the rows from left to right in the periodic table is called what​

Answers

Answer 1

Answer:

The periodic table has rows that go left to right and columns that go up and down, just like any other grid. The rows are referred to as PERIODS, while the columns are referred to as GROUPS.

Explanation:


Related Questions

How many joules are required to heat 120.5!grams of water from 5.6°C to 62.5°C

Answers

Answer:

The amount of energy required is 17 kJ.

Explanation:

What is the percentage composition of each element in ammonia, NH3?
82.35% N; 17.65% H
80.55% N; 19.45% H
79.46% N; 20.54% H
78.57% N; 21.43% H

Answers

Whats is the percentage composition of each element in ammonia, NH3?
The answer is A

Taking into account the molar mass of each elemente and ammonia, the correct answer is the first option: the percentage composition of each element in ammonia, NH₃ is 82.35% N; 17.65% H

First of all, molar mass is the mass of one mole of a substance, which can be an element or a compound. In the case of a compound, it is calculated by adding the atomic masses of the atoms that make up the molecule.

In this case, being the atomic mass of N equal to 14 and the atomic mass of H equal to 1, the molar mass of NH₃ is calculated as:

NH₃= 14 + 3* 1= 17

Now, to obtain the percentage composition of each element, you must divide each individual atom with the mass of ammonia and multiply by 100 to obtain the percentage:

N: [tex]\frac{14}{17} x100[/tex]

H: [tex]\frac{1x3}{17} x100[/tex] In this case, the atomic mass of hydrogen H is multiplied by 3 because 3 hydrogens are present in ammonia.

Solving:

N: [tex]\frac{14}{17} x100[/tex]= 0.8235×100= 82.35 %

H: [tex]\frac{3}{17} x100[/tex]= 0.1765×100= 17.65 %

Finally, the correct answer is the first option: the percentage composition of each element in ammonia, NH₃ is 82.35% N; 17.65% H

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Which of these is correct?

Answers

Answer:

1.89 nol Cu(NO3)2

Explanation:

if you calculate it it will be 1.89

Jello has a density of 1.14 g/mL. A box of Jello makes 475 mL of Jello and has 13 g of sugar. Determine the % m/m of sugar in the Jello. (Hint: d=m/v) ​

Answers

Answer:

2.34 %

Explanation:

Since the density of the Jello, ρ = 1.14 g/mL and ρ = m/v where m = mass of jello and v = volume of jello = 475 mL.

So, m = ρv

substituting the values of the variables into the equation, we have

m = ρv

m = 1.14 g/mL × 475 mL = 541.5 g

Since we have 13 g of sugar in the jello, the total mass present is 13 g + 541.5 g = 554.5 g

So, the percentage by mass of sugar present % m/m = mass of sugar present/total mass × 100 %

= 13 g/554.5 g × 100 %

= 0.0234 × 100 %

= 2.34 %

So, the percentage by mass of sugar present % m/m = 2.34 %

What process takes place when hydrogen-3 and hydrogen-2 combine to form
helium-4 plus a neutron?

A. Fusion
B. Alpha decay
C. Beta decay
D. Fission

Answers

Answer:

A. Fusion

Explanation:

Potassium (K):
g/mol?

Answers

19 g/mol (pic below)

Name two types of silk

Answers

Answer:

Tussar silk

Charmeuse

Explanation:

Hope this helps! :)

A student is provided with a sample of iron pyrite and a sample of gold. Suggest how the student could distinguish between the two substances

Answers

Answer:

Gold and pyrite both have a brilliant metallic luster, but are different tones of yellow. Gold is golden to silvery yellow, whereas pyrite is a pale to medium brassy yellow that sometimes tarnishes.

Explanation:

What is the limiting reactant in a reaction where 10.0 mol of iron is treated with 12.0 mol of bromine? The product that forms is FeBr3. First, write and balance the chemical equation. Next, calculate the moles of FeBr3 that can be made from 10.0 mol of Fe. Then calculate the moles of FeBr3 that can be made from 12.0 mol of bromine. The smaller amount of FeBr3 reveals the limiting reactant.

Answers

Answer: The limiting reagent in the reaction is bromine.

Explanation:

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

Given values:

Moles of iron = 10.0 moles

Moles of bromine = 12.0 moles

The chemical equation for the reaction of iron and bromine follows:

[tex]2Fe+3Br_2\rightarrow 2FeBr_3[/tex]

By the stoichiometry of the reaction:

If 3 moles of bromine reacts with 2 moles of iron

So, 12.0 moles of bromine will react with = [tex]\frac{2}{3}\times 12.0=8moles[/tex] of iron

As the given amount of iron is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Hence, bromine is considered a limiting reagent because it limits the formation of the product.

Thus, the limiting reagent in the reaction is bromine.

I need to know the answer to this question

Answers

Answer:

your awnser would be 72.1

Explanation:

hope this helps have a good day :]

WHAT IS A SAFE WAY TO BAKE SODA IN THE OVEN WITHOUT IT SPEWING EVERYWHERE?

Answers

put the glass lid on and turn or turn down the heat

How does a nuclear reactor produce electricity

Answers

Answer:

Explanation:

Nuclear reactors are the heart of a nuclear power plant. They contain and control nuclear chain reactions that produce heat through a physical process called fission. That heat is used to make steam that spins a turbine to create electricity. Nuclear power plants use heat produced during nuclear fission to heat water. The heat produced during nuclear fission in the reactor core is used to boil water into steam, which turns the blades of a steam turbine. As the turbine blades turn, they drive generators that make electricity

How many moles in 4.65 g of Helium?

Answers

Answer:

4.65 g x 1 mol/4.0026 g/mol = 1.162 mol helium

Explanation:

Please somone help me with a chemistry question brainliest to whoever answers correctly and 20 points

Answers

Answer:

3132 is the answer

Explanation:

3BaCl2 + Al2S3 → 3BaS + 2AlCl3

Answer:

Explanation:

Hope this helps u !!

A gas has a volume of 1000.0 mL at a temperature of 20.OK and a pressure
of 1.0 atm. What will be the new volume when the temperature is changed
to 40.0K and the pressure is changed to
0.5 atm?

Answers

Answer:

4000mL

Explanation:

Using the combined gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information given in this question:

V1 = 1000mL

T1 = 20K

P1 = 1.0atm

V2 = ?

P2 = 0.5atm

T2 = 40K

Using P1V1/T1 = P2V2/T2

1 × 1000/20 = 0.5 × V2/40

1000/20 = 0.5V2/40

50 = 0.5V2/40

50 × 40 = 0.5V2

2000 = 0.5V2

V2 = 2000/0.5

V2 = 4000mL

The solubility of gases in liquids The solubility of gases in liquids increases as temperature increases and increases as pressure increases. increases as temperature increases and decreases as pressure increases. decreases as temperature increases and decreases as pressure increases. decreases as temperature increases and increases as pressure increases. is independent of temperature and increases as pressure increases.

Answers

Answer:

As the kinetic energy of the gaseous solute increases, its molecules have a greater tendency to escape the attraction of the solvent molecules and return to the gas phase. Therefore, the solubility of a gas decreases as the temperature increases.

Explanation:

As the kinetic energy of the gaseous solute increases, its molecules have a greater tendency to escape the attraction of the solvent molecules and return to the gas phase. Therefore, the solubility of a gas decreases as the temperature increases

Scenario 1: Sarah, your lab partner, accidentally poured too much
sodium chloride (chemical) into a beaker. She wants to pour the rest back
into the original container. What should you do? Explain
Scenario 2: You notice that yout lab partner is chewing gum and using a
beaker as a cup to get water. He then takes a drink from the beaker. He
assures you that it is clean and you don't have to worry. Why is this
dangerous in lab? Explain.
Scenario 3: In lab, you are working with an open flame (a birthday
candle) and your friend calls you over to see new background picture on
his chromebook. What should you do? Explain

Answers

Scenario one: you should ask for help from your teacher to assist
Scenario 2: chemicals have been on beakers and they should not be drank out of, your partner should also not be eating or drinking in the lab.
Scenario 3: you should never walk away from an open flame

According to this balanced equation, how many grams of water (H.0) form in
this reaction?
Beo
2HCI
+
BeCl2
79.919
Н,0
?
25.019
72.919
A. 177.84 grams
B. 127.82 grams
C. 32.00 grams
O D. 18.02 grams

Answers

Answer:

your simpal answer is 177.32

If you could somehow travel inside an atom and look around, what part of the atom would you want to look at? What would you want to understand better as a result of your "travels"? Write your answers in 2-3 paragraphs.

Answers

Answer:

See explanation

Explanation:

The interior of the atom is composed of electrons which move around in orbits and the nucleus. The nucleus contains protons and neutrons. The electrons are negatively charged while the protons are positively charged, the neutrons have no charge at all.

The atom is held together by electrostatic interaction between the electrons and protons in the nucleus. The protons and neutrons account for most of the mass of the atom.

The greatest wonder that I will like to really understand in the interior of the atom is the nature of the interaction between the neutrons and protons in the atomic nucleus which holds the nucleons together. The neutrons have no charge while the protons are positively charged. What sort of interaction could exist between an uncharged particle and a charged particle? That is what I will like to understand better as a result of my travels into the interior of the atom.

Answer:

help

Explanation:


An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the
substance absorbed 5895 J of energy. What is the specific heat of the substance?

A. 5895 J/(g*C)
B. 4.18 J/(g*C)
C. 4.84 J/( g*C)
D. O.06 J/(g*C)

Answers

Answer:

A. 5895 J/g*C)

Explanation:

An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the substance absorbed 5895 J of energy.

Angiosperms produce brightly colored blooms and sweet-smelling flowers. Why have angiosperms developed these adaptations? A. to ensure seed dispersal B. to keep predators from eating the plants C. to attract pollinators and help ensure fertilization D. to allow time for seed development

Answers

Answer:

C

Explanation:

Angiosperms have developed these adaptations because it attracts pollinators which helps the ecosystem grow.

Use the reaction N2(g) + 3H2(g) 2NH3(g) to answer the following questions

a. 1 pt: What does Le Châtelier's principle predict would happen to the equilibrium conditions if N2(g) + 3H2(g) were added to the system?

b. 1 pt: What would happen to the equilibrium if the pressure were decreased?

c. 2 pts: Write the equation for calculating Keq

d. 3 pts: Calculate the value for Keq given the following concentrations

[NH3] = 6 M

[H2] = 4 M

[N2] = 3 M

Answers

Answer:

Explanation:

a ) If N₂(g) and 3H₂(g) is added to the system , 2 moles of additional  ammonia will be produced .

b ) If pressure is decreased , less amount of ammonia will be formed, because forward reaction reduces the pressure. So, reaction will take place in reverse direction.

c ) Keq = [ NH₃ ] ² / [ N₂ ] [ H₂]³

d ) Substituting the given values in the equation ,

Keq = [ 6M ] ² / [ 3M] [ 4M]³

= 36 / 3 x 64 M⁻²

= 18.75 x 10⁻² M⁻² .

help bc i need it lol

Answers

Answer:

2 XE + 1 AB. --> 1 AE2 + 2 XB

Above equation is now balanced

Which is a characteristic of nuclear fission?

Answers

Answer:

Contrasting Nuclear Fission and Nuclear Fusion

Nuclear FissionByproducts of the reaction: Fission produces many highly radioactive particles.Conditions: Critical mass of the substance and high-speed neutrons are required.Energy Requirement: Takes little energy to split two atoms in a fission Explanation:

Which of the following is the strongest acid?
a.pH = 12
b.pOH = 5
c.[H+] = 1 x 10-8
d.pOH = 12

Answers

Answer:

d. pOH = 12 => pH = 14 - 10 = 2 => most acidic

Explanation:

pH = -log[H⁺] => [H⁺] = 10^-pH

By definition, if ...

[H⁺] > 10⁻⁷ > [OH⁻] => pH < -log(10⁻⁷) < 7 => pOH > 14 - 7 > 7 => acidic solution

[H⁺] = 10⁻⁷ = [OH⁻]  => pH = -log(10⁻⁷) = 7 => pOH = 14 - 7 = 7 => neutral solution

[H⁺] < 10⁻⁷ < [OH⁻]  => pH > -log(10⁻⁷) > 7 => pOH < 14 - 7 < 7 => basic solution

∴ From most basic to most acidic ...

a. pH = 12 => most basic

b. pOH = 5 => pH = 14 - 5 = 9

c. [H⁺] = 1 x 10⁻⁸ => pH = -log(10⁻⁸) = -(-8) = 8

d. pOH = 12 => pH = 14 - 10 = 2 => most acidic

Perform the following
mathematical operation, and
report the answer to the correct number of significant figures.

7.68 x 4.564 = [?]

Answers

35.1 i’m not sure it’s it’s correct but that’s what i got

please help me thank u !​

Answers

You should just try your best out what u think it will be okay ! I don’t know the answer I’m sorry

On a warm sunny day, a deer is searching something to drink. The deer is most likely responding to which kind of stimulus?

Answers

Answer:

External stimulus of thirst

Answer:

your answer is:         the external stimulus of thirst

Explanation:

I took the test :)) hope this helps!!!!!!

An electron in a hydrogen atom moves from level 1 to level 4. The electron then drops from level 4 to level 2. Which
statement describes the most likely result?
O The energy absorbed in the first move equals the energy released in the second move.
O The energy absorbed in the first move is greater than the energy released in the second move.
O The energy released in the first move equals the energy absorbed in the second move.
O The energy released in the first move is greater than the energy absorbed in the second move.

Answers

Answer:

The energy absorbed in the first move is greater than the energy released in the second move

Explanation:

Electrons require (absorb) energy to move to a higher energy level when there is a large external heat source, the presence of an electric field or by colliding with other electrons

And the amount of energy absorbed by the electron is exactly equal to the change in the energy state between the initial energy level of the electron and the destination energy level

Therefore, given that the energy level of the electron at level 2 is higher than the energy level of the electron when at level 1, we have;

The difference in the energy level between level 4 and level 1 is greater than the difference in the energy level between level 4 and level 2 and more energy is absorbed and therefore, released when the electron moves from level 1 to level 4 than when the electron drops from level 4 to level 2.

The most likely result is that 'the energy absorbed in the first move is greater than the energy released in the second move'.

PLEASE HELP

If 62.6 g of lead (II) chloride is produced, how many grams of lead (II) nitrate were reacted?

Answers

Answer: The mass of lead (II) nitrate required is 74.52 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of lead (II) chloride = 62.6 g

Molar mass of lead (II) chloride = 278.1 g/mol

Plugging values in equation 1:

[tex]\text{Moles of lead (II) chloride}=\frac{62.6g}{278.1g/mol}=0.225 mol[/tex]

The chemical equation for the reaction of lead (II) chloride and sodium nitrate follows:

[tex]Pb(NO_3)_2+2NaCl\rightarrow PbCl_2+2NaNO_3[/tex]

By the stoichiometry of the reaction:

1 mole of lead (II) chloride is produced from 1 mole of lead (II) nitrate

Then, 0.225 moles of lead (II) chloride will react with = [tex]\frac{1}{1}\times 0.225=0.225mol[/tex] of lead(II) nitrate

Molar mass of lead (II) nitrate = 331.2 g/mol

Plugging values in equation 1:

[tex]\text{Mass of lead (II) nitrate}=(0.225mol\times 331.2g/mol)=74.52g[/tex]

Hence, the mass of lead (II) nitrate required is 74.52 g

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