The graph of the function p(x)=x^3+x^2+4x+4 is shown below

Find all real and complex roots of the function. The Zeros are:



List the zeros as complex numbers. Separate answers by commas as needed.

Answer:

B, 28.

Step-by-step explanation:

728 divided by 208, which is 3.5. then you multiply 3.5 & 8 to get 28.

The answer above me has the answer.

Step-by-step explanation: He is 101% confident its it and I back it up because got it right (he should've been 102% confident tho)

Answer:

1. How much did the 2 lb of the first type of candy cost the owner?

2x

2. How much did the 3 lb of the second type of candy cost the owner?

3*1.5 = 4.5

3. How much did the two types of candy cost the store owner in total?

2x + 4.5

4. How much money will the store owner get if she sells all of the new mixture?

(2 + 3)*2.5 = 12.5

5. Write an equation to find the cost per pound of the first candy

2x + 4.5 = 12.5

6. Solve the equation to find the owners cost of the first candy per pound

2x + 4.5 = 12.5

2x = 8

x = 4

Answer:

b

Step-by-step explanation:

because you need ti 2x +

The total mass of sugar used is 1.7 kg.

The mass of sugar he has left is 0.3 kg.

In mathematics, a fraction is a numerical value that represents a portion of a whole. The entire can be any number, a specific value, or an item. Fractions are written as p/q.

Given:

Total mass of sugar Mr tan has = 2 kg

Fraction of sugar used to make dessert = 1/4 kg

Fraction of sugar used to bake some cakes = 3/5 kg

The total mass of sugar used is calculated as,

= Mass of sugar used to make dessert + Mass of sugar used to bake some cakes

Mass of sugar used to make dessert = (1/4 of 2) kg = 1/2 kg

Mass of sugar used to bake some cakes = (3/5 of 2) kg = 6/5 kg

Total mass of sugar used = (1/2 + 6/5) kg = 17/10 = 1.7 kg

Mass of sugar left =  Total mass of sugar - Total mass of sugar used

                             = 2 kg - 1.7 kg  = 0.3 kg

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[tex]5 \div 6 \times 2100 = 1750[/tex]

The percentage is that indicating the hundredth total number of students surveyed such that 20% of them are 25 will be 125.

What is the percentage?

The percentage is defined as a given amount in every hundred. It is a fraction with 100 as the denominator percentage is represented by the one symbol %.

Let's suppose the total number of students that are surveyed was x.

It is known that x% of y is given as, (x/100)y.

Therefore,20% of x is (20/100)x = 0.2x

The 20% of the total students is 25.

So, 0.2x = 25

x = 25/0.2 = 125

Hence "The percentage is that indicating the hundredth total number of students surveyed such that 20% of them are 25 will be 125".

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1/2 is the factor which converts right angled triangles ΔRPQ to ΔVAQ

Triangle: A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. A triangle with vertices A, B, and C is denoted triangle ABC. In Euclidean geometry, any three points, when non-collinear, determine a unique triangle and simultaneously, a unique plane

Both the triangles are right angled triangles at ΔVAQ and ΔRPQ

side AV=3 units and AQ=4 units

side RP=6 units and PQ=8 units

AV is half of RP and AQ is half of PQ

AV=1/2(RP) and AQ=1/2(PQ)

1/2 factor converts ΔRPQ to ΔVAQ

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Answer:

-4 + -10

Step-by-step explanation:

Even with an addition sign, it still adds up to the same amount.

Hope this helps!

(Btw, if u get this right, pls do brainliest, I really need it! Thanks!)

Answer: C

Step-by-step explanation:

This is the definition of a negative exponent.

The value of the given monomial, -8[tex]m^{4}n^{4}[/tex], when m = 0.5 and n = 2 is -8.

According to the question,

We have the following monomial:

-8[tex]m^{4} n^{4}[/tex]

We have m = 0.5 and n = 2.

Now, putting these values of m and n in the monomial:

-8 [tex](0.5)^{4} (2)^{4}[/tex]

(Please note that when a power is there on a number then it means that to solve the expression we have to multiply the base as many times as the given power. For example, in this case, we will multiply 2 four times and the result will be 16. This concept is applicable to every expression we are solving whether the base is in decimal or in fraction or a integer.)

-8*0.0625*16

-128*0.0625

-8

Hence, the value of the given monomial is -8.

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Step-by-step explanation:

it is a rectangle.

the area is a rectangle is

length × width

in our case

length × width = 55 ft²

length = 3×width + 4

we use that in the first equation :

(3×width + 4)×width = 55

3×width² + 4×width - 55 = 0

the general solution to a quadratic equation like

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

so,

width = (-4 ± sqrt(4² - 4×3×-55))/(2×3) =

= (-4 ± sqrt(16 + 660))/6 = (-4 ± sqrt(676))/6 =

= (-4 ± 26))/6

width1 = (-4 + 26)/6 = 22/6 = 11/3 = 3 2/3 ft

width2 = (-4 - 26)/6 = -30/6 = -5

negative numbers for the size of a physical object don't make sense, so

11/3 = 3 2/3 ft is our solution.

length = 3×width + 4 = 3×11/3 + 4 = 11 + 4 = 15 ft

so,

the length = 15 ft

the width = 3 2/3 ft (or 11/3 ft)

The correct option is A, the system of inequalities is:

On the graph, we can see two lines.

One is a dashed line (so we need to use the symbols > or < ) and it is horizontal, such that the line is:

y = -3

And the shaded region is above that line, so the inequality is:

y > -3.

The other inequality is below a line y = -x, and we can see that the line is solid (so we use the symbols ≤ or ≥).

Then here the inequality is.

y ≤ -x

Then the system of inequalities is:

y > -3.

y ≤ -x

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Given:

The lengths of time spent in the store are normally distributed and are represented by the variable X

The survey indicates that for each trip to a supermarket, a shopper spends an average of 43 minutes with a standard deviation of 12 minutes in the store.

so, the mean = μ = 43

And the standard deviation = σ = 12 minutes

We will find the probability that supermarkets between 31 and 58 minutes

We will use the following formula to convert to the z-scores

So, we will find Z when x = 31 and When x = 58

So, we will find the probability of P (-1 < z < 1.25)

From the tables of the z-score:

===================================================

Work Shown:

[tex]\frac{n^2+n-6}{n-2}\\\\\frac{(n+3)(n-2)}{n-2}\\\\n+3[/tex]

---------------

Explanation:

Often when simplifying, it's a good idea to factor and see what cancels (if anything does cancel).

To factor the numerator, think of two numbers that

Through trial and error, you should find the two numbers to be 3 and -2

So that's how [tex]n^2+n-6[/tex] factors to [tex](n+3)(n-2)[/tex].

After this point, the (n-2) terms cancel leaving n+3 behind

We can say [tex]\frac{n^2+n-6}{n-2}=n+3 \ \ \text{when } n \ne 2[/tex]

The [tex]n \ne 2[/tex] is to avoid a division by zero error.

Answer:

52 yards across

Step-by-step explanation:

Hakim drew a scale drawing of a neighborhood park. he used the scale 5 inches : 2 yards. a soccer field in the park is 130 inches wide in the drawing. how wide is the actual field?

130/5 = 26

26*2 = 52 yards across

Answer:

10

Step-by-step explanation:

486-466 = 20

1/2 x 20 = 10

:]

Answer:

an expression that equals 10

Step-by-step explanation:

486 - 466 = 20

1/2 of 20 is 10

You don't list choices.

You need an expression that equals 10.

Answer: 7.3 < 12

Step-by-step explanation:

[tex] \frac{4}{5} (w + z) \\ = \frac{4}{5} (12 + 43) \\ = \frac{4}{5} (55) \\ = 4(11) \\ = 44[/tex]

ATTACHED IS THE SOLUTION

Answer:

Step-by-step explanation:

52 + b = 52b or 52(b = 52b         ( means x

The equation will be y = -15x + 40

Equations help us to understand a particular problem better, they give us possible insights into the situation. Equation Formation is an important aspect of Mathematics. We can form equations on the basis of the information given and then analyze it.

Given:

The biker, Dudley wants to travel 40 miles.

It is given that he travels 30 miles every 2 hours.

Obtaining Equation,

Distance traveled in 2 hours = 30 miles

Then, distance traveled in x hours = [tex]\frac{30}{2}*x = 15x[/tex]

So, the remaining distance to cover = 40 - 15x

or  y = 15x - 40

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You will need to use at least 267 minutes in a month in order for the second plan to be preferable.

Given the following:

First plan=23 cent per minute

Second plan=$34.95 plus 10 cents per minute

Calculate the number of mins to use in a month to make second plan preferable:

We first change $34.95 to cents:

1 usd=100 cents

$34.95=($34.95*100 cents)/$1

           =3495 cents

Second plan will now be 3495 plus 10 cents per minute

Now, calculate the number of mins to use:

Let x represents the number of mins, now 23 cent per minute will be:

23(x)>3495 plus 10 cents per minute

23x>3495+10x

23x-10x>3495

13x=3495

x=3495/13

x>268.85 mins

Therefore, one will need to use at least 267 minutes in a month in order for the second plan to be preferable.

The question is incomplete, complete question is given below:

You are choosing between two different cell phone plans. The first plan charges a rate of 23 cents per minute. The second plan charges a monthly fee of $34.95 plus 10 cents per minute. How many minutes would you have to use in a month in order for the second plan to be preferable?

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Answer: 2.7 kg

1 kilogram (kg) = 2.204623 pounds (lb)

[tex]\frac{6 lb}{1}[/tex] × [tex]\frac{1 kg }{2.204623 lb}[/tex] = 2.721553753 kg

You place 1 kg over 2.204623 lb since they are equal. In the above equation, the pounds (lb) cancel out since one is in the numerator (the number on top of the fraction) and one is in the denominator (the number on the bottom of the fraction). You multiply 6 by the 1 in the numerator and multiply the 1 in the denominator by 2.204623. This turns the equation into:

[tex]\frac{6 kg}{2.204623}[/tex] =2.721553753 kg

You divide 6 by 2.204623 to get 2.721553753

To round to the tenths place, you include only the first number to the right of the decimal, which is 7. Since the number to the right of the 7 is less than five, it stays 7. If it were five or bigger, 7 would turn into 8.

The answer: 2.7 kg

To maximize the number of circular tables, he must thus employ 9 circular tables and 3 square tables.

Combinatorics is a branch of math focused on the arrangements of objects.

Estimates of the number of operations needed by a computer algorithm can be created using combinatorial approaches.

It is given that the number of persons in each circular table and the square table will be 10 and 4 respectively.

We now need to determine the largest multiple of 10 in order to maximize the number of circular tables.

Now, if we take 100, there will only be 2 seats left. However, 4 people are needed for square tables. Therefore, 100 is incorrect.

The circular tables utilized would be if we choose 90 as a multiple of 10 is,

= 90 / 9

= 10

Number of guests left,

=102 - 90

= 12

12 is a multiple of 4 as a result 3 square tables may therefore fit 12 people,

=4 × 3

=12

Thus, to maximize the number of circular tables, he must thus employ 9 circular tables and 3 square tables.

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Answer: Option (D) property of distribution

Step-by-step explanation:

got it right on test

When the result of one function is utilized as the input for another, this is known as a composite function. If f(x) = (6x³ - 7)³ and g(x) = 6x³ - 7 then the value of h(x) = x³.

A function is composed in mathematics when two functions, f and g, are used to create a new function, h, such that h(x) = g(f(x)). The function of g is being applied to the function of x, in this case. Therefore, a function exists essentially applied to the output of another function.

Function composition is an operation used in mathematics that takes two functions, f and g, and creates a function, h = g ° f, such that h(x) = g. The function g is applied in this operation on the outcome of applying the function f to x.

Let the two functions be f(x) = (6x³ - 7)³ and g(x) = 6x³ - 7.

f(x) = (h° g)(x)

⇒ f(x) = (h(g(x))

If f(x) = (h° g)(x) (6x³ - 7)³ = (h(g(x)) then h(x) = x³.

The complete question is:

Let f(x) = (6x³ - 7)³ and g(x) = 6x³ - 7. Given that f(x) = (h° g)(x), find h(x).

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Answer:

h(x) = x³

Step-by-step explanation:

Given:

  [tex]f(x)=(6x^3-7)^3[/tex]

  [tex]g(x)=6x^3-7[/tex]

  [tex]f(x)=(h \circ g)(x)[/tex]

The relationship between f(x) and g(x) is that function f is function g cubed:

[tex]f(x)=(g(x))^3[/tex]

(h o g)(x) means we replace the x-variable of function h(x) with function g(x). So:

[tex](h \circ g)(x)=h(g(x))[/tex]

If (h o g)(x) equals f(x), then h(x) must be h(x) = x³.

Check by replacing the x-variable of function h(x) with the function g(x) and comparing it to f(x):

[tex]\begin{aligned}(h \circ g)(x)&=h(g(x))\\&=(g(x))^3\\&=(6x^3-7)^3\\&=f(x)\end{aligned}[/tex]

Hence proving that h(x) = x³.

Answer:

x=1

Step-by-step explanation:

3x−1+2=4

Add −1 and 2 to get 1.

3x+1=4

Subtract 1 from both sides.

3x=4−1

Subtract 1 from 4 to get 3.

3x=3

Divide both sides by 3.

x=

3

3

​

Divide 3 by 3 to get 1.

x=1

Answer:

y=-3x+7

Step-by-step explanation:

:]

Answer:

Y=-3x+7

Step-by-step explanation:

Use rise/run