A body's inertia is a passive characteristic that prevents it from doing anything other than opposing active agents like forces and torques. A moving body continues to move not because of its inertia but rather because no force exists to stop it, alter its direction, or accelerate it.

A body's moment of inertia, which quantifies its resistance to the action of a force, and its mass, which determines how resistant it is to the action of a force, are two numerical measures of inertia.

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Rocket B's speed in relation to rocket A is 0.4c

If the two frames of reference's directions are at odds with one another, the two frames of reference would see the relative speed as the total of their individual speeds. Furthermore, if the motion of the two frames is parallel, relative speed would be seen as the difference between the individual speeds.

The Earth's frame of reference is at rest, but the two rockets passing by are traveling relativistically with respect to Earth.

Since both rockets are moving in the same general direction, rocket B's relative speed to rocket A is equal to the difference between the two rockets' individual speeds.

Speed of rocket A is v = 0.70c

speed of the rocket B is u =0.86c

let,

speed of the rocket B with respect to rocket A is u₁

Now,

u₁ = (u - v) / [(1 - u) * (v / c²)]

u₁ = (0.86 - 0.70) / (1 - 0.86 * 0.70 / c²)

u₁ = 0.16 / (1 - 0.6) = 0.16 / 0.4

∴ u₁ = 0.4c

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The assumptions of the kinetic theory is given below.

The kinetic theory postulates that liquid molecules constantly move, expressing their thermal energy. These molecules frequently clash with one another, and occasionally one or another surface collision gains enough momentum to propel it out of the liquid and into the sky.

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Answer:

18m/s

Explanation:

Divide 450 into 25 to know how many m per second and it gives 18m per second

Fuse, breakers, and other overcurrent protection devices set an appropriate current limit and sever short circuits.

The size of the overcurrent protection system depends on the overcurrent protection system type and the maximum current that can travel through the circuit components. National codes specify the size and design of the overcurrent protection system. The size of the overcurrent protection devices is typically determined by the array's short-circuit current.

The PV is a limited current source, meaning that the short-circuit current is the highest current produced by this source, which is the major justification for choosing the array's short-circuit current.

The distribution lines of electric grids integrated with DER are safeguarded by an overcurrent protection system. The phase overcurrent protection and the ground overcurrent protection are two further classifications for this protection strategy. Depending on the distribution method, the relays employed in such schemes could be either directional (functioning for in-front events) or nondirectional (working for all). Radial distribution systems are where nondirectional relays are most frequently employed.

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8.33 x 10²v .

The potential difference at which proton fall is :   = 8.33 x 10²v .

Here,

The potential difference is as follows:

Energy change, [tex]e^{v}[/tex] = 1/2 m(v2² - v1²)

By substituting,

1 . 602 x 10 ⁻¹⁹ = 1/2 x 1.67 x 10 ⁻²⁷( 5² - 3²) x 10 ¹⁰

v x 1.602 x 10⁻¹⁹ = 0.835 x 10⁻¹⁷ x 16

v = ( 0.835 x 10⁻¹⁷ x 16 ) / 1.602 x 10⁻¹⁹

  = 0.835 x 10²x16 / 1.602

  = 13.36 x 10² / 1.602

  = 8.33 x 10²v

So the potential difference is : 8.33 x 10²v .

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The angle θ which the left-hand cable makes with respect to the wall is  17⁰.

The resultant force on the cables is determined by resolving the forces into x and y components as shown below.

y-component of the weight;

Wy = -636 N

y-component of the tension in the right cable;

Ty = 890 x sin(26)

Ty = 390.15 N

x-component of the tension in the right cable;

Tx = 890 x cos(26)

Tx = 799.93 N

y-component of the tension in the left cable;

Ty = T sinθ

x-component of the tension in the left cable;

Tx = -T cosθ

Sum of the forces in y-direction;

∑F_y = 0

T sinθ - 636 + 390.15 = 0

T sinθ - 245.85 = 0

T sinθ = 245.85 -------- (1)

Sum of the forces in x-direction;

∑Fx = 0

-T cosθ + 799.93 = 0

T cosθ = 799.93  -------- (2)

Divide equation (1) by (2)

T sinθ / T cosθ = 245.85/799.93

tanθ = 0.307

θ = arc tan(0.307)

θ = 17.1⁰ ≈ 17⁰

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Forward thrust has positive values and reverse thrust has negative values.

Thrust is a sudden push or pull in a certain direction.

a)

Flight speed u = 150 km/h

1 km/h = [tex]\frac{1}{3.6}[/tex] km/s

therefore, 150 km/h =  41.67 km / s

The thrust force represents the horizontal or x-component of momentum equation:

[tex]T = m_{exhaust} * U_{exhaust} - U_{flight}[/tex]

T = 50 * (150 - 41.67)

T = 5416.67 N

Therefore, the value of forward thrust is 5416.67 N.

b)

Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,

thus thrust equation is:

[tex]T = m_{exhaust} * U_{exhaust} - U_{flight}[/tex]

T = 50 * (0 - 41.67)

T = -2083.5 N

Therefore, the thrust force T is -2083.5 N in the reverse direction.

c)

Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero because[tex]U_{exhaust} = U_{flight} = 0\\[/tex]

T = 0

Therefore, there is no difference in two velocities in x direction.

The given question is incomplete, the complete question is,

"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.

a. What is the forward thrust of this engine?

b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?

c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"

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Answer:

See below

Explanation:

The half life is 12 year, so after 12 years HALF Of the sample will be gone and half will be left

1/2   *   1 x 10^16  =   .5 x 10^16   = 5 x 10^15 nuclei