a high driver jumps horizontally off the diving board with a speed of 1.3m/s how long does it take before he hits the water 27m below and how far will he have traveled horizontally in this time.
If a high driver jumps horizontally off the diving board with a speed of 1.3 m/s, it would take 2.34 seconds to hit the water.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem a high driver jumps horizontally off the diving board with a speed of 1.3 m/s.
By using the second equation of the motion,
S = ut + 1/2×a×t²
27 = 0 + 0.5 × 9.8 × t²
t = 2.34 seconds
Thus, it would take 2.34 seconds to hit the water.
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A bird on a long migration flies 63 kilometers per hour for 2900 kilometers. How long does he fly?
determine the resulting displacement traveled by the skier moving from a to b to c to d during these ten minutes. (hint: how far is he from his starting point at a). 0 points
Vector values like displacement are aware of their direction. Distance and other scalar quantities are directionless. The different directions of motion can be disregarded when calculating the total distance traveled.
While distance and displacement appear to signify the same thing, they actually have very different definitions and meanings.
A scalar quantity known as distance measures "how much ground an object has traversed" while moving.
An object's total change in position is referred to as displacement, a vector variable that measures "how far out of place an object is."
Think about the motion shown in the following diagram as a way to test your grasp of this distinction. Walking 4 meters east, 2 meters south, 4 meters west, and then 2 meters north is a physics teacher.
The physics instructor has walked 12 meters in total, yet her displacement is 0 meters. She has "covered 12 meters of ground" (distance = 12 m) during the course of her move. However, when she has done moving, she is not "out of position"; that is, her motion has not caused any displacement (displacement = 0 m). Being a vector quantity, displacement must pay attention to direction.
In the same way as the 2 meters south cancels the 2 meters north, the 4 meters east cancels the 4 meters west. Vector values like displacement are aware of their direction. Distance and other scalar quantities are directionless. The different directions of motion of the physics teachers can be disregarded in calculating the overall distance traveled.
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here are the temperatures of stars at the main-sequence turnoff in four clusters. are older clusters more likely to appear blue or red? cluster temperature (k) 47 tuc 5,000 m67 4,000 ngc 188 9,000 orion 22,000
This is because all of the stars in a cluster are thought to have formed practically simultaneously from the same cloud of interstellar space, therefore they should all have extremely similar characteristics.
We can learn a lot from star clusters that is applicable to the study of stars in general. The fundamental justification for this is because all of the stars in a cluster are thought to have formed practically simultaneously from the same cloud of interstellar space, therefore they should all have extremely similar characteristics. Accordingly, the sole distinguishing factor among stars in a cluster is their mass, and if we measure the characteristics of one star (such as its age, distance from us, composition, etc.), we may infer that the characteristics of the other stars in the cluster will be strikingly similar.
Although certain stars in the cluster do in fact originate earlier than others, this difference is negligible when compared to their lifespans and can be disregarded. We also suppose that each star in a cluster is located at a constant distance from Earth. Once more, there is a dispersion in distance, but it is usually considerably smaller than the distance to the cluster and may therefore be disregarded. The most distant stars, for instance, are roughly 50 parsecs from the cluster's center in the globular cluster M13, which is about 7,700 parsecs from Earth.
Finally, since the gas cloud from which they formed is anticipated to have been thoroughly mixed, the individual cloud fragments that formed individual stars should all have contained the same mix of elements and molecules. Accordingly, we assume that the chemical makeup of all of the stars in a given cluster should be very similar.
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19. If a car accelerates uniformly from rest to 15 meters
per second over a distance of 100 meters, the magni-
tude of the car's acceleration is
1. 0.15 m/s²
2. 1.1 m/s²
3. 2.3 m/s²
4. 6.7 m/s²
The magnitude of the car's acceleration is 1.1 m/[tex]s^{2}[/tex].
Use this formula of acceleration, [tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as, Here, initial velocity is zero.
a = [tex]v^{2}[/tex] / 2s
v = velocity
s = distance
a = acceleration
Put the values in this formula, a = [tex]v^{2}[/tex] / 2s
a = 15 × 15 / 2 × 100
a = 1.125 m/[tex]s^{2}[/tex]
Hence, the magnitude of the car's acceleration is 1.125 m/[tex]s^{2}[/tex].
Acceleration is the rate of change of velocity per unit time. It is vector quantity and its S.I. unit is m/[tex]s^{2}[/tex].
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What is the instantaneous velocity of a freely falling object 15 s after it is released from a position of rest? Express your answer to two significant figures and include the appropriate units. v = nothing nothing Request Answer Part B What is its average velocity during this 15- s interval? Express your answer to two significant figures and include the appropriate units. v = nothing nothing Request Answer Part C How far will it fall during this time? Express your answer to two significant figures and include the appropriate units. d = nothing nothing
Using concepts of acceleration, velocity and position, it is found that:
A. The instantaneous velocity in 15 seconds is of -147 m/s².
B. The average velocity during this interval is of -9.8 m/s.
Cc. The distance fallen during this time is of 1102.5 meters.
Acceleration, velocity and positionThe velocity after t seconds is given by the following equation:
v(t) = v(0) + at.
In which:
v(0) is the initial velocity.a is the acceleration.In the context of this problem, the values of these parameters are given as follows:
v(0) = 0, as the object was released from rest.a = -9.8, as the object is freely falling in the air, hence the acceleration is the gravity.Then the velocity equation is given as follows:
v(t) = -9.8t.
In 15 seconds, the instantaneous velocity is given as follows:
v(15) = -9.8(15) = -147 m/s².
The average velocity during this interval is of given by the change in velocity divided by the change in time, hence:
v(0) = 0.v(15) = -147.Average velocity = (-147 - 0)/(15 - 0) = -9.8 m/s.
The position function is the integral of the velocity function, hence:
s(t) = -4.9t². (integral of -9.8t = -9.8t²/2 = -4.9t²).
The distance fallen in 15 seconds is:
s(t) = -4.9(15)² = -1102.5 (1102.5 meters fallen).
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A projectile is fired into the air from the edge of a 100 m high cliff at an angle of 37° above the horizontal. The projectile hits a target 400 m away from the base of the cliff. What is the initial velocity of the projectile, vo? (Neglect air friction and assume x-axis to be horizontal and y-axis to be vertical). r 100m 400 m m
The initial velocity of the projectile, Vo is 25√5 m/s.
What is initial velocity?
initial velocity is the velocity at time interval t=0 and it's representative as u.
It is velocity which the motion start.
Sol-as per the question
Sx=400 Vx=Vo cos 37°=4/5Vo
Sy= -100 Vy=Vo sin 37° 3/5Vo ay=-10 m/s^2
Let the time of flight be t
Sx=u^xt +1/2axt^2
=>400= 4/5Vot----------(eq1)
Sy=uyt +1/2 ay t^2
=>-100=3/5 Vot -5t^2-----(eq2)
By solving this we are get-
Vo=25√5 m/s
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what is the defining characteristic of a main sequence star? what is the defining characteristic of a main sequence star? it is yellow. there are no longer any fusion reactions in its core.. it is fusing hydrogen into helium in its core. it is fusing helium into carbon in its core.
The defining character of a main sequence star is the fusing of hydrogen into helium in its core.
The main sequence is actually a stage in the life cycle of any star. At first, stars start out as clouds of dust. These cluster of dust then come together under the influence of gravity. If the cluster forms a small body, let's say 0.08 times the mass of our sun, it cannot undergo nuclear fusion, so they just become brown dwarfs. If the body formed is big enough, the resulting star gets hotter until temperatures become sufficient enough for hydrogen fusion to occur. This marks the beginning of the main sequence.
The size of the star determines how long the star will stay in its main sequence. Smaller stars are cooler, and burn through their hydrogen fuel slower, so they are able to stay in the main sequence longer, compared to higher mass stars. During the main sequence, the star generates lots of energy through nuclear fusion. This energy counteracts the force of gravity, keeping the star stable and preventing collapse.
An example of a main sequence star is the sun.
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when resistors 1 and 2 are connected in series, the equivalent resistance is 16.0 0. when they are connected in parallel, the equivalent resistance is 3.0 o. what are (a) the smaller resistance and (b) the larger resistance of these two resistors
a) The smaller resistance (R₁) is 4.
b) The larger resistance (R₂) is 12.
What is the rule for parallel resistors?When resistors are connected in parallel, the supply current is equal to the sum of the currents passing through each one of them. The total current flowing through the branches of a parallel circuit is the supply current. Resistor parallel connections have the same potential difference.
Given,
R₁ + R₂ = 16,
R₂ = 16 - R₁
[tex]\frac{R_{1} R_{2} }{R_{1}+R_{2} }[/tex] [tex]= 3[/tex],
This statement can be written as,
[tex]\frac{1}{R_{1} } +\frac{1}{R_{2} } =\frac{1}{3}[/tex]
Substitute [tex]R_{2}[/tex] value in above equation,
[tex]\frac{1}{R_{1} } +\frac{1}{16-R_{1} } =\frac{1}{3}\\\\\frac{16-R_{1} +R_{1} }{R_{1}(16-R_{1}) } =\frac{1}{3}\\\\\frac{16}{R_{1(16-R_{1}) } } =\frac{1}{3} \\\\[/tex]
48 = R₁(16 - R₁)
16R₁ - R₁² = 48
- R₁²+ 16R₁ - 48 = 0
Multiply both sides by (-1).
R₁²- 16R₁ + 48 = 0
R₁² - (12 + 4)R₁ + 48 = 0
R₁ (R₁ - 12) - 4 (R₁ - 12) = 0
(R₁ - 4)(R₁ - 12) = 0
If R₁ = 4 then R₂ = 12 and if R₁ = 12 then R₂ = 4.
Therefore, it can be said that the smaller resistance is 4 and larger resistance is 12.
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a 0.11 kg tin can is resting on top of a 1.7 m high fence post. a 0.0020 kg bullet is fired horizontally at the can. it strikes the can with a speed of 900 m/s, passes through it, and emerges with a speed of 720 m/s. when the can hits the ground, how far is it from the fence post? disregard friction while the can is in contact with the post.
A mass of can 0.11 kg rests on a fence post 1.7 m high. a 0.0020 kg bullet is fired horizontally at a can. it hits the can at 900 m/s, passes through it, and emerges at 720 m/s.
when the can hits the ground, it is 1.93 m away from the fence post.
for vertical fall,
d = 0.5*g*t^2
1.7 = 0.5*9.8*t^2
t = 0.589 s
use conservation of momentum to calculate the initial horizontal velocity to tin
mb*vbi = mb*vbf + mt*vt
2*10^-3*900 = 2*10^-3*720 + 0.11*vt
vt = 3.273 m/s
horizontal distance = vt*time
= 3.273 m/s * 0.589 s
= 1.93 m
Answer= 1.93 m
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one paint bucket weighing 40.0n is hanging by a massless cord from another paint bucket also weighing 40.0 n. the two are being pulled upward with an acceleration of 1.50 m/s^2 by a massless cord attached to an upper bucket. calculate the tension in each cord
The tension in each cord would be
T1=92.24N
T2=46.12N
Solution
40N = mg
m = 4.08kg
Coupled System
∑F = Ma
F=ma, which stands for Newton's second law, states that a force acting on an object is equal to that object's mass times its acceleration (a). This implies that the force required to accelerate an item increases with its mass. Additionally, the acceleration of an item increases with increasing force.
T1 - Mg = Ma
T1 - 80 = (4.08 + 4.08)(1.5)
T1 = 92.24N
T1- T2-Mₐg=mₐ a
92.24-T2-40=4.08(15)
T2 = 46.12 N
T2- Mᵇ g = mᵇa
T2 - 40 = 4.08(1.5)
T2 = 46.12N
Therefore the tension in each cord would be
T1=92.24N
T2=46.12N
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suppose oil spills from a ruptured tanker and spreads in a circular pattern. if the radius of the oil spill increases at a constant rate of 2 m/s, exactly how fast (in m2/s) is the area of the spill increasing when the radius is 26 m?
They have more than DT, which is equivalent to 9/20 pots. Therefore, this is the rate of change for both the radius and the shape's radiance.
Given that the pool is growing, the area is expanding at a rate of four. How quickly do you think the pool will grow when the radius is two centimeters. So allow me to simply correct something. The radius of the pool, then, is said to rise at a rate of four in the question.
So, we'll just say R for the radius. This is why art prevails over DT. which is provided for us Therefore, the subject of how quickly the pool's area. So let's pretend that Area is exactly where she should be. Let's assume that area is equal to A. Which is equivalent to pi R squared, which is equal to a. Therefore, we will calculate this function's derivative with respect to T. What stands for both sides is the A R D T. That is over DT by two pi times r times.
As a result, we must enter the values in the appropriate places. R has a value of two. Additionally, we are provided four R over DT. Let's enter these values, which are equal to two pi times R. S. 2. Additionally, they exceed DT, which is also four. Let's divide them by 16, which is 16.The spill's surface area grows by nine square feet each second. So let's say this circle has a radius of R once more. Therefore, D. A. above D. T. And that's so A. is the region for which nine is specified.
Accordingly, based on what I gather from the query, that is nine. That is pi times; they are over DT in our time. Plug in 10 for our, which is 10, 2 times 10 times they are over DT, to make the an over DT, which is nine, equal to pi times when R is equal to ten. The R over DT, which is equal to, shall be left unaffected. They are therefore over DT from here, which is equivalent to this is 9/20 pots. Therefore, this is the rate of change for both the radius and the shape's radiance.
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A bus and a Car are traveling along the EDSA having the same velocity. which if the two vehicles would have a greater momentum?a. the busb. the carc. both have the same momentumd. cant be easily determined
The momentum of an object can be calculated with the formula below:
[tex]p=mv[/tex]Where p is the momentum, m is the mass and v is the velocity.
The mass of the bus is greater than the mass of the car.
So, if they have the same velocity, the momentum of the bus will be greater.
Correct option: a.
A painter sets up a uniform plank so that he can paint a high wall. The plank is 2 m long and weighs 400 Ν. The two supports holding the plank are placed 0.2m from either end.
A painter now stands on the plank closest to the left hand support. Describe what now happens to the forces provided by the support when the painter is on the plank.
The forces provided by the support will have to increase proportionally to the weight or force of the painter acting downward.
What are balanced forces?Balanced forces are forces that are equal but oppositely directed in their line of action.
When forces are balanced, there is no net movement of the object that the forces are acting upon.
The uniform plank is balanced by the supports.
When the painter stands on the plank, the force of gravity or the weight of the painter acts downwards.
In order for the forces to be balanced, the forces provided by the support increase according to the third law of motion which states that action and reaction are equal and opposite.
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PLEASE SOLVE NO I NEED IT DONE IM ON A DEADLINE!!! a bird flying 3.45 m / s directly north feels a wind directly East that accelerates at 0.558 m / S^2. What is its velocity 5.25 s later
The velocity of the bird can be obtained as 6.38 m/s.
What is the velocity?Let us recall that the acceleration is the rate at which the velocity is changed. In this case, we are told that; a bird flying 3.45 m / s directly north feels a wind directly East that accelerates at 0.558 m / S^2. Having seen the question we can pick the following parameters out from the question;
Initial velocity u = 3.45 m / s
Acceleration a = 0.558 m / S^2
Time taken = 5.25 s
Given that;
v = u + at
v = final velocity
u = initial velocity
a = acceleration
t = time taken
v = 3.45 + (0.558 * 5.25)
v = 6.38 m/s
We can see that as the bird tends to be flying as we can see in the question that have been shown above that the final velocity that it can have after 5.25 seconds is 6.38 m/s.
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Two lifeguards pull on ropes attached to a
raft. If they pull in the same direction, the raft
experiences a net external force of 343 N to
the right. If they pull in opposite directions,
the raft experiences a net external force of
177 N to the left.
Draw a free body diagram for each situation
and find the magnitude of the larger of the two
individual forces.
Answer in units of N.
The magnitude of the larger of the two individual forces. is 120.5N.
Solution:
x + y = 343
x - y = 177
2x = 520
x = 222.5 N
y = 343 N - 222.5 N = 120.5N.
The resultant force of two forces of equal magnitude is equal to one of the two vectors. In physics, the magnitude of a force is the sum of all forces acting on an object. If all forces act in the same direction, the force magnitude increases. When forces act on an object in different directions, the force magnitude decreases. If one force is stronger than the other, the force will move to the smaller side but the acceleration will be slower. So the result is the difference between the two forces.
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Tambora volcano on the island of Sumbawa Indonesia has been known to throw ash into the air with the speed of 625 m/s during an eruption, how high could this volcano plume have risen
The maximum height reached by the Tambora volcano after the eruption is 19,929.85 m.
What is the maximum height reached by the Tambora volcano?The maximum height reached by the Tambora volcano is calculated by applying the following kinematic equation as shown below;
v² = u² - 2gh
where;
v is the final velocity of the volcanou is the initial velocity of the volcanoh is the maximum height reached by the volcanog is acceleration due to gravityat maximum height, the final velocity, v = 0
0 = u² - 2gh
2gh = u²
h = u²/2g
h = (625²) / (2 x 9.8)
h = 19,929.85 m
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a cyclotron is a device that can accelerate charged particles to very high velocities, and can be used to generate protons with radiative wavelengths that can kill cancer cells. what is the de broglie wavelength of a proton (mass 1.673 x 10-27 kg) that has been accelerated to a velocity of 1.35 x 104 m/s?
The de Broglie wavelength of a proton in a linear accelerator is 122 pm. A photon's de Broglie wavelength is twice that of an electron.
The rate of The electron is then defined as E 10 (b) = 10-2 (c) Pe=100 ca) Pt = 10 mee. The wavelength of a particle or matter can be calculated using the formula below. Thus, when the microscope is set to 100 keV, the wavelength of electrons is calculated to be 3.88 pm, 2.74 pm at 200 keV, and 2.24 pm at 300 keV. A photon's frequency is defined as the number of wavelengths it travels per second. A photon, unlike an electromagnetic wave, cannot be colored. A photon, on the other hand, will correspond to light of a specific color.
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What is the weight of a 172 kg football player?
Answer:
Explanation:
Given:
m= 172 kg
g = 9.8 m/s²
___________
F - ?
F = m*g = 172*9.8 ≈ 1690 N
Which point of view does the narrator use in the passage? "keep those balls going!" he fist-thumped at us. "no one sits out this fire fight! never underestimate the enemy!" but there was a broad smile on his face. now that he was actually seeing the other team, he seemed not at all concerned about the outcome of the game. in the interim between throwing a ball and having it thrown back to me, i told myself that i liked mr. galanter.
Maintain the ones balls going , he fist-thumped at us. no one sits out this fireplace fight, never underestimate the enemy , however there has been a wide smile.
Narration is using a written or spoken statement to convey a tale to an audience. Narration is conveyed by using a narrator: a particular individual or unspecified literary voice, evolved by the author of the story, to supply facts to the target market, specially approximately the plot.
The narrator's handiest exists within the global of the tale and gives it in a manner the target audience can draw close. In non-fiction, the narrator and the author may be the same individual, because the actual global and the world of the story may be the equal.
Narration is a way wherein one or more performers communicate without delay to the target audience to tell a tale, supply facts or touch upon the movement of the scene or the motivations of characters. Characters may additionally narrate, or a performer who isn't worried in the action can carry out the role of 'narrator.
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Answer: I think its first person.
Explanation:
A dart shot at a monkey is traveling 8 m/s horizontally, while simultaneously traveling 9 m/s downward. What is the magnitude of the total velocity of the dart?
The angle below the horizontal the dart shot at 8 m/s horizontally and 9 m/s downward is 41.67°
In a right angled triangle,
tan θ = Opposite side / Adjacent side
Here the resultant velocity, horizontal and vertical components makes a right angled triangle.
Opposite side = Horizontal component = 8 m / s
Adjacent side = Vertical component = 9 m / s
tan θ = 8 / 9
tan θ = 0.89
θ = [tex]tan^{-1}[/tex] ( 0.89 )
θ = 41.67°
The formula used to solve the problem is a trigonometric ratio. Trigonometric ratios are applicable only on a right angled triangle. Some of the basic trigonometric ratios are:
sin θ = Opposite side / Hypotenusecos θ = Adjacent side / HypotenuseTherefore, the angle below the horizontal, the dart is traveling is 41.67°
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You have two springs, and you have tested both and graphed the results. Spring A has a slope kA = 30g/cm, and spring B has a slope kB = 50 g/cm.
A) Spring A is a shorter spring than B when they are both unstretched.
B) Spring A will stretch more than B if you hang the same amount of mass on each spring.
C) No! Spring B will stretch more than A if you hang the same amount of mass from each spring.
Spring A will stretch more than spring B if same mass is hanged from both of them because the value of Ka is less than that of Kb.
According to hook's law, for a spring,
F = -Kx
where,
F is applied force on the spring,
x is the extension or compression in string,
K is the constant of proportionality known as spring constant,
The value of spring constant tells us about the stiffness of the spring,
According to the situation,
Ka = 30g/cm
Kb = 50g/cm
So, the answer is option B,
As we can see, the value of Kb is more than Ka so, we can say that the spring B is more stiff than spring A,
So, if same mass is hanged from the spring A and Spring B, the spring A will stretch more.
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what causes a low-mass star, like the sun, to evolve away from the main sequence? hydrogen is exhausted in the core. all of the hydrogen becomes helium. carbon fusion begins
Hydrogen and helium are fused together in the cores of stars on the main sequence. Low-mass stars process their hydrogen rather slowly, so they spend a lot of time on the main sequence.
Hydrogen is converted to helium in the cores of stars on the main sequence. Low-mass stars remain on the main sequence for a considerable amount of time because they process their hydrogen very slowly. But what happens when the hydrogen in their cores is completely depleted? The precise mass of the star turns out to be a determining factor in the response; the greater the star, the more violent the conclusion.
The star's ability to produce energy gradually decreases as its hydrogen supply gets depleted. The outer layers of the core are drawn inside by gravity, but the temperatures never get hot enough for any additional nuclear reactions to occur. The star shrinks, cools, and grows fainter over time. It will eventually contract into a black dwarf, a chilly ball the size of the Earth.
Of course, all of this is simply conjecture. It takes a star with such a little mass a very, very long time to exhaust all of its hydrogen fuel. It might take a star of 0.2 solar masses a trillion years to exhaust all of its hydrogen.
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What can be concluded about
the current size of the Mediterranean Sea?
A football field with end zones is 120 yards long. Suppose we were to fly over tiger stadium at 0. 8c. How long would the field appear from our spaceship?.
solution given there
what happens to the magnitude of the charge on each plate of a capacitor if the potential difference between the conductors is doubled? it becomes four times larger.
The temperature inside my refrigerator is about 4 degrees C. If I place a balloon in my fridge that initially has a temperature of 22 degrees C and a volume of 0.5 L, what will be the volume of the balloon when it is fully cooled by my refrigerator?
v
Convert the given temperatures from celsius to kelvin since we are dealing with gas.
To convert to kelvin, add 273.15 to the temperature in celsius.
T1 = 22 + 273.15 = 295.15 k
T2 = 4 + 273.15 = 277.15 k
V1 = 0.5 L
Let's find the final volume (V2).
To solve for V2 apply Charles Law formula below:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]A helicopter changes its velocity from 22.0 m/s [E] to 10.0 m/s [W] during a time interval of 8.0 s. What was the helicopter’s average acceleration?
The average acceleration of the helicopter, given that it changes its velocity from 22.0 m/s to 10.0 m/s is –1.5 m/s²
How do I determine the average acceleration ?We understood that acceleration is defined as the change in velocity with time i.e
a = (v – u) / t
a is the acceleration v is the final velocity u is the initial velocity t is the timeWith the above formula, we can determine the average acceleration of the helicopter. Details below
The following data were obtained from the question:
Initial velocity (u) = 22.0 m/sFinal velocity (v) = 10.0 m/sTime (t) = 8.0 s Average acceleration (a) =?a = (10 – 22) / 8
a = –12 / 8
a = –1.5 m/s²
Thus, we can conclude that the average acceleration is –1.5 m/s²
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Alma understands that for the body to be healthy, there must be a balance between the food we take in and the energy we put out. Which would be an
example of showing balance?
O A
working out two hours a day and eating one high protein meal
O B.
binging on ice cream and pizza for lunch and then skipping dinner
cutting out junk food and spending an hour a day exercising
O c.
O D. drinking nothing but smoothies and running five miles a day
The balance between food and energy is necessary. So, cutting out junk food and spending an hour a day exercising is good for health. Hence, option C is correct.
What is Energy?Energy in physics is the capacity to do work. It could take on several shapes, such as potential, kinetic, thermal, electrical, chemical, radioactive, and more. In addition, heat and effort are two other ways that energy is exchanged between bodies.
After being transferred, energy is always recognized according to its nature. As a result, the generation of thermal energy may happen through heat transfer while the formation of mechanical energy may result from work being done.
Hence, from this information Option C is correct.
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Answer:
c. cutting out junk food and spending an hour a day exercising
Explanation:
A car starts from rest and travels for 5.0 s with a constant acceleration of +1.5 m/s^2. The driver then applies the brakes, causing a constant acceleration of -2.1m/s^2. The brakes are applied for 3 seconds. How fast is the car moving at the end of the braking period?
car starts from rest and travels for 5.0 s with a constant acceleration of +1.5 m/s^2.
The car's speed was 1.2 m/s faster at the end of the breaking period.
What it means acceleration?The act or process of moving more swiftly or making something happen more quickly: the act or process of speeding economic growth.the rate of change of velocity generally with respect to time.The metre per second per second (m/s2) unit of acceleration.Acceleration is a vector quantity since it has both a magnitude and a direction. A vector quantity is also velocity. The velocity vector change during a time interval divided by the time interval is the definition of acceleration.From Equation of the motion
v = u + at
car starts from rest and travels for 5.0 s with a constant acceleration of +1.5 m/s^2
v = 0+ 1.5 * 5 = 7.5 m/s
a constant acceleration of -2.1m/s^2. The brakes are applied for 3 seconds
Then
u= 7.5 m/s t= 3s a= -2.1 m/s^2
v= 7.5 + -2.1 * 3 = 7.5 -6.3 = 1.2 m/s
The car's speed was 1.2 m/s faster at the end of the breaking period .
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