Answer:
8,-9,9
Step-by-step explanation:
The following condensed information was reported by Peabody Toys, Inc., for 2021 and 2020: ($ in thousands) 2021 2020 Income statement information Net sales $ 6,900 $ 5,900 Net income 374 158 Balance sheet information Current assets $ 970 $ 920 Property, plant, and equipment (net) 2,630 2,280 Total assets $ 3,600 $ 3,200 Current liabilities $ 1,660 $ 1,310 Long-term liabilities 920 920 Common stock 700 700 Retained earnings 320 270 Liabilities and shareholders’ equity $ 3,600 $ 3,200 Required: Determine the following ratios for 2021: (Round your percentage answers to 1 decimal place.) Determine the amount of dividends paid to shareholders during 2021. (Enter your answers in whole dollars, not in thousands. For example, $150,000 rather than 150.)
1a. Profit margin on sales 5.4 %
1b. Return on assets %
1c. Return on equity %
2. Dividends paid ?
Answer:
The answers are given below.
Step-by-step explanation:
The computation is shown below:
1.a.
Profit Margin = Net Income ÷ Sales × 100
= $374 ÷ $6,900 ×100
= 5.4%
1-b:
Average Assets = (Beginning Assets + Ending Assets) ÷ 2
= ($3,200 + $3,600) ÷ 2
= $3,400
Now
Return on Assets = Net Income ÷ Average Assets
= $374 ÷ $3,400
= 11%
1-c
Average Equity = ($700 + $700 + $320 + $270) ÷ 2
= $995
Now
Return on Equity = Net Income ÷ Average Equity *100
= $374 ÷ $995
= 37.59%
2:
Dividends Paid = Beginning Retained Earnings + Net Income – Ending Retained Earnings
= $270 + $374 - $320
= $324
Find the surface area of the prism.
Answer:
D
Step-by-step explanation:
Base area = (leg 1 x leg 2)/2 = (9 x 12)/2 = 54 ft^2
Base perimeter = leg 1 + leg 2 + hypotenuse = 9 + 12 + 15 = 36 ft
LA= base perimeter x 24 = 36 x 24 = 864 ft^2
SA = 2 x base area + LA = 54 x 2 + 864 = 972 ft^2
Question in pic, please help
Answer:
The first one
(I can't see it too properly but if the dot on -10 has a hole in it then this is the answer)
(7.3 × 10-9) + (1.5 × 10−9) in standard form
Answer:
The answer in standard form is 70.
Answer:
(7.3*10-9)+(1.5*10-9)
(73-9)+(15-9)
64+6=70
Step-by-step explanation:
8. In rural third world countries, farmers use a
conical bucket, the "Gầu Dây” to drain/transfer
water from one rice field to another. If the height
is 20" & the diameter of the opening is 15”, how
much cubic feet of water can two farmers drain
in three hours if their rate is 28 “gầu" per
minute?
9514 1404 393
Answer:
6872 cubic feet
Step-by-step explanation:
The volume of the conical bucket is ...
V = 1/3πr²h
V = 1/3π(15/2 in)²(20 in) = 375π in³
There are 60 minutes in 1 hour, so 3×60 = 180 minutes in 3 hours.
If each of 2 farmers can transfer 28 buckets per minute the total amount transferred is ...
(375π in³)(180 min)(2 farmers)(28/min/farmer) = 3,780,000π in³
There are 1728 in³ in 1 ft³, so this is ...
(3,780,000π/1728) ft³ = 2187.5π ft³, about 6872 cubic feet.
If the sixth term of a geometric sequence is 972, and the tenth term is 78732, what is
the first term?
Answer:
the first term is 4
HELP SUMMER ALGEBRA 2! the rest of the answer d is numerator and denominator of both fractions
9514 1404 393
Answer:
the correct choice is marked
Step-by-step explanation:
The denominators of the two fractions must be the same. To make that happen, Juan can multiply the second fraction by (x-2)/(x-2) -- the marked answer choice -- and multiply the first fraction by 3/3. These operations can be done in some order.
The offered choices suggest that treating the second fraction first is Juan's preferred choice.
multiply the second fraction by (x-2)/(x-2)The average mass of a grain of sand is 1.5 x 10^-5 grams. Erin's sandbox has approximately 3.067 x 10^11 grains of sand in it. What is the mass of the sand in Erin's sandbox?
Answer:
4.6005 * 10^6 grams
Step-by-step explanation:
Average mass of sand grain = 1.5 * 10^-5 grams
Number of grains in Erin's sandbox = 3.067 * 10^11 grains
To obtain the mass of sand in Erin's grain box :
We multiply the mass per sand grain and the number of grains
(1.5 * 10^-5) * (3.067 * 10^11)
1.5 * 3.067 = 4.6005 * (10^(-5+11))
4.6005 * 10^6 grams
Which expression is equivalent to
3/14x + (- 1) + (- 4) – 2/7x?
Choose the correct answer below.
A. -5 1/14x - 5
B. 5 1/14x + 5
C. -1/14x - 5
D. 5/14x - 5
Answer:
A and b
Step-by-step explanation: Because ....
A box has seven orange hats and 19 yellow hats if you pick three hats without replacement what is the probability that you pick at least two orange hats from the box?
Answer:
a chance of 3.16
Step-by-step explanation:
What is the factorization of the trinomial below?
x2 - 6x + 5
O A. (X - 4)(x - 2)
O B. (X - 5)(x - 1)
O C. (x + 4)(x - 2)
O D. (x + 5)(x - 1)
B. [tex](x - 5)(x - 1)[/tex] ✅
Step-by-step explanation:
[tex] {x}^{2} - 6x + 5 \\ \\ = \:{x}^{2} - 5x - x + 5 [/tex]
Taking [tex]x[/tex] as common from first two terms and 1 from last two terms, we have
[tex] =\: x(x - 5) - 1(x - 5)[/tex]
Taking the factor [tex](x-5)[/tex] as common,
[tex]=\:(x - 5)(x - 1)[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]
what is the measure of angle W in the figure
Evaluate the expression when b= 2 and c=-5. -b+6c
Answer:
-32
Step-by-step explanation:
- 2 + 6 * -5 = -32
Answer:
- 32
Step-by-step explanation:
- b + 6 c
Where we've
b = 2 and c = -5- ( 2 ) + 6 ( -5 )
- 2 - 30
Urgent!! Please I'm flan cup!!!
using data from 2010 and projected to 2020, the population of the United Kingdom (y, in millions) can be approximated by the equation 10.0y-4.55x=581. where x is the number of years after 2000 what is projected population in 2026?
Answer:
The projected population in 2026 is of 699.3 million.
Step-by-step explanation:
Population:
The population, in x years after 2000, is given by the follwing equation:
[tex]y - 4.55x = 581[/tex]
That is:
[tex]y(x) = 4.55x + 581[/tex]
What is projected population in 2026?
2026 - 2000 = 26, so this is y(26).
[tex]y(26) = 4.55(26) + 581 = 699.3[/tex]
The projected population in 2026 is of 699.3 million.
Simplify the given expression and enter in numerical form.6+5
Answer:
6+5=11
Step-by-step explanation:
6 is added to 5
i am sorry if i am wrong
which expresion is equivalent to-12(3x-3/4)
A -36x-8
B -36x+8
C -36x-9
D -36x+9
The perimter of a rectangle is 34 units. Its width is 6.5 units. Write an equation to determine the length (l) if the rectangle
Answer:
Step-by-step explanation:
P=2(w)+2(l)
34=2(6.5)+2(l)
34=13+2(l)
21=2(l)
10.5=l
2x^2=50 solve the equation algebraically?
A trapezoid has bases that measure 9 cm and 5 cm. The height of the figure is 4 cm. What is the area of the trapezoid?
?
O 28 cm
O 36 cm
O 45 cm
O 90 cm?
Answer:
28 square centimeters
Step-by-step explanation:
The area of a trapezoid (formula):
(a + b) ÷ 2 x h
Where a & b are the bases, and h is height.
Use formula with given measurements:
(9 + 5) ÷ 2 x 4 = 28
Area is measured in square centimeters
(centimeters in this case)
Therefore the area if the trapezoid is 28 cm^2
I really hope this helps!
Determine algebraically whether the function is even, odd, or neither even nor odd.
f(x) = -3x^4 - 2x - 5
Neither
Even
Odd
Answer:
Neither
Step-by-step explanation:
let X1 and X2 have the joint pdf, f(x1, x2) 0
Answer:
Please find the complete question in the attached file.
Step-by-step explanation:
For point a:
[tex]\to fx_1(x_1)=\int^{x_{1}}_{0} f(x_1,x_2)\ dx\\\\[/tex]
[tex]=\int^{x_{1}}_{0} e^{-x_1}\ dx_2\\\\= e^{-x_1} \ [x_2]^{x_1}_0 \\\\\therefore f x_1(x_1)=x_1e^{-x_1}; \ \ x_1>0\\\\[/tex]
For point b:
[tex]\to f(x_2|x_1)=\frac{f(x_1,x_2)}{f(x_1)}\ =\frac{e^{-x_1}}{x_1\ e^{-x_1}}=\frac{1}{x_1} ; \\\\ \ \ 0\leq x_2 \leq x_1 \\\\[/tex]
For point c:
[tex]P(x_1>2|x_2=7)= 1.00 \\\\\because x_2=7\to x_1>7\to x_1>2\\\\[/tex]
Define the word coeffcent
Answer:
Step-by-step explanation:
a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4x y).
or:
a multiplier or factor that measures some property.
Can y’all help me on question 27?!
Answer:
A cube can be made out of this
Step-by-step explanation:
Hope this helps you :)
Help solve this problem
Answer:
x = -7
Step-by-step explanation:
(x + 14) + (x + 12) = 12
Combine like terms
2x + 26 = 12
Subtract 26 from both sides
2x = -14
Divide both sides by 2
x = -7
Answer:
Step-by-step explanation:
PQ +QR = PR
x + 14 + x + 12 = 12
Combine like terms
x + x + 14 + 12 = 12
2x + 26 = 12
Subtract 26 from both sides
2x = 12 - 26
2x = -14
Divide both side by 2
x = -14/2 =
x = -7
Calculate a critical z-score for a left-tailed, right-tailed, or two-tailed test.
a. The critical z-score for a left-tailed test at a 12% significance level is -0.45.
b. The critical z-score for a right-tailed test at a 9% significance level is 1.34.
c. The critical z-score for a two-sided test at a 4% significance level is 1.75.
d. The critical z-score for a two-sided test at a 20% significance level is 0.85.
Answer:
a. Z = -1.175.
b. Z = 1.34.
c. |Z| = 2.054.
d. |Z| = 1.28.
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
a. The critical z-score for a left-tailed test at a 12% significance level
Left-tailed test: The region of interest is the 12th percentile or below.
Thus, the critical z-score is Z with a p-value of 0.12, so Z = -1.175.
b. The critical z-score for a right-tailed test at a 9% significance level
Right-tailed test: The region of interest is the 100 - 9 = 91th percentile and above.
Thus, the critical z-score is Z with a p-value of 0.91, so Z = 1.34.
c. The critical z-score for a two-sided test at a 4% significance level is 1.75.
Two-tailed test: The region of interest is between the 4/2 = 2th percentile and the 100 - (4/2) = 98th percentile.
Thus, the critical z-score is |Z| with a p-value of 0.02 or 0.98, so |Z| = 2.054.
d. The critical z-score for a two-sided test at a 20% significance level is 0.85.
Region of interest is between the 20/2 = 10th percentile and the 100 - (20/2) = 90th percentile.
Thus, the critical z-score is |Z| with a p-value of 0.1 or 0.9, so |Z| = 1.28.
Can someone help me solve this
Answer:
Yup! There are 6 possible 0s, 4 actual 0s, and the factored form is -2x^5-6
Step-by-step explanation:
Solve the equation for w 5(w-2)+10=2w+6
Answer:
w=2
Step-by-step explanation:
See image below:)
Answer:
w = 1/2 or w = 3/6
Step-by-step explanation:
5(w-2) + 10 = 2w + 6
5(w-2) + 10 = 5w + 10 - 10 = 5w (the 5 outside of the bracket multiplies with the digits inside, including the w)
Now you have : 5w = 2w+6
Transfer the 2w to the left side, which would make it negative, therefore
5w - 2w= 6
3w = 6
w = 3/6
or
w = 1/2 (simplified)
The formula A(t) = 756e^(0.035)t models the growth of an investment due to continuously compounded interest. What does 0.035 stand for?
A) the numbers of years since the initial investment
B) the amount after t years
C) the initial amount invested
D) the interest rate
Answer:
D) the interest rate
Step-by-step explanation:
The formula for continuously compounded interest is [tex]A(t)=Pe^{rt[/tex] where [tex]P[/tex] is the principal/initial value, [tex]r[/tex] is the interest rate in decimal form, and [tex]t[/tex] is the amount of time since the initial investment. In this case, [tex]r=0.035[/tex] would be an annual interest rate of 3.5% per year.
For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r < d. n = −67, d = 8
Answer:
[tex]q = 8[/tex]
[tex]r = 3[/tex]
Step-by-step explanation:
Given
[tex]n = dq + r[/tex]
[tex]0 \le r < d[/tex]
[tex]n = 67[/tex] --- not -67
[tex]d = 8[/tex]
Required
Find q and r
Substitute values for d and b
[tex]n = dq + r[/tex]
[tex]67 = 8 * q + r[/tex]
[tex]67 = 8q + r[/tex]
Make q the subject
[tex]q = \frac{67 - r}{8}[/tex]
[tex]0 \le r < d[/tex] means that r is less than 8 but greater than or equal to 0
And r and q are integers.
Let [tex]r = 3[/tex]
[tex]q = \frac{67 - 3}{8}[/tex]
[tex]q = \frac{64}{8}[/tex]
[tex]q = 8[/tex]
No other true values of r and q can be gotten.