Answer:
a) 1.58
Explanation:
= 0.681 M Need grams of NaF
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The pH of the hydrofluoric acid solution prior to adding sodium fluoride - = 1.606 and the amount of sodium fluoride should be added to prepare the buffer solution - 35.75g or 36 g.
a) Weak acid such as hydrofluoric acid is not entirely dissociate. The capacity of dissociation of the compound will be given by it's acid dissociation constant ka
HF <==> H+ + F-
I 1.0 0 0
C -x +x +x
E 1.0-x x x
I = initial conc. C = Change in conc. E = Conc. at equilibrium
Ka = (Ka for HF is 6.3 x 10-4 constant)
= 6.3 x 10-4 =
= 6.3 x 10-4 (1.0- x ) =
Solve for x using quadratic equation method. Neglecting negative value as concentration is always positive value
x = -0.0254 and x = 0.0248 = [H+]
pH = - log []
pH = - log 0.0248
= 1.606 ( pH of HF before adding NaF)
b) Given:
pH = 3.00
[HF] = 1.00 M
[F-] - ?
Solution:
a buffer follows the Henderson-Hasselbach equation:
pH = pKa + log
3.00 = 3.167 + log
log = -0.167
[] = (0.681) ([HF])
= (0.681) (1.00)
= 0.681 M
NaF --> + [NaF]
= 0.681 M Need grams of NaF
The amount of would be =
=
= 35.75g NaF
Thus, the pH of the hydrofluoric acid solution prior to adding sodium fluoride - = 1.606 and the amount of sodium fluoride should be added to prepare the buffer solution - 35.75g or 36 g.
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in the chlorine monoxide molecule, chlorine has a charge of 0.167 e-. if the bond length is 154.6 pm, calculate the dipole moment of the molecule in debyes. a. 3.11 d b. 2.30 d c. 0.167 d d. 1.24 d e. 1.65 d
The correct option is option d 1.24
What is dipole moment?
A dipole moment forms in any system where the charges are dispersed. A dipole moment could be created by both covalent and ionic bonding. The development of the dipole moments is caused by the difference in electronegativity. Electronegativity describes the chemical bonding between these two atoms.
A bond dipole moment measures the polarity between two atoms in a molecule. Bond dipole and the concept of electric dipole moment are connected. It evaluates how effectively a system separates positive and negative charges. The bond dipole moment has magnitude and direction because it is a vector quantity.
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if a star close to earth si 6.78 light years away, how many years does it take for this star's light to reach earth
The time (in years) taken for the star's light to reach the earth, given it is 6.78 light years away is 6.78 years
How do I determine the time?From the definition 6.78 light years speed, we can obtain a formula to calculate time. This is illustrated below:
Speed = distance / time
Cross multiply
Speed × time = distance
Divide both side speed
Time = distance / speed
With the above formula, we can determine the time.
The following data were obtained from the question give above:
Distance = 6.78 light yearsSpeed of light in space = 3×10⁸ m/s = 1 Light year/yearTime =?Time = distance / speedTime = distance / speed
Time = 6.78 / 1
Time = 6.78 years
Thus, we can conclude that the time required is 6.78 years
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At the end of the video, the man getting interviewed provides an analogy about meditation and states of matter. Create your own analogy that explains the differences between the behavior of molecules in different states of matter. Explain.
Marathon runners well exhibit the differences between the behavior of molecules in different states of matter.
At the starting point before the start of the race, the runners would gather in a common place before the starting line. They would be close to each other and are tightly packed like solid molecules.
After the race was started, some players would start to move fast and some remain in a group for a certain period. They were loosely packed compared to solid.
As the game reaches the end point, the players would be more spread out based on their stamina. They would be more loosely packed compared to solid and liquid.
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part a a solution is prepared by dissolving 0.69 mol of mgcl2 in 0.40 kg of water. how many moles of ions are present in solution? express your answer to two significant figures and include the appropriate units. n
The moles of ions present in the solution when a solution is prepared by dissolving 0.69 mol of mgcl2 in 0.40 kg of water is 2.0 moles.
0.69 moles of MgCl2 in 0.4 kg water
MgCl2 disassociates as Mg2+ + 2Cl-
So 1 MgCl2 from 3 moles
Moles of ion present is 3x0.69=2.0 moles
The number of moles is given mass by molecular mass.Significant figures are a way of expressing numbers.In positional notation, significant figures are the digits in a number that is trustworthy and required to denote the amount of something.To learn more about significant figures visit:
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Cadmium (Cd) is a solid at room temperature, forms an ion that has a +1 or +2 charge, is a less reactive metal, and forms more than one unique compound with a given nonmetal. Because of these properties, cadmium (Cd) could also be identified as
a halogen.
an alkaline earth metal.
a transition metal.
an alkali metal.
Because of these properties, cadmium (Cd) could also be identified as a transition metal.
Cadmium (Cd) is a solid at room temperature, forms an ion that has a +1 or +2 charge, is a less reactive metal, and forms more than one unique compound with a given nonmetal.
Transition metal, any of various chemical factors which have valence electrons i.e., electrons that can participate inside the formation of chemical bonds in two shells as opposed to simplest one.
Transition metals are determined within the periodic desk among the s-block and p-block elements. Hence, they are known as d-block elements. Transition metals are unstable metals that display transitional conduct between s and p block elements, therefore their name.
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abs plastic is a polymer consisting of three monomer units: acrylonitrile (c₃h₃n), butadiene (c₄h₆), and styrene (c₈h₈). a sample of abs plastic contains 14.9% n by mass. it took 1.56 g of br₂ to react completely with a 2.00 g sample of abs plastic. bromine reacts 1:1 (by moles) with the butadiene units in the polymer and nothing else, so bromination is a method for determining the quantity of butadiene in the polymer. what is the percent by mass of styrene in the polymer?
The ABS plastic is a polymer which has styrene 28.5% by mass.
A polymer is a substance or material made up of macromolecules, which are very big molecules made up of several repeating subunits.
Styrene and acrylonitrile are polymerized with polybutadiene to create ABS, a terpolymer. Since ABS plastic is amorphous, it lacks a proper melting point.
A polymer called a terpolymer is created when three distinct monomers are copolymerized.
Let the mass of sample ABS plastic = 100 g
Given, mass of Nitrogen (N) in ABS plastic = 11.9 g
Moles of Nitrogen (N) in ABS plastic = 11.9 / 14 = 0.85 mol
1 mole of N is present in 1 mole of acrylonitrile
0.85 mol of N is present in acrylonitrile = 0.85 mol
Moles of acrylonitrile = 0.85 mol
Mass of acrylonitrile = 0.85 mol X 53 g/mol = 45.05 g
Moles of [tex]Br_2[/tex] reacted = 1.56 g / 159.8 g/mol = 0.0098 mol
As given, [tex]Br_2[/tex] and butadiene react in 1:1 by moles
So, moles of butadiene = 0.0098 mol
Mass of butadiene in 2g ABS sample = 0.0098 mol X 54 g/mol = 0.529 g
Mass of butadiene in 100g ABS sample= 0.529 / 2 x 100 g = 26.45 g
Mass of styrene in 100g ABS Sample = mass of sample - mass of butadiene - mass of acrylonitrile
Mass of styrene = 100 – 26.45 – 45.05 = 28.5g
% Mass of styrene = 28.5%
Result:
28.5% of styrene is present in 100g ABS plastic, which is a polymer.
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ANSWER QUICKLY calcium carbide reacts with water to form calcium hydroxide and acetylene gas according to the reaction below what mass of Cac2 is used when 2.00 moles of water react
Answer: Calcium carbide (CaC2) reacts with water to produce acetylene (C₂H₂):. CaC2 (s) + 2H2O (g) → Ca(OH)2 (s) + C₂H₂ (g).
If three quarters of the elements are metals how are the remaining elements categorize?
Answer: The elements with properties intermediate between those of metals and nonmetals are called semimetals (or metalloids).
During a phase change, the temperature remains constant although heat is still being added. What is the best explanation for what the heat energy is being used to do?
A) Breaking chemical bonds to form new substances.
B) Moving the particles closer together.
C) Weakening or breaking the intermolecular forces.
D) Increasing the movement of particles.
A phase change is a physical change involves no bond making or breaking. The heat energy is used to weaken the intermolecular forces of attraction and moves the molecules apart. Thus option C and D are correct.
What is a phase change?A phase change is the change in phase or state of the substance. For example, solid to liquid, liquid to gas conversions etc. are phase changes.
During a phase change, no chemical bond is breaked or maked but the intermolecular force of attraction holding the molecules together weakens and moves the molecules apart.
Consider the phase change of solid to liquid. The closely packed molecules in solid uses heat energy to to move apart by weakening the intermolecular force and form the liquid state.
Therefore, during a phase change, heat is used to weaken or break the intermolecular force and increasing movement of particles. Thus options C and D are correct.
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which reaction takes place in the catalytic converter of an automobile? group of answer choices conversion of co2 to co conversion of no to n2 and o2 conversion of n2 and o2 to no2 conversion of so2 to s and o2
The conversion of NO to N2 is the reaction that takes place in the catalytic converter of an automobile.
To minimize harmful pollutants, catalytic converters use redox (reduction and oxidation) reactions. They make use of a platinum and rhodium-based reduction catalyst. It helps to reduce nitrogen oxides (NOx) by eliminating nitrogen atoms from nitrogen oxide molecules (NO and NO2).Thus, oxygen gas can be created from free oxygen (O2)Another illustration of surface catalysis is the catalytic converter, in which the reactant molecules are adsorbed onto a solid surface before they react with the catalyst to create the product. The surface area of the catalyst in contact with the reactants influences the rate of a surface-catalyzed reaction.To learn more about catalytic converter visit:
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need help on this for science
Answer:
For part A : Length = 3
Width = 3
Height = 4
For part B : on multiplying 3 × 4 × 3 = 36
For part C : Answer = 36
how might the process of making paper from wood be changed to produce paper that is not so acidic
During the production of paper, use a mild base such as calcium or magnesium bicarbonate to neutralize the natural acids occurring in wood pulp, and prevent the formation of additional acids.
What is acid-free paper?Acid-free paper is paper if soaked in water, gives a neutral or basic pH. The production of such paper can be done from any cellulose fiber as long as the active acid pulp is removed during processing. Acid-free paper is a solution to the problem of preserving documents and preserving artwork for long periods.
The wood pulp paper becomes to be acidic from alum-rosin sizing which, generates sulfuric acid in the presence of moisture. Acids also are formed in a paper by the absorption of pollutants such as mainly sulfur and nitrogen oxides.
The addition of bicarbonate is in excess, to provide the paper with an alkaline reserve to offer protection from further attack by acids remaining in the paper.
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(a) what fraction of the neutron's kinetic energy is transferred to the carbon nucleus? (the mass of the carbon nucleus is about 12.0 times the mass of the neutron.)
There is the neutron's total kinetic energy. E is the same as the final kinetic energy of the EF-2 carbon nucleus. Okay, I'm down one from k E F one. In other words, Jews, this is 1.3 incremental -13 -4, -3.69 into 10 to the Power -14. 1.3 into a power of 10 to the -13th Minour.
Two will equal twelve in one if we subscribe one river to the neutron and another to carbon. Okay. EI one, which is a brand-new drone's first kind of technology, is equivalent to one three into ten to thirteen. For the first support, no. Half of Mnu square is equal to E I and E F, respectively, as well as one V squared. Additionally, if you apply the law of conservation of momentum, M 1 - M 2 will equal 1 + M 2 into Vi, giving you v = 2 and M 1 - M 2. And to you, multiplied by M1 + M2, is mmhmm.
As a result, if you substitute, the answer to the second equation will be K E F 1, which is equal to half of M 1, which is divided by M 1 plus M 2 entire square to give you square. We make this much simpler. And if we divide KEF one by KEI one, we get four, which is equal to M1 plus M2 divided by M1. Cool square, can you divide 4 M1 12 by M 1 + 12? My father has all this. One divided by M. They were by 1 69, which is equal to 40.
This serves as the first support's response. The final kinetic energy is provided by k e F one as a result of the neutron's current technology being transmitted to carbon during the collision's second support. That is equivalent to 3.69 into 10 and 48 x 1, respectively, and to 1.3 into 10 to the power of 13 and 69. Jews, to the Power -14. There is the neutron's total kinetic energy. E is the same as the final kinetic energy of the EF-2 carbon nucleus. Okay, I'm down one from k E F one. In other words, Jews, this is 1.3 incremental -13 -4, -3.69 into 10 to the Power -14. 1.3 into 10 to the power -13 Minor of the original solution.
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a 0.755g sample of hydrated copper (ii) sulfate, cuso4 x h2o was heated carefully until it had changed completely to anhydrous copper (ii) sulfate, cuso4, with a mass of 0.483 g. determine the value of x.
The value of x is 5.
We know that,
Molar mass of CuSO4 = 156.609g/mol
Molar mass of H2O = 18.015g/mol
So ,Molar mass of CuSO4 .xH2O = molar mass of CuSO4 +X(molar mass of H2O)
Molar mass of CuSO4.xH2O=[( 156.609) + (18.015)X] g/mol
mass of CuSO4.xH2O = 0.755gmass of CuSO4 = 0.483g
And if we change 4.895 to a whole number or one significant figure,
then we get
x = 5
chemical formula is = CuSO4.5H2O (Blue Vitriol)
What is molar mass?
The molar mass of a chemical compound is determined by dividing its mass by the quantity of that compound, expressed as the number of moles in the sample, measured in moles.
Therefore the value of x is 5.
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The hydrochloric acid utilized in this experiment can often discolor gloves if it is spilled on them during use. If this does occur, what should be done in order to remedy this potentially hazardous situation?.
There are many applications for hydrochloric acid. It is used for the production of chlorides, fertilizers and dyes, as well as in galvanic plating and in the photographic, textile and rubber industries.
Eyes, skin and mucous membranes are corroded by hydrochloric acid. In humans, acute (short-term) inhalation exposure may cause eye, nose, and respiratory tract irritation, as well as inflammation and pulmonary edema. Acute oral exposure can cause mucosal, esophageal, and stomach burns, and dermal contact can cause severe burns, ulceration, and scarring in humans. Gastritis, chronic bronchitis, dermatitis, and photosensitization have all been associated with chronic (long-term) exposure to hydrochloric acid. Long-term exposure to low concentrations can also cause tooth discoloration and erosion. Hydrochloric acid has not been classified as a carcinogen by the EPA.
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3. There are 2 questions about isotopes.a) If an element has three isotopes with the following characteristics, what is theaverage atomic mass of the element?Isotope #1 is 10.0% abundant and has a mass of 23.8 amu. Isotope #2 is40.0% abundant and has a mass of 24.6 amu. Isotope # 3 has a mass of25.8 amu.b) An isotope has a half life of 5 minutes. How much of a 100 gram sample ofthis isotope is left after 20 minutes?
Question a
Step 1
The average atomic mass of the element is calculated as:
[tex]Average\text{ atomic mass =}\frac{\sum_^(eachmass\text{ }x\text{ }\%abundance\rparen}{100}[/tex]--------------------
Step 2
Information provided:
Isotope 1:
10.0 % abundant and 23.8 amu.
Isotope 2:
40.0 % abundant and 24.6 amu.
Isotope 3:
25.8 amu, the % abundant = 100 % - 10.0 % - 40.0 % = 50.0 %
-----------------------
Step 3
Procedure:
Average atom mass = (10.0% x 23.8 amu + 40.0% x 24.6 amu + 50.0 % x 25.8 amu)/100 = 25.12 amu
Answer: 25.12 amu
1) An alloy called nichrome contains the elements chromium and nickel. 100g of nichrome contains 20g of chromium. How much nickel does it contain?
2) Why does bronze not rust?
3) Complete the equation: iron + copper sulphate = ____ + ____
Assume that the given alloy nichrome is pure of nickel and chromium then, if 100 g of nichrome contains 20 g of chromium , remaining is nickel thus, it contains 80 g of nickel.
Bronze hardly rust because the iron content in this alloy is very less. The reaction iron + copper sulphate gives iron sulphate + copper.
What is an alloy?An alloy is a metallic substance made of two or more metals. For example nichrome is a combination of nickel and chromium and brass is a combination of copper and zinc.
If the 100 g of nichrome with 20 g of chromium purely contains nickel and chromium then, it contains 100-20= 80 g of nickel.
Bronze is an alloy of copper and tin. Rust is iron oxide and since bronze contains only traces of iron hence, it hardly undergo corrosion and form rust.
Iron and copper sulphate reacts to form iron sulphate and metallic copper: iron + copper sulphate [tex]\rightarrow[/tex] iron sulphate+ Cu.
Hence, the mass of 100 g of nichrome with 20g chromium is 80 g. Bronze does not rust because of the small iron content and iron and copper sulphate reacts to give iron sulphate and Cu.
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a 71.0 ml portion of a 1.50 m solution is diluted to a total volume of 258 ml. a 129 ml portion of that solution is diluted by adding 149 ml of water. what is the final concentration? assume the volumes are additive.
The final concentration assuming the volumes are additive when a 71.0 ml portion of a 1.50 m solution is diluted to a total volume of 258 ml. a 129 ml portion of that solution is diluted by adding 149 ml of water is 0.191 M
This can be solved by using the dilution factor.
So the dilution factor for the first dilution is 71.0 ml to 258 ml
DF1=258/71=3.63
For the first solution, the dilution factor is
3.163, refers that the concentration is decreased by a factor of 3.163.
The concentration of diluted solution is
c(diluted)=1.50/3.63=0.413
Now, you take a sample of 129 mL of this diluted solution and add another 165 mL of water. So,
V(final)=129ml +149 ml=278 mL
The concentration of the 129 mL sample is equal to the concentration of the first diluted solution, i.e. 0.413 M
So,
DF2=278/129=2.155
So, the final concentration is
c(final)=0.413/2.155=0.191 M
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whats the wavelength of the radiation with a frequency of 6.00 x 10^15 Hz
Given Data:
Frequency of radiation = 6.00 x [tex]10^{15}[/tex] Hz
The relationship between frequency and wavelength is expressed by the formula , c = λν, where λ is the wavelength of the radiation,
ν is the frequency of the radiation, c is the velocity of light in free space.
c =3 x [tex]10^{8}[/tex] m/s , ν = 6.00 x [tex]10^{15}[/tex] Hz
Then , wavelength of the radiation is , λ = [tex]\frac{c}{v}[/tex] = [tex]\frac{3X10^{8} }{6X10^{15} }[/tex] = 0.5 x [tex]10^{-7}[/tex] m
= 50 nm.
Hence, the radiation with a frequency will have a wavelength of 50 x [tex]10^{-9}[/tex] m = 50 nm.
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Which elements are represented by the following electron configurations:
7 1s²2s²2p 3s²3pº4s¹
1s²2s22p 3s 3p 4s² → (add all of the exponents) → 20-Ca
8 1s²2s²2p 3s²3p 3d³4s²
Which elements are represented by the following shorthand notation:
9 [Ne]3s²
10 [Ne]3s 3p6
[He]2s²2p3→ (write the electron configuration of the element inside the brackets & then add
what you see outside of the brackets)→→ [1s²]2s22p³→ (add all of the exponents)
7- Nitrogen
1s²2s²2p° → 3s² → 3p6 →4s²3d¹04p6 → 5s² →
4d¹05p6
5p6s²4f¹4
6s²4f45d¹0
6d ¹0
6p7s²5f¹4 ->>
Electron configurations, the atomic number of the above element is 2+2+6+2+3=15. The atomic number of the element below the given element is 15+18=33.
Titanium, Nitrogen (N), Phosphorus, Sulfur (S)
What is Electronic configuration ;The arrangement of an atom's or molecule's electrons in atomic or molecular orbitals is known as the electron configuration in atomic physics and quantum chemistry.
The placement of electrons in orbitals surrounding an atomic nucleus is known as electronic configuration, also known as electronic structure or electron configuration.Since at least the 1920s, the phrase "electronic configuration" has been in use. Niels Bohr, a quantum physicist, is credited with creating a model that depicts how electrons are arranged around a nucleus.Electron configurations written down. The energy level (the period) should come first when writing an electron configuration, followed by the subshell that needs to be filled and the superscript, which indicates how many electrons are in that subshell. The atomic number Z represents the total number of electrons.
In other words, we adhere to the Aufbau Principle, Pauli-exclusion Principle, and Hund's Rule, which are the three key rules.
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based on the amounts of starting materials used, a chemist calculates a possible yield of 213.4 g213.4 g in a reaction. however, after isolating her purified product, she finds that she has only 198.5 g198.5 g of products. what is her percent yield for this reaction?
The percent yield of this reaction when based on the amounts of starting materials used, a chemist calculates a possible yield of 213.4 g in a reaction and isolating her purified product, she finds that she has only 198.5g of products is 93%
The percent yield is the experimental yield upon theoretical yield divided by 100
The experimental yield is 198.5 g
The theoretical yield is 213.4 g
The percent yield is as follows;
% yield= 198.5 g/213.4= 0.93x100
%yield=93%
The actual yield is the quantity of product that is produced from a certain quantity of reactant.It is a way of measuring the reaction's progress and the products formed in the reaction.To learn more about percent yield visit:
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at the low temperatures found in some interstellar molecular clouds (around 100 k), molecular oxygen emission is strongest at a wavelength is 0.2521 cm. determine the speed (in km/s) of a low temperature molecular cloud containing molecular oxygen if its strongest emission is at a wavelength of 0.1835 cm
By using the Doppler effect, - 81634.27km/s is found to be the velocity of the cloud.
The Doppler effect can be used to solve this problem. When an observer travels in relation to the wave source, the frequency or wavelength changes from the viewpoint of the observed. The Doppler Effect is commonly used to calculate the velocity of the origin of waves or the velocity of the viewer. The generic waveform and frequency equations are used to derive the Doppler Effect velocity equations. The source velocity may then be calculated by setting the observer velocity to zero.
The Doppler shift in wavelength or frequency is calculated using the following relationship:
Δλ / λne = ν / c
where,
Δλ = wavelength shift
λne = wavelength of stationary source
ν = velocity of source
c = velocity of light = 3 x [tex]10^5[/tex] km/s
Given:
Initial wavelength, λini = 0.2521cm
New wavelength, λnew = 0.1835cm
Calculation:
Wavelength shift,
Δλ = λnew - λini
Δλ = (0.1835cm) - (0.2521cm)
Δλ = - 0.0686
On substitution of the known values in the above equation, we get:
Δλ / λne = ν / c
- 0.0686 / 0.2521 = ν / 3 x [tex]10^5[/tex]
ν = - 0.0686 x 3 x [tex]10^5[/tex] / 0.2521
ν = - 81634.27km/s
Result:
- 81634.27km/s is found to be the required velocity of the cloud moving towards us.
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an orbital is described by combining the n quantum number with the quantum number, for example, 1s and 3p are descriptions of orbitals. group of answer choices true false
Yes, the given statement is true that an orbital is described by combining the n quantum number with the l quantum number, for example, 1s and 3p are descriptions of orbitals.
Quantum numbers are those numbers that are used to identify and describe the distribution and position of an electron in an atom.
In general, quantum numbers are classified as principal (n), angular (l) and magnetic (m) and consist of integers starting from 0, 1, 2, 3 and so on.
The estimated values for the principal quantum i.e. 'n' are 1, 2, 3, 4, and so on.
Similarly, for angular quantum numbers i.e. 'l' the values range between 0 and n - 1.
Orbitals are found in sub-shells and are made up of these quantum numbers i.e. n and l.
A two-digit code is assigned to an orbital e.g. 2p or 4f. Here 'n' is the shell whose value is 2 and 4 and 'p' and 'f' are subshells.
If we combine the abovementioned quantum numbers then we see that for shell n= 3 there will be three subshells 3s, 3p, and 3d orbitals.
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A piece of aluminium foil is 8.0×1^-5cm thick . what is its thickness in micrometers?
Answer: 80000 micrometers
hope i helped
i will give 100 points for help
Answer: Hope this helps!
Explanation:
Oxygen has the atomic number 8; its atoms contain 8 protons and 8 electrons. Uranium has the atomic number 92; its atoms contain 92 protons and 92 electrons.
I don't know if this is what your looking for but i think it should help!
an aqueous solution of hydrobromic acid is standardized by titration with a 0.162 m solution of barium hydroxide. if 29.3 ml of base are required to neutralize 25.9 ml of the acid, what is the molarity of the hydrobromic acid solution? m hydrobromic acid
The molarity of hydrobromic acid is 0.2909 M and molarity of barium hydroxide is 0.1517 M.
The balanced chemical reaction of hydrobromic acid(HBr) and barium hydroxide(Ba(OH)2) is :2HBr(aq) + Ba(OH)2(aq) BaBr2(aq) + 2H2O(l)
So for every 2 moles of hydrobromic acid (acid) 1 mole of barium hydroxide(base) is used for neutralisation.
It is given that 22.0ml of 0.162M solution of barium hydroxide is used for complete neutralisation So no of millimoles of base used =22*0.162=3.564
Number of millimoles of acid required=2*3.564=7.128
Let x be the molarity of acid.then x multiplied by volume(in ml) would give the number of millimoles as molarity=moles/volume7.128=x*24.5x=0.2909
So molarity of hydrobromic acid is 0.2909 M
The balanced chemical reaction of hydroiodic acid (HCl) and barium hydroxide(Ba(OH)2) is :2HI (aq) + Ba(OH)2 (aq) Bal2(aq) +2H2O(l)
So for every 2 moles of hydroiodic acid (acid) 1 mole of barium hydroxide(base) is used for neutralisation.
It is given that 18.8 ml of 0.197M solution of hydroiodic acid is used for complete neutralisation
So no of millimoles of acid used = 18.8*0.197=3.7036Number of millimoles of base required=3.7036/2=1.8518
Let x be the molarity of base.then x multiplied by volume(in ml) would give the number of millimoles as molarity=moles/volume1.8518=x*12.2x=0.1517So molarity of barium hydroxide is 0.1517 M
Therefore, molarity of hydrobromic acid is 0.2909 M and molarity of barium hydroxide is 0.1517 M.
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whats the molarity of phosphoric acid in a solution labelled 20% of Phosphoric acid by weight and a density of 1.12g/mL
The molarity of phosphoric acid in a solution labelled 20% of Phosphoric acid by weight and a density of 1.12g/mL is 11.85 mol/L.
What is molarity?
The number of moles of solute divided by the number of liters of solution is the definition of molarity, a concentration unit in chemistry. Molarity is measured in moles per liter (mol/L).
Number of moles of phosphoric acid whose molar mass is 98:
[tex]Number of moles = \frac{mass}{molar mass}[/tex]
n = 20/98
n = 0.204 mols
[tex]Volume = \frac{mass}{density }[/tex]
V = 20/1.22
V = 17.85 ml
Molarity is the number of moles of solute per liter of solution.
[tex]M = \frac{n}{V}[/tex]
Where, M = molarity, V = volume of solvent in liters, n = no. of moles of solute.
So, [tex]M = \frac{0.204}{17.85} \times \frac{1000}{1}[/tex]
M = 11.85 mol/L
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How can you use different properties and changes to identify a chemical substance? Choose all that apply.
Specific pure substances have their own unique properties.
When separating mixtures, you can use their properties to determine what separation technique is needed.
You can compare properties and changes of an unknown substance to a known one to see if they are the same or different.
Different substances will have different properties and will change in different ways.
You can create classifications of substances based on their properties and/or changes.
We can use different properties and changes to identify a chemical substance through the following below:
Specific pure substances have their own unique properties.When separating mixtures, you can use their properties to determine what separation technique is needed.You can compare properties and changes of an unknown substance to a known one to see if they are the same or different.Different substances will have different properties and will change in different ways.You can create classifications of substances based on their properties and/or changes.What is a Chemical substance?This is referred to as a type of substance which has a definite composition and properties and it is based on different factors.
Pure substances have their own unique properties and a mixture can be separated by using the right techniques through this which is why all is the correct choice.
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5. Describe A ruler is on the table with the
higher numbers to the right. An ant
crawls along the ruler from 6 cm to 2 cm
in 2 seconds. Describe the ant's distance,
speed, and velocity
The distance the ant would have covered crawling from 6 cm to 2 cm on ruler scale would be 4 cm and the speed would be 2 cm/s.
What is distance , speed and velocity and how it comes out to be so?Speed is a quantity which depicts the distance travelled per unit time of a period given.Distance is also a scalar quantity which represents the product of speed and time .Velocity is a vector quantity which is measured as the displacement per unit time.Here the ant covered from 6 cm to 2 cm , so distance covered would be 6 -4 = 2 cm.And speed = 4/2 = 2 cm/sec , hence the speed of the ant covering 4 cm distance on the ruler scale would be 2 cm/sec.To know more about distance visit:
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problem 3 how many rearrangements of are there in which no two adjacent letters are also adjacent letters in the alphabet? for example, no such rearrangements could include either or .
There are 2 rearrangements of abcd in which no two adjacent letters are also adjacent letters in the alphabets.
Here's the Complete question:
How many rearrangements of abcd are there in which no two adjacent letters are also adjacent letters in the alphabet? For example, no such rearrangements could include either ab or ba.
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Using XXXX
We can't put B in either of the middle positions, as there would only be the far end at which to put both A and C and we can't put two things in one slot. That is, XBXX would require A and C to both be in the red X in order to avoid putting them next to B...can't do that, so B can't go in the middle.
Similarly, we can't put C in either of the middle positions, as there would only be the far end at which to put both B and D and we can't put two things in one slot.
So, B and C must go on the ends.
BXXC can only be filled in as BDAC.
CXXB can only be filled in as CADB.
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