Answers
The values of x and y will be 100° and 10° when two parallel lines are being cut by a transversal line.
According to the question,
We have a figure where two parallel lines are being cut by a transversal line.
Now, we know that the angles formed on a straight line is 180° and vertically opposite angles are equal.
The sum of consecutive interior angles is 180°.
Now, we will use these three statements in finding the values of x and y.
Now, adding (2x-70)° and (5y)° will give 180° because the angles made are on a straight line.
(2x-70)°+(5y)° = 180°
2x+5y = (180+70)°
2x+5y = 250° .... (1)
Now, (x+30)° will be the interior angle consecutive to 5y° because they are vertically opposite angles.
So, we have:
(x+30)°+5y° = 180°
x+5y = (180-30)°
x+5y = 150°
5y = 150-x
Now, putting this value of 5y in equation 1:
2x+5y = 250
2x+150-x = 250
x+150 = 250
x = (250-150)°
x = 100°
Now, we will find the value of y:
5y = 150-x
5y = 150-100
5y = 50
y = 50/5
y = 10°
(Note that the values of x and y will be in ° because angles are measured in degree.)
Hence, the value of x is 100° and the value of y is 10°.
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Related Questions
Use the graph to complete the statement. O is the origin. R(y-axis) o R(y=x): (2,3)A. (-2, -3)B. (-3, 2)C. (3, -2)D. (2, -3)
Answers
Answer:
C. (3, -2)
Explanation:
First, we need to reflect the point (2, 3) across the line y = x. To reflect this point, we need to find another point that is at the same distance but on the opposite side of the line, so the reflection is
Therefore, the reflection is the point (3, 2)
Then, reflect (3, 2) across the y-axis, to get:
So, the answer is
C. (3, -2)
7 times blank equals 1
Answers
Answer: 0.1429.
Step-by-step explanation: To double-check our work, multiply 0.1429 by 7 to see that it equals 1.
(12-1) (-2-3) slope p l z
Answers
[tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{ - 3 - ( - 1)}{ - 2 - 12} \\ m = \frac{ - 3 + 1}{ - 14} \\ m = \frac{ - 2}{ - 14} \\ m = \frac{1}{7} [/tex]
ATTACHED IS THE SOLUTION..I also provided you with the formula used to get the gradient.
Solve the following system of equations using the substitution method.
–6x + 2y = 8
y = 3x + 4
Answers
Answer:
Infinite solutions or some courses say all real numbers
Step-by-step explanation:
-6x + 2(3x + 4) = 8 substitute 3x + 4 for y
-6x + 6x + 8 = 8 Distribute the 2
8=8 The x's cancel out leaving a true statement. This means that there are infinite solutions.
Cynthia Besch wants to buy a rug for a room that is 25 ft wide and 31 ft long. She wants to leave a uniform strip
of floor around the rug. She can afford to buy 567 square feet of carpeting. What dimensions should the rug
have?
Answers
Answer:
21 ft by 27 ft
Step-by-step explanation:
You want the dimensions of a rug with an area of 567 square feet such that it fits in a 25 ft by 31 ft room with a uniform space all around.
SetupWe note the room is 31-25=6 ft longer than it is wide. Since the rug has a uniform border around it, the rug dimensions will be 6 ft longer than wide. We want the rug area to be 567 square feet, so for width w we have ...
w(w+6) = 567
Solutionw² +6w +9 = 576 . . . . . . add 9 to complete the square
(w +3)² = 24² . . . . . . . . express as squares
w +3 = 24 . . . . . . . . . positive square root
w = 21 . . . . . . . . . . subtract 3 to find the width
w+6 = 27 . . . . . . add 6 to find the length
The rug should have dimensions 21 ft wide by 27 ft long.
__
Additional comment
The uniform strip of floor around the rug will be 2 feet wide.
Use point-slope form to write the equation of a line that passes through the point (-5,7)(−5,7) with slope -5−5
Answers
The equation of the line that passes through the point (-5,7) with slope -5 in the point-slope form is 5x + y = -18 .
The Point - Slope form of the line passing through (x₁,y₁) with slope m is given by the equation
(y-y₁)= m(x-x₁)
In the question ,
it is given that the required line passes through the point(-5,7) and have the slope = -5 .
the point is (-5,7)
so x₁= -5 and y₁=7 and m = -5
Substituting the value in the equation of point slope form , we get
(y-y₁)= m(x-x₁)
(y-7)= (-5)(x-(-5))
simplifying further , we get
(y-7)= (-5)(x+5)
y-7 = -5x -25
5x + y = -25 +7
5x + y = -18
Therefore , the equation of the line that passes through the point (-5,7) with slope -5 in the point-slope form is 5x + y = -18 .
The given question is incomplete , the complete question is
Use point-slope form to write the equation of a line that passes through the point (-5,7) with slope -5 .
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4. Find the value of p if 2P=2^2 p-7
Answers
Answer:
P = 7
Step-by-step explanation:
[tex]{ \tt{ {2}^{p} = {2}^{2p - 7} }} \\ [/tex]
- From the law of indices; If an index has same base, then the powers are equal.
[tex]{ \boxed{ \rm{ \blue{ ({x}^{a} = {x}^{b}) \rightarrow{ \red{a = b}} }}}}[/tex]
[tex]{ \tt{p = 2p - 7}} \\ { \tt{p -2 p = - 7}} \\ { \tt{p = 7}}[/tex]
OR:
Applying logarithms can also be borrowed;
[tex]{ \tt{ log( {2}^{p} ) = log( {2}^{2p - 7} ) }} \\ \\ { \tt{p log(2) = (2p - 7) log(2) }} \\ \\ { \tt{ \frac{p log(2) }{ log(2) } = \frac{(2p - 7) log(2) }{ log(2) } }} \\ \\ { \tt{p = 2p - 7}} \\ \\ { \tt{p - 2p = - 7}} \\ \\ { \tt{p = 7}}[/tex]
5. John had 2 Snickers bars for every 4 Kit-Kit bars. If John had a total of 16 candy bars,how many Snickers bars did he have?as
Answers
An expert witness for a paternity lawsuit testifies that the length of a pregnancy is normally distributed with a mean of
280 days and a standard deviation of 13 days. An alleged father was out of the country from 242 to 301 days before the birth
of the child, so the pregnancy would have been less than 242 days or more than 301 days long if he was the father. The birth
was uncomplicated, and the child needed no medical intervention. What is the probability that he was NOT the father?
Calculate the z-scores first, and then use those to calculate the probability. (Round your answer to four decimal places.)
What is the probability that he could be the father? (Round your answer to four decimal places.)
Answers
1. The z scores in the question are - 2.92 and 1.615
2. The probability that he is the father = 0.054905
How to solve for the probability and the z scoreThe z score for the 242 days
= 242 - 280 / 13
= -2.92
The z score for the 30 days
= 301 - 280 / 13
= 1.615
Next we have to solve for The probability that he is not the father
this is written as
p(242 < x < 301)
p value of -2.92 = 0.00175
p value of 1.615 = 0.946845
Then we would have 0.946845 - 0.00175
= 0.945095
The probability that he is the father is given as 1 - probaility that he is not the father of the child
= 1 - .945095
= 0.054905
The probability that he is the father is 0.054905
What is probability?This is the term that is used in Statistics and also in the field of mathematics to explain the chances and the likelihood of an event occurring.
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given the following trig equations find the exact value of the remaining five trig functions.cos0 = 4/9 where sin0 < 0( sin, tan, csc, cot, sec)
Answers
we have that:
[tex]\sin ^2\theta=1-\cos ^2\theta=1-\frac{16}{81}=\frac{65}{81}\rightarrow\sin \theta=-\frac{\sqrt[]{65}}{9}[/tex]having this we get that
[tex]\tan \theta=\frac{-\sqrt[]{65}}{4},\cot \theta=-\frac{4}{\sqrt[]{65}},\sec \theta=\frac{9}{4},\csc \theta=-\frac{9}{\sqrt[]{65}}[/tex]Which postulate or theorem proves that these two triangles are
congruent?
• SAS Congruence Postulate
• ASA Congruence Postulate
O AAS Congruence Theorem
R
O HL Congruence Theorem
Answers
According to the Angle-Side-Angle Postulate (ASA), if two angles and an included side of one triangle are congruent to two angles and an included side of another triangle, the two triangles are congruent.
What is postulate?A postulate is a statement that is assumed to be true in the absence of proof. A theorem is an unprovable true statement. Six postulates and theorems that can be proven from them are listed below. A statement, also known as an axiom, that is assumed to be true in the absence of proof. Postulates are the fundamental building blocks from which lemmas and theorems are derived. Euclidean geometry, for example, is built around five postulates known as Euclid's postulates. A postulate is a statement accepted without evidence. A postulate is another name for an axiom.To learn more about postulate, refer to:
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The length of sides of a triangle are xem, (x + 1)cm and (x + 2)cm. Determine x so that this triangle is a right- angled triangle.
Answers
The value of x = 3
3cm, 4cm, and 5cm are the sides of a right-angled triangle.
What is Pythagoras theorem?
In a right-angled triangle, the hypotenuse is the largest of the three sides, so hypotenuse is (x +2).
As a result of Pythagoras' theorem,
hyp² = base² + alt²
here ,
x² + (x+1)² = (x+2)²
by simplifying the equation,
x² + x² + 2x +1 = x² + 4 + 4x
=> 2x² + 2x + 1 = x² + 4x + 4
=> x² - 2x -3 = 0
=> x² - 3x + x - 3 = 0
=> x(x-3) + 1(x-3) = 0
=> (x+1) (x-3) = 0
so, x+1 = 0 or x-3 = 0
x = -1 or x = 3
since length cannot be negative,
x = -1 is not considered .
so x= 3.
value of x is 3.
So the triangle's three sides are 3cm, 4cm, and 5cm.
to double-check the answer
Pythagoras' theorem substitute values
hyp² = b²+a²
hyp = [tex]\sqrt{3^{2}+4^{2} }[/tex]
= [tex]\sqrt{9+16}[/tex]
= [tex]\sqrt{25}[/tex]
= 5
As a result, the three sides of a right-angled triangle are 3cm, 4cm, and 5cm.
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Aviation A plane leaves an airport and flies south at 180 mph.
Later, a second plane leaves the same airport and flies south at
450 mph. If the second plane overtakes the first one in 12 hours,
how much of a head start did the first plane have?
Answers
The first plane had a head start of 432 minutes.
The speed, time and distance of any entity can be related by the following expression as Distance = Speed × Time. The speed of the first plane is 180 mph and the time given is 12 hours whereas the speed of second plane is 450 mph. Now, the distance travelled by plane A in time 12 hours is given by
Distance = Speed × Time
Distance = 180 × 12
Distance = 2160 miles.
The second also flies 2160 miles to overtake the first plane. It does this at a rate of 450 mph. So, the time taken for it to fly will be
Time = Distance/Speed
Time = 2160/450
Time = 4.8 hours
Since, 1 hour = 60 minutes, Therefore, 4.8 hours = 4.8×60 = 288 minutes. Now, since the first plane flies for 12 hours = 12×60 = 720 minutes. So, the head start = 720 minutes - 288 minutes = 432 minutes.
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Tools Question 2 Nicolas makes toys at a toy shop. The graph represents the relationship between the number of toys (1) that Nicolas makes and the number of hours Toy Making 50 45 40 35 30 Number of Toys 25 20 15 10 2 6 10 Number of Hours Which of the following equations represents a toy-making rate, in toys per hour, that is HALF that of Nicolas's toy-making rate?
Answers
The equation of a proportional relationship between two variables x and y with a constant of proportionality k, is:
[tex]y=kx[/tex]If y represents the number of toys and x represents the number of hours, substitute the corresponding values of x and y to find the constant of proportionality k. Use, for instance, the fact that Nicholas made 40 toys in 10 hours:
[tex]40=k\cdot10[/tex]Divide both sides of the equation by 10:
[tex]k=4[/tex]Since Nicholas's toy-making rate is 4 toys per hour, half that rate would be 2 toys per hour. Then, out equation would become:
[tex]y=2x[/tex]Using the letter "t" for toys instead of y and "h" for hours instead of x, then:
[tex]t=2h[/tex]A. Let h be the number of hours Chris worked. How many hours did Mark work?
Answers
a. We start by noting the number of hours Mark worked, given that h is the number of hours Chris worked.
To get this, we look for the relationship between the number of hours Mark worked and the number of hours Chris worked
From the question, we are told that they worked the same umber of hours, so the number of hours Mark worked is also h hours since they worked equal number of hours.
b. We shll now use the relationship with Kari for both Chris annd Mark to write two equations.
For Chris, we rae told that Kari worked twicw as many hours as he worked.
So if Chris worked h hoirs, then Kari worked 2 * h = 2h hours
For Mark, we are told that Kari worked 10 less than 3 times the number of hours Mark worked
The number of hours Mark worked was h hours, 3 times this is 3 * h = 3h
10 less than this would be (3h - 10) hours
c. An equation describing the expression above;
Since each expressin represents the number o hours Kari worked, then the two expressions must be equal.
Thus;
2h = 3h - 10
PLEASEEE HELP Find the rate of change of the line that contains the two points (1, 4) and (5, -4). Be sure to show all calculations and reduce your slope to a fraction in simplest form.
Answers
The rate of change of the line or the slope of the line that contains the two points (1, 4) and (5, -4) is m = 2
As per the question statement, we are supposed to find the rate of change of the line or the slope of the line that contains the two points (1, 4) and (5, -4).
We know slope [tex]m = \frac{y_{2}-y_{1}}{x_{2} -x_{1}}[/tex] for the line passing though the points (x1,y1) and (x2, y2)
Using the same formula and finding out the rate of change of the line or the slope of the line that contains the two points (1, 4) and (5, -4).
slope m = (-4-4)/(5-1)
m=-8/4
m = -2
Hence the rate of change of the line or the slope of the line that contains the two points (1, 4) and (5, -4) is m = 2
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3. Consider the following system of equations.Line 1: 2x - y = -3Line 2: -6x - 2y = -6Part A:Is (0,3) a solution to Line 1? Explain your answer.Part B:Is coordinate (0, -3) is a solution to Line 2? Explain your answer.Part C:What are the slopes of Linel and Line 2?Part D:What are the y-intercepts of Line 1 and Line 2?
Answers
Part A
replace (0,3) on (x,y)
[tex]\begin{gathered} 2(0)-(3)=-3 \\ 0-3=-3 \\ -3=-3 \end{gathered}[/tex]the equivalence is correct so (0,3) is a solution of the first equation
Part B.
replace (0,-3) on (x,y)
[tex]\begin{gathered} -6(0)-2(-3)=-6 \\ 0-(-6)=-6 \\ 6=-6 \end{gathered}[/tex]the equivalence is incorrect so (0,-3) isnt a solution of the second equation
Part C
To find the slope we need to solve each expresion and take the coefficient of x
first equation
[tex]\begin{gathered} 2x-y=-3 \\ y=2x+3 \end{gathered}[/tex]the slope is 2
second equation
[tex]\begin{gathered} -6x-2y=-6 \\ 2y=-6x+6 \\ y=-3x+3 \end{gathered}[/tex]the slope is -3
Part D
the y-intercept is the constant without variable on each equation
first equation
[tex]y=2x+3[/tex]the y-intercept is 3
second equation
[tex]y=-3x+3[/tex]the y-intercep is 3 too
The Graph
we need two points of the line and join by a right infinite line
first equation
the points (0,3) and (-3/2,0) belong to the line 1
second equation
the points (0,3) and (1,0) belong to the line 2
Solution of the system
we can note the two lines trought the point (3,0) so this is the solution and we can check matching the equations and solving x
[tex]\begin{gathered} 2x+3=-3x+3 \\ 2x+3x=3-3 \\ 5x=0 \\ x=0 \end{gathered}[/tex]and replace x=0 on any equation to solve y I will use the first equation
[tex]\begin{gathered} y=2x+3 \\ y=2(0)+3 \\ y=3 \end{gathered}[/tex]so the solution point is (0,3)
Solve the quadratic equation x2=2536.What are the solutions of the equation x2=2536?
Answers
Given
[tex]x^2=2536[/tex]Answer
[tex]\begin{gathered} x^2=2536 \\ x=5036 \end{gathered}[/tex]Please help and round to the nearest minute if needed
Answers
Solution
For this case we have the following angle:
30 1/6 º
and then we need to convert to degrees and minutes so we can do this:
1 º= 60 min
then 1/6º* (60min/ 1º)= 10 min
Then the answer is:
30º 60'
Kuta Software - Infinite Algebra 2 Graphing Absolute Value Equations Graph each equation. 1-1-11 Name Date > 1512020 2) y-lx-a 13
Answers
we have the equation
[tex]y=-3\lvert-2x+4\rvert+3[/tex]using a grahing tool
see the attached figure
The length of a rectangular room is 5 yards more than the width. If the area is 300 yd2, find the length and the width of the room.
Answers
Okay, here we have this:
Considering that the area of a rectangle is:
Area=length*width
Replacing we obtain:
300=(5+x)*x
300=5x+x²
0=5x+x²-300
0=(x-15)(x+20)
This mean that:
x-15=0 or x+20=0
x=15 or x=-20
And considering that the distances are positive we are left with the first solution, x=15; this mean that:
Width=15 yd
Length=(15+5) yd=20 yd.
Finally we obtain that the width is 15 yd and length is 20 yd.
Solve the inequality for x and identify the graph of its solution. 4[x+ 2] < 8
Answers
Answer:
x < 0
Step-by-step explanation:
4(x + 2) < 8
4x + 8 < 8
4x < 0
x < 0
◀━━━━━|──>
0
PLEASE HURRY
What is the quotient of (−152) ÷ (−19) ÷ (−4)?
Answers
Answer:
-2
I did the math and it came out -2
Jill works at a coffee shop on weekends. Every now and then, a customer will order a hot tea and ask Jill to surprise them with the flavor. The teas are categorized by flavor and caffeine level. Mint Fruity Caffeine-free 2 7 Caffeinated 5 5 What is the probability that a randomly selected tea is caffeinated or mint? Simplify any fractions.
Answers
The grand total is given by
[tex]n=2+7+5+5=19[/tex]so, the probability of Caffeinated is
[tex]P(Caffeinated)=\frac{5}{19}+\frac{5}{19}=\frac{10}{19}[/tex]the probability of mint is
[tex]P(\min t)=\frac{2}{19}+\frac{5}{19}=\frac{7}{19}[/tex]and the probability of the intersection is
[tex]P(Caffeinated\cap\min t)=\frac{5}{19}[/tex]Then, the probabilty of the union is given by
[tex]undefined[/tex]Let f(a) = x^2 + 5.a) Find the y-value when x = 0.The y-value, output value is ___b) Find the y-intercept, when x = 0.The y-intercept is ___c) Find the x-values, when y = 46.The x-values are ____
Answers
To solve a, we need to replace x = 0 in the formula of the function:
[tex]\begin{cases}f(x)=x^2+5 \\ x=0\end{cases}\Rightarrow f(0)=0^2+5=5[/tex]The y value when x = 0 is 5.
b is asking the same as a but in a different way. The y-intercept of a function is when x = 0, we just calculated that. The point of y-intercept is (0, 5)
Finally, to solve c, we need to find the values of x that gives us a value of f(x) = 46:
[tex]f(x)=46\Rightarrow46=x^2+5[/tex]Then solve:
[tex]\begin{gathered} x^2=46-5 \\ x=\pm\sqrt[]{41} \end{gathered}[/tex]Remember that we must that plus-minus the value when we take square root. ± √41 is the answer to c.
............sksksjsjsjs
Answers
9.823 x 10^-9 = 9.823/ 10^ 9
9.823/ 1000000000 = 0.000000009823
the long form has the same number of zeros that 10^-9, then it have 9 zeros.
Janie has $3dollar sign, 3. She earns \$1.20$1.20dollar sign, 1, point, 20 for each chore she does and can do fractions of chores. She wants to earn enough money to buy a CD for $13.50
Answers
The inequality to represent the situation for Janie will be 3 + 1.2c > 13.50.
How to calculate the inequality?From the information, it was illustrated that Janie has $3 and that she earns $1.20 for every chore.
Let the total number of chores that she can do be represented as c.
It should be noted that she also wants about $13.50 to buy her CD. Therefore, the inequality can be represented as:
3 + (1.2 × c) > 13.50
3 + 1.2c > 13.50
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Beginning with the general form of a quadratic equation. ax^2+bx+c=0, solve for x by using the completing the square method, thus deriving the quadratic formula. To earn full credit be sure to show all steps/calculations. You may want to do the work by hand and upload a picture of that written work rather than try to type it out.
Answers
to solve ax^2 + bx + c = 0 using completing the square method
divide all terms by a so as to reduce the coefficient of x^2 to 1
x^2 + bx/a + c/a = 0
subtract the constant term from both sides of the equation
x^2 + bx/a = -c/a
to have a square on the left sie the third term (constant) should be
(b/2a)^2
so add that amount to both side
x^2 + bx/a + (b/2a)^2 = (b/2a)^2 - c/a
rewrite the left side as a square
(x + (b/2a))^2 = (b/2a) - c/a
take the square root of both sides
x + (b/2a) = + square root of (b/2a)^2 - c/a
subtract the constant term on the left side from both sides
[tex]\begin{gathered} x\text{ = }\pm\sqrt[]{(\frac{b}{2a}})^2\text{ - c/a - (b/2a)} \\ x\text{ = -b }\pm\sqrt[]{\frac{b^2\text{ - 4ac}}{2a}} \end{gathered}[/tex]Hi, can you help me to evaluate (if possible) thesix trigonometric functions of the real number.Please.
Answers
Okay, here we have this:
Considering the provided angle, we are going to evaluate the trigonometric functions, so we obtain the following:
Sine:
[tex]\begin{gathered} \sin (-\frac{2\pi}{3}) \\ =-\sin (\frac{2\pi}{3}) \\ =-\cos \mleft(\frac{\pi}{2}-\frac{2\pi}{3}\mright) \\ =-\cos \mleft(-\frac{\pi}{6}\mright) \\ =-\cos \mleft(\frac{\pi}{6}\mright) \\ =-\frac{\sqrt{3}}{2} \end{gathered}[/tex]Cos:
[tex]\begin{gathered} cos\mleft(-\frac{2\pi}{3}\mright) \\ =\cos \mleft(\frac{2\pi}{3}\mright) \\ =\sin \mleft(\frac{\pi}{2}-\frac{2\pi}{3}\mright) \\ =\sin \mleft(-\frac{\pi}{6}\mright) \\ =-\sin \mleft(\frac{\pi}{6}\mright) \\ =-\frac{1}{2} \end{gathered}[/tex]Tan:
[tex]\begin{gathered} tan\mleft(-\frac{2\pi\:}{3}\mright) \\ =\frac{\sin (-\frac{2\pi\: }{3})}{\cos (-\frac{2\pi\: }{3})} \\ =\frac{-\frac{\sqrt[]{3}}{2}}{-\frac{1}{2}} \\ =\sqrt[]{3} \end{gathered}[/tex]Csc:
[tex]\begin{gathered} \csc \mleft(-\frac{2\pi}{3}\mright) \\ =\frac{1}{\sin\left(-\frac{2\pi}{3}\right)} \\ =-\frac{1}{\frac{\sqrt{3}}{2}} \\ =-\frac{2\sqrt{3}}{3} \end{gathered}[/tex]Sec:
[tex]\begin{gathered} \sec \mleft(-\frac{2\pi}{3}\mright) \\ =\frac{1}{\cos\left(-\frac{2\pi}{3}\right)} \\ =\frac{1}{-\frac{1}{2}} \\ =-2 \end{gathered}[/tex]Cot:
[tex]\begin{gathered} \cot \mleft(-\frac{2\pi}{3}\mright) \\ =\frac{1}{\tan (-\frac{2\pi}{3})} \\ =\frac{1}{\sqrt[]{3}} \\ =\frac{\sqrt{3}}{3} \end{gathered}[/tex]i’m trying to find the slope and y intercept of number 2.. can someone help me please. thank you (:
Answers
According to the problem,
• Jennifer is 20 miles North.
,• The rate is 55 miles per hour.
Remember that rate of change refers to the slope.
Therefore, the slope is 55.
On the other hand, the y-intercept is the initial condition of the problem since Jennifer started 20 miles North, then the y-intercept is (0,20).