Which statement best describes energy and matter in a closed system? (2 po
O Energy and matter flow into and out of the system.
Energy can flow into and out of the system but matter cannot.
Energy and matter are contained within a closed system.
O There is no energy in a closed system; there is matter.

Answer:

an object that is in motion wont go out of motion until there is another force pushing on it

Answer:

98J

Explanation:

Given parameters:

Mass of rock  = 5kg

Height = 2m

Unknown:

Work done  = ?

Solution:

The amount of work done is given as:

 Work done  = Force x distance

 Work done = Weight x height

  Work done  = mgH

Now insert the parameters and solve;

 Work done  = 5 x 9.8 x 2 = 98J

The amount of work done on the rock is equal to 98 Nm.

Given the following data:

To determine the amount of work done:

First of all, we would calculate the force acting on the rock:

[tex]Force = mg\\\\Force = 5 \times 9.8[/tex]

Force = 49 Newton

Now, we can determine the amount of work done:

[tex]Work \;done = force \times distance\\\\Work \;done = 49 \times 2[/tex]

Work done = 98 Nm

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Answer:c

Explanation:its the answer because its the answer

Answer:

Option A

Explanation:

Ast the force is equal and the diayance is equal the beam is also balanced

Answer:

the book is 4 meters from the floor

Explanation:

Use the formula for potential energy:

U = m g h

196 J = 5kg 9.8m/s^2 h

h = 196 / (5*9.8 ) m

h = 4 m

Answer:

it is scientific knowledge

Explanation:

got i right on edge

The scientific knowledge refers to information gathered by the systematic study of nature.

A generalized corpus of laws and ideas developed employing the scientific method to describe an interesting occurrence or behavior is referred to as scientific knowledge.

Science would be the systematic study of the composition and dynamics of the physical as well as the natural world via experimentation and observation.

the systematic study of natural circumstances and phenomena. empirical proof. the term for the facts and figures that support an explanation in science.

Therefore, the correct answer will be option (C)

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Answer:

If a ball rolls down an incline with a starting velocity of 0m/s and a final velocity of 6m/s

and it takes a total of 1.4 seconds, calculate its acceleration.

Answer:

Acceleration is 4.28 m/s²

Explanation:

Acceleration is change of speed in time. To solve this, we will assume that the acceleration is constant, meaning that every second the velocity increases for the same constant value.

a = ∆v/t

∆v is the difference between two measured velocities:

a = (v2 - v1) / t

v1 = 0m/s

v2 = 6m/s

t = 1.4 s

Now, we only plug in the given values:

a = (6 - 0) / 1.4

a = 6 m/s / 1.4 s

a = 4.28 m/s²

Answer:

9.8m/s^2 down  (option C)

Explanation:

The only acceleration acting on this motion case in the acceleration due to gravity: 9.8 m/s^2 in the downwards direction.

Answer:

2.93 m  (which agrees with answer "C" on the list)

Explanation:

Recall that the speed of the wave equals the product of the wave's length times its frequency. Therefore, the wavelength is going to be the quotient of the speed of the signal divided its frequency:

Wavelength = 2.997  10^8 / 1.023  10^8 =  2.93 m

Answer:

Explanation:

velocity is the rate of change of displacement with respect to time.

Velocity = displacement/time

If a  line runs straight from 0 seconds 5 meters to 10 seconds 30 meters.

The velocity will be expressed as;

v = d2-d2/t2-t1

v = 30-5/10-0

v = 25/10

v = 2.5m/s

Hence her velocity is 2.5m/s

Daniela's velocity is 2.5 m/s.

Velocity is the ratio of displacement to time taken. It is given by:

Velocity = displacement / time

The velocity of Daniela can be gotten by calculating the slope of the graph. Considering the points (0, 5) and (4, 15).

[tex]Velocity(slope)=\frac{15-5}{4-0}=2.5\ m/s[/tex]

Therefore Daniela's velocity is 2.5 m/s.

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Answer:

2 to 3 weeks

Explanation:

Answer:

h' = 55.3 m

Explanation:

First, we analyze the horizontal motion of the projectile, to find the time taken by the arrow to reach the orange. Since, air friction is negligible, therefore, the motion shall be uniform:

s = vt

where,

s = horizontal distance between arrow and orange = 60 m

v = initial horizontal speed of the arrow = v₀ Cos θ

θ = launch angle = 30°

v₀ = launch speed = 35 m/s

Therefore,

60 m = (35 m/s)Cos 30° t

t = 60 m/30.31 m/s

t = 1.98 s

Now, we analyze the vertical motion to find the height if arrow at this time. Using second equation of motion:

h = Vi t + (1/2)gt²

where,

Vi = Vertical Component of initial Velocity = v₀ Sin θ = (35 m/s)Sin 30°

Vi = 17.5 m/s

Therefore,

h = (17.5 m/s)(1.98 s) + (1/2)(9.81 m/s²)(1.98 s)²

h = 34.6 m + 19.2 m

h = 53.8 m

since, the arrow initially had a height of y = 1.5 m. Therefore, its final height will be:

h' = h + y

h' = 53.8 m + 1.5 m

h' = 55.3 m

Answer:

Explanation:

y-component = - mgcos(8.7)

= - (1150)(9.81)cos(8.7)

= - 11151.69378

= - 11151.69 N

The weight of the y-component is 11140.33N.

To find the weight of the y-component:

Given,

Car weight = 1150 kg

Anfle = 8.70 degree

weight = mg = 1150 * 9.8

= 11270 N

Y-component =  mg cos∅

= 11270 * cos(8.70)

= 11140.33N

The aspect that pushes proper or left is referred to as the x-factor, and the element that pushes up or down is known as the y-component.

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Answer:

Hello there! The answer your would be looking for is:

A 33 kg object that is moving north at 10 m/s

Momentum can be defined as the product of mass and velocity. Thus momentum is directly proportional to both velocity and momentum. Thus, the object with greater mass as well as velocity has greater momentum. Therefore, option C is correct.

Force can be described as an external agent acting on a body, to change its state of rest or motion. There are several kinds of forces such as magnetic force, frictional force, nuclear force, etc.

In physics, force can be described as the product of the mass and acceleration of the body. Greater mass results in greater force required to be exerted on the object to make it move or stop.

Therefore, when mass or velocity or both increases, the momentum of the object increases as well. Therefore, the larger object moving faster gain greater momentum.

Therefore, when the same force is exerted on the object then, the 41 kg object that is moving north at 12 m/s will undergo the greatest change in momentum.

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Your question was incomplete but most probably the complete question was,

A force of 20 N to the south is applied to each object below. Which object will undergo the greatest change in momentum?

A. A 33 kg object that is moving north at 12 m/s

B. A 41 kg object that is moving north at 10 m/s

C. A 41 kg object that is moving north at 12 m/s

D. A 33 kg object that is moving north at 10 m/s

Answer:

its something that hold the air for forceing liy by the exgen

Explanation:

Answer:

b. 29.2 rev/min

Explanation:

       [tex]L_{0} = L_{f} (1)[/tex]

        [tex]L_{0} = I_{0} * \omega_{0} (2)[/tex]

        where I₀ = initial moment of inertia = moment of inertia of the disk +

        moment of inertia of the cylinder and ω₀ = initial angular velocity  =

       30.0 rev/min.

       [tex]L_{f} = I_{f} * \omega_{f} (4)[/tex]

       where If = final moment of inertia = moment of the inertia of the solid

      disk + moment of  inertia of the clay flattened on a disk, and ωf = final

      angular velocity.

   [tex]I_{f} = \frac{1}{2} * m_{d} *r_{d} ^{2} + \frac{1}{2}* m_{fd} *r_{fd} ^{2} = 0.2 kg*m2 +6.4e-3 kg*m2 = 0.2064 kg*m2 (5)[/tex]

       ⇒ Lo =Lf = If*ωf

        [tex]\omega_{f} = \frac{L_{o}}{I_{f} } = \frac{6.027kg*m2*rev/min}{0.2064kg*m2} = 29.2 rev/min (6)[/tex]

The rate of change of angular displacement is defined as angular speed. The final angular speed of the wheel will be 29.2 rev/min.

The rate of change of angular displacement is defined as angular speed.  is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular speed

The given data in the problem is

m is the mass of wheel = 10.0 kg

r₁ is the radius of disk = 20.0 cm=0.2

M is the mass of clay= 2.0 kg

R is the radius of cylinder =  3.0cm

[tex]\rm \omega_i[/tex] is the initial rotational speed =30.0 rev/min

r₂ is the final radius of disk=  8.0 cm.

[tex]\rm \omega_f[/tex] is the initial rotational speed=?

When the external torques act on the body is zero the total angular momentum must be conserved, as follows:

Initial momentum = Final momentum

[tex]\rm L_0=L_f[/tex]

The value of the initial angular momentum L₀ is found by

I₀ = initial moment of inertia = moment of inertia of the disk +moment of inertia of the cylinder

[tex]\rm I_0= \frac{1}{2}m_dr_d^2+ \frac{1}{2}m_cr_c^2\\\\ \rm I_0= \frac{1}{2}\times 10\times (0.2)^2+ \frac{1}{2}\times m_2(0.03)^2[/tex]

[tex]\rm L_0 = I_0\times \omega_0\\\\ L_0 = 2009\times 30\\\\ \rm L_0 =6.027 \;kgm^2rev/min[/tex]

The value of the final angular momentum [tex]I_f[/tex] is found by

[tex]\rm I_f= \frac{1}{2}m_dr_d^2+ \frac{1}{2}m_fr_fd^2\\\\ \rm I_0= 0.2064 m_2[/tex]

[tex]\rm I_f[/tex] is the final moment of inertia = moment of the inertia of the solid disk + moment of inertia of the clay flattened on a disk.

[tex]L_0 =L_f = I_f \times \omega_f[/tex]

[tex]\rm \omega_f=\frac{L_0}{I_f} \\\\ \rm \omega_f=\frac{6.027 m_2}{0.2064 m_2} \\\\ \rm \omega_f= 29.2\; rev/min[/tex]

Hence the final angular speed of the wheel will be 29.2 rev/min.

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Answer:

The height risen by the ball is 39.8 m.

Explanation:

Given;

total time spent in air by the ball, t = 5.7 s

time to rise to maximum height, t = 5.7 /2 = 2.85 s

The initial velocity of the ball is given by;

v = u - gt

where;

v is the final velocity at maximum height = 0

u is the initial velocity of the ball

0 = u - gt

u = gt

u = (9.8 x 2.85)

u = 27.93 m/s

The vertical height traveled by the ball is given by;

v² = u² - 2gh

where;

v is the final velocity of the ball at maximum height = 0

g is acceleration due to gravity = 9.8 m/s²

0 = u² - 2gh

2gh = u²

h = u² / 2g

h = (27.93)² / ( 2 x 9.8)

h = 39.8 m

Therefore, the height risen by the ball is 39.8 m.

Answer:

b.dance

Explanation:

don't know the explanation

Answer:

121m

Explanation:

Magnetic field = 0.03

Current = 1.00A

Diameter = 0.5

Length = 10vm

B = UoIN/Lcylinder * n

n = number of layer

n = 0.5x10^-3 x 0.03/4pi x 10^-7 x 1

= 0.0005x0.03/12.56x10^-7

= 11.94

~12

Average radius

= 0.008

Length of wire = 2x3.13x0.008x12x200

= 120.6m

= 121m

Answer:

a) The kinetic energy of the particle at any time t is [tex]K = 50+120\cdot t^{2}+72\cdot t^{4}[/tex].

b) The acceleration of the particle at time t is [tex]a= 12\cdot t[/tex]. The force acting on the particle at time t is [tex]F = 48\cdot t[/tex].

c) The power being delivered to the particle at time t is [tex]\dot W = 240\cdot t +288\cdot t^{3}[/tex].

d) The work done on the particle in the interval t = 0 to t = 5 is 48000 joules.

Explanation:

a) The kinetic energy of the particle is entirely translational, whose formula is:

[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (1)

Where:

[tex]K[/tex] - Translational kinetic energy, measured in joules.

[tex]m[/tex] - Mass of the particle, measured in kilograms.

[tex]v[/tex] - Velocity of the particle, measured in meters per second.

The velocity of the particle is the rate of change of the position of the particle in time, that is:

[tex]v = 5+6\cdot t^{2}[/tex] (2)

Where [tex]t[/tex] is the time, measured in seconds.

By substituting on (1), we have the following expression: ([tex]m = 4\,kg[/tex])

[tex]K = 2\cdot (5+6\cdot t^{2})^{2}[/tex]

[tex]K = 2\cdot (25+60\cdot t^{2} +36\cdot t^{4})[/tex]

[tex]K = 50+120\cdot t^{2}+72\cdot t^{4}[/tex]

The kinetic energy of the particle at any time t is [tex]K = 50+120\cdot t^{2}+72\cdot t^{4}[/tex].

b) The acceleration of the particle is the rate of change of the velocity of the particle in time, that is:

[tex]a= 12\cdot t[/tex] (3)

Where [tex]a[/tex] is the acceleration of the particle, measured in meters per square second.

The acceleration of the particle at time t is [tex]a= 12\cdot t[/tex].

The force is obtained by multiplying (3) by the mass of the particle. That is to say: ([tex]m = 4\,kg[/tex])

[tex]F = m\cdot a[/tex] (4)

[tex]F = 48\cdot t[/tex]

The force acting on the particle at time t is [tex]F = 48\cdot t[/tex].

c) According to the Work-Energy Theorem, the change in kinetic energy of the particle equals the change in the net work done on the particle. In this case, the power is equal to the rate of change in kinetic energy.

[tex]\dot W = \dot K[/tex] (5)

[tex]\dot W = \frac{d}{dt}(50+120\cdot t^{2}+72\cdot t^{4})[/tex]

[tex]\dot W = 240\cdot t +288\cdot t^{3}[/tex]

The power being delivered to the particle at time t is [tex]\dot W = 240\cdot t +288\cdot t^{3}[/tex].

d) The work done on the particle ([tex]W[/tex]), measured in joules, is equal to the change of the kinetic energy of the particle:

[tex]W = K(5)-K(0)[/tex] (6)

[tex]W = [50+120\cdot (5)^{2}+72\cdot (5)^{4}]-[50+120\cdot (0)^{2}+72\cdot (0)^{4}][/tex]

[tex]W = 48000\,J[/tex]

The work done on the particle in the interval t = 0 to t = 5 is 48000 joules.

Answer:

Weightlessness

Explanation:

When the elevator is in free fall, this can only occur when the cord of the elevator breaks.

The acceleration of the elevator will be equal to the acceleration due to gravity. That is:

a = g

Then, the body will experience what we called WEIGHTLESSNESS

Where the normal reaction N of the person will tend to zero. That is

N = 0

The value of FN < 0 because the person inside the lift will experience weightlessness.

Answer:

The fastest satellite must change orbit

The most massive body (m₁) transfers more momentum to the satellite,

Explanation:

For this problem we consider a system formed by the satellite and each of the bodies with which it collides, in this system the forces during the collision are internal, the amount of movement must be conserved. Let's write the momentum is two instants

Most massive body (m1)

initial. Before the crash

      p₀₁ = M v + m₁ v₁

after the crash

      [tex]p_{f1}[/tex] = M v´ + m₁ v₁´

how momentum is conserved

     p₀ = p_{f}

Lighter body (m2)

      p₀₂ = M v + m₂ v₂

       p_{f2} = M v´ + m₂ v₂´

Let's clarify that the speed of the satellite and the object do not have the same direction, in general these shocks are elastic.

We can see that  p₀₁> p₀₂

Let us analyze the two cases when the body collides, The most massive body (m₁) transfers more momentum to the satellite, therefore there must be a greater change in its momentum and velocity.

The fastest satellite must change orbit, thus rotating at a different distance from Earth

Answer:

bcuz ov yo fat mamma

Explanation:

Answer:

Water pollution

Explanation:

Answer:

a. 250kg I think it's the right answer. hope it helps:)

Answer:

C.10

Explanation:

because when you divide 50 divided by 5 = 10

Answer: the washer would slow down depending on how strong the magnet is even though the gravitational pull is the same. the change would be .6

Explanation: i don't really get it

Answer:

Because shoes protect our feet from some of the most harmful platforms

Gravel has some small pebbles on it sometimes (or other sharp objects)

Gravel is pretty hard.

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{6}{12} = \frac{1}{2} \\ [/tex]

We have the final answer as

Hope this helps you