Detritivore
Explanation:
they eat the dead things
Fire a single electron towards the hydrogen atom. Describe what happens in a step by step fashion. [N.B. - It may be helpful to utilize the Run in Slow Motion option for this part.]
Answer:
The electrons will be added by the hydrogen.
Explanation:
If we fire a single electron towards the hydrogen atom, the hydrogen atoms added the electron to its shell by applying force of attraction and becomes stable as well as non reactive in nature because the hydrogen attains the electronic configuration of helium which is a noble gas and have completed its outermost shell. The proton that is present in the nucleus attracts this electron and compel it to add in the electron.
14. Which block in the periodic table contains the metalloids?
O A. p block
OB. s block
O C. d block
D. f block
Answer
the answer is p block
3. Available energy increases as it is transferred from one organism to another in food chain.
True or false
Answer:
False
Explanation:
Gets used by other animals.
21.5g of sodium chloride dissolves in 60g of water at25C. Calculate the concentration of the solution.
what elements don't form bonds
Answer:
Noble gases are a set of elements in the periodic table because they don't naturally bond with other elements. *Examples ...Helium; Neon; Radon; Xenon; Argon etc
Explanation:
theyre noble gases.
What volume of 6.49 MHCl is needed to prepare 2.11 L of 1.07 MHCl? Your answer should have three significant figures.
Answer:
0.348 L
Explanation:
Step 1: Given data
Concentration of the concentrated solution (C₁): 6.49 MVolume of the concentrated solution (V₁): ?Concentration of the dilute solution (C₂): 1.07 MVolume of the dilute solution (V₂): 2.11 LStep 2: Calculate the volume of the concentrated solution
We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 1.07 M × 2.11 L / 6.49 M = 0.348 L
A 1.0 g sample of propane, C3H8, was burned in calorimeter. The temperature rose from 28.5 0C to 32.0 0C and heat of combustion 10.5 kJ/g. Calculate the heat capacity of the calorimeter apparatus in kJ/0C
Answer:
A 1.0 g sample of propane, C3H8, was burned in the calorimeter.
The temperature rose from 28.5 0C to 32.0 0C and the heat of combustion 10.5 kJ/g.
Calculate the heat capacity of the calorimeter apparatus in kJ/0C
Explanation:
[tex]Heat of combustion = heat capacity of calorimeter * deltaT\\[/tex]
Given,
The heat of combustion = 10.5kJ/g.
[tex]deltaT = (32.0-28.5)^oC\\deltaT = 3.5^oC[/tex]
Substitute these values in the above formula to get the value of heat capacity of the calorimeter.
[tex]deltaT =heat capacity of calorimeter * (change in temperature)\\10.5kJ/g = heat capacity of calorimeter * (3.5^oC)\\\\=>heat capacity of calorimeter = \frac{10.5kJ/g}{3.5^oC} \\=>heat capacity of calorimeter = 3.0 kJ/g.^oC[/tex]
Answer:
The heat capacity of the calorimeter is [tex]3.0kJ/g.^oC.[/tex]
Hexane, C6H14, is a(n)
hydrocarbon.
Saturated or Unsaturated
Answer:
Like any compound ending in '-ane', hexane is an alkane. It is commonly referred to as n-hexane and classified as a saturated hydrocarbon
Answer:
its saturated
cus its like
CnH2n+2
How much work (in J) is involved in a chemical reaction if the volume decreases from 4.35 to 1.20 L against a constant pressure of 0.822 atm?
Express your answer to three significant figures and include the appropriate units.
Answer:
W = -262 J.
Explanation:
Hello there!
In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:
[tex]W=P(V_2-V_1)[/tex]
So we plug in the given pressure and volumes to obtain:
[tex]W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L[/tex]
Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:
[tex]W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J[/tex]
Regards!
The rate equation for a reaction between substances C and D is:
rate = k[C]^2 [D]^2
The initial rate is found to be 7.5 x 10^-3mol dm^-3s^-1when the initial concentration of
C is of 0.25 mol dm^-3and the initial concentration of D is 0.50 mol dm^-3.
Calculate the value of the rate constant, k, at this temperature and deduce its units.
*Important Asap please *
Answer:
[tex]rate = k[C] {}^{2} [D] {}^{2} \\ 7.5 \times {10}^{ - 3} = k {(0.25)}^{2} {(0.50)}^{2} \\ k = \frac{7.5 \times {10}^{ - 3} }{ {(0.25)}^{2} {(0.50)}^{2} } \\ k = 0.48 \: {mol}^{ - 3} {dm}^{9} {s}^{ - 1} [/tex]
Gaseous ethane (CH,CH,) will react with gaseous oxygen (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H,0). Suppose 4.21 g of
ethane is mixed with 31. 9 of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has
the correct number of significant digits.
Answer: The mass of [tex]CO_2[/tex] produced is 12.32 g
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
For ethane:Given mass of ethane = 4.21 g
Molar mass of ethane = 30 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of ethane}=\frac{4.21g}{30g/mol}=0.140mol[/tex]
For oxygen gas:Given mass of oxygen gas = 31.9 g
Molar mass of oxygen gas= 32 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of oxygen gas}=\frac{31.9g}{32g/mol}=0.997mol[/tex]
The chemical equation for the combustion of ethane follows:
[tex]2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O[/tex]
By stoichiometry of the reaction:
If 2 moles of ethane reacts with 7 moles of oxygen gas
So, 0.140 moles of ethane will react with = [tex]\frac{7}{2}\times 0.140=0.49mol[/tex] of oxygen gas
As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.
Thus, ethane is considered a limiting reagent because it limits the formation of the product.
By the stoichiometry of the reaction:
If 2 moles of ethane produces 4 moles of [tex]CO_2[/tex]
So, 0.140 moles of ethane will produce = [tex]\frac{4}{2}\times 0.140=0.28mol[/tex] of [tex]CO_2[/tex]
We know, molar mass of [tex]CO_2[/tex] = 44 g/mol
Putting values in above equation, we get:
[tex]\text{Mass of }CO_2=(0.28mol\times 44g/mol)=12.32g[/tex]
Hence, the mass of [tex]CO_2[/tex] produced is 12.32 g
A solution of which of the following coordination compounds will form a precipitate when treated with aqueous AgNO3?
a. [Cr(NH3)3C13]
b. All will form a precipitate
c. Na3[Cr(CN)6]
d. Na3[CrCl6]
e. [Cr(NH3)6.]C13
Answer:
[Cr(NH3)6.]C13
Explanation:
Alfred Werner's coordination theory (1893) recognized two kinds of valency;
Primary valency which are nondirectional and secondary valency which are directional.
Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.
We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.
If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.
15.4 g of methanol (CH3OH) reacts completely according to the following reaction:
CH3OH (g) → CH2O (g) + H2 (g)
If 12.35 g of formaldehyde (CH2O) is produced, what is the percent yield for this reaction?
Explanation:
hope the working on picture helps :)
93.5 is the percent yield for this reaction.
What is a theoretical yield?The theoretical yield is the maximum possible mass of a product that can be made in a chemical reaction.
Step 1: Solve for the mass of CH_2O produced.
Mass [tex]CH_2O[/tex] = 15.4 g [tex]CH_3OH[/tex] × (1 mol [tex]CH_3OH[/tex] ÷ 32.04 g [tex]CH_3OH[/tex]) × (1 mol [tex]CH_2O[/tex] ÷ 1 mol [tex]CH_3OH[/tex]) × (30.03 g [tex]CH_2O[/tex] ÷ 1 mol [tex]CH_2O[/tex])
Mass [tex]CH_2O[/tex]= 14.43 g
Step 2: Determine the theoretical yield.
Theoretical yield = mass [tex]CH_2O[/tex]
Theoretical yield = 14.43 g
Step 3: Solve for the percent yield.
Percent yield = (actual yield ÷ theoretical yield) × 100
Percent yield = (13.5 g ÷ 14.43 g) × 100
Percent yield = 0.9355509356 × 100 =93.5 percent
Hence, 93.5 is the percent yield for this reaction.
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Helpppp
What is the volume of 2.99 moles of C3H8 at STP?
0.0680L
5.87 L
ОООО
1.52 L
67.0L
Answer:
67.0 L
Explanation:
Step 1: Given data
Moles of C₃H₈: 2.99 molPressure: 1 atm (standard pressure)Temperature: 273.15 K (standard temperature)Step 2: Calculate the volume occupied by 2.99 moles of C₃H₈ at STP
C₃H₈ is a gas. If we assume ideal behavior, 1 mole of C₃H₈ at STP occupies 22.4 L.
2.99 mol × 22.4 L/1 mol = 67.0 L
Write the first step of this elimination using curved arrows to show electron reorganization. Remember that a mechanism step may require more than one curved arrow.
Answer:
Explanation:
The missing image can be seen below.
From the given information:
The elimination process follows E2 mechanism which is a 2nd order kinetics.
At E2 mechanism, the base attaches with the beta hydrogen while also removing the leaving group in the same process. In the given compound 2-chloro-2-methylpropane, chloride is the leaving group that results in the product; 2-methylprop-1-ene.
The mechanism is seen in the second image,
Which molecule is pentanoic acid?
ОА.
Н
1
НЕС-ОН
ОВ.
Н
ОН
ор.н.н
Answer:
PubChem CID 7991
Structure Find Similar Structures
Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet
Molecular Formula C5H10O2 or CH3(CH2)3COOH
Synonyms Valeric acid PENTANOIC ACID n-Valeric acid 109-52-4 n-Pentanoic acid More.
Which is most likely the first step in a basic food chain?
1. The snake obtain energy by eating the mouse
2. Plants make energy-rich food using sunlight
3. The hawk obtains energy by eating the snake
4. The sun emits energy.
Answer:
4
Explanation:
What determines the ending units of a stoichiometry problem?
Answer:
1.Write the balanced chemical equation.
2.Convert the units of the given substance (A) to moles.
3.Use the mole ratio to calculate the moles of wanted substance (B).
4.Convert moles of the wanted substance to the desired units.
Explanation:
What is the limiting reagent when 22 g of sodium is added to 28 g water?
Answer:
Limiting reagent is Na
Explanation:
Reaction of Na with water is:
Na + H₂O → NaOH + H₂
It is a very exothermic reaction.
The correctly balanced equation is:
2Na + 2H₂O → 2NaOH + H₂
Ratio is 2:2, between reactants, according to stoichiometry.
We convert mass to moles:
22 g . 1 mol / 23 g = 0.956 moles of Na
28 g . 1mol / 18 g = 1.56 moles of water.
Certainly the limiting reagent is sodium. For 1.56 moles, we need the same amount of sodium and we only have 0.956 moles.
We do not have enough sodium to complete the reaction.
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how many hydrogen atoms are in one mole of caffeine
[tex] \huge \mathbb{ HI !!}[/tex]
My Answer 10My ExplanationAlthough caffeine (a stimulant found in coffee and tea) is a relatively complicated molecule, it's only eight atoms of carbon, ten of hydrogen, four of nitrogen and two of oxygen – C8H10N4O2. This kind of representation is called a molecular formula – it tells us what kind of atoms we have, and how many of each.
#CarryOnLearningThere are 10 hydrogen atoms in one mole of caffeine.
What is caffeine?Caffeine belongs to the methylxanthine category of nervous system stimulants. It's just a cognitive booster that improves alertness but also attentional performance.
Caffeine's chemical formula would be C8H10N4O2, that indicates it contains eight carbon atoms, ten hydrogen atoms, four nitrogen atoms, and two oxygen atoms.
So it can be seen that , 10 hydrogen resent in caffeine molecule.
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Which of the following is a testable hypothesis
Answer:
C
Explanation:
Answer:
C.
Explanation:
Brainiest?
NaOH is an Arrhenius base because it increases the concentration of hydroxide ions when dissolved in solution. (3 points) True False
When NaOH is an Arrhenius base so it is dissociated in water so the given statement is false.
NaOH is an Arrhenius base:It is this base since it dissociates in water to provide the hydroxide (OH-) and sodium (Na+) ions.
It is the substance that is ionized at the time when it is dissolved in water to provide the hydrogen ion.
hence, the given statement is false.
Learn more about ions here: https://brainly.com/question/14423944
Answer:
true
Explanation:
i took the test and got it right the other guy is wrong
Use the periodic table to determine the electron configuration for aluminum (Al) and arsenic (As) in noble-gas notation.
Al:
Explanation:
2,8,3don't know .............
.....how
5.96 g of ammonia reacts completely according to the following reaction:
2 NH, (g) + Co, (g) → CN,OH, (s) + H20 (1)
(a) What is the theoretical yield of urea (CN,OH,) for this reaction?
(b) If 13.74 g of urea are produced, what is the percent yield for this equation?
please show work, will give brainliest
Explanation:
this explanation may help u to understand:)
Name the subatomic parts of the atom, their charges and where they are located.
Answer:
protons: positively charged, located in the nucleus
electrons: negatively charged, located outside the nucleus
neutrons: no charge, located in the nucleus
Will mark Brainlest ( molecular weight of ammonium sulphate)
step by step
Answer:
132 amu
Explanation:
ammonium sulphate is [tex](NH_4)_{2} SO_4[/tex]
to calculate molecular weight we need
atomic weight of the element of the compound
here ammonium sulphate is formed by two elements
2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen
atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16
so lets calculate molecular weight of ammonium sulphate
2*14 + 8*1 + 1*32 + 4*16
28 + 8 + 32 + 64
132 amu
define molecular formula?
A molecular formula is an expression that states the number and type of atoms present in a molecule of a substance.
Example : H2O (water) There are 2 atoms of Hydrogen and 1 atom of Oxygen in this substance
classify the following compounds as chiral, achiral (but not meso), or meso. 1st structure: _________ 2nd structure: _________ 3rd structure: _________
Answer:
1st structure - Meso
2nd structure - Chiral
3rd structure - achiral
Explanation:
In the 1st structure there is nitrogen atom bonded with 4 different groups. It is Meso compound. In the second structure a carbon atom is attached with hydroxide molecule OH and has four different environment. It is Chiral compound. In the third structure no atom have different atom or group surrounding it. Therefore it is Achiral compound.
Imagine that one night on the news, you saw a report that chemists had discovered a medicine to cure cancer. Would you believe that this report was true? What questions would you want to see answered in the report to help you make your decision? Answer in two to three paragraphs.
Answer:
Yes I would believe that this report was true, because nobody would lie on a news channel that they cured cancer and then not cure it. That would completely ruin their credibility as well as the news channels credibility. So no news channel would take the story if it was made up.
I would like to see there studies on how the medicine kills off the cancer and the side effects of the medicine on the human body. I would want to know how the medicine is made, if its FDA approved, and how the medicine will be distributed across the globe and at what prices, as well as how easily the medicine expires.
Answer:
Explanation:
I will probably believe the report but want to find out more details. First is cure for which cancer has been found. Cancer is a general name for a large family of different diseases. So it is very likely that the cure is for some specific cancers.
Secondly I want to know if the cure has any side effect. The typical treatments for cancer now are radiation and chemo therapy. Both can cause serious side effects.
Lastly the cost of cure is important. New drugs with patent protection can be very expensive which limit on how many people can afford the treatment.