What is the z value for calcium atom with 35neutrons?

Answers

Answer 1

The atomic number of calcium i.e. Z value is 20 with 35 neutrons and 20 electrons.

What is atomic number?

Atomic number is defined as a chemical element's nuclear charge number (symbol Z) is the charge number of an atomic nucleus.
It can also be defined as  the number of protons or positive charges in the nucleus of an atom of a specific element, and thus the number of electrons generally surrounding the nucleus.

The number of protons is equal to number of number of electrons.

Thus. the atomic number of calcium i.e. Z value is 20 with 35 neutrons and 20 electrons.

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Related Questions

how many moles of sulfur dioxide are needed to form 2.31 moles of sulfur trioxide

Answers

Answer:

[tex]2.31\text{ moles}[/tex]

Explanation:

Here, we want to get the number of moles of sulfur dioxide needed to form 2.31 moles of sulfur trioxide

The first thing we would be needing here is to write the equation of the reaction

We have that as:

[tex]SO_2\text{ + }\frac{1}{2}\text{O}_2\text{ }\rightarrow\text{ SO}_3[/tex]

From the equation of reaction, the number of moles are in the same ratio

1 mole of sulfur dioxide formed 1 mole of sulfur trioxide

That means:

2.31 moles of sulfur trioxide was formed from 2.31 moles of sulfur dioxide

The energy stored in the chemical bonds of a carbohydrate molecule isA. specific heat. B. Kinetic energy. C. potential energy. D. worked.

Answers

Answer

C. Potential energy

Explanation

A carbohydrate molecule has chemical bonds, Potential energy is available between chemical bonds.

2. What is the percent sulfur in iron (III) sulfate?

Answers

Step 1

The chemical formula of iron (III) sulfate is the next one:

Fe2(SO4)3

As we can see, there are 3 x 1 atom of S, 3 atoms of S

----------------

Step 2

Information needed:

The atomic masses of:

Fe) 55.8 g/mol

S) 32.0 g/mol

O) 16.0 g/mol

(Please, the periodic table is useful here)

----------------

Step 3

The % of S in Fe2(SO4)3 is calculated as follows:

[tex]\frac{3\text{ x 32.0 g/mol of S}}{(2\text{ x 55.8 g/mol Fe + 3 x 32.0 g/mol S + 3 x 4 x 16.0 g/mol O\rparen}}x100\text{ = 24.0 \%}[/tex]

Answer: 24 % of S

Predict the missing component
in the nuclear equation.
209/84 Po → 205/82 Pb + X

Answers

The missing component in the nuclear equation [tex]\frac{209}{84} Po\\[/tex] → [tex]\frac{205}{82}Pb[/tex] + X is predicted to be [tex]\frac{4}{2} He[/tex].

This nuclear reaction is form of an alpha decay process. In this alpha decay process, the nucleus gets decayed through the release of an alpha particle. The mass number of the nucleus is decreased by 4 units and atomic number of the nucleus is also reduced by 2 units. The particle which is released is nucleus of helium.

The general equation which represents the alpha decay process is -

[tex]\frac{A}{Z} X[/tex] → [tex]\frac{A-4}{Z-2} Y[/tex] + [tex]\frac{4}{2} \alpha[/tex]

The nuclear equation is -

[tex]\frac{209}{84}Po[/tex] → [tex]\frac{205}{82} Pb[/tex] + X

We will balance the reaction and we have to remember in balancing the nuclear equation is that the sums of the superscripts and the subscripts has to be the same on both sides of the equation.  

Sum of superscripts : 210 = 206 + y,

                                   so, y =4.  

Sum of subscripts : 84 = 82 + x,

                                    so, x = 2.

Therefore, the nuclear equation is -

[tex]\frac{209}{84} Po[/tex] → [tex]\frac{205}{82} Pb[/tex] + [tex]\frac{4}{2} He[/tex]

Hence, the missing component is [tex]\frac{4}{2} He[/tex].

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1. For the reaction CO(g) + NO₂(g) → CO₂(g) + NO(g), a CO₂ concentration of 0.040
moles/liter was measures at 2 seconds. What was the average reaction rate
for this reaction? (Please note that at t = 0, no CO₂ was present.)

Answers

Average reaction rate is 0.02 mol/liter/sec

What is an average reaction rate?

Change in concentration divided by the change in time gives average reaction rate. The rate of a chemical reaction is measured in mol/l/s.

Average rate is defined as the change in molar concentration of either reactants or products in time is called as average rate. The concentration of reactants decreases during reaction, whereas the concentration of products keeps on increasing until an equilibrium is reached.

Evaluating an average rate shows the amount of change of one variable with respect to another. The other variable is generally time that describes the average change in distance or chemical concentrations.

For the given reaction

CO(g) + NO₂(g) → CO₂(g) + NO(g), a CO₂

concentration of 0.040

moles/liter was measured at 2 seconds.

Average reaction rate = concentration/ time

0.040/ 2

=0.02 mol/l/sec

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Starting with the following equation,

Fe₂O₃(s) + Al(s) → Fe(l) + Al₂O₃(s)

calculate the moles of Fe₂O₃ that will be required to produce 645 grams of Fe.

Where do i start and how do I calculate? Need help please

Answers

The number of moles of Fe₂O₃ that will be required to produce 645 grams of Fe is 5.78 moles

How to determine the moles of Fe₂O₃ needed

We'll begin by obtainig the number of mole of Fe. This can be obtained as follow:

Mass of Fe = 645 gramsMolar mass of Fe = 55.85 g/molMole of Fe =?

Mole = mass / molar

Mole of Fe = 645 / 55.85

Mole of Fe = 11.55 moles

Finally, we shall determine the number of moles of Fe₂O₃ needed. Details below

Fe₂O₃(s) + 2Al(s) → 2Fe(l) + Al₂O₃(s)

From the balanced equation above,

2 moles of Fe were produced from 1 mole of Fe₂O₃

Therefore,

11.55 moles of Fe will be produce from = (11.55 × 1) / 2 = 5.78 moles of Fe₂O₃

Thus, the mole of Fe₂O₃ needed is 5.78 moles

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(4.4) Which reactant is in excess and what quantity (in moles) are in excess after the acid-base
meutralization reaction of 250 mL of 0.127 M sulfuric acid with 0.200 L of 0.254 M NaOH?
H₂SO4) +2 NaOH → NaSO4) + 2 H₂O

Answers

Taking into account the reaction stoichiometry, H₂SO₄ is the reactant in excess and 0.00635 moles are in excess after the acid-base neutralization reaction.

Definition of molarity

Molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity= number of moles÷ volume

Molarity is expressed in units moles/ L.

Reaction stoichiometry

In first place, the balanced reaction is:

H₂SO₄ + 2 NaOH  → Na₂SO₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂SO₄: 1 moleNaOH: 2 moles  Na₂SO₄: 1 moleH₂O: 2 moles

Limiting reagent

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

Reactant in excess in this case

You have the acid-base neutralization reaction of:

250 mL (0.250 L, being 1000 mL equal to 1 L) of 0.127 M sulfuric acid.0.200 L of 0.254 M NaOH.

Considering the definition of molarity, you can get the amount of each compound that you have in this reaction:

H₂SO₄: 0.250 L× 0.127 M= 0.03175 molesNaOH: 0.200 L× 0.254 M= 0.0508 moles

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of H₂SO₄ reacts with 2 moles of NaOH, 0.03175 moles of H₂SO₄ reacts with how many moles of NaOH?

moles of NaOH= (0.03175 moles of H₂SO₄× 2 moles of NaOH)÷ 1 mole of H₂SO₄

moles of NaOH= 0.0635 moles

But 0.0635 moles of NaOH are not available, 0.0508 moles are available. Since you have less mass than you need to react with 0.03175 moles of H₂SO₄, NaOH will be the limiting reagent and H₂SO₄ will be the excess reagent.

To determine the amount of excess reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 2 moles of NaOH reacts with 1 mole of H₂SO₄, 0.0508 moles of NaOH reacts with how many moles of H₂SO₄?

moles of H₂SO₄= (1 mole of H₂SO₄× 0.0508 moles of NaOH)÷ 2 moles of NaOH

moles of H₂SO₄= 0.0254 moles

If you have 0.03175 moles of H₂SO₄, the amount of moles in excess is calculated as:

moles in excess= 0.03175 moles - 0.0254 moles

moles in excess= 0.00635 moles

Finally, there are 0.00635 moles of NaOH in excess.

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Compare the reactivity of the alkali metals family with the reactivity of thehalogen family. (2 points)

Answers

The alkali metals grow more reactive as you move down the group, but the halogens become less reactive as you move down, which is one distinction between the reactivity of the groups. The most active halogen is fluorine, whereas the most active naturally occurring alkali metal is cesium.

What are halogens and alkali metals ?

The features of the halogen elements' compounds with other elements and their overall chemical behavior are remarkably similar to one another. However, there is a progressive change in characteristics from fluorine through chlorine, bromine, and iodine to astatine, with fluorine and chlorine having the most marked differences between two succeeding elements. In addition to being the most reactive halogen and element overall, fluorine has a few other characteristics that set it apart from the other halogens.

Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Cesium (Cs), and Francium are alkali metals, which are elements of group 1. (Fr). Since they only have one electron in their valence shell, they are extremely reactive and strive to adopt the stable octet configuration of the noble gases. The alkali metals exhibit metal properties such as strong thermal and electrical conductivity, lustre, ductility, and malleability. In the outermost shell of each atom of an alkali metal, there is just one electron.

The alkali metals grow more reactive as you move down the group, but the halogens become less reactive as you move down, which is one distinction between the reactivity of the groups. The most active halogen is fluorine, whereas the most active naturally occurring alkali metal is cesium.

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hello I need help to calculate the corresponding stoichiometric mass in milligrams of CaCO3the answer to number 8 is 2.72 moles and I'll take a picture of equation 2

Answers

We have the balanced equation of the reaction, this is a neutralization reaction.

We have the moles of CO2 generated, equal to 2.72 moles. The number of moles of CaCO3 is found by reviewing the stoichiometric coefficients of equation 2. We have that the ratio CaCO3 to CO2 is 1/1.

Therefore, the moles of CaCO3 will be:

[tex]molCaCO_3=2.72molCO_2\times\frac{1molCaCO_3}{1molCO_2}=2.72molCaCO_3[/tex]

The mass of CaCO3 we will be found by multiplying the moles of CaCO3 by its molar mass. The molar mass of CaCO3 is 100.0869g/mol.

[tex]\begin{gathered} MassCaCO_3=2.72molCaCO_3\times\frac{MolarMass,gCaCO_3}{1molCaCO_3} \\ MassCaCO_3=2.72molCaCO_3\times\frac{100.0869gCaCO_3}{1molCaCO_3}=272.24gCaCO_3 \\ MassCaCO_3=2.72\times10^5mgCaCO_3 \end{gathered}[/tex]

Answer: The mass of CaCO3 needed will be 2.72x10^5 milligrams

What does the author describe in this passage?
The author describes different types of t-shirts.
The author describes reasons for moving to New York City.
The author describes two types of energy.
The author describes the dangers of riding in taxis.

Answers

The author describes about two types of energy, in this passage which is motion energy and heat energy.

What are motion energy and heat energy?

The energy that results from the movement of atoms and molecules within a substance is known as thermal energy, also known as heat energy. These particles generate more heat as they move more quickly. The thermal energy of the earth is referred to as geothermal energy.

Motion energy is energy that is held in the motion of objects. More energy is stored as they move faster. Energy is required to start an object moving, and energy is released when an object slows down. Motion energy includes things like the wind. A car crash is a dramatic example of motion energy; the vehicle comes to a complete stop and abruptly and uncontrollably releases all of its motion energy.

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Determine the empirical formula for each of the following compounds:19% tin and 81% iodine

Answers

Answer

The empirical formula for this compound is SnI₄

Explanation

Given:

% composition: 19% tin and 81% iodine​

What to find:

The empirical formula for the compound

Step-by-step solution:

Assume we have 100 grams total of the substance.

Grams Sn: 19 g

Grams I: 81 g

Now, let's convert the number of grams of each element into moles below:

Moles Sn: 19 g/118.71 g/mol = 0.16 mol

Moles I: 81 g/126.90 g/mol = 0.64 mol

Finally, let's divide the number of moles of each element by the smallest number obtained:

Sn = 0.16/0.16 = 1

I = 0.64/0.16 = 4

Therefore the empirical formula for this compound is SnI₄

im confused help me please

Answers

The energy of an orange lamp with a frequency of 5.10 x 10¹⁴ Hz is 3.38 x 10⁻¹⁹ J.

What is frequency ?

Frequency is defined as the number occurrences of repeated events per unit of time. SI unit is hertz (Hz).

Briefing:

Using the formula,

E = hν

where,

E = energy in joules (J)

h = Planck's constant =  6.63 x 10⁻³⁴ J

ν = frequency in hertz

Given :

Frequency = 5.10 x 10¹⁴ Hz

h = 6.63 x 10⁻³⁴ J

Putting the values,

E = (6.63 x 10⁻³⁴) x (5.10 x 10¹⁴) J

E = 3.38 x 10⁻¹⁹ J

The energy of an orange lamp with a frequency of 5.10 x 10¹⁴ is  3.38 x 10⁻¹⁹J.

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The complete question is -

What is the energy of an orange lamp with a frequency of 5.10 x 10¹⁴ Hz ?

Please help with this

Answers

Answer:

its the 3rd one

Explanation:

Write the ions present in solution of Pb(C2H3O2)2 .

Answers

From the chemical structure of the compound that is clearly shown in the question, the ions that should be in the solution are;  lead II ion and the acetate ion.

What are ions?

The term ions has to do with the species that have a positive charge or a negative charge. Thus we could define an ion as as a charged specie. The charge could owe to an excess of electrons in which case the charge is negative or due to a deficiency of electrons which gives us a positive charge.

Looking at the compound that is in solution, we can see that the ions that are present are lead II ion and the acetate ion.

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What is the total moles of particles in 3.0 L of each of the following solutionhalf-normal NaCl , 0.40 % (m/v) , used to provide electrolytesExpress your answer using two significant figures.

Answers

The given concentration, 0.40% (m/v), is a mass volume percent concentration. It indicates us that there are 0.40g of NaCl in every 100mL of solution.

We can use this information to detemine how many grams of NaCl are there in 3.0L (3000mL) of solution:

[tex]3000mL\cdot\frac{0.40g}{100mL}=12g[/tex]

Now, convert this amount of mass to moles using NaCl molar mass:

[tex]12gNaCl\cdot\frac{1molNaCl}{58.44gNaCl}=0.20molNaCl[/tex]

It means that the corect answer is 0.20 moles of NaCl.

The lithium-iodine battery is used in pacemakers to generate small electrical impulses that trigger the heart to beat according to the following equation. Identify
the species oxidized.
2 Li(s) + I2 (s) → 2 Lil(aq)

Answers

Answer:

The species that oxidizes is lithium, or Li

Explanation:

Since I2 is know to be a halogen, and halogens are oxidizers, iodine is probably not the species being oxidized. So, Li is being oxidized.


Another way to look at the problem is to assign oxidation numbers to all elements on the right and left

The left:
lithium = 0
iodine = 0
Both are 0 since they are in their most stable elemental states

The right:
lithium : +1
Iodine: -1

When something looses an electron and becomes more positive, it is oxidized. Lithium goes from 0 to 1, clearly displaying a rise in oxidization state. So, lithium is being oxidized.

23.When balancing a chemical equation, one uses all of the following principals except...Select one:a. The number of atoms of each element on the reactant side of the equation must equal the number of atoms of each element on the product side of the equation.b. Subscripts in a formula may be changed so that the equation is balanced.c. The coefficients for the reactants and products may be changed to balance the equation.d. The law of conservation of matter must be obeyed.

Answers

Answer:

b. Subscripts in a formula may be changed so that the equation is balanced.

Explanation:

The statement b is not correct, because only the coefficients may be changed to balance the equation. If we change the subscript in a formula, we will change the compound.

A group of similar tissues that perform a specific function is called _______


an organ


a cell


a system


an organism

Answers

Answer: an organ

Explanation:

The answer is an organ

When molecules in a substance vibrate faster and faster, what happens to the temperature of the substance?

Answers

Answer:

The temperature increases (gets warmer)

Explanations

When the molecules in a substsnce vibrate faster ans faster, it shows that there is an increase the spaces between the molecules thereby leading to an increase in the kinetic enrgy of the molecule

The presence of this extra spaces causes the molecule to move freely thereby increasing the temperature of the substance.

In summary, the higher the vibration, the higher the kinetic energy, and the higher the temperature.

Given that the concentration of ascorbic acid is ~0.001 M in lemon juice, is this error significant? Why or why not?

Answers

The concentration of ascorbic acid is approximately 0.001 M in lemon juice, this is not a significant error.

The chemical reactions which can be shown as a simple exchange of valence electron pairs to break the bonds and to form the bonds. It is an acid-base reaction.

We will calculate the number of moles-

Number of moles = Given mass

                                 Molar mass

Moles = 176.1

               4

Moles = 113 mol

Then, moles is divided by the volume of 9.1 L

Concentration = 113/9.1 = 12.4 M

Here, we take the H⁺ concentration.

Significant Error is defined as an error in an assessment where a compound's clinical status is not accurately represented and the error has not been corrected when submission of a more recent result is done.

In chemistry, Significant figures are those digits of value that carries meanings for the correct result of the measurements. All the measurement of the experiments have some kind of uncertainty which are associated with them.

Therefore, the concentration is not significant error.

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Which substance contains particles with the highest average kinetic energy?
A. 1 kilogram of ice
B. 1 liter of water
C. 1 liter of water vapor
D. 1 kilogram of snow

Answers

Answer: C. 1 liter of water vapor

Explanation:

The average kinetic energy increases as follows.

Gas > Liquid > Solid

You can think about it as how fast and freely the molecules are moving in each state, with gases being the greatest.

What volume, in liters, is occupied by 1.5 x 1023 atoms of argon gas (Ar) at STP?

Answers

ANSWER

The volume of Argon gas is 5.60L

STEP-BY-STEP EXPLANATION:

Given information:

The number of atoms of argon = 1.5 x 10^23 atoms

To find the volume of Argon, we need to find the number of moles of argon, then, we assume the number of moles of argon to be x

To find the number of moles, we will need to apply the below formula

[tex]\text{Number of atoms = mole x Avogadro's number}[/tex]

Recall that, Avogadro's number = 6.022 x 10^23

[tex]\begin{gathered} 1.5\cdot10^{23}\text{ = x }\cdot\text{ 6.022 }\cdot10^{23} \\ \text{Isolate x by dividing through by 6.022 }\cdot10^{23} \\ x\text{ = }\frac{1.5\cdot10^{23}}{6.022\cdot10^{23}} \\ x\text{ = 0.2498 mole} \end{gathered}[/tex]

Since x represents the number of moles of argon gas, then, the mole of argon gas is 0.2498 mole.

The next step is to find the volume of Argon in liters

Recall that, at S.T.P, 1 mole is equivalent to 22.4L

Let x represent the volume in liters of argon

Then, this can be solved mathematically below

[tex]\begin{gathered} 1\text{ mole }\rightarrow\text{ 22.4 L} \\ 0.2498\text{ mole }\rightarrow\text{ xL} \\ \text{Mathematically,} \\ 1\text{ = 22.4} \\ 0.2498\text{ = x} \\ \text{Cross multiply} \\ 1\cdot\text{ x = 0.2498 }\cdot\text{ 22.4} \\ x\text{ = }5.60L \end{gathered}[/tex]

Therefore, the volume of Argon gas is 5.60L

Is there any limit to the distance through which diffusion can occur?

Answers

Answer

Yes, there is a limit to the distance through which diffusion can occur. This is because diffusion time increases with the square of diffusion distance. Diffusion time is inversely proportional to the diffusion coefficient. hus, if the diffusion distance is small, diffusion happens faster because the particles do not have as far to travel.

Calculate % concentration of of solution prepared by dissolving 8.5 g of glucose (C6H1206) in 35 g of water24 %none of the other answers are correct1.35 %20.%4.1 %

Answers

- First, to calculate the % concentration of glucose in the solution, we need to add the 8.5g of glucose to the 35 g of water, to get the weight of the solution:

[tex]\begin{gathered} \text{solution weight=8.5g + 35g} \\ \text{solution weight=43.5g} \end{gathered}[/tex]

- Second, we calculate the %w/w (weight/weight) with the solute weight and the solution weight:

[tex]undefined[/tex]

- So,

Select the structure that corresponds to themolecule name:3,4,4-trimethyl-2-pentanoneB.A. O||CH3CCH₂C(CH3)3C. both

Answers

Answer: structure B corresponds to the compound 3,4,4-trimethyl-2-pentanone

Explanation:

The question requires us to choose the structure that corresponds to the compound 3,4,4-trimethyl-2-pentanone.

The compound 3,4,4-trimethyl-2-pentanone presents a main chain of 5 carbons (indicated by the prefix pent-), with a ketone group bonded to the second carbon in the chain (indicated by the number 2 and the suffix -one). Also, there are 3 methyl groups: the first one is bonded to the third carbon in the main chain, while the other two methyl groups are bonded to the fourth carbon.

We can draw the structure of 3,4,4-trimethyl-2-pentanone as it follows:

(Note that the number of each carbon from the main chain is shown in blue near the C symbol)

Now, let's compare the structure drawn above to the structures provided by the question:

Even though structure A presents a ketone group bonded to the second carbon, the methyl groups are not positioned in the right place. Also, there is only 2 methyl groups bonded to the main chain at the 4th carbon of the chain.

Structure B presents the ketone bonded to the 2nd carbon from the main chain, a methyl group at the 3rd carbon and two methyl groups at the 4th carbon.

Therefore, structure B corresponds to the compound 3,4,4-trimethyl-2-pentanone.

The reaction HCl(1) + H₂O(1)→ H30(aq) + Cl(aq) can be abbreviated as HCI → H+ + CI™.
How is this apparently important omission justified?
A)
It's understood that H+ doesn't exist on its own in water, and H30(aq) + Cl(aq)
are both aqueous.
B) It's generally understood that H3O+ is a hypothetical intermediary.
OC) Because water isn't important to the reaction
D) It isn't justified, and the abbreviation is an error.

Answers

Reaction - It's understood that H+ doesn't exist on its own in water, and H₃O⁺(aq)⁺Cl⁻(aq) are both aqueous.

What is Reaction?
An act that changes one group of chemical constituents chemically into another is known as a chemical reaction. Chemical reactions typically involve changes that only influence the positions of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei. Chemical processes are commonly described by a chemical equation (no change to the elements present). The study of chemical processes involving unstable and radioactive elements—where both electronic and nuclear changes may take place—is known as nuclear chemistry.

When Acid HCl react with water it dissociates as H⁺ + Cl⁻ ion. H⁺ is a proton (Hydrogen ion is a proton with the charge on it) but this single unit of the charge is very small as compared to it value of the solution is water and acid. The resulting extraordinary high change desity of the proton strongly atom or molecule in ehich there exist an excess of the
⁻ve charge. In the case of water, the lone pair (e⁻) on oxygen attract the proton and form a co-ordinate bond with it creating a hydronium ion (H₃O⁺)

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Answer:

It's understood that H+ doesn't exist on its own in water, and H30(aq) + Cl(aq) are both aqueous.

Explanation:

took quiz

Why is KMnO4 regarded as a secondary standard solution ?

Answers

Potassium permanganate is not used as primary standard because is not able to release in MnO2 in the reaction. According to the above discussion, we conclude KMnO4 is used as the secondary standard. It is also hygroscopic in nature.

What is Secondary Standard solution?

A solution created especially for a certain analysis is known as a secondary standard solution. A substance whose active agent contents have been identified by comparison with a primary standard is referred to as a secondary standard. This indicates that it is frequently standardized against a fundamental standard.

Analytical tools and methodologies are calibrated using secondary standard solutions.

The molecular formula of potassium permanganate is KMnO4. Potassium permanganate is one of the oxidising agents in chemistry. Potassium permanganate is not used as primary standard because is not able to release in MnO2 in the reaction. Potassium permanganate is always in the stable form. The reason KMnO4 is also used as a colour indicator in analysis.

According to the above discussion, we conclude KMnO4 is used as the secondary standard. It is also hygroscopic in nature.

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How does the availability of WATER affect the growth of plants and animals?

Answers

Answer:

all living things need water. no water, no life.

2.Consider the relationship between the temperature and pressure of a gas, when the volume is held constant. Is the relationship directly proportional or indirectly proportional? 3.Which gas law does this demonstrate?

Answers

Explanations:

According to the pressure law, the pressure (P) of a fixed mass of a gas is directly proportional to its absolute temperature (T) provided that the volume remains constant. Mathematically;

[tex]\begin{gathered} P\alpha T \\ P=kT \\ k=\frac{P}{T} \end{gathered}[/tex]

k is the variation constant

If we have initial and final pressure and initial and final temperature, the formula can be written as:

[tex]k=\frac{P_1}{T_1}=\frac{P_2}{T_2}_{}_{}[/tex]

3) The gas law that demonstrates the equation and definition above is known as the PRESSURE LAW.

A mixture of helium and oxygen gas is expanded from a volume of 90.0L to a volume of 97.0L, while the pressure is held constant at 40.0atm. Calculate the work done on the gas mixture. Round your answer to 2 significant digits, and be sure it has the correct sign (positive or negative).

Answers

So,

First remember that the work done can be found if we remember the following equation:

[tex]W=P\cdot\Delta V[/tex]

Where W is the work done, P is the pressure (constant) and ΔV represents the change in the volume. (The substraction between the final volume and the initial volume)

If we replace our values, we got that:

[tex]\begin{gathered} W=40atm\cdot(97L-90L) \\ W=40atm\cdot7L \\ W=280J \end{gathered}[/tex]

The gas is being expanded, the sign of the work done is positive.

The work done is 280J.

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