Answer:
All fossils in the rock layers on Earth
it is important
Explanation:
please make me brain list answer
PLEASE ANSWER BEFORE 2PM C JUNE 8TH, 2021. Four students were trying to apply their knowledge of cell theory to scenarios outside of the classroom. Here is what each said.
What student best applied cell theory to the real world?
Answer:
Hi, there it's Jasmine because the cell theory consist
1. All living things are made of cells
2. Cells are basic unit of life in living things
3. All new cells are created from preexisitng cells
Explanation:
So, the answer is Jasmine
Give three reasons why you might have a situation in which bacterial colonies were found on the first section of a streak plate, but not on sections two and three.
Hi. You have not shown the sections this question refers to, nor have you provided more information about those sections. This makes it difficult for your question to be answered. However, I will try to help you as best I can.
Generally speaking, we can consider that there was no growth of bacterial colonies in sections 2 and 3, because, for some reason, the bacteria was not inoculated in sections 2 and 3. What could also have happened, is that the bacteria in the sections 2 and 3 were eliminated, but the bacteria from section 1 managed to survive and form colonies.
Another possibility is that after inoculating the bacteria in section 1, you didn't handle the bacteria correctly in the other sections, leaving that bacteria to dry out and die.
Finally, the culture media in sections 2 and 3 could be inappropriate for bacteria to develop and form colonies.
What 2 things change about the molecules of different states of matter?
Answer: speed and proximity
Explanation:
science
Explanation:
heating and evaporation
Nicholas,, a 3 year-old boy, is brought into your gastroenterology practice by his mother. They were referred to you by their pediatrician because Ali has been complaining of severe abdominal pain, especially after eating, for the past few weeks. He has an otherwise normal health history. His pediatrician ordered a fecal occult (hidden) blood test, hematocrit, and urinalysis. The fecal occult blood test is positive and the hematocrit (red blood cell count) is lower than normal for a child his age. Body temperature and urinalysis are normal.
You perform a surface abdominal exam, which appears normal, but Ali complains of pain in the lower right abdominal quadrant during palpitation. You order a CT enterography procedure, which uses a contrast dye to make an X-ray of the small intestine. The CT shows a diverticulum. After confirmation with a technetium scan, you diagnose Nicholas withMeckel’s diverticulum.
Treatment for Meckel’s diverticulum includes surgical removal of the diverticulum.
What do you mean by diverticulum?
Diverticulum is a small pouch or sac that forms in the wall of the digestive tract. It can occur in any part of the digestive tract, including the esophagus, stomach, small intestine, and large intestine. Diverticula can cause symptoms such as abdominal pain, constipation, and diarrhea.
You recommend that Nicholas have a laparoscopic removal of the diverticulum, a minimally invasive procedure that involves making small incisions in the abdomen and inserting a camera and surgical tools to remove the diverticulum. You explain to Nicholas’ mother the benefits of the procedure and the potential risks associated with it.
After the procedure, you recommend that Nicholas follow up with his pediatrician in two weeks. You also suggest that Nicholas and his mother modify his diet to include more fiber and fluids to help ease his symptoms and prevent the diverticulum from returning. You also suggest that Nicholas take an antacid to help reduce the abdominal pain.
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#SPJ1
Which of the following is not a product of glycolysis?
True
False
Answer:
We need a full question it's a half question
ecologically, termites are classified as a carnivore b, detritivores c, insectivore d, herbivore
Answer:
b. detritivores
Explanation:
Detritivores (also known as detrivores, detritophages, detritus feeders, or detritus eaters) are heterotrophs that obtain nutrients by consuming detritus (decomposing plant and animal parts as well as faeces).
10 POINTSSSSSSSSS!!!!!!!!!!!!!!!!!!
Answer:
13. A group of Roaches moving in a group
14. Stepping on the Roaches to kill them
Answer: First image shows 3 groups with 14 Roaches in each group moving towards an human.
Second image shows the human stepping on the middle group of roaches.
Explanation: Roaches are nasty. Get an exterminator, ya nasty.
hola como estan soy nueva
Answer:
Buena gracias
Explanation:
When proteins help transport molecules in and out of the cell, it is called _____.
passive diffusion
facilitated diffusion
active transport
endocytosis and exocytosis
Answer:answer is active transport
Explanation:
"S PRACTICE Exam#1 68Qs.doc
PII CVS PRACTICE Exam#1 68Qs.doc (69 KB)
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30. The largest cells in the blood that leave the bloodstream to become macrophages are th
A. Neutrophils
B. Eosinophils
C. Lymphocytes
D. Monocytes
21
ruthroblastocie fatalie also
Your Answer will be D. Monocytes
[tex] \frak{hope \: it \: helps \: you.....}[/tex]
Answer:
The largest cells in the blood that leave the bloodstream to become macrophages are the
Monocycles
Vaccines are effective in preventing disease because they:
a
Interfere with the release of Suppressor T-Cells
b
Are antibodies directed against specific pathogens
c
Trigger Memory B-Cell & antibody formation
d
None of the Above
Answer:
C. Trigger memory B-cell and antibody formation
why do we find tea to be tasteless after we have eaten sweet or candies
Explanation:
The answer is that when you eat the sweet candies and chocolates the buds will remain sweet so that's why the tea become tasteless. The buds only relive the sweetness by staying for few minutes or eat something else.
I hope this answers to your question
Hydrothermal vent ecosystems do not have sunlight available, and hence there are no kinetic energy. Instead, play the role of on which other organisms rely for energy. They compounds such as hydrogen sulfide to obtain energy for themselves. This energy is used to sugar molecules. create an additional energy transfer when they these sugars or eat each other. As in other ecosystems, organisms in hydrothermal vent communities also transform into other forms, such as (energy of motion).
Answer:
- Hydrothermal vent ecosystems do not have sunlight available and hence there are no photoautotrophs.
- Instead, chemoautotrophs play the role of producers on which other organisms rely for energy. They oxidize compounds such as hydrogen sulfide to obtain energy for themselves. This energy is used to synthesize sugar molecules.
- Consumers create an additional energy transfer when they utilize these sugars or eat each other.
- As in other ecosystem organisms in hydrothermal vent communities also transforms chemical energy into other forms such as kinetic energy (energy of motion).
Explanation:
A hydrothermal vent is a geyser on the seafloor that is generated by underwater volcanoes or tectonic activity through which geothermally heated water erupts. Hydrothermal vent ecosystems contain hydrothermal microorganisms which are able to survive just outside the hottest waters. For example, Methanopyrus kandleri are hyperthermophile prokaryotic microorganisms that live in these ecosystems where they produce methane from reducing CO2. Chemosynthesizers are able to convert carbon molecules (e.g., CO2) and nutrients into organic matter by the oxidation of inorganic compounds such as hydrogen sulfide and/or ferrous ions. Moreover, hydrothermal vent ecosystems have the potential to support high biomass and productivity levels due to the establishment of symbiotic relationships between chemosynthesizers with respiring heterotrophs, which obtain energy from other organisms. Chemosynthesizers are eaten by other organisms (e.g., amphipods and copepods), whereas larger organisms (e.g., snails and crabs) form predator and prey relationships above these primary consumers.
This is the type of ecosystem found on seafloor with geothermally heated water discharges. It lacks sunlight and there are no presence of photoautotrophs.
Organisms present mostly convert chemical energy into other available forms.
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As the most junior member of a lab, you are tasked with generating cell lines that accumulate DNA damage to investigate how random mutations affect transformation of cells into cancer cells. You decide to mutate proteins in the p53 pathway. Which three proteins would you mutate
Answer:
In p53 pathways, 3 proteins which are mutate and cause cancer that proteins are:
1.BRCA2
2. p53 in Rb genes binds with deoxyribonucleic acid that stimulates another gene to produce a protein known as p21 that interacts with cdk2. When p21 is combined with cdk2 cell will not pass through to the next stage of cell division. This is Li-Fraumeni syndrome (when p53 causes cancer from parents to offspring)
3.BRCA1
The parent that transmits mutation in one of these genes has a 50% chance of inheriting the mutation. The effects of mutations in BRCA2 and BRCA1 are seen when the person's second copy of the gene is normal.
in a cell all organells works together to carry out ?
Answer:
Cell organelles must work together to carry out protein synthesis, utilize proteins within the cell, and transport them out of the cell.
Why is it important to know the proper ways on how to sustain Earth's resources?
⚠Nonsense = Report
Answer:
Sustainability is important for many reasons including: Environmental Quality – In order to have healthy communities, we need clean air, natural resources, and a nontoxic environment. ... We need clean air, natural resources, and a nontoxic environment.
What is transaction between school and post school destination
Answer:
The transition between school to a post school is a difficult phase in one's life because it opens a lot of adjustments whether it is socially, mentally and/or psychologically. Most students find it difficult to transfer because of these following reasons visit these links and see the answers below: brainly.ph/question/2641856, brainly.ph/question/2635171, brainly.ph/question/2627976
There are a bunch of strangers. Not all students are gifted with an extropersonal skills that allows them to make friends easily. Transition makes it difficult for introvert pupils to accept.
The new school is bigger than their previous school. Though in others the size of a place is not bothering their performance, there are individuals who find it difficult to adjust when it comes to the size of their environment. For example a student who studied in a small private school with only one section will find it difficult to adjust moving around a larger environment.
There are different teaching styles coming from the school's faculty. Learning styles are somewhat define by the teacher's teaching styles and strategies. In their previous school, some of the seniors might have already leaked the strategies used by the teacher in their school. But in a post school, some students are 100% newbie wherein they have no idea what is going on inside a class of a single professor or instructor. This is difficult since they do have to observe every single day and learn a new way to follow the lesson's phase.
Friends are not with the same post school. It is said that you can go through anything with your friends but most of the time you will never be with them when you transfer to a post school but still you need to move forward and learn to mix with the public.
Lessons are difficult and new. Most learners are not accustomed in learning quick in a new environment especially when the lesson is more difficult and new.
New policies are too intimidating to break. Some students are struggling when it comes to adjusting to rules whether it is inside the classroom or just a simple campus rule so they feel intimidated and and fearful in breaking one. But it must be remembered that rules keep the society moving forward peacefully.
Explanation:
There are different reason for an individual to fear and feel difficulty adjusting to a post school. But one must remember that humans are created with an adaptability skill that allows us to mix well with a new habitat and environment. Social skills are just part of our adaptability. You can just follow the wind and let the flow take you. Life is a constant change and all you have to do is to embrace it to make yourself belong anywhere you go.
Transaction between school and post school destination is the entering from one stage to another stage of live.
What is transaction between school and post school destination?The transition between school and post school destination means that the youth is ready for next stage of their lives. The perfect transition of the students from high school to college or the adult world is very important.
This is because these years provides the direction to the students for their future so we can conclude that transaction between school and post school destination is the entering from one stage to another stage of live.
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Which of the following statements best explains the hypothesis that the development of sexual reproduction has resulted in acceleration of the rate of evolution?
(A) Mutations are more likely to occur in spermatogenesis and oogenesis than in mitotically dividing cells.
(B) Sexual reproduction results in more offspring than does asexual reproduction.
(C) Those members of a species that are best adapted to their environment are most likely to be successful in sexual reproduction.
(D) Mutations usually do not occur in the production of spores or in cells dividing by fission.
(E) Sexual reproduction is more likely to result in genetic recombination than is asexual reproduction.
Answer:
c
Explanation:
A cross between a plant with red flowers and a plant with white flowers produces offspring with pink flowers. What is this an example of?
Answer:
Example of incomplete dominance
Explanation:
the offspring is different the parent
The information in DNA in the nucleus is used to produce
Answer:
Proteins
Explanation:
DNA courses can be turned into messages that can be used to make proteins
A series of experiments shows that oil content in a diploid grain is influenced by five genes (a through e) with additive alleles. The highest producing strain is 20% oil content; the lowest has close to 0%. A plant of unknown genotype has an oil content of 12%. What is a possible genotype for this plant
Answer:
All the possible genotypes of the plants that have an oil content of 12% include six dominant alleles. Following we are mentioning some of them
AABbCcDdEe, AaBBCcDdEe, AaBbCCDdEe, AaBbCcDDEe, AaBbCcDdEE
Explanation:
Due to technical problems, you will find the complete explanation in the attached files.
The possible genotypes involving a combination of six dominant alleles required for the grain to have an oil content of 12% are:
AABbCcDdEe, AaBBCcDdEe, AaBbCCDdEe, AaBbCcDDEe, AaBbCcDdEE
Additive alleles are alleles which result from polygenic traits.
Polygenic traits are traits which are encoded by several genes resulting in more than two alleles contributing to the phenotype.
The phenotype of additive alleles is continuous due to the many different combinations of the alleles of the genes.
From the data provided:
oil content in a diploid grain is influenced by five genes: a, b, c, d, e The highest producing strain is 20% oil content The lowest has close to 0%Since the grain is diploid, grains that are:
h0m0zygous recessive for the five genes, aabbccddee, will have 0% oil content.h0m0zygous dominant for the five genes, AABBCCDDEE, will have 20% oil content.Each dominant gene will contribute 20% / 5 = 4% of oil content.
Since the grains are diploid, each dominant allele will equally contribute 4% / 2 = 2% to the oil content.
Thus:
0 dominant allele → 0% oil content 1 dominant allele → 2% oil content 2 dominant alleles → 4% oil content 3 dominant alleles → 6% oil content 4 dominant alleles → 8% oil content 5 dominant alleles → 10% oil content 6 dominant alleles → 12% oil contentTherefore, a combination of six dominant alleles are required for the grain to have an oil content of 12%.
All the possible genotype involving a combination of six dominant alleles required for the grain to have an oil content of 12% are given below:
AABbCcDdEe, AaBBCcDdEe, AaBbCCDdEe, AaBbCcDDEe, AaBbCcDdEE.
Learn more about phenotypes, genotypes, genes and alleles at: https://brainly.com/question/1193907
The closest living ancestors of birds are crocodilians. What provides morphological evidence for this relationship?
a) both are homeothermic
b) both have extensive air sac system
c) both have a 4-chambered heart
d) both have differentiated teeth
e) none of the above
Answer:
c) both have a 4-chambered heart
Explanation:
The heart that consists of four chambers where the blood flows. In this, the blood entered into the right atrium and passes via the right ventricle. Now the right ventricle pumps the blood into the lungs in which it is oxygenated. Now the oxygenated blood would be bring back to the heart via the pulmonary veins that entered into the left atrium
So as per the given situation, the option c is correct
A mutation in Complex I decreases the efficiency of the electron transport chain. However, not all components of the electron transport chain are affected by this mutation. Which component of the electron transport chain will remain unaffected by a mutation in Complex I?
a. Ubiquinone
b. Complex II
c. Complex III
d. Complex IV
Answer:
b. Complex II
Explanation:
The electron transport chain is a sequential series of proteins located in the inner membrane of the mitochondria that act to transfer electrons from different members of the transport chain in a series of redox reactions, which is coupled to the movement of protons (H+) across the membrane. Complex I (also called NADH dehydrogenase or NADH- CoQ reductase) accepts electrons from NADH and passes them to Complex III (also known as coenzyme Q reductase), which also receives electrons from Complex II (succinate coenzyme Q reductase). Ubiquinone (Coenzyme Q) accepts electrons from both complex I and complex II and transfer them to complex III. From complex III electrons pass to complex IV through cytochrome c oxidase and finally to molecular oxygen (O2, the final electron acceptor). In consequence, Complex I and Complex II are linked by different pathways to Complex III, thereby it is expected that Complex II remains unaffected by a mutation in Complex I.
………………………………………………………………….
whats with the dots ._.
Describe the neural and renal mechanisms that control blood pressure.
Answer:
The autonomic nervous system is the main neural regulator of circulation and blood pressure in the short term and beat by beat and exerts its function through various reflexes that regulate vasomotor tone, heart rate and cardiac output. At the renal level, the renin–angiotensin–aldosterone system is possibly the most important in the maintenance of arterial homeostasis.
Explanation:
Blood pressure is regulated by a series of interrelated autonomic systems and humoral reflexes, which continually adjust the determining elements of the system (heart rate, stroke volume, total peripheral resistance and circulating volume).The effective circulating volume is controlled by a series of reflex systems, which obtain information about the perfusion pressure (baroreceptors in the carotid bulb and aortic arch), plasma osmolarity (hypothalamus) and urinary sodium (distal tubule).The kidney has its own self-regulatory mechanisms. The reduction in renal blood flow is detected at the level of the mesangial cells of the juxtaglomerular apparatus, starting the renin-angiotensin system. The increase in angiotensin II produces on the one hand local vasoconstriction, and on the other hand stimulates the production of aldosterone by the adrenal cortex with the consequent tubular reabsorption of sodium and water.Antidiuretic hormone or vasopressin (released from the hypothalamus by stimulation of arterial baroreceptors and also by stimulation of angiotensin II) also acts at the renal level, which acts as a powerful and water-saving vasoconstrictor in the distal tubule.
(c) Predict the growth rate pattern of the E. coli-M bacteria when they are initially added to the growth medium if the mutation does not interfere with glucose utilization.
(d) Provide reasoning to justify your prediction.
The question is incomplete. The complete question is :
Glucose is the preferred carbon source for Escherichia coli bacteria. Researchers isolated E. coli-M, a strain of E. coli with a single mutation that inactivates a key enzyme in one of the three glycolytic pathways E. coli bacteria use to break down glucose. In an initial experiment to study the effect of the mutation on glucose utilization and ATP production by the bacteria, the researchers add 2×104 E. coli-M bacteria to 400 mL of a growth medium that contains glucose. To measure the rate of bacterial growth, they monitor the optical density of the culture as a measure of bacterial concentration over time.
(c) Predict the growth rate pattern of the E. coli-M bacteria when they are initially added to the growth medium if the mutation does not interfere with glucose utilization.
(d) Provide reasoning to justify your prediction.
Solution :
c). It is given that Glucose is preferred as the carbon source for the Escherichia coli bacteria or the E. coli-M bacteria. If the growth medium of the E. coli-M bacteria contains a higher concentration of the acetate, then the growth of the bacteria will inhibit without inhibiting the central metabolism.
d). This is predicted because as E. coli-M bacteria grows, it starts secreting acetate. This is known as overflow mechanism. The regulatory interactions mediated by the acetyl-phosphate that plays an important role in the inhibiting growth by the acetate.
Can somebody help me?
Answer:
Sorry but this isn't clear. What I understood was something related to meosis or something. Not sure tho. Plz post it clear so that you do get answer
Explanation:
Choose All that apply !!
Help!!
Answer:
1.5
Explanation:
The greatest probability must not exceed 1
[tex] { \boxed{ \sum(P) \leqslant 1}}[/tex]
How does water move around the ocean?
You have a novel virus that can kill mice when injected into them. This novel virus can transform a non-virulent virus, causing it to become virulent. You want to understand what the transforming factor is made of. You heat kill the novel virus and treat different samples of the heat killed sample with either an RNase, a DNase, or a Proteinase. Of the novel virus uses double-stranded RNA as its genetic material, which treated sample will no longer be capable of transforming the non-virulent strain
Answer:
The sample treated with RNase
Explanation:
According to this question, a novel virus was found which was capable of killing mice when injected into them and capable of making a nonvirulent virus to be virulent by transforming them.
After heat killing the novel virus, different samples were treated with either an RNase, a DNase, or a Proteinase. If the novel virus uses double-stranded RNA as its genetic material, the sample treated with RNase will no longer be capable of transforming the non-virulent strain. This is because RNase is a catalytic enzyme that degrades RNA, hence, the RNA will no longer be present to transform.